I'd like to count total events, which can have two different values, and I could not figure out how to merge them together. My query is the following:
SELECT TOP(20)
[MatchEvents].[PlayerID], [MatchEvents].[EventType],
COUNT([MatchEvents].[ID]) AS [TOTAL]
FROM
[MatchEvents]
INNER JOIN
[Match] ON [MatchEvents].[MatchID] = [Match].[ID]
AND [Match].[Season] = 1
WHERE
([MatchEvents].[EventType] = 0 OR [MatchEvents].[EventType] = 1)
GROUP BY
[MatchEvents].[PlayerID], [MatchEvents].[EventType]
ORDER BY
[TOTAL] ESC
Current output:
PlayerID
EventType
Total
1
0
8
1
1
3
2
0
8
2
1
3
3
0
8
3
1
3
Expected output:
PlayerID
Total
1
11
2
11
3
11
How could I merge my current results further?
Thanks!
From your expected results it appears you just need to remove grouping by EventType
I would suggest the following:
select top(20) me.PlayerID, Count(*) as Total
from MatchEvents me
join [Match] m on m.Id = me.MatchId and m.Season = 1
where me.EventType in (0, 1)
group by me.PlayerID
order by Total desc;
I need help with writing a query to generate a result that will provide me with all record numbers NOT assigned to Group D from a table structured like the below example. From the below table my desired result would be record number "3" .
Record_Number Assigned_To_Group
1 A
1 B
1 C
1 D
2 A
2 E
2 D
3 A
3 B
3 E
One method uses aggregation:
select Record_Number
from t
group by Record_Number
having sum(case when Assigned_To_Group = 'D' then 1 else 0 end) = 0;
Consider the following table Orders:
OrderID Name Amount
-----------------------
1 A 100
2 A 5
3 B 32
4 C 4000
5 D 701
6 E 32
7 F 200
8 G 100
9 H 12
10 I 17
11 J 100
12 J 100
13 J 11
14 A 5
I need to identify, for each unique 'Amount', if there are 2 or more users that have ordered that exact amount, and then list the details of those orders. So the desired output would be:
OrderID Name Amount
---------------------
1 A 100
8 G 100
11 J 100
12 J 100
3 B 32
6 E 32
please note that user A has ordered 2 x an order of 5 (order 2 and 14) but this shouldn't be in the output as it is within the same user. Only if another user would have made a order of 5, it should be in the output.
Can anyone help me out?
I would just use exists:
select o.*
from orders o
where exists (select 1
from orders o2
where o2.amount = o.amount and o2.name <> o.name
);
You can do :
select t.*
from table t
where exists (select 1 from table t1 where t1.amount = t.amount and t1.name <> t.name);
If you want only selected field then
SELECT Amount,name,
count(*) AS c
FROM TABLE
GROUP BY Amount, name
HAVING c > 1
ORDER BY c DESC
if you want full row
select * from table where Amount in (
select Amount, name from table
group by Amount, name having count(*) > 1)
I have a data set with four columns (author, document, rating 1, rating 2)
How do I pick authors who have written a document that has been rated higher in rating 1 than rating 2, and has also written another document that has been rated higher in rating 2 than rating 1.
Basically:
AUTHOR DOCUMENT RATING 1 RATING 2
A 1 1 2
B 2 1 2
B 3 3 1
C 4 2 2
C 5 3 4
C 6 1 3
D 7 1 2
D 8 1 2
So my desired query will give me B and C because it has written docs that have had both higher and lower numbers in both ratings.
What I have:
SELECT DISTINCT author
FROM(
(SELECT author
FROM table_name
WHERE rating1 < rating2)
UNION
(SELECT author
FROM table_name
WHERE rating1 > rating2)
)
AS a
What I cant figure out is how to group the authors, test whether rating 1 and rating 2 are both higher and lower, output the name and then move on to the next group of authors. What the above prints is just the set of distinct names with either higher or lower numbers. So this one would print D as well for example.
What is my SQL code missing that would satisfy the criteria mentioned above
Try this,
select *
from myTable as t1
inner join MyTable as t2
on t1.author = t2.author
and t2.rating1 > t2.rating2
where t1.rating1 > t1.rating2
My SQL query returns results with 4 columns "A", "B", "C", "D".
Suppose the results are:
A B C D
1 1 1 1
1 1 1 2
2 2 2 1
Is it possible to get the count of duplicate rows with columns "A", "B", "C" in each row.
e.g. the expected result is:
A B C D cnt
1 1 1 1 2
1 1 1 2 2
2 2 2 1 1
I tried using count(*) over. But it returns me the total number of rows returned by the query.
Another information is that in example I have mentioned only 3 columns based on which I need to check the count. But my actual query has such 8 columns. And number of rows in database are huge. So I think group by will not be a feasible option here.
Any hint is appreciable.
Thanks.
Maybe too late, but probably the count over as analytic function (aka window function) within oracle helps you. When I understand your request correctly, this should solve your problem :
create table sne_test(a number(1)
,b number(1)
,c number(1)
,d number(1)
,e number(1)
,f number(1));
insert into sne_test values(1,1,1,1,1,1);
insert into sne_test values(1,1,2,1,1,1);
insert into sne_test values(1,1,2,4,1,1);
insert into sne_test values(1,1,2,5,1,1);
insert into sne_test values(1,2,1,1,3,1);
insert into sne_test values(1,2,1,2,1,2);
insert into sne_test values(2,1,1,1,1,1);
commit;
SELECT a,b,c,d,e,f,
count(*) over (PARTITION BY a,b,c)
FROM sne_test;
A B C D E F AMOUNT
-- -- -- -- -- -- ------
1 1 1 1 1 1 1
1 1 2 4 1 1 3
1 1 2 1 1 1 3
1 1 2 5 1 1 3
1 2 1 1 3 1 2
1 2 1 2 1 2 2
2 1 1 1 1 1 1
To find duplicates you must group the data based on key column
select
count(*)
,empno
from
emp
group by
empno
having
count(*) > 1;
This allows you to aggregate by empno even when multiple records exist for each category (more than one).
You have to use a subquery where you get the count of rows, grouped by A, B and C. And then you join this subquery again with your table (or with your query), like this:
select your_table.A, your_table.B, your_table.C, your_table.D, cnt
from
your_table inner join
(SELECT A, B, C, count(*) as cnt
FROM your_table
GROUP BY A, B, C) t
on t.A = your_table.A
and t.B = your_table.B
and t.C = your_table.C