I've tried to do a pagination on data in using ROW_NUMBER()
Here is my query:
SELECT * FROM
(SELECT ROW_NUMBER() OVER (ORDER BY OrderID) AS Row,* FROM SpecificOrders)
AS EMP
inner join Users as c on EMP.UserID = c.UserID
inner join Users as u on EMP.CreatedBy = u.UserID
inner join SpecificOrderPayment as p on EMP.OrderID= p.OrderID
WHERE Row BETWEEN 0 AND 10
When I execute this query, I get output like following with :
Row | OrderID | UserID |
1 | | |
5 | | |
6 | | |
7 | | |
8 | | |
9 | | |
10 | | |
If I remove this WHERE Row BETWEEN 0 AND 10 condition then it'll gives me all records
Here my question is why I get only 7 rows and why here 2,3 and 4 is missing in the row column.
Moreover, If i remove 3rd join query (SpecificOrderPayment)then it will give me proper result.
you've got OrderID that are null or blanks in SpecificOrders and they are sorting to the top - the approach isn't wrong otherwise, although there are other ways of doing it such as TOP 10..etc
SELECT * FROM
(SELECT ROW_NUMBER() OVER (ORDER BY OrderID) AS Row,* FROM SpecificOrders
WHERE RTRIM(COALESCE(OrderID, '')) <> '')
AS EMP
inner join Users as c on EMP.UserID = c.UserID
inner join Users as u on EMP.CreatedBy = u.UserID
inner join SpecificOrderPayment as p on EMP.OrderID= p.OrderID
WHERE Row BETWEEN 0 AND 10
The problem is that you are numbering the rows of SpecificOrders and not of final result.
In your case you only have one row per order, so using left joins should solve the issue
But, if the inner query could return multiple rows for each OrderID you will see the same row number many times
And if the join (inner) will filter some row you will not get that row number in result.
You have simply to separate the query for data extraction from the query for pagination,
Try this:
SELECT *
FROM (
SELECT ROW_NUMBER() OVER (ORDER BY EMP.OrderID) AS Row, EMP.*
FROM SpecificOrders AS EMP
left join Users as c on EMP.UserID = c.UserID
left join Users as u on EMP.CreatedBy = u.UserID
left join SpecificOrderPayment as p on EMP.OrderID= p.OrderID
) D
WHERE [Row] BETWEEN 0 AND 10
Related
I have a table RESTAURANT:
Id | Name
------------------
0 | 'McDonalds'
1 | 'Burger King'
2 | 'Starbucks'
3 | 'Pans'
And a table ORDER:
Id | ResId | Client
--------------------
0 | 1 | 'Peter'
1 | 2 | 'John'
2 | 2 | 'Peter'
Where 'ResId' is a foreign key from RESTAURANT.Id.
I want to select the number of order per restaurant:
Expected result:
Restaurant | Number of orders
----------------------------------
'McDonalds' | 0
'Burguer King' | 1
'Starbucks' | 2
'Pans' | 0
Actual result:
Restaurant | Number of orders
----------------------------------
'McDonalds' | 0
'Burguer King' | 1
'Starbucks' | 2
Command used:
select r.Name, count(o.ResId)
from RESTAURANT r
left join ORDER o on r.Id like o.ResId
group by o.ResId;
Just fix the group by clause:
select r.name, count(*) as cnt_orders
from restaurants r
left join orders o on r.id = o.resid
group by r.id, r.name;
That way, the SELECT and GROUP BY clauses are consistent; I also added the restaurant id to the group, so potential restaurants having the same name are not aggregated together. I also changed like to =: this is more efficient, and does not alter the logic.
You could also phrase this with a subquery, so there is no need for outer aggregation. I would prefer:
select r.*,
(select count(*) from orders o where o.resid = r.id) as cnt_orders
from restaurants r
Your query should be generating an error because the select columns and the group by columns are incompatible. Just aggregate by the unaggregated columns in the select:
select r.Name, count(o.ResId)
from RESTAURANT r left join
ORDER o
on r.Id = o.ResId
group by r.Name;
Notes:
You might want to include r.id in the GROUP BY (and SELECT) in case restaurants can have the same name.
Note the use of = instead of LIKE. The ids look like numbers, so you should use number operations. LIKE is a string operation.
ORDER is a bad name for a table because it is a SQL keyword.
As a general rule, in a LEFT JOIN, you don't want the aggregation keys to be from the second table, because those values could be NULL.
I have joined two queries with UNION keyword (Access 2016). It looks like that:
SELECT ITEM.IName, Sum(STOCK_IN.StockIn) AS SumOfIN
FROM ITEM INNER JOIN STOCK_IN ON ITEM.IName = STOCK_IN.IName
GROUP BY ITEM.IName
UNION SELECT ITEM.IName, Sum(STOCK_OUT.StockOut) AS SumOfOut
FROM ITEM INNER JOIN STOCK_OUT ON ITEM.IName = STOCK_OUT.IName
GROUP BY ITEM.IName
I get the following result:
IName | SumOfIN
----------------
Abis Nig | 3
Abrotanum | 1
Acid Acet | 2
Aconite Nap | 2
Aconite Nap | 3
Antim Crud | 3
Antim Tart | 1
But I want the following result:
IName | SumOfIN | SumOfOut
----------------
Abis Nig | 3 | 0
Abrotanum | 1 | 0
Acid Acet | 2 | 0
Aconite Nap | 2 | 3
Antim Crud | 0 | 3
Antim Tart | 0 | 1
Can anyone tell me what changes should I make here?
You need to add dummy values for the third column where they don't exist in the table you are UNIONing. In addition, you need an overall SELECT/GROUP BY since you can have values for both StockIn and StockOut:
SELECT IName, SUM(SumOfIN), Sum(SumOfOut)
FROM (SELECT ITEM.IName, Sum(STOCK_IN.StockIn) AS SumOfIN, 0 AS SumOfOut
FROM ITEM INNER JOIN STOCK_IN ON ITEM.IName = STOCK_IN.IName
GROUP BY ITEM.IName
UNION ALL
SELECT ITEM.IName, 0, Sum(STOCK_OUT.StockOut)
FROM ITEM INNER JOIN STOCK_OUT ON ITEM.IName = STOCK_OUT.IName
GROUP BY ITEM.IName) s
GROUP BY IName
Note that column names in the result table are all taken from the first table in the UNION, so we must name SumOfOut in that query.
You can do this query without UNION at all:
select i.iname, si.sumofin, so.sumofout
from (item as i left join
(select si.iname, sum(si.stockin) as sumofin
from stock_in as si
group by si.iname
) as si
on si.iname = i.iname
) left join
(select so.iname, sum(so.stockout) as sumofout
from stock_out as so
group by so.iname
) as so
on so.iname = i.iname;
This will include items that have no stock in or stock out. That might be a good thing, or a bad thing. If a bad thing, then add:
where si.sumofin > 0 or so.sumofout > 0
If you are going to use union all, then you can dispense with the join to items entirely:
SELECT IName, SUM(SumOfIN), Sum(SumOfOut)
FROM (SELECT si.IName, Sum(si.StockIn) AS SumOfIN, 0 AS SumOfOut
FROM STOCK_IN as si
GROUP BY si.INAME
UNION ALL
SELECT so.IName, 0, Sum(so.StockOut)
STOCK_OUT so
GROUP BY so.IName
) s
GROUP BY IName;
The JOIN would only be necessary if you had stock items that are not in the items table. That would be a sign of bad data modeling.
TABLES:
Players
player_no | transaction_id
----------------------------
1 | 11
2 | 22
3 | (null)
1 | 33
Transactions
id | value |
-----------------------
11 | 5
22 | 10
33 | 2
My goal is to fetch all data, maintaining all the players, even with null values in following query:
SELECT p.player_no, COUNT(p.player_no), SUM(t.value) FROM Players p
INNER JOIN Transactions t ON p.transaction_id = t.id
GROUP BY p.player_no
nevertheless results omit null value, example:
player_no | count | sum
------------------------
1 | 2 | 7
2 | 1 | 10
What I would like to have is mention about the empty value:
player_no | count | sum
------------------------
1 | 2 | 7
2 | 1 | 10
3 | 0 | 0
What do I miss here?
Actually I use QueryDSL for that, but translated example into pure SQL since it behaves in the same manner.
using LEFT JOIN and coalesce function
SELECT p.player_no, COUNT(p.player_no), coalesce(SUM(t.value),0)
FROM Players p
LEFT JOIN Transactions t ON p.transaction_id = t.id
GROUP BY p.player_no
Change your JOIN to a LEFT JOIN, then add IFNULL(value, 0) in your SUM()
left join keeps all the rows in the left table
SELECT p.player_no
, COUNT(*) as count
, SUM(isnull(t.value,0))
FROM Players p
LEFT JOIN Transactions t
ON p.transaction_id = t.id
GROUP BY p.player_no
You might be looking for count(t.value) rather than count(*)
I'm just offering this so you have a correct answer:
SELECT p.player_no, COUNT(t.id) as [count], COALESCE(SUM(t.value), 0) as [sum]
FROM Players p LEFT JOIN
Transactions t
ON p.transaction_id = t.id
GROUP BY p.player_no;
You need to pay attention to the aggregation functions as well as the JOIN.
Please Try This:
SELECT P.player_no,
COUNT(*) as count,
SUM(isnull(T.value,0))
FROM Players P
LEFT JOIN Transactions T
ON P.transaction_id = T.id
GROUP BY P.player_no
Hope this helps.
I have information in a CheckLine table that essentially breaks down the various fees and information on a particular check. For this query I am wanting to SUM the total of the CheckLine but it is instead giving a SUM for ALL CheckLines together. I know I am missing something blatantly obvious, but I keep scratching my head on why I individualize the SUMs. Here is my query:
SELECT DISTINCT
O.FileNumber
,(SELECT DISTINCT
SUM(CL.Amount)
FROM
dbo.Orders O
LEFT JOIN dbo.Checks C
ON O.OrdersID = C.OrdersID
LEFT JOIN dbo.CheckLine CL
ON C.ChecksID = CL.ChecksID
) AS 'Total'
FROM
dbo.Orders O
LEFT JOIN dbo.Checks C
ON O.OrdersID = C.OrdersID
LEFT JOIN dbo.CheckLine CL
ON C.ChecksID = CL.ChecksID
This is what it is returning:
| FileNumber | … | Total |
| 1 | | 2000 |
| 2 | | 2000 |
What it should be returning is:
| FileNumber | … | Total |
| 1 | | 700 |
| 2 | | 1300 |
Thoughts on my complete brain fart here? Thanks guys!
SELECT
O.FileNumber,
O.CloseDate,
SUM(CL.Amount) as Total
FROM dbo.Orders O
LEFT JOIN dbo.Checks C
ON O.OrdersID = C.OrdersID
LEFT JOIN dbo.CheckLine CL
ON C.ChecksID = CL.ChecksID
GROUP BY O.FileNumber, O.CloseDate
When you calculate Total in a subquery, that value will be treated as constant by SQL Server that will repeat every row.
It is very common to confuse GROUP BY with DISTINCT (please look at here and here) since they return the same values if no aggregation function is in the SELECT clause. In your example:
SELECT DISTINCT FileNumber FROM ORDERS
will return the same of
SELECT FileNumber FROM ORDERS GROUP BY FileNumber
Use GROUP BY if you are wanting to aggregate information (like your field TOTAL).
You probably want this:
SELECT O.FileNumber, SUM(CL.Amount) as total
FROM dbo.Orders O
LEFT JOIN dbo.Checks C
ON O.OrdersID = C.OrdersID
LEFT JOIN dbo.CheckLine CL
ON C.ChecksID = CL.ChecksID
group by O.FileNumber
Firstly, I apologize for my English. I want get auctions with count of bids and buys. It should look like this:
id | name | bids | buys
-----------------------
1 | Foo | 4 | 1
2 | Bar | 0 | 0
I have tables like following:
auction:
id | name
---------
1 | Foo
2 | Bar
auction_bid:
id | auction_id
---------------
1 | 1
2 | 1
3 | 1
4 | 1
auction_buy:
id | auction_id
---------------
1 | 1
I can get numbers in two queries:
SELECT *, COUNT(abid.id) AS `bids` FROM `auction` `t` LEFT JOIN auction_bid abid ON (t.id = abid.auction) GROUP BY t.id
SELECT *, COUNT(abuy.id) AS `buys` FROM `auction` `t` LEFT JOIN auction_buy abuy ON (t.id = abuy.auction) GROUP BY t.id
But when i combined it into one:
SELECT *, COUNT(abid.id) AS `bids`, COUNT(abuy.id) AS `buys` FROM `auction` `t` LEFT JOIN auction_bid abid ON (t.id = abid.auction) LEFT JOIN auction_buy abuy ON (t.id = abuy.auction) GROUP BY t.id
It was returning wrong amount (bids as much as buys).
How to fix this and get counts in one query?
You'll need to count DISTINCT abuy and abid IDs to eliminate the duplicates;
SELECT t.id, t.name,
COUNT(DISTINCT abid.id) `bids`,
COUNT(DISTINCT abuy.id) `buys`
FROM `auction` `t`
LEFT JOIN auction_bid abid ON t.id = abid.auction_id
LEFT JOIN auction_buy abuy ON t.id = abuy.auction_id
GROUP BY t.id, t.name;
An SQLfiddle to test with.
Try this:
SELECT t.*,COUNT(abid.id) as bids,buys
FROM auction t LEFT JOIN
auction_bid abid ON t.id = abid.auction_id LEFT JOIN
(SELECT t.id, Count(abuy.id) as buys
FROM auction t LEFT JOIN
auction_buy abuy ON t.id = abuy.auction_id
GROUP BY t.id) Temp ON t.id=Temp.id
GROUP BY t.id
Result:
ID NAME BIDS BUYS
1 Foo 2 0
2 Bar 1 1
Result in SQL Fiddle.