I've got a dataset (exposed via D2RQ) from which I can run the following SPARQL query
SELECT ?index ?freetext ?label WHERE
{
?s a prov:Agent ;
skos:notation ?index.
?s skos:description ?freetext .
OPTIONAL { ?s skos:prefLabel ?label }
}
and get a sensible result back:
index freetext label
--------------------------
1 "Some text containing Manchester" "Lancashire"
2 "Some text containing Liverpool" -
3 "Some text containing Manchester and Liverpool" "The North"
4 "Some text containing London" -
So far so good... now, I want to return the rows mentioning Liverpool:
SELECT ?index ?freetext ?label WHERE
{
?s a prov:Agent ;
skos:notation ?index.
?s skos:description ?freetext .
OPTIONAL { ?s skos:prefLabel ?label }
FILTER (regex(str(?freetext), "Liverpool", "i"))
}
which I want to return
index freetext label
--------------------------
2 "Some text containing Liverpool" -
3 "Some text containing Manchester and Liverpool" "The North"
but this returns all 4 rows again - i.e. the filtering is having no effect. I have tried every combination of FILTER EXISTS, FILTER NOT EXISTS, MINUS, subquerying, etc I can think of, but to no avail.
Is what I'm trying to do possibe?
Related
<This question is now resolved, see comment by Valerio Cocchi>
I am trying to pass a variable from a subquery, that takes the minimum date of a set of dates ?date1 belonging to ?p and passes this to the outer query, which then takes another date ?date2 belonging to ?p (there can be at most 1 ?date2 for every ?p) and subtracts ?minDate from ?date2 to get an integer value for the number of years between. I am getting a blank value for this, i.e. ?diffDate returns no value.
I am using Fuseki version 4.3.2. Here is an example of the query:
SELECT ?p ?minDate ?date2 ?diffDate
{
?p a abc:P;
abc:hasAnotherDate ?date2.
BIND((YEAR(?minDate) - YEAR(?date2)) AS ?diffDate)
{
SELECT ?p (MIN(?date1) as ?minDate)
WHERE
{
?p a abc:P;
abc:hasDate ?date1.
} group by ?p
}
}
and an example of the kind of result I am getting:
|-?p----|-----------------?minDate-------------|-----------------?date2------------- |?diffDate|
|<123>|20012-11-22T00:00:00"^^xsd:dateTime|2008-08-18T00:00:00"^^xsd:dateTime| |
I would expect that ?diffDate would give me an integer value. Am I missing something fundamental about how subqueries work in SPARQL?
It seems you have encountered quite an obscure part of the SPARQL spec, namely how BIND works.
Normally SPARQL is evaluated without regard for the position of atoms, i.e.
SELECT *
WHERE {
?a :p1 ?b .
?b :p2 ?c .}
is the same query as:
SELECT *
WHERE {
?b :p2 ?c .
?a :p1 ?b .}
However, BIND is position dependent, so e.g.:
SELECT *
WHERE {
?a :p1 ?b .
BIND(:john AS ?a)}
is not a valid query, whereas:
SELECT *
WHERE {
BIND(:john AS ?a)
?a :p1 ?b .
}
is entirely valid. The same applies to variables used inside of the BIND, which must be declared before the BIND appears.
See here for more.
To go back to your problem, your BIND is using the ?minDate variable before it has been bound, which is why it fails to produce a value for ?diffDate.
This query should do the trick:
SELECT ?p ?minDate ?date2 ?diffDate
{
?p a abc:P;
abc:hasAnotherDate ?date2.
{
SELECT ?p (MIN(?date1) as ?minDate)
WHERE
{
?p a abc:P;
abc:hasDate ?date1.
} group by ?p
}
BIND((YEAR(?minDate) - YEAR(?date2)) AS ?diffDate) #Put the BIND after all the variables it uses are bound.
}
Alternatively, you could evaluate the difference in the SELECT, like so:
SELECT ?p ?minDate ?date2 (YEAR(?minDate) - YEAR(?date2) AS ?diffDate)
{
?p a abc:P;
abc:hasAnotherDate ?date2.
{
SELECT ?p (MIN(?date1) as ?minDate)
WHERE
{
?p a abc:P;
abc:hasDate ?date1.
} group by ?p
}
}
In my turtle file I have 2 lines with the same predicate, but different values:
1_schema:hasObject <http://dzx/op/P007865> ;
1_schema:hasObject <http://dzx/op/P001176> ;
I'm using the following to retrieve both values:
SELECT ?result
FROM <urn:graph>
WHERE
{ ?s <http://purl.org/dc/terms/identifier> ?identifier.
OPTIONAL { ?s <http://xxx#hasObject ?result .}
}
The problem is that I'm getting only one result from two expected http://dzx/op/P007865 http://dzx/op/P001176
I want to edit a set of URIs replacing a substring "iso-693" with "iso-639" using a SPARQL query. I am using REPLACE but it doesn't seem to do anything.
I have a large SKOS taxonomy with URIs that have an incorrect string. They should have this string: "iso-639" but I made a mistake when creating it and put "iso-693". I'd like to correct it. I used the SPARQL query shown below, which when run returns a message "update successful", but none of the triples data actually changes. Where am I going wrong?
INSERT
{
?s ?p ?o2
}
WHERE
{
?s ?p ?o .
FILTER (regex(str(?s), "iso-693") || regex(str(?o), "iso-693"))
BIND(REPLACE(?o, "iso-693", "iso-639", "i") AS ?o2) .
}
I expected all of the occurrences of the substring to change to the desired value, but nothing seems to change at all despite the success message.
You are missing the bit that removes the old value (INSERT just adds a new triples). To replace a triple, you should DELETE the old triple at the same time as you are INSERTing the new one, like this:
DELETE
{
?s ?p ?o
}
INSERT
{
?s ?p ?o2
}
WHERE
{
?s ?p ?o .
FILTER (regex(str(?s), "iso-693") || regex(str(?o), "iso-693"))
BIND(REPLACE(?o, "iso-693", "iso-639", "i") AS ?o2) .
}
If you are targeting URIs then you need to construct new IRIs with the required substitution and use these in the INSERT part of the update along with the original values fro ?s and ?o for DELETE part. The REPLACE will produce Literals which is not correct fro subjects.
Suggest using something along following lines:
DELETE {
?s ?p ?o
}
INSERT {
?newS ?p ?newO
} WHERE {
?s ?p ?o .
bind("iso-693" as ?match) .
bind("iso-639" as ?replacement) .
bind (regex(str(?s), ?match) as ?subjMatch) .
bind (regex(str(?o), ?match) as ?objMatch) .
filter (?subjMatch || ?objMatch)
bind (if(?subjMatch, IRI(replace(str(?s), ?match, ?replacement)), ?s) as ?newS)
bind (if(?objMatch, IRI(replace(str(?o), ?match, ?replacement)), ?o) as ?newO)
}
I want to extract graphs for 5 individuals who are Film(or movies) from DBPedia.
My query is:
ParameterizedSparqlString qs = new ParameterizedSparqlString( "" +
"construct{?s ?p ?o}"+
"where{?s a http://dbpedia.org/ontology/Film ."+
"?s ?p ?o"} OFFSET 0 LIMIT 5" );
I get the following result:
1- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://dbpedia.org/ontology/Film .
2- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://www.w3.org/2002/07/owl#Thing .
3- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://www.wikidata.org/entity/Q386724 .
4- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://dbpedia.org/ontology/Wikidata:Q11424 .
5- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://dbpedia.org/ontology/Work .
Problem:
The same film is returned 5 times as all the class: Film, Thing, Q386724,WIKIdata:Q11424, and Work are equivalent class (or Subclass relation exist).
My question:
I want to return once the triple
<http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham>
<http://www.w3.org/1999/02/22-rdf-syntax-ns#type>
<http://dbpedia.org/ontology/Film> .
and filter out the other 4 triples.
How do it please?
Thank you in advance
I think the following should work for you:
CONSTRUCT {?s ?p ?o}
WHERE {
{ SELECT DISTINCT ?s
WHERE {
?s a <http://dbpedia.org/ontology/Film> .
} LIMIT 5
}
?s ?p ?o .
}
I think you want this query
construct {?s a <http://dbpedia.org/ontology/Film> .}
where { ?s a <http://dbpedia.org/ontology/Film>. }
limit 5
I am try to Implement a Sparql Query which will give some result.I am trying to Implement Like this:
My Data points are below from where I getting the data:
Subject:
<http://rhizomik.net/semanticxbrl/0001397832_agph-20110930/Context_9ME_30-Sep-2011/ConvertibleNotesPayableTextBlock/>
Predicate:
<http:// www.w3.org/1999/02/22-rdf-syntax-ns#type>
Object:
<http://www.atlanticgreenpower.com/20110930#ConvertibleNotesPayableTextBlock>
My Query is
PREFIX ab: <http:// www.atlanticgreenpower.com/20110930#>
SELECT ?node ?val_type ?value
WHERE {
?node ab:val_type ?val_type .
?node ab:value ?value .
}
I want to get the result of all subject predicate and object.I am new to sparql.please help me out
In SPARQL everything with a ? in front of it is a variable. If you want everything from the subject, predicate and object you can do it like this:
SELECT ?s ?p ?o WHERE { ?s ?p ?o }
But then you list everything. When you want to only list the values of your given subject you will have to do it like this:
SELECT * WHERE { <http://rhizomik.net/semanticxbrl/0001397832_agph-20110930/Context_9ME_30-Sep-2011/ConvertibleNotesPayableTextBlock/> ?p ?o }
And your query could easily be formatted to something like this:
PREFIX ab: <http:// www.atlanticgreenpower.com/20110930#>
SELECT ?s ?valType ?value WHERE {
?s ab:val_type ?valType ;
ab:value ?value .
}
Where ; marks when you want to include something else in your query with your given subject, but . marks the end of your query. If you want more information about how SPARQL works or how you can query check out the Euclid project with webinar recording: Querying linked data, 2013-03-04 or just test it yourself on a SPARQL endpoint like from FactForge.
To reflect my comment below:
SELECT * WHERE { ?s ?p <http://www.atlanticgreenpower.com/20110930#ConvertibleNotesPayableTextBlock> }
will select everything with the given object.
Try this:
SELECT * WHERE
{
?s ?p <http://www.atlanticgreenpower.com/20110930#ConvertibleNotesPayableTextBlock>
}