SQL Server how to retrieve all numbers between 2 numbers - sql

Question

I have 4 columns- Code, Amount, Start, End. I would like to take the between amounts in the start and end columns and change them into one column with all results. Any suggestions on how to achieve this? Thanks.
Current Results:
Code Amount Start End
1 5000 2015 2016
2 5000 2014 2016
3 20000 2012 2016
Desired Results:
Code Amount StartEnd
1 5000 2015
1 5000 2016
2 5000 2014
2 5000 2015
2 5000 2016
3 20000 2012
3 20000 2013
3 20000 2014
3 20000 2015
3 20000 2016

Answer 1

You can use a recursive cte to generate all the numbers between minimum start and maximum end and join on the generated numbers.
with cte as (select min(start) col,max(end) mx from tablename
union all
select col+1,mx from cte where col < mx)
select t.code,t.amount,c.col
from cte c
join tablename t on c.col between t.start and t.end
or more simply
with cte as (select id,amount,start startend,end from tablename
union all
select id,amount,start+1,end from cte where start<end)
select id,amount,startend
from cte
order by 1,3

Answer 2

You can query like this
SELECT
c.code,
c.amount,
f.yr
FROM #code c
CROSS APPLY fn_yearslist(c.startyr, c.endyr) f
function you cancreate like this
CREATE FUNCTION fn_yearslist (#startyear int, #endyear int)
RETURNS #t TABLE (
yr int
)
AS
BEGIN
WHILE (#startyear <= #endyear)
BEGIN
INSERT INTO #t (yr)
VALUES (#startyear)
SET #startyear += 1
END
RETURN
END

Answer 3

Another option is a UDF. I use this TVF to generate dynamic ranges
Declare #YourTable table (Code int, Amount int, Start int , [End] int)
Insert into #YourTable values
(1,5000 ,2015,2016),
(2,5000 ,2014,2016),
(3,20000,2012,2016)
Select A.Code
,A.Amount
,StartEnd = cast(B.RetVal as int)
From #YourTable A
Cross Apply (Select * from [dbo].[udf-Range-Number](A.Start,A.[End],1)) B
Returns
Code Amount StartEnd
1 5000 2015
1 5000 2016
2 5000 2014
2 5000 2015
2 5000 2016
3 20000 2012
3 20000 2013
3 20000 2014
3 20000 2015
3 20000 2016
The Function
CREATE FUNCTION [dbo].[udf-Range-Number] (#R1 money,#R2 money,#Incr money)
Returns Table
Return (
with cte0(M) As (Select cast((#R2-#R1)/#Incr as int)),
cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (Select M from cte0) Row_Number() over (Order By (Select NULL)) From cte1 a,cte1 b,cte1 c,cte1 d,cte1 e,cte1 f,cte1 g,cte1 h )
Select RetSeq=1,RetVal=#R1 Union All Select N+1,(N*#Incr)+#R1
From cte2
)
/*
Max 100 million observations --
Syntax:
Select * from [dbo].[udf-Range-Number](0,4,0.25)
*/

Answer 4

I am not sure if it works on SQL 2008, but here's a CTE:
;with sel_cte as (
select Code, Amount, start StartEnd
from #tblTest t
union all
select t.code, t.amount, c.StartEnd + 1 StartEnd
from sel_cte c
inner join #tblTest t on t.code = c.code
where c.StartEnd + 1 <= [end]
)
select *
from sel_cte
order by Code, StartEnd
Note: replace #tblTest with the actual table name.

Answer 5

If the requirements allow you to ONLY have successive numbers (like 2014, 2015, then 2016, etc) then the approach above (cte) would work fine. However, if not, you could create a another temp table (say numbers having 1 column) with numbers in successive sequence of what all you want to be the result output, like.
Number
2014
2015
2016
2018 <-- Missing 2017 and jumping on 2018
2019
And then use a right join to get results in the progressive series with a query similar to the one below.
select Code, StartEnd, Amount from numbers
right join inputs on number between Start and End