Return top N rows ordered by date after table join - sql

Question

I posted a few weeks back with an issue, now I've gotten past it and found a new need and new issue. I'm using access 2010, unsure what version database, have on;y access grunt tools to use (no objects, for instance). I have a query that works, it looks like this. The goal of this query is to use one row as a baseline and find all related rows that come after it chronologically. For all I know, this may be a very crude solution.
SELECT QueueA.cnlyMemberId, QueueA.updateUser AS 305UpdateUser, QueueA.updateDt AS 305UpdateDt, QueueB.statusCd
FROM (SELECT cnlyMemberID, updateUser, updateDt
FROM V_Queue_History
WHERE statusCd = "305" AND
V_Queue_History.updateDt Between [Enter Start Date:] And [Enter End Date: (must be at least one day apart)]
) AS QueueA INNER JOIN
V_Queue_History AS QueueB
ON (QueueA.cnlyMemberID = QueueB.cnlyMemberID AND
QueueA.updateDt < QueueB.updateDt
)
Now what I want to do is I want to find the first 305 statusCd and the next statusCd chronologically, rather than every statusCd that follows. I've tried a few things now, mostly trying to take the TOP 2 with an ORDER BY updateDt slipped in the ON condition. Then I tried replacing the V_Queue_History with a table and doing the same, didn't work. I just tried using a where condition where I check to see if the
QueueB.cnlyMemberId is IN (SELECT TOP 2 cnlylMemberID FROM QueueB WHERE conditions);
but still nothing. The system would tell me it didn't know what QueueB was anymore, so none of it would run in the WHERE statement. I would be more specific on but I just made Access crash and my mind is starting to get hazy from how frustrating this can be. I don't have much experience with Access/SQL at all and I'm learning it pretty much as I go.
So to recap, the first query runs fine but I need to return only the row with the status updated first after the initial 305.
Thanks!

Answer 1

I'm not sure what you want without a sample output, maybe something like this would help:
SELECT QueueA.cnlyMemberId, QueueA.updateUser AS 305UpdateUser, QueueA.updateDt AS 305UpdateDt, QueueB.statusCd
FROM (SELECT cnlyMemberID, updateUser, updateDt
FROM V_Queue_History
WHERE statusCd = "305" AND
V_Queue_History.updateDt Between [Enter Start Date:] And [Enter End Date: (must be at least one day apart)]
) AS QueueA INNER JOIN
V_Queue_History AS QueueB
ON QueueA.cnlyMemberID = QueueB.cnlyMemberID
WHERE (QueueB.updateDt =
(SELECT Min(updateDt) FROM V_Queue_History V2
WHERE V2.cnlyMemberID = QueueA.cnlyMemberID
AND V2.updateDt > QueueA.updateDt))
This assumes there is always a status code after the 305, and also that no two records have the same update date.
If you need to get the top N status codes after the 305 then you could change the WHERE clause as following, although I don't know if the performance will be good enough for your situation:
WHERE QueueB.updateDt IN
(SELECT TOP 5 updateDt FROM V_Queue_History V2
WHERE V2.cnlyMemberID = QueueA.cnlyMemberID
AND V2.updateDt > QueueA.updateDt
ORDER BY V2.updateDt)