I am having the IMDB database; I am looking for the top two years in which most movies were produced, and I have to sort them chronologically after the years and print only the years.
I am trying this to compute the list and sort it 'the other way around' afterwards but I cannot order by anthing in the last 'order by' statement because in the FROM-statement I dont refer to any tables and instead open the next statement. It says "unknown column topTwo" as well so that I cannot order my results accordingly.
What am I doing wrong?
SELECT *
FROM
(SELECT m.year, COUNT(*)
FROM movies as m
GROUP BY m.year
ORDER BY m.year DESC) AS topTwo
ORDER BY **topTwo** ASC
LIMIT 2;
I think you are looking for this:
SELECT topTwo.year
FROM (SELECT m.year, COUNT(*) as cnt
FROM movies m
GROUP BY m.year
ORDER BY COUNT(*) DESC
LIMIT 2
) topTwo
ORDER BY year ASC;
Notes:
The LIMIT goes in the subquery.
The COUNT(*) is given an alias.
The ORDER BY in the subquery is based on the count.
The ORDER BY in the outer query is based on the year.
You only seem to want the year, so the outer query only select that column.
Related
I have an SQL query where I can look up the maximum occurrence of a column. It works fine for what I needed, but now need to expand on this to only return the name of the column.
There's likely a way to improve my original query but I haven't been able to work it out.
select COMMUNITY_AREA_NUMBER, count(*) as CRIMES
from CHICAGO_CRIME_DATA
group by COMMUNITY_AREA_NUMBER
order by CRIMES desc
limit 1
My basic question is, how can I re-write this to only return the COMMUNITY_AREA_NUMBER?
I've tried to restructure as:
select COMMUNITY_AREA_NUMBER from CHICAGO_CRIME_DATA
where count(*) as CRIMES group by COMMUNITY_AREA_NUMBER order by CRIMES desc limit 1
I've also tried to incorporate a MAX function, but I don't seem to be getting anywhere with it.
edit:
Apparently I've just learned something inner queries. I needed to keep my original query and create an outer query that request something from that result.
select COMMUNITY_AREA_NUMBER from
(select COMMUNITY_AREA_NUMBER, count(*) as CRIMES
from CHICAGO_CRIME_DATA
group by COMMUNITY_AREA_NUMBER
order by CRIMES desc
limit 1)
Is this what you want?
SELECT COMMUNITY_AREA_NUMBER
FROM CHICAGO_CRIME_DATA
GROUP BY COMMUNITY_AREA_NUMBER
ORDER BY COUNT(*) DESC
LIMIT 1;
This returns a single community number having the most crime records. I have simply moved COUNT(*) from the select clause, where you don't want it, to the ORDER BY clause.
I am fairly new to SQL and i have tried my hardest to code this, but it does not seem to work for me so help would be appreciated very much.
The question states that i need to list the total number of books published by each publisher and then list them from highest and lowest using the publisher code.
I have gotten this far;
SELECT COUNT (pub_code)
FROM Library_Books
GROUP BY pub_code
ORDER BY pub_code
Any help would be appreciated whatsoever
SELECT kb_pub_code, COUNT (kb_pub_code)
FROM Library_Books
GROUP BY kb_pub_code
ORDER BY 2
You are very close:
SELECT kb_pub_code, COUNT(*) TotalBooks
FROM Library_Books
GROUP BY kb_pub_code
ORDER BY TotalBooks DESC
TotalBooks is an alias for the count column, which is counting the total number of rows for each kb_pub_code
You can reference a column alias in your ORDER BY: ie.ORDER BY TotalBooks DESC
Note, if books can be repeated in the Library_Books table, you may want a DISTINCT count. Something like:
SELECT kb_pub_code, COUNT(DISTINCT title) TotalBooks
FROM Library_Books
GROUP BY kb_pub_code
ORDER BY TotalBooks DESC
SELECT kb_pub_code
,COUNT (*) as 'TotalBooks'
FROM Library_Books
GROUP BY kb_pub_code
ORDER BY TotalBooks desc
Edit: with the additional information of possible duplicates you may wish to use a CTE.
With DistinctList as(
Select Distinct kb_pub_code as 'PubCode'
,kb_title as 'Title'
FROM Library_Books)
Select PubCode
,Count(*) as 'TotalBooks'
From DistinctList
Group by PubCode
ORDER BY TotalBooks desc
ORDER BY DESC will sort in descending order. The publisher code should be included in the result set (SELECT) otherwise you would not know which publisher is the count for.
SELECT kb_pub_code, COUNT (kb_pub_code)
FROM Library_Books
GROUP BY kb_pub_code
ORDER BY COUNT(kb_pub_code) DESC
I am trying to distinct and then find the count of the teams a player played for in any single season and number of teams he played for. This is tripping me up and ofcourse i have a sample down below(2nd) one. The first ones is my failed attempt
SELECT o.id,o.year,COUNT(DISTINCT(o.team)) b JOIN
(SELECT id, year, team FROM batting
GROUP BY id,year,team
ORDER BY id DESC
LIMIT 25) o
0.id =b.id;
SELECT id, year, team FROM batting
GROUP BY id,year,team
ORDER BY id DESC
LIMIT 25;
produces
IGNORE the ^A, i think they represent either space or comma, just column seperatpr
Get the count of teams for each player for each year and order by the count desc,get the 1 row
SELECT id, year, COUNT(DISTINCT(team)) FROM batting
GROUP BY id,year
ORDER BY COUNT(DISTINCT(team)) DESC
LIMIT 1;
I have this query currently, which selects the top "number of pickups" in descending order. I need to filter only the top 10 rows/highest numbers though. How can I do this?
I have tried adding 'WHERE ROWNUM <= 10' at the bottom, to no avail.
SELECT customer.company_name, COUNT (item.pickup_reference) as "Number of Pickups"
FROM customer
JOIN item ON (customer.reference_no=item.pickup_reference)
GROUP BY customer.company_name, item.pickup_reference
ORDER BY COUNT (customer.company_name) DESC;
Thanks for any help!
You need to subquery it for the rownum to work.
SELECT *
FROM
(
SELECT customer.company_name, COUNT (item.pickup_reference) as "Number of Pickups"
FROM customer
JOIN item ON (customer.reference_no=item.pickup_reference)
GROUP BY customer.company_name, item.pickup_reference
ORDER BY COUNT (customer.company_name) DESC
)
WHERE rownum <= 10
You could alternatively use ranking functions, but given the relative simplicity of this, I'm not sure whether I would.
The solution by using the rank is something like this :
select customer.company_name, COUNT (item.pickup_reference) from (
select distinct customer.company_name, COUNT (item.pickup_reference) ,
rank() over ( order by count(item.pickup_reference) desc) rnk
from customer
JOIN item ON (customer.reference_no=item.pickup_reference)
group by customer.company_name, item.pickup_reference
order by COUNT (customer.company_name) )
where rnk < 10
Using the 'rownum' to get the top result doesn't give the expected result, because it get the 10 first rows which are not ordred, and then order them (Please notify this on a comment on Andrew's response, I don't have the right to add the comment) .
I have a simple query in a tabloid control that gets all the leads in one month. I then use the tabloid control to group them into lead source. And then I have an associated count column. I want to sort my report on the count descending, without doing it in the query. I keep getting an error saying you cannot sort on an aggregate.
Thanks.
you can do one more thing..
just write your query in subquery part and write order by clause in outer query.
(suppose you have group by query as follow-
select lead_source, count(*) cnt
from your_table
group by lead_source
)
so you can do as follow -
select lead_source, cnt from (
select lead_source, count(*) cnt
from your_table
group by lead_source
)
order by cnt
this your_table and group by column list you have to edit accordingly your table structure ..