subset a data frame based on date range [duplicate] - pandas

Question

I have a Pandas DataFrame with a 'date' column. Now I need to filter out all rows in the DataFrame that have dates outside of the next two months. Essentially, I only need to retain the rows that are within the next two months.
What is the best way to achieve this?

Answer 1

If date column is the index, then use .loc for label based indexing or .iloc for positional indexing.
For example:
df.loc['2014-01-01':'2014-02-01']
See details here http://pandas.pydata.org/pandas-docs/stable/dsintro.html#indexing-selection
If the column is not the index you have two choices:
Make it the index (either temporarily or permanently if it's time-series data)
df[(df['date'] > '2013-01-01') & (df['date'] < '2013-02-01')]
See here for the general explanation
Note: .ix is deprecated.

Answer 2

Previous answer is not correct in my experience, you can't pass it a simple string, needs to be a datetime object. So:
import datetime
df.loc[datetime.date(year=2014,month=1,day=1):datetime.date(year=2014,month=2,day=1)]

Answer 3

And if your dates are standardized by importing datetime package, you can simply use:
df[(df['date']>datetime.date(2016,1,1)) & (df['date']<datetime.date(2016,3,1))]
For standarding your date string using datetime package, you can use this function:
import datetime
datetime.datetime.strptime

Answer 4

If you have already converted the string to a date format using pd.to_datetime you can just use:
df = df[(df['Date'] > "2018-01-01") & (df['Date'] < "2019-07-01")]

Answer 5

The shortest way to filter your dataframe by date:
Lets suppose your date column is type of datetime64[ns]
# filter by single day
df_filtered = df[df['date'].dt.strftime('%Y-%m-%d') == '2014-01-01']
# filter by single month
df_filtered = df[df['date'].dt.strftime('%Y-%m') == '2014-01']
# filter by single year
df_filtered = df[df['date'].dt.strftime('%Y') == '2014']

Answer 6

If your datetime column have the Pandas datetime type (e.g. datetime64[ns]), for proper filtering you need the pd.Timestamp object, for example:
from datetime import date
import pandas as pd
value_to_check = pd.Timestamp(date.today().year, 1, 1)
filter_mask = df['date_column'] < value_to_check
filtered_df = df[filter_mask]

Answer 7

If the dates are in the index then simply:
df['20160101':'20160301']

Answer 8

You can use pd.Timestamp to perform a query and a local reference
import pandas as pd
import numpy as np
df = pd.DataFrame()
ts = pd.Timestamp
df['date'] = np.array(np.arange(10) + datetime.now().timestamp(), dtype='M8[s]')
print(df)
print(df.query('date > #ts("20190515T071320")')
with the output
date
0 2019-05-15 07:13:16
1 2019-05-15 07:13:17
2 2019-05-15 07:13:18
3 2019-05-15 07:13:19
4 2019-05-15 07:13:20
5 2019-05-15 07:13:21
6 2019-05-15 07:13:22
7 2019-05-15 07:13:23
8 2019-05-15 07:13:24
9 2019-05-15 07:13:25
date
5 2019-05-15 07:13:21
6 2019-05-15 07:13:22
7 2019-05-15 07:13:23
8 2019-05-15 07:13:24
9 2019-05-15 07:13:25
Have a look at the pandas documentation for DataFrame.query, specifically the mention about the local variabile referenced udsing # prefix. In this case we reference pd.Timestamp using the local alias ts to be able to supply a timestamp string

Answer 9

So when loading the csv data file, we'll need to set the date column as index now as below, in order to filter data based on a range of dates. This was not needed for the now deprecated method: pd.DataFrame.from_csv().
If you just want to show the data for two months from Jan to Feb, e.g. 2020-01-01 to 2020-02-29, you can do so:
import pandas as pd
mydata = pd.read_csv('mydata.csv',index_col='date') # or its index number, e.g. index_col=[0]
mydata['2020-01-01':'2020-02-29'] # will pull all the columns
#if just need one column, e.g. Cost, can be done:
mydata['2020-01-01':'2020-02-29','Cost']
This has been tested working for Python 3.7. Hope you will find this useful.

Answer 10

I'm not allowed to write any comments yet, so I'll write an answer, if somebody will read all of them and reach this one.
If the index of the dataset is a datetime and you want to filter that just by (for example) months, you can do following:
df.loc[df.index.month == 3]
That will filter the dataset for you by March.

Answer 11

How about using pyjanitor
It has cool features.
After pip install pyjanitor
import janitor
df_filtered = df.filter_date(your_date_column_name, start_date, end_date)

Answer 12

You could just select the time range by doing: df.loc['start_date':'end_date']

Answer 13

In pandas version 1.1.3 I encountered a situation where the python datetime based index was in descending order. In this case
df.loc['2021-08-01':'2021-08-31']
returned empty. Whereas
df.loc['2021-08-31':'2021-08-01']
returned the expected data.

Answer 14

Another solution if you would like to use the .query() method.
It allows you to use write readable code like .query(f"{start} < MyDate < {end}") on the trade off, that .query() parses strings and the columns values must be in pandas date format (so that it is also understandable for .query())
df = pd.DataFrame({
'MyValue': [1,2,3],
'MyDate': pd.to_datetime(['2021-01-01','2021-01-02','2021-01-03'])
})
start = datetime.date(2021,1,1).strftime('%Y%m%d')
end = datetime.date(2021,1,3).strftime('%Y%m%d')
df.query(f"{start} < MyDate < {end}")
(following the comment from #Phillip Cloud, answer from #Retozi)

Answer 15

import the pandas library
import pandas as pd
STEP 1: convert the date column into a string using the pd.to_datetime() method
df['date']=pd.to_datetime(df["date"],unit='s')
STEP 2: perform the filtering in any predetermined manner ( i.e 2 months)
df = df[(df["date"] >"2022-03-01" & df["date"] < "2022-05-03")]
STEP 3 : Check the output
print(df)

Answer 16

# 60 days from today
after_60d = pd.to_datetime('today').date() + datetime.timedelta(days=60)
# filter date col less than 60 days date
df[df['date_col'] < after_60d]