I have below records
but when i tried to do query where FullName like '%Gd. Mahendra%', it doesn't return any result.
Why ?
it should return the first row, shouldn't it ?
Your comparison should be fine:
where FullName like '%Gd. Mahendra%'
If you suspect the ., you can replace it with the single character wildcard:
where FullName like '%Gd_ Mahendra%'
In general, this type of problem is caused by "invisible" characters or characters that look the same (like zero and a capital O, or a tab and a space, or two spaces). This can particularly occur with national character sets that extend the basic ASCII characters.
You can see the ASCII value of a character using the ASCII(). That can sometimes help you figure out what is happening.
Try this:
WHERE FullName LIKE '%Gd.%Mahendra%'
Apparently the problem is:
The value that's been sent by the request is different from the actual record.
It's because the html doesn't use <pre> tag, which is able to render multiple spaces. Then the user just copyies the rendered value that doesn't have multiple spaces. That's why it can't get the correct result.
Related
I have a dataset with columns containing numbers. However, some of the rows in that column have missing data. Instead of numbers, a dash (-) is placed in the cell.
What I want to happen is to separate those rows with a dash and output them to a separate excel file. Those without the dash, should output to a csv file.
I tried the "filter rows" but it gives me an error:
Unexpected conversion error while converting value [constant String] to a Number
constant String : couldn't convert String to number
constant String : couldn't convert String to number : non-numeric character found at position 1 for value [-]
My condition is if
Column1 CONTAINS - (String)
You cant try to convert to number in the select step,and handler the error, if can not convert to number that mean that is (-)
You can convert missing value indicators (like a dash or any other string) to null in Text-File-Input - see field option "Null if". That way you still can use the metadata detection feature and will not trip over a dash arriving in a Number field.
With CSV-File-Input you should stick to the String datatype until a Null-If step has cleansed the values, so you can change the datatype to Number in a Select-Values step.
If you must preserve the dash character, don't use metadata detection (as it suggests datatype Number) or use more rows to sample (so a field with a dash is encountered) or just revert the datatype to String again before saving and running the transformation.
My solution lies on the first 'Replace in String'. I replaced the dash into something numeric and can easily be distinguished from the rest of the numbers (I used 9999) and carried on with the rest of my process.
In filter rows, I had no problems anymore with the data type because both my variables and condition contained numbers, therefore, it no longer had to convert anything.
After filter rows, I added the 'Null-if' to remove the random 9999 that I used
just to have something to replace the dash.
After that, the separation was made just as I hope it would.
Thanks to #marabu for the Null-if idea.
My task is to validate existing data in an MSSQL database. I've got some SQL experience, but not enough, apparently. We have a zip code field that must be either 5 or 9 digits (US zip). What we are finding in the zip field are embedded spaces and other oddities that will be prevented in the future. I've searched enough to find the references for LIKE that leave me with this "novice approach":
ZIP NOT LIKE '[0-9][0-9][0-9][0-9][0-9]'
AND ZIP NOT LIKE '[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]'
Is this really what I must code? Is there nothing similar to...?
ZIP NOT LIKE '[\d]{5}' AND ZIP NOT LIKE '[\d]{9}'
I will loath validating longer fields! I suppose, ultimately, both code sequences will be equally efficient (or should be).
Thanks for your help
Unfortunately, LIKE is not regex-compatible so nothing of the sort \d. Although, combining a length function with a numeric function may provide an acceptable result:
WHERE ISNUMERIC(ZIP) <> 1 OR LEN(ZIP) NOT IN(5,9)
I would however not recommend it because it ISNUMERIC will return 1 for a +, - or valid currency symbol. Especially the minus sign may be prevalent in the data set, so I'd still favor your "novice" approach.
Another approach is to use:
ZIP NOT LIKE '%[^0-9]%' OR LEN(ZIP) NOT IN(5,9)
which will find any row where zip does not contain any character that is not 0-9 (i.e only 0-9 allowed) where the length is not 5 or 9.
There are few ways you could achieve that.
You can replace [0-9] with _ like
ZIP NOT LIKE '_'
USE LEN() so it's like
LEN(ZIP) NOT IN(5,9)
You are looking for LENGTH()
select * from table WHERE length(ZIP)=5;
select * from table WHERE length(ZIP)=9;
To test for non-numeric values you can use ISNUMERIC():
WHERE ISNUMERIC(ZIP) <> 1
I have a PHP function that accepts a parameter called $letter and I want to set the default value of the parameter to a pattern which is "any number or any symbol". How can I do that?
This is my query by the way .
select ID from $wpdb->posts where post_title LIKE '".$letter."%
I tried posting at wordpress stackexchange and they told me to post it here as this is an SQL/general programming question that specific to wordpress.
Thank you! Replies much appreciated :)
In order to match just numbers or letters (I'm not sure exactly what you mean by symbols) you can use the RLIKE operator in MySQL:
SELECT ... WHERE post_title RLIKE '^[A-Za-z0-9]'
That means by default $letter would be [A-Za-z0-9] - this means all letters from a to z (both cases) and numbers from 0-9. If you need specific symbols you can add them to the list (but - has to be first or last, since otherwise it has a special meaning of range). The ^ character tells it to be at the beginning of the string. So you will need something like:
"select ID from $wpdb->posts where post_title RLIKE '^".$letter."%'"
Of course I have to warn you against SQL injection attacks if you build your query like this without sanitizing the input (making sure it doesn't have any ' (apostrophe) in it.
Edit
To match a title that starts with a number just use [0-9] - that means it will match one digit from 0 to 9
I have the following regular expression:
WHERE A.srvc_call_id = '40750564' AND REGEXP_LIKE (A.SRVC_CALL_DN, '[^TEST]')
The row that contains 40750564 has "TEST CALL" in the column SRVC_CALL_DN and REGEXP_LIKE doesn't seem to be filtering it out. Whenever I run the query it returns the row when it shouldn't.
Is my regex pattern wrong? Or does SQL not accept [^whatever]?
The carat anchors the expression to the start of a string. By enclosing the letters T, E, S & T in square brackets you're searching, as barsju suggests for any of these characters, not for the string TEST.
You say that SRVC_CALL_DN contains the string 'TEST CALL', but you don't say where in the string. You also say that you're looking for where this string doesn't match. This implies that you want to use not regexp_like(...
Putting all this together I think you need:
AND NOT REGEXP_LIKE (A.SRVC_CALL_DN, '^TEST[[:space:]]CALL')
This excludes every match from your query where the string starts with 'TEST CALL'. However, if this string may be in any position in the column you need to remove the carat - ^.
This also assumes that the string is always in upper case. If it's in mixed case or lower, then you need to change it again. Something like the following:
AND NOT REGEXP_LIKE (upper(A.SRVC_CALL_DN), '^TEST[[:space:]]CALL')
By upper-casing SRV_CALL_DN you ensure that you're always going to match but ensure that your query may not use an index on this column. I wouldn't worry about this particular point as regular expressions queries can be fairly poor at using indexes anyway and it appears as though SRVC_CALL_ID is indexed.
Also if it may not include 'CALL' you will have to remove this. It is best when using regular expressions to make your match pattern as explicit as possible; so include 'CALL' if you can.
Try with '^TEST' or '^TEST.*'
Your regexp means any string not starting with any of the characters: T,E,S,T.
But your case is so simple, starts with TEST. Why not use a simple like:
LIKE 'TEST%'
I'd like to create a regular expression such that when I compare the a string against an array of strings, matches are returned with the regex ignoring certain characters.
Here's one example. Consider the following array of names:
{
"Andy O'Brien",
"Bob O'Brian",
"Jim OBrien",
"Larry Oberlin"
}
If a user enters "ob", I'd like the app to apply a regex predicate to the array and all of the names in the above array would match (e.g. the ' is ignored).
I know I can run the match twice, first against each name and second against each name with the ignored chars stripped from the string. I'd rather this by done by a single regex so I don't need two passes.
Is this possible? This is for an iOS app and I'm using NSPredicate.
EDIT: clarification on use
From the initial answers I realized I wasn't clear. The example above is a specific one. I need a general solution where the array of names is a large array with diverse names and the string I am matching against is entered by the user. So I can't hard code the regex like [o]'?[b].
Also, I know how to do case-insensitive searches so don't need the answer to focus on that. Just need a solution to ignore the chars I don't want to match against.
Since you have discarded all the answers showing the ways it can be done, you are left with the answer:
NO, this cannot be done. Regex does not have an option to 'ignore' characters. Your only options are to modify the regex to match them, or to do a pass on your source text to get rid of the characters you want to ignore and then match against that. (Of course, then you may have the problem of correlating your 'cleaned' text with the actual source text.)
If I understand correctly, you want a way to match the characters "ob" 1) regardless of capitalization, and 2) regardless of whether there is an apostrophe in between them. That should be easy enough.
1) Use a case-insensitivity modifier, or use a regexp that specifies that the capital and lowercase version of the letter are both acceptable: [Oo][Bb]
2) Use the ? modifier to indicate that a character may be present either one or zero times. o'?b will match both "o'b" and "ob". If you want to include other characters that may or may not be present, you can group them with the apostrophe. For example, o['-~]?b will match "ob", "o'b", "o-b", and "o~b".
So the complete answer would be [Oo]'?[Bb].
Update: The OP asked for a solution that would cause the given character to be ignored in an arbitrary search string. You can do this by inserting '? after every character of the search string. For example, if you were given the search string oleary, you'd transform it into o'?l'?e'?a'?r'?y'?. Foolproof, though probably not optimal for performance. Note that this would match "o'leary" but also "o'lea'r'y'" if that's a concern.
In this particular case, just throw the set of characters into the middle of the regex as optional. This works specifically because you have only two characters in your match string, otherwise the regex might get a bit verbose. For example, match case-insensitive against:
o[']*b
You can add more characters to that character class in the middle to ignore them. Note that the * matches any number of characters (so O'''Brien will match) - for a single instance, change to ?:
o[']?b
You can make particular characters optional with a question mark, which means that it will match whether they're there or not, e.g:
/o\'?b/
Would match all of the above, add .+ to either side to match all other characters, and a space to denote the start of the surname:
/.+? o\'?b.+/
And use the case-insensitivity modifier to make it match regardless of capitalisation.