I have a field cost with values 0.987878656435798654 , 0.765656787898767
I am trying to figure out what would be the datatype for this.
When I give decimal 15,15 and trying to load data it is throwing me an error
Arithmetic overflow error converting varchar to data type numeric.
The problem is that you are not allocating any length to the value before the decimal.
DECIMAL (15, 15) means that it has a precision of 15 digits after the decimal, but only enough room for 15 digits total - thus leaving no room for values greater than 1.
This means that DECIMAL (15, 15) only supports values in the following range:
-0.999999999999999 to 0.999999999999999 (15 digits after the decimal).
You have 18 digits in your first example, so I would recommend using something like DECIMAL (21, 18)
DECIMAL (21, 18) will support values in the range from: -999.999999999999999999 to 999.999999999999999999 (18 digits after the decimal).
But, you should analyze your own data to see what the maximum value would be that you need to support.
Try this...
SELECT LEN(YourColumn)
FROM YourTable
Then , if they are below 1 every time, try this...
SELECT CONVERT(DECIMAL(X,X-1),YourColumn)
Where X is what is returned in the LEN statement. and X-1 is one less than that.
Remember, it's DECIMAL(TotalLength,Precision) so you need to make sure have enough space for the total value.
Related
I have a double type column in impala
while I am trying to cut it upto some decimal places
I got this error
ERROR: AnalysisException: No matching function with signature: truncate(DOUBLE, TINYINT).
e.g select truncate(cast(0.4893617021276596 as double),7);
any workaround will be welcome
You can use round():
select round(col, 6)
If you actually want a truncate, then subtract 0.0000005:
select round(col - 0.0000005, 6)
Using the DECIMAL type, it is possible to represent numbers with greater precision than the FLOAT or DOUBLE types can represent.
The maximum allowed precision and scale of the DECIMAL type are both 38.
Precision is the total number of digits, regardless of the location of the decimal point.
Scale is the number of digits after the decimal place.
To represent the number 8.54 without a loss of precision, you would need a
DECIMAL type with precision of at least 3, and scale of at least 2.
Example:
Note that the DECIMAL(17,16) type means there is a total of 17 digits, with 16 of them after the decimal point.
DECIMAL(17,16) 3.1415926535897932
You could ALTER your table with DECIMAL type as follow:
ALTER TABLE my_table CHANGE field field DECIMAL(precision, scale);
or as suggest #Gordon Linoff, you could use round() function.
I need to set the value of a field in table depending on conditions whose value I am getting from another table. The data type of this field is float. The requirement is I need to have 2 digits before decimal and 4 after. So if a value is 9.45, I need to set it 09.4500. I am wondering what might be the best way to do this. Should I convert the value into varchar and then do substring? Or can this be done setting precision?
Thanks!
First, don't store such a value as a float. You have described the decimal(6, 4)/numeric(6, 4) data type very closely.
If you have this as a float or decimal, you can use str() and then pad to the right:
select right('000000' + str(9.45, 6, 4), 7)
I am getting this error
Arithmetic overflow error converting float to data type numeric
when I try to run my view but not sure what am I doing wrong with my calculation. I have researched but could not solve it so far.
Here is the line of code that is causing the error:
ISNULL(CAST(CAST(TOTAL_APPTS.APPT_CNT AS FLOAT) / TOTAL_RECS.PAT_CNT AS NUMERIC(3, 2)), 0) AS [CONVERSION RATE]
Your precision and scale arguments to NUMERIC are very small. Have you tried increasing those? Your numeric value can only handle numbers up to 9.99.
You should peruse this page:
decimal and numeric (Transact-SQL)
It's too much to explain here, but basically the first argument (precision) is the max number of digits (in your case 3) and the second argument (scale) is the number of digits to the right of the decimal point, which always takes away from the number of digits you can have to the left of the decimal point. So in your case, 3-2 = 1 digit allowed to the left of the decimal point, which is why your max value can only be 9.99.
i am having hard time determining the length of a Decimal data type. The data i have in column is like 0.08,1.2,12.35,121.36. Now if i go for (2,2) it throws an error : Arithmetic overflow error converting numeric to data type numeric. Just wondering should it be (6,2)? and if yes can anybody tell me Why 6 and 2?
In syntax like
NUMERIC(precision, scale)
precision is the total number of digits (count digits on both sides of the decimal point), and scale is the number of digits to the right of the decimal point.
From your examples, should be NUMERIC(5,2) - meaning five numbers in total and 2 after the decimal point.
I have a column which has decimal value of 18,8. I was asked to extend it to 18,18 to hold more places after ,.
ALTER TABLE [dbo].[TransakcjeGotowkowe]
ALTER COLUMN TransakcjeGotowkoweKwota decimal (18,18) NULL
Msg 8115, Level 16, State 8, Line 1
Arithmetic overflow error converting numeric to data type numeric.
The statement has been terminated.
I have also tried to do it by GUI. Nothing else changes just want to hold more data after ,.
Is there other way to do this ?
The Decimal datatype is made up of (precision, scale)
Precision is the total number of digits to the left AND the right of the decimal point.
Scale is the number of digits to the right of the decimal point.
If you want to increase the number of digits to the right to 18 you will need to increase the overall precision. In your case increase it by 10.
So you will need decimal(28,18)
MSDN Article on Precision & Scale
You would need to change it to 28,18 Your current column allows 10 digits to the left of the decimal point.
Changing it to 18,18 would only allow a range between +/-0.999999999999999999