I have a table old_data and a table new_data. I want to write a select statement that gives me
Rows in old_data stay there
New rows in new_data get added to old_data
unique key is id so rows with id in new_data should update existing ones in old_data
I need to write a select statement that would give me old_data updated with new data and new data added to it.
Example:
Table a:
id count
1 2
2 19
3 4
Table b:
id count
2 22
5 7
I need a SELECT statement that gives me
id count
1 2
2 22
3 4
5 7
Based on your desired results:
SELECT
*
FROM
[TableB] AS B
UNION ALL
SELECT
*
FROM
[TableA] AS A
WHERE
A.id NOT IN (SELECT id FROM [TableB])
I think this would work pretty neatly with COALESCE:
SELECT a.id, COALESCE(b.count, a.count)
FROM a
FULL OUTER JOIN b
ON a.id = b.id
Note - if your RDBMS does not contain COALESCE, you can write out the function using CASE as follows:
SELECT a.id,
CASE WHEN b.count IS NULL THEN a.count
ELSE b.count END AS count
FROM ...
You can write a FULL OUTER JOIN as follows:
SELECT *
FROM a
LEFT JOIN b
ON a.id = b.id
UNION ALL
SELECT *
FROM b
LEFT a
ON b.id = a.id
You have to use UPSERT to update old data and add new data in Old_data table and select all rows from Old_data. Check following and let me know what you think about this query
UPDATE [old_data]
SET [count] = B.[count]
FROM [old_data] AS A
INNER JOIN [new_Data] AS B
ON A.[id] = B.[id]
INSERT INTO [old_data]
([id]
,[count])
SELECT A.[id]
,A.[count]
FROM [new_Data] AS A
LEFT JOIN [old_data] AS B
ON A.[id] = B.[id]
WHERE B.[id] IS NULL
SELECT *
FROM [old_data]
Related
Table A Table B Table B Table B
Itemnr Itemnr Item Status Remark
100000 100000 1 Approved
200000 100000 2 Use up
100000 3 Obsolete
200000 1 Approved
200000 2 Use up
200000 3 Obsolete
I would like to see only one result per line in table A item with as result the Remark based on Item status 1. I tried a lot with the option of a left join but without the good result.
Is this what you want?
select a.itemnr, b.remark
from tablea a
inner join tableb b on b.itemnr = a.itemnr and b.item_status = 1
If some records in tablea might not have a corresponding row in tableb with item_status = 1 and you want to keep these in the resultset, then you can use left join instead of inner join.
For the data example you have provided, you don't need tablea:
select b.itemnr, b.remark
from tableb b
where b.item_status = 1;
You specify that you want a left join, which implies rows in tablea that are not in tableb, although you have no such examples in the question. In that case:
select a.itemnr, b.remark
from tablea a left join
tableb b
on b.itemnr = a.itemnr and b.item_status = 1;
You can use row_number()
select t.*
from (select a.*, b.*, row_number() over (partition by a.itemr order by b.status) as seq
from a inner join
b
on a.itemr = b.itemr
) t
where seq = 1;
This will return rows total itemrs along with first status. Also this assumes Itemnr, Item Status, Remark are the columns name.
EDIT : If you want to check, first status 1 is available or not then you can do :
SELECT a.itemr, b.remark
FROM a LEFT JOIN
b
ON b.itemr = a.itemr AND b.status = 1;
I'm struggling getting this query to produce the results I want.
I have:
table1, columns=empid, alt_id
table2, columns=empid, alt_id
I want to get the empid, and alt_id from table 1 where the alt_id does not match the alt_id in table2. They will both have alt_id numbers I just want to get the ones that do not match.
Any ideas?
SELECT * FROM table1
INNER JOIN table2 ON table2.empid = table1.empid AND table2.alt_id <> table1.alt_id
What does that really mean though? Normally when this is asked, it is of the form "I want all rows from A that have no row matching in B and all in B that have no match in A"
Which looks like this:
SELECT * FROM
A
FULL OUTER JOIN
B
ON
a.id = b.id
You'll see a null for any row data where there isn't a matching row on the other side:
A.id
1
2
B.id
1
3
Result of full outer join:
A.id B.id
1 1
2 null
null 3
You, however have asked for A-B join where the IDs aren't equal, which would be the more useless query of:
SELECT * FROM
A
INNER JOIN
B
ON
a.id != b.id
And it would look like:
A.id B.id
1 3
2 1
2 3
You seem to want not exists:
select t1.*
from table1 t1
where not exists (select 1 from table2 t2 where t2.alt_id = t1.alt_id);
It is unclear whether or not you also want to join on empid, so you might really want:
select t1.*
from table1 t1
where not exists (select 1 from table2 t2 where t2.alt_id = t1.alt_id and t2.empid = t1.empid);
A left join will find all records in Table A that do not match those in Table B. Then use a Where filter to find the Nulls from Table B. That will give you all those in Table A that do not have a matching ID in Table B.
Select A.*
from Table A
Left Join
Table B
on a.altid = b.altid
where b.altid is null;
select *
from [Login] L inner join Employee E
on l.EmployeeID = e.EmployeeID
where l.EmployeeID not in (select EmployeeID from Employee)
I'm trying to get all ids from one table and a count of transactions from another table. The trick is that an id may not be listed in the transaction table. In that case, I want the query to return 0 for that id. (I apologize for the bad formatting)
ID Table
ID
1
2
3
Trans Table
ID Trans
1 123
1 234
3 345
3 456
3 567
Query results
ID - Trans Count
1 2
2 0
3 3
I have this code, but it just isn't working for me and I can't figure out why.
SELECT A.ID, COUNT (B.TRANS) AS CNT
FROM A
LEFT JOIN B
ON A.ID = B.ID
WHERE B.DTE BETWEEN '01-Mar-2017' AND '31-Mar-2017' AND
A.CURRENT_FLAG = 1
GROUP BY A.ID
When using left join, conditions on the first table go in the where clause. Conditions on the second table go in the on clause:
SELECT A.ID, COUNT (B.TRANS) AS CNT
FROM A LEFT JOIN
B
ON A.ID = B.ID AND
B.DTE BETWEEN '01-Mar-2017' AND '31-Mar-2017' AND
WHERE A.CURRENT_FLAG = 1
GROUP BY A.ID;
I would check if the value is null if then just replace it with a 0
The NVL Function will work perfect for this scenario.
SELECT A.ID, COUNT (NVL(B.TRANS,0)) AS CNT
FROM A
LEFT JOIN B
ON A.ID = B.ID
WHERE B.DTE BETWEEN '01-Mar-2017' AND '31-Mar-2017' AND A.CURRENT_FLAG = 1
GROUP BY A.ID
i have 3 tables. Table a pk = userid, table b and c fk = userid. On table b RoleID column is equal to Usermanager column from table c but w a new value.
So i joined table a and b with below query
select a.Username, a.Userid, b.Roleid
from NewTable a
join RoleTable b
on a.UserID=b.UserID
where b.RoleID = 2
This results in 502 records.
Table c query is
select *
from OldTable
where UserManager = 1
and Authorized = 1
and Status = 'A'
This results in 500 records.
So I'm trying to join the 2 queries to find the 2 records that are not on table c but are only on table a.
Thanks.
Try this:
select a.Username, a.Userid, b.Roleid
from NewTable a
join RoleTable b
on a.UserID=b.UserID
where
b.RoleID = 2
AND
NOT EXISTS
(select *
from OldTable AS c
where c.UserManager = 1
and
c.Authorized = 1
and
c.Status = 'A'
AND
a.userid = c.userid)
I used the two queries you mentioned you were using and just made the table c query into a WHERE NOT EXISTS subquery. It should provide those 2 results you are looking for.
Something like this should do the trick. You can work out the details for your database.
select fields
from tableA join tableB on something
where whatever
and tableA.someField in
(select someField
from tableA join tableB on something
where whatever
except
select someEquivalentField
from tableC)
The two where whatevers should be the same.
If I understand your question correctly... the following will join Table A and Table C and then find those that dont have corresponding values in Table C
Select * from Table A A
LEFT JOIN Table C C On A.UserId = C.UserId
Where C.UserId is NULL
This is the basic concept.. you need to work on it to get the syntax to fit your motives
You can do this with a Left Join
select subA.*
from (
select a.Username, a.Userid, b.Roleid
from NewTable a
join RoleTable b
on a.UserID=b.UserID
where b.RoleID = 2
) subA
left join (
select userID
from OldTable
where UserManager = 1
and Authorized = 1
and Status = 'A'
) subB
on subA.Userid = subB.UserID
Where subB.userid is null
I have a table name "a"
Id name
1 abc
2 xyz
3 mmm
4 xxx
and Other table name is "b"
Id suId
3 2
3 1
My requirement is get detail from "a" table from "b" table where id=3. Any help?
SELECT a.Id, a.name, b.Id, b.suId FROM b JOIN a ON b.suId = a.Id WHERE b.Id = 3;
I wont recommend join for this kind of scenarios(you want all details from Table A whose ids are in Table B suId column, where Table B id should be 3., Its bad English but hope you got me and may be i got you too.)
SELECT a.name FROM a
WHERE
a.id IN(SELECT b.suId FROM b WHERE b.id = 3);
If you want to use join only then,
SELECT a.name FROM a,b
WHERE a.id = b.suId
AND
b.id = 3;
Simple answer:
SELECT a.Id,a.name FROM a,b
WHERE a.Id=b.suId AND b.Id=3
It will give you the result:
Id Name
1 abc
2 xyz
See result in SQL Fiddle
This should get the job done:
SELECT * FROM table_a a JOIN table_b b ON b.suId = a.Id WHERE b.Id = 3;
You can try this...You can try different JOIN clauses like INNER JOIN, LEFT OUTER JOIN or just simply JOIN etc. You will get different number of rows depending on field connections from 1 table to the other.
SELECT T1.*
FROM a T1
INNER JOIN b T2
ON T1.Id = T2.Id
WHERE T1.Id='3'