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I have similar requirement, i have file feeding to SQL Server 2012 for a month but i wanted to convert the same file as a next month file.
For Example I have below
02/22/2018 02/23/2018 02/24/2018
and I want 03/22/2018 03/23/2018 02/24/2018
I am able to get upto this point but facing issue when i have below situation.
02/28/2018 02/24/2018
and I want 03/31/2018 03/31/2018
I have a normal calendar set up which I can use Can somebody please help.
you can use DATEADD() function for this like below :
SELECT DATEADD(month, 1, '02/22/2018') AS DateAdd;
I guess you are looking for EOMONTH function
somethink like this might help you solve your issue
DECLARE #date VARCHAR(10) = '02/28/2019'
SELECT CASE WHEN (EOMONTH(#date) = FORMAT(CAST(#date AS DATETIME),'yyyy-MM-dd'))
THEN EOMONTH(DATEADD(month,1,#date))
ELSE DATEADD(month,1,#date)
END
Note: I have used format function because EOMONTH returns date in 'yyyy-MM-dd' format
UPDATE
DECLARE #dates TABLE
(
FromDate DATETIME,
ToDate DATETIME
)
INSERT INTO #dates (FromDate)
VALUES('12/31/2017'),('1/31/2018'),('2/28/2018'),('3/31/2018')
select * from #dates
UPDATE #dates
SET ToDate =CASE WHEN (EOMONTH(FromDate) = FORMAT(CAST(FromDate AS DATETIME),'yyyy-MM-dd'))
THEN EOMONTH(DATEADD(month,1,FromDate))
ELSE DATEADD(month,1,FromDate)
END
SELECT * FROM #dates
Run this and you can see the final output
#Rdatetime ='2017-04-18 11:49:38.633'
#Date to add = 2
#Output = '2017-04-20 11:49:38.633'
Hi all,
This is my Problem , i am getting Rdatetime and date to be added in another table . i have yo add the date and save it in datetime format
thanks in advance
Use DATEADD built in function :
DECLARE #Rdatetime DATETIME ='2017-04-18 11:49:38.633'
DECLARE #Date INT = 2
DECLARE #Output DATETIME = DATEADD(DAY,#Date,#Rdatetime)
SELECT #Output
You can make use DATEADD function by giving D as the first parameter.Then the number of days you want to add and the date to which you want to add.
SET #Output=DATEADD(D,#Date,#Rdatetime)
How would I be able to extract the time part of a DateTime field in SQL? For my project I have to return data that has a timestamp of 5pm of a DateTime field no matter what the date is
This will return the time-Only
For SQL Server:
SELECT convert(varchar(8), getdate(), 108)
Explanation:
getDate() is giving current date and time.
108 is formatting/giving us the required portion i.e time in this case.
varchar(8) gives us the number of characters from that portion.
Like:
If you wrote varchar(7) there, it will give you 00:00:0
If you wrote varchar(6) there, it will give you 00:00:
If you wrote varchar(15) there, it will still give you 00:00:00 because it is giving output of just time portion.
SQLFiddle Demo
For MySQL:
SELECT DATE_FORMAT(NOW(), '%H:%i:%s')
SQLFiddle Demo
In SQL Server if you need only the hh:mi, you can use:
DECLARE #datetime datetime
SELECT #datetime = GETDATE()
SELECT RIGHT('0'+CAST(DATEPART(hour, #datetime) as varchar(2)),2) + ':' +
RIGHT('0'+CAST(DATEPART(minute, #datetime)as varchar(2)),2)
If you want only the hour of your datetime, then you can use DATEPART() - SQL Server:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select datepart(hour, #dt) -- returns 8
In SQL Server 2008+ you can CAST() as time:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select CAST(#dt as time) -- returns 08:25:53
I know this is an old question, but since the other answers all
return strings (rather than datetimes),
rely on the internal representation of dates (conversion to float, int, and back) or
require SQL Server 2008 or beyond,
I thought I'd add a "pure" option which only requires datetime operations and works with SQL Server 2005+:
SELECT DATEADD(dd, -DATEDIFF(dd, 0, mydatetime), mydatetime)
This calculates the difference (in whole days) between date zero (1900-01-01) and the given date and then subtracts that number of days from the given date, thereby setting its date component to zero.
Try this in SQL Server 2008:
select *
from some_table t
where convert(time,t.some_datetime_column) = '5pm'
If you want take a random datetime value and adjust it so the time component is 5pm, then in SQL Server 2008 there are a number of ways. First you need start-of-day (e.g., 2011-09-30 00:00:00.000).
One technique that works for all versions of Microsoft SQL Server as well as all versions of Sybase is to use convert/3 to convert the datetime value to a varchar that lacks a time component and then back into a datetime value:
select convert(datetime,convert(varchar,current_timestamp,112),112)
The above gives you start-of-day for the current day.
In SQL Server 2008, though, you can say something like this:
select start_of_day = t.some_datetime_column
- convert(time, t.some_datetime_column ) ,
from some_table t
which is likely faster.
Once you have start-of-day, getting to 5pm is easy. Just add 17 hours to your start-of-day value:
select five_pm = dateadd(hour,17, t.some_datetime_column
- convert(time,t.some_datetime_column)
)
from some_table t
Note that from MS SQL 2012 onwards you can use FORMAT(value,'format')
e.g. WHERE FORMAT(YourDatetime,'HH:mm') = '17:00'
"For my project, I have to return data that has a timestamp of 5pm of a DateTime field, No matter what the date is."
So I think what you meant was that you needed the date, not the time. You can do something like this to get a date with 5:00 as the time:
SELECT CONVERT(VARCHAR(10), GetDate(), 110) + ' 05:00:00'
This should strip away the date part:
select convert(datetime,convert(float, getdate()) - convert(int,getdate())), getdate()
and return a datetime with a default date of 1900-01-01.
you can use CONVERT(TIME,GETDATE()) in this case:
INSERT INTO infoTbl
(itDate, itTime)
VALUES (GETDATE(),CONVERT(TIME,GETDATE()))
or if you want print it or return that time use like this:
DECLARE #dt TIME
SET #dt = CONVERT(TIME,GETDATE())
PRINT #dt
select cast(getdate() as time(0))
returns for example :- 15:19:43
replace getdate() with the date time you want to extract just time from!
SELECT DISTINCT
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108)
FROM
CONSOLIDATED_LIST AS A
WHERE
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108) BETWEEN '15:00:00' AND '15:45:00'
declare #datetime as datetime
set #datetime = getdate()
select cast(cast(#datetime as time) as varchar(8))
For year:
SELECT DATEPART(YEAR, '2021-03-21' );
For hour:
SELECT DATEPART(HOUR, '2021-03-21 08:50:30' );
I want to assign '1392-04-31' using this code:
DECLARE #t DATETIME
SET #t = '92-04-31'
I see this error:
Conversion failed when converting date and/or time from character string.
Any one know why?
The solution is:
use datetime2!
DECLARE #t datetime2
SET #t = '1392-04-30'
Because you can't use datetime:
The minimum date stored in datetime is January 1, 1753. So 1392 is not storeable.
April has 30 days.
Using formatted date with datetime:
Second, when you write a date in Sql Server, the format I prefer is {d 'YYYY-MM-DD'}, so in your case becomes:
DECLARE #t DATETIME
SET #t = {d '1992-04-30'}
To complete this discussion, if you want use hh mm ss so you must use this format: {ts 'yyy-mm-dd hh:mm:ss.mmm'}
DECLARE #t DATETIME
SET #t = {ts '1992-04-30 23:59:59.123'}
try this :
declare #t DATETIME
set #t = '1992-04-30 10:54:30'
The date you are trying to set is probably invalid.
Also there are several ways of representing dates in SQL as a string, depending on Language, Dateformat and other setting. Typically the safest way to do this is to use the 'YYYYMMDD' format.
The article below will also answer the question : Why is 1753 the earliest date for datetime?
You should read this if you would like some detailed information:
http://karaszi.com/the-ultimate-guide-to-the-datetime-datatypes
First of all, April only has 30 days. I'm not going to take the time to look up historically whether that was the case in 1392, but either way I'm pretty sure the date 4/31/1392 is invalid for a SQL Server DATETIME.
Also, you should use the full year in the format '01-01-2013'.
Try the following and you'll get the output Jan 1 2013 12:00AM.
declare #t DATETIME
set #t = '01-01-2013'
PRINT #t
The above should work for any valid date.
How would I be able to extract the time part of a DateTime field in SQL? For my project I have to return data that has a timestamp of 5pm of a DateTime field no matter what the date is
This will return the time-Only
For SQL Server:
SELECT convert(varchar(8), getdate(), 108)
Explanation:
getDate() is giving current date and time.
108 is formatting/giving us the required portion i.e time in this case.
varchar(8) gives us the number of characters from that portion.
Like:
If you wrote varchar(7) there, it will give you 00:00:0
If you wrote varchar(6) there, it will give you 00:00:
If you wrote varchar(15) there, it will still give you 00:00:00 because it is giving output of just time portion.
SQLFiddle Demo
For MySQL:
SELECT DATE_FORMAT(NOW(), '%H:%i:%s')
SQLFiddle Demo
In SQL Server if you need only the hh:mi, you can use:
DECLARE #datetime datetime
SELECT #datetime = GETDATE()
SELECT RIGHT('0'+CAST(DATEPART(hour, #datetime) as varchar(2)),2) + ':' +
RIGHT('0'+CAST(DATEPART(minute, #datetime)as varchar(2)),2)
If you want only the hour of your datetime, then you can use DATEPART() - SQL Server:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select datepart(hour, #dt) -- returns 8
In SQL Server 2008+ you can CAST() as time:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select CAST(#dt as time) -- returns 08:25:53
I know this is an old question, but since the other answers all
return strings (rather than datetimes),
rely on the internal representation of dates (conversion to float, int, and back) or
require SQL Server 2008 or beyond,
I thought I'd add a "pure" option which only requires datetime operations and works with SQL Server 2005+:
SELECT DATEADD(dd, -DATEDIFF(dd, 0, mydatetime), mydatetime)
This calculates the difference (in whole days) between date zero (1900-01-01) and the given date and then subtracts that number of days from the given date, thereby setting its date component to zero.
Try this in SQL Server 2008:
select *
from some_table t
where convert(time,t.some_datetime_column) = '5pm'
If you want take a random datetime value and adjust it so the time component is 5pm, then in SQL Server 2008 there are a number of ways. First you need start-of-day (e.g., 2011-09-30 00:00:00.000).
One technique that works for all versions of Microsoft SQL Server as well as all versions of Sybase is to use convert/3 to convert the datetime value to a varchar that lacks a time component and then back into a datetime value:
select convert(datetime,convert(varchar,current_timestamp,112),112)
The above gives you start-of-day for the current day.
In SQL Server 2008, though, you can say something like this:
select start_of_day = t.some_datetime_column
- convert(time, t.some_datetime_column ) ,
from some_table t
which is likely faster.
Once you have start-of-day, getting to 5pm is easy. Just add 17 hours to your start-of-day value:
select five_pm = dateadd(hour,17, t.some_datetime_column
- convert(time,t.some_datetime_column)
)
from some_table t
Note that from MS SQL 2012 onwards you can use FORMAT(value,'format')
e.g. WHERE FORMAT(YourDatetime,'HH:mm') = '17:00'
"For my project, I have to return data that has a timestamp of 5pm of a DateTime field, No matter what the date is."
So I think what you meant was that you needed the date, not the time. You can do something like this to get a date with 5:00 as the time:
SELECT CONVERT(VARCHAR(10), GetDate(), 110) + ' 05:00:00'
This should strip away the date part:
select convert(datetime,convert(float, getdate()) - convert(int,getdate())), getdate()
and return a datetime with a default date of 1900-01-01.
you can use CONVERT(TIME,GETDATE()) in this case:
INSERT INTO infoTbl
(itDate, itTime)
VALUES (GETDATE(),CONVERT(TIME,GETDATE()))
or if you want print it or return that time use like this:
DECLARE #dt TIME
SET #dt = CONVERT(TIME,GETDATE())
PRINT #dt
select cast(getdate() as time(0))
returns for example :- 15:19:43
replace getdate() with the date time you want to extract just time from!
SELECT DISTINCT
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108)
FROM
CONSOLIDATED_LIST AS A
WHERE
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108) BETWEEN '15:00:00' AND '15:45:00'
declare #datetime as datetime
set #datetime = getdate()
select cast(cast(#datetime as time) as varchar(8))
For year:
SELECT DATEPART(YEAR, '2021-03-21' );
For hour:
SELECT DATEPART(HOUR, '2021-03-21 08:50:30' );