For the below query
Scenario 1: Current Year (Previous Week) - For eg- Week 31
sum(case when s.Date between '2016-07-17' and '2016-07-23' then s.SELLINC else 0 end) ActualSales
Scenario 2: Last Year (Previous Week) - For eg- Week 31
sum(case when s.Date between '2015-07-19' and '2015-07-25' then s.SELLINC else 0 end) LastYrVarianc
Scenario 3: Picking dates between beginning of current year till today's date
sum(case when s.Date between '2016-01-01' and '2016-09-05' then s.SELLINC else 0 end) YrToDateActual
Scenario 4: Picking dates between beginning of last year till last year today's date
sum(case when s.Date between '2015-01-01' AND '2015-09-05' then s.SELLINC else 0 end) LastYrToDateActual
Instead of hard coding the date. I would like to pick current date from machine and compare.
Week start from Sunday and ends Saturday. Any help please?
First off, GETDATE() is the SQL Server function for today's date
DATEADD(..) is the function to add stuff to dates
1) case when s.date between DATEADD(dd,-6,getdate()) and getdate()) then...
2) case when s.date between DATEADD(yy,-1,DATEADD(dd,-6,getdate())) and DATEADD(yy,-1,getdate()) then ...
3) case when s.date between DATEADD(yy, DATEDIFF(yy,0,getdate()), 0) and getdate() then ...
4) case when s.date between dateadd(yy,-1,DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)) and DATEADD(yy,-1,GETDATE()) then ..
A little help from here
I assume that your week starts from sunday to saturday.
You can use this query,
Scenario-1 (PreviousWeekStartDate and PreviousWeekEndDate)
s.Date between convert(date,dateadd(wk, datediff(wk, 0, getdate()) - 1, 0) - 1) and convert(date,dateadd(wk, datediff(wk, 0, getdate()) - 1, 0) + 5)
Scenario-2 (LastYearPreviousWeekStartDate and LastYearPreviousWeekEndDate)
s.Date between convert(date,dateadd(wk, datediff(wk, 0, dateadd(YEAR, - 1, getdate())) - 1, 0) - 1) and convert(date,dateadd(wk, datediff(wk, 0, dateadd(YEAR, - 1, getdate())) - 1, 0) + 5)
Scenario-3 (StartOfYear and CurrentDate)
s.Date between convert(date,DATEADD(yy, DATEDIFF(yy, 0, getdate()), 0)) and convert(date,getdate())
Scenario-4 (StartOfLastYear and CurrentDateLastYear)
s.Date between convert(date,DATEADD(yy, DATEDIFF(yy, 0, dateadd(YEAR, - 1, getdate())), 0)) and convert(date,dateadd(YEAR, - 1, getdate()))
Use date arithmetic
declare #weekNo int = 31;
--start of the year
declare #ys datetime = dateadd(year,datediff(year,0,getdate()),0)
-- start of the first week of the year (may start in December of prev year)
declare #y1ws datetime = dateadd(week,datediff(week,0,#ys),0)
select #ys, #y1ws, dateadd(week, #weekNo-1, #y1ws) [week31 start], dateadd(week, #weekNo, #y1ws) [week32 start]
-- use it this way for week 31
-- .. where somedate >= [week31 start] and somedate < [week32 start]
SELECT
GETDATE(), -- Today
DATEADD(YEAR, DATEDIFF(YEAR, 0, GETDATE()), 0), -- Start of this year
DATEADD(YEAR, DATEDIFF(YEAR, 0, GETDATE()) - 1, 0), -- Start of last year
DATEADD(WEEK, DATEDIFF(WEEK, 0, GETDATE()), 0), -- Start of this week
DATEADD(WEEK, DATEDIFF(WEEK, 0, GETDATE()) - 1, 0) -- Start of last week
I think using DATEPART (Transact-SQL) is a more portable solution. My answers for scenario 1 and scenario 2 refer a natural week starting from Sunday, which are different from JohnHC's answers (referring last 7 days).
--
-- Scenario 1: Current Year (Previous Week) - For eg- Week 31
--
CASE WHEN
DATEPART(ww, s.Date) = DATEPART(ww, GETDATE()) - 1 AND
DATEPART(yy, s.Date) = DATEPART(yy, GETDATE())
THEN ...
--
-- Scenario 2: Last Year (Previous Week) - For eg- Week 31
--
CASE WHEN
DATEPART(ww, s.Date) = DATEPART(ww, GETDATE()) - 1 AND
DATEPART(yy, s.Date) = DATEPART(yy, GETDATE()) - 1
THEN ...
--
-- Scenario 3: Picking dates between beginning of current year till today's date
--
CASE WHEN
DATEPART(yy, s.Date) = DATEPART(yy, GETDATE())
THEN ...
--
-- Scenario 4: Picking dates between beginning of last year till last year today's date
--
CASE WHEN
DATEPART(yy, s.Date) >= DATEPART(yy, GETDATE()) - 1
THEN ...
Related
Am trying to fetch data in SQL until previous week Friday for the present year from the datetime field fetchDate
I tried something like this but it fetches until today
(year(fetchDate) = year(GETDATE()) and month(fetchDate) <= month(GETDATE()) and day(fetchDate) <= day(GETDATE()))
whereas
(year(fetchDate) = year(GETDATE()) and month(fetchDate) <= month(GETDATE()) and day(fetchDate) <= day(DATEADD(wk,DATEDIFF(wk,7,GETDATE()),4)))
brings me data only for the present month of the year until last week.
I believe what you need is the following:
WHERE YEAR(fetchDate) = YEAR(CURDATE())
AND fetchDate < DATE_SUB(NOW(), INTERVAL ((7 + WEEKDAY(DATE_SUB(NOW(), INTERVAL 1 WEEK)) - 4) % 7) DAY)
We get how many days ago last week's Friday was with:
((7 + WEEKDAY(DATE_SUB(NOW(), INTERVAL 1 WEEK)) - 4) % 7)
I would rather go for the following solution as it is sargable. Inside the WHERE predicate we are not wrapping the fetchdate into a function (e.g. YEAR(Fetchdate)), the query optimizer could use existing indexes and does not have to scan the whole table. Especially for BI workloads where this query is common, it is extremely important to optimize for that a lot of records are queried. It comes at the cost of little less readability
declare #tab table
(
fetchdate datetime
)
insert into #tab
values ('2019-01-01'),('2019-03-15'),('2018-12-31'),('2019-03-16')
SELECT
*,
case when datepart(weekday, getdate()) >5 then
DATEADD(DAY, +4, DATEADD(WEEK, DATEDIFF(WEEK, 0, getdate()), 0))
else DATEADD(DAY, -3, DATEADD(WEEK, DATEDIFF(WEEK, 0, getdate()), 0)) end as TestLastFriday,
DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0) as TestFirstDayOfYear
FROM #tab
where
fetchdate <= case when datepart(weekday, getdate()) >5 then DATEADD(DAY, +4, DATEADD(WEEK, DATEDIFF(WEEK, 0, getdate()), 0))
else DATEADD(DAY, -3, DATEADD(WEEK, DATEDIFF(WEEK, 0, getdate()), 0)) end and
fetchdate >= DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0)
How could I get the first business day of the current month?
Without create a function, only select.
something like that:
SELECT CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(GETDATE())-1), GETDATE()), 101)
somebody knows please?
Thanks.
A Simple case statement could do it
SELECT CASE
WHEN DATENAME(WEEKDAY, dateadd(mm, DATEDIFF(MM, 0, getdate()), 0)) = 'Saturday'
THEN dateadd(mm, DATEDIFF(MM, 0, getdate()), 0) + 2
WHEN DATENAME(WEEKDAY, dateadd(mm, DATEDIFF(MM, 0, getdate()), 0)) = 'Sunday'
THEN dateadd(mm, DATEDIFF(MM, 0, getdate()), 0) + 1
ELSE dateadd(mm, DATEDIFF(MM, 0, getdate()), 0)
END
This will literally give you what you're asking for -- the first business day in a month if we define a business day as "any day that's not a Saturday or a Sunday". But this is is a very narrow definition of "business day" that is not appropriate when taking into account holidays and cultural differences, so it generalizes poorly. The typical solution for this problem is to create a table that actually holds the working days (which is generated somewhere just before he year, or calculated in advance if that's feasible), and simply look it up in that.
SELECT DATEADD(DAY,
CASE
(DATEPART(WEEKDAY, DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0)) + ##DATEFIRST - 1) % 7
WHEN 6 THEN 2
WHEN 7 THEN 1
ELSE 0
END,
DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0)
)
This solution uses ##DATEFIRST to avoid any language issues -- using DATEPART(WEEKDAY, ...) on its own or DATENAME() only works if we assume a specific region.
If you have more flexibility in your SELECT statement, you might be able to use something like this:
;With Daterange As
(
Select DateAdd(Month, DateDiff(Month, 0, GetDate()), 0) As Date Union All
Select DateAdd(Day, 1, Date) As Date
From DateRange
Where Date < DateAdd(Day, 6, DateAdd(Month, DateDiff(Month, 0, GetDate()), 0))
)
Select Convert(Date, Min(Date)) FirstBusinessDay
From Daterange
Where DatePart(WeekDay, Date) Not In (7, 1)
Try this.
SELECT CASE
WHEN Datename(dw, Dateadd(dd, -Datepart(dd, Getdate()) + 1, Getdate())) = 'Saturday' THEN Dateadd(dd, -Datepart(dd, Getdate()) + 3, Getdate())
WHEN Datename(dw, Dateadd(dd, -Datepart(dd, Getdate()) + 1, Getdate())) = 'Sunday' THEN Dateadd(dd, -Datepart(dd, Getdate()) + 2, Getdate())
ELSE Dateadd(dd, -Datepart(dd, Getdate()) + 1, Getdate())
END
Explanation :
Find the first day of the month.
Dateadd(dd, -Datepart(dd, Getdate()) + 1, Getdate())
Then check the day of the previous date by using Datename function.
Datename(dw, Dateadd(dd, -Datepart(dd, Getdate()) + 1, Getdate()))
If the Datename is Saturday the add 2 days to the first day of the month . if it is sunday then add 1 day to the first day of the month else get the first day of the month
I have this code in crystal reports that gives me last week date range based on the current date.
First day of the week:
If DayOfWeek(currentdate) = 2 Then
currentdate
Else If DayOfWeek(currentdate) = 3 Then
dateadd ("d",-1,currentdate)
Else If DayOfWeek(currentdate) = 4 Then
dateadd ("d",-2,currentdate)
Else If DayOfWeek(currentdate) = 5 Then
dateadd ("d",-3,currentdate)
Else If DayOfWeek(currentdate) = 6 Then
dateadd ("d",-4,currentdate)
Else If DayOfWeek(currentdate) = 7 Then
dateadd ("d",-5,currentdate)
Else If DayOfWeek(currentdate) = 1 Then
dateadd ("d",-6,currentdate)
Last day of week:
If DayOfWeek(currentdate) = 2 Then
dateadd ("d",+6,currentdate)
Else If DayOfWeek(currentdate) = 3 Then
dateadd ("d",+5,currentdate)
Else If DayOfWeek(currentdate) = 4 Then
dateadd ("d",+4,currentdate)
Else If DayOfWeek(currentdate) = 5 Then
dateadd ("d",+3,currentdate)
Else If DayOfWeek(currentdate) = 6 Then
dateadd ("d",+2,currentdate)
Else If DayOfWeek(currentdate) = 7 Then
dateadd ("d",+1,currentdate)
Else If DayOfWeek(currentdate) = 1 then currentdate
How can I do the same in SQL using 2 variables to storage Monday(startdate) and Sunday(enddate)?
I found this select datepart(dw,getdate()) --6 in this site, but I do not know how to use it.
I generated some spaced out dates in the parms CTE then SELECT the CurrentDate from parms, the Sunday of the week prior to CurrentDate and the Saturday of the week prior to CurrentDate. I'm assuming that you want the dtate range to be Sunday - Saturday.
Sunday - Saturday Ranges
;WITH parms (CurrentDate) AS (
SELECT DATEADD(dd, -14, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, -6, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, 2, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, 8, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, 15, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, 20, CURRENT_TIMESTAMP)
)
SELECT CurrentDate
, LastWeekSunday = DATEADD(dd, -1, DATEADD(ww, DATEDIFF(ww, 0, CurrentDate) - 1, 0))
, LastWeekSaturday = DATEADD(dd, 5, DATEADD(ww, DATEDIFF(ww, 0, CurrentDate) - 1, 0))
FROM parms
Monday to Sunday Ranges
;WITH parms (CurrentDate) AS (
SELECT DATEADD(dd, -14, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, -6, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, 2, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, 8, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, 15, CURRENT_TIMESTAMP) UNION
SELECT DATEADD(dd, 20, CURRENT_TIMESTAMP)
)
SELECT CurrentDate
, LastWeekMonday = DATEADD(dd, 0, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CurrentDate)) - 1, 0))
, LastWeekSunday = DATEADD(dd, 6, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CurrentDate)) - 1, 0))
FROM parms
If you just want the prior week's Monday to the prior week's Sunday from today rather than from a column of dates you can use this
SELECT CURRENT_TIMESTAMP
, LastWeekSunday = DATEADD(dd, 0, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CURRENT_TIMESTAMP)) - 1, 0))
, LastWeekSaturday = DATEADD(dd, 6, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CURRENT_TIMESTAMP)) - 1, 0))
This solution is tested and works. I am getting the previous week's Monday and Sunday as upper and lower bounds.
SELECT
-- 17530101 or 1753-01-01 is the minimum date in SQL Server
DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 7, '17530101') AS [LowerLimit], -- Last Week's Monday
DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 1, '17530101') AS [UpperLimit] -- Last Week's Sunday.
Which can be used like this in a real world query:
SELECT
*
FROM
SomeTable
WHERE
SomeTable.[Date] >= DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 7, '17530101') AND
SomeTable.[Date] <= DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 1, '17530101')
Here are some tests:
1. Leap Year
Current Date: 2016-02-29 00:00:00.000
Results:
LowerLimit UpperLimit
2016-02-22 00:00:00.000 2016-02-28 00:00:00.000
2. Last Week was in different year
Current Date: 2016-01-06 00:00:00.000
LowerLimit UpperLimit
2015-12-28 00:00:00.000 2016-01-03 00:00:00.000
3. Lower limit in previous month and upper limit in current month
Current Date: 2016-05-04 00:00:00.000
LowerLimit UpperLimit
2016-04-25 00:00:00.000 2016-05-01 00:00:00.000
4. Current Date is Sunday
Current Date: 2016-05-08 00:00:00.000
LowerLimit UpperLimit
2016-04-25 00:00:00.000 2016-05-01 00:00:00.000
Bill's code worked well, but I needed to make a slight edit if I wanted to get last Sunday to Saturday based on today's date.
select CURRENT_TIMESTAMP,
LastWeekSunday = DATEADD(dd, -1, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CURRENT_TIMESTAMP)) - (case datename(weekday,CURRENT_TIMESTAMP) when 'Sunday' then 0 else 1 end), 0)),
LastWeekSaturday = DATEADD(dd, 5, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CURRENT_TIMESTAMP)) - (case datename(weekday,CURRENT_TIMESTAMP) when 'Sunday' then 0 else 1 end), 0))
Rgds - Matt
For everything date and date interval related, I'd almost always recommend using a calendar table. A table with columns representing date, week, month, year, day of week, hiliday, weekand, etc, prepopulated as needed and indexed on every column. It's only 365 rows per year.
select min(date), max(date)
from calendar
where week = datepart(week, getdate() - 7)
and year = datepart(year, getdate() - 7)
A shortened version concise syntax
last week, in my vision is the prev adjacent week, so if Im doing report during the week days, I want to receive dates of previous adjacent week Monday to Sunday.
prev Monday is DATE_ADD(CURDATE(), INTERVAL -(5 + dayofweek(CURDATE())) DAY)
prev Sunday is DATE_ADD(CURDATE(), INTERVAL -(dayofweek(CURDATE()) - 1) DAY)
then to take the report from the table need just to integrate those two in SELECT statement
select * from XXX where DateCol between DATE_ADD(CURDATE(), INTERVAL -(5 + dayofweek(CURDATE())) DAY) and DATE_ADD(CURDATE(), INTERVAL -(dayofweek(CURDATE()) - 1) DAY) order by DateCol
I'm late to this party, but wanted to add a simpler way that works for me in SQL Server (when the other examples did not).
select * from table
-- this is for the previous week:
where (datefield >= DATEADD(dd, -1, DATEADD(ww, DATEDIFF(ww, 0, GETDATE()) - 1, 0)) and datefield < DATEADD(dd, 6, DATEADD(ww, DATEDIFF(ww, 0, GETDATE()) - 1, 0)))
-- alternatively, this is for a rolling 7 days:
and DATEDIFF(day, datefield, GETDATE()) between 0 and 7
I'm trying to get the correct SQL code to obtain last Friday's date. A few days ago, I thought I had my code correct. But just noticed that it's getting last week's Friday date, not the last Friday. The day I'm writing this question is Saturday, 8/11/2012 # 12:23am. In SQL Server, this code is returning Friday, 8/3/2012. However, I want this to return Friday, 8/10/2012 instead. How can I fix this code? Since we're getting to specifics here, if the current day is Friday, then I want to return today's date. So if it were yesterday (8/10/2012) and I ran this code yesterday, then I would want this code to return 8/10/2012, not 8/3/2012.
SELECT DATEADD(DAY, -3, DATEADD(WEEK, DATEDIFF(WEEK, 0, GETDATE()), 0))
try this:
declare #date datetime;
set #date='2012-08-09'
SELECT case when datepart(weekday, #date) >5 then
DATEADD(DAY, +4, DATEADD(WEEK, DATEDIFF(WEEK, 0, #date), 0))
else DATEADD(DAY, -3, DATEADD(WEEK, DATEDIFF(WEEK, 0, #date), 0)) end
result:
2012-08-03
Example2:
declare #date datetime;
set #date='2012-08-10'
SELECT case when datepart(weekday, #date) >5 then
DATEADD(DAY, +4, DATEADD(WEEK, DATEDIFF(WEEK, 0, #date), 0))
else DATEADD(DAY, -3, DATEADD(WEEK, DATEDIFF(WEEK, 0, #date), 0)) end
result:
2012-08-10
Modular arithmetic is the most direct approach, and order of operations decides how Fridays are treated:
DECLARE #test_date DATETIME = '2012-09-28'
SELECT DATEADD(d,-1-(DATEPART(dw,#test_date) % 7),#test_date) AS Last_Friday
,DATEADD(d,-(DATEPART(dw,#test_date+1) % 7),#test_date) AS This_Friday
Use this :
SELECT DATEADD(day, (DATEDIFF (day, '19800104', CURRENT_TIMESTAMP) / 7) * 7, '19800104') as Last_Friday
None of that? Try this:
DECLARE #D DATE = GETDATE()
SELECT DATEADD(D,-(DATEPART(W,#D)+1)%7,#D)
A tested function which works no matter what ##DATEFIRST is set to.
-- ==============
-- fn_Get_Week_Ending_forDate
-- Author: Shawn C. Teague
-- Create date: 2017
-- Modified date:
-- Description: Returns the Week Ending Date on DayOfWeek for a given stop date
-- Parameters: DayOfWeek varchar(10) i.e. Monday,Tues,Wed,Friday,Sat,Su,1-7
-- DateInWeek DATE
-- ==============
CREATE FUNCTION [dbo].[fn_Get_Week_Ending_forDate] (
#DayOfWeek VARCHAR(10),#DateInWeek DATE)
RETURNS DATE
AS
BEGIN
DECLARE #End_Date DATE
,#DoW TINYINT
SET #DoW = CASE WHEN ISNUMERIC(#DayOfWeek) = 1
THEN CAST(#DayOfWeek AS TINYINT)
WHEN #DayOfWeek like 'Su%' THEN 1
WHEN #DayOfWeek like 'M%' THEN 2
WHEN #DayOfWeek like 'Tu%' THEN 3
WHEN #DayOfWeek like 'W%' THEN 4
WHEN #DayOfWeek like 'Th%' THEN 5
WHEN #DayOfWeek like 'F%' THEN 6
ELSE 7
END
select #End_Date =
CAST(DATEADD(DAY,
CASE WHEN (#DoW - (((##datefirst) + datepart(weekday, #DateInWeek)) % 7)) = 7
THEN 0
WHEN (#DoW - (((##datefirst) + datepart(weekday, #DateInWeek)) % 7)) < 0
THEN 7 - ABS(#DoW - (((##datefirst) + datepart(weekday, #DateInWeek)) % 7))
ELSE (#DoW - (((##datefirst) + datepart(weekday, #DateInWeek)) % 7) )
END
,#DateInWeek) AS DATE)
RETURN #End_Date
END
This will give you the Friday of Last week.
SELECT DATEADD(day, -3 - (DATEPART(dw, GETDATE()) + ##DATEFIRST - 2) % 7, GETDATE()) AS LastWeekFriday
This will give you last Friday's Date.
SELECT DATEADD(day, +4 - (DATEPART(dw, GETDATE()) + ##DATEFIRST-2) % 7, GETDATE()) AS LastFriday
select convert(varchar(10),dateadd(d, -((datepart(weekday, getdate()) + 1 + ##DATEFIRST) % 7), getdate()),101)
Following code can be use to return any last day by replacing #dw_wk, test case below use friday as asked in original questions
DECLARE #date SMALLDATETIME
,#dw_wk INT --last day of week required - its integer representation
,#dw_day int --current day integer reprsentation
SELECT #date='8/11/2012'
SELECT #dw_day=DATEPART(dw,#date)
SELECT #dw_wk=DATEPART(dw,'1/2/2015') --Just trying not to hard code 5 for friday, here we can substitute with any date which is friday
SELECT case when #dw_day<#dw_wk then DATEADD(DAY, #dw_wk-7-#dw_day,#date) else DATEADD(DAY,#dw_wk-#dw_day, #date) END
Here's an answer I found here adapted from MySQL to T-SQL that is a one liner using all basic arithmetic (no division or modulos):
SELECT DATEADD(d, 1 - datepart(weekday, dateadd(d, 2, GETDATE())), GETDATE())
You can do all sorts of combinations of this, like get next Friday's date unless today is Friday, or get last Thursday's date unless today is Thursday by just changing the 1 and the 2 literals in the command:
Get next Friday's date unless today is Friday
SELECT DATEADD(d, 7 - datepart(weekday, dateadd(d, 1, GETDATE())), GETDATE())
Get last Thursday's date unless today is Thursday
SELECT DATEADD(d, 1 - datepart(weekday, dateadd(d, 3, GETDATE())), GETDATE())
I have had this same issue, and created the following example to show how to do this and to make it flexible to use whichever day of the week you want. I have different lines in the SELECT statement, just to show what this is doing, but you just need the [Results] line to get the answer. I also used variables for the current date and the target day of the week, to make it easier to see what needs to change.
Finally, there is an example of results when you want to include the current date as a possible example or when you always want to go back to the previous week.
DECLARE #GetDate AS DATETIME = GETDATE();
DECLARE #Target INT = 6 -- 6 = Friday
SELECT
#GetDate AS [Current Date] ,
DATEPART(dw, #GetDate) AS [Current Day of Week],
#Target AS [Target Day of Week] ,
IIF(#Target = DATEPART(dw, #GetDate), 'Yes' , 'No') AS [IsMatch] ,
IIF(#Target = DATEPART(dw, #GetDate), 0 , ((7 + #Target - DATEPART(dw, #GetDate)) % 7) - 7) AS [DateAdjust] ,
------------------------------------------------------------------------------------------------------------------------------------------------
CAST(IIF(#Target = DATEPART(dw, #GetDate), #GetDate, DATEADD(d, (((7 + #Target - DATEPART(dw, #GetDate)) % 7) - 7), #GetDate)) AS DATE) AS [Result]
------------------------------------------------------------------------------------------------------------------------------------------------
;
SELECT
#GetDate AS [Current Date] ,
DATEPART(dw, #GetDate) AS [Current Day of Week],
#Target AS [Target Day of Week] ,
((7 + #Target - DATEPART(dw, #GetDate)) % 7) - 7 AS [DateAdjust] ,
------------------------------------------------------------------------------------------------------------------------------------------------
CAST(DATEADD(d, (((7 + #Target - DATEPART(dw, #GetDate)) % 7) - 7), #GetDate) AS DATE) AS [NOTIncludeCurrent]
------------------------------------------------------------------------------------------------------------------------------------------------
;
SELECT DECODE(TO_CHAR(SYSDATE,'DY'),'FRI',SYSDATE,NEXT_DAY(SYSDATE, 'FRI')-7) FROM dual;
I may be using the wrong term (hence why I can't find it on google).
"Are there any functions or common code for Accounting Months Deliminations?"
For Example, this month started on a friday but on most accounting journals the weeks are measured by the first monday of the month so instead of having the 1st of July it would be the 4th of July. Same thing with the month end (29th instead of the 31st)
Again, I'm sure someone has created this 'wheel' before, and I can't seem to find it for the life of me.
The following query assumes a table, SalesTable, has a field called Amount (the value you want to sum) and a field called SaleDate (the date on which the sale occured.) It also assumes that accounting months begin the first Monday of the month and end on the Sunday prior to the beginning of the next accounting month.
Again, I highly recommend a table-based approach to this, but if you can't modify the schema, this should do the trick in T-SQL:
SELECT
CASE WHEN s.SaleDate < DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
THEN DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, DATEADD(day,-7,s.SaleDate) ),DATEADD(day,-7,s.SaleDate) )), 0)
ELSE DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
END AccountingMonth,
SUM(s.Amount) TotalSales
FROM SalesTable s
GROUP BY
CASE WHEN s.SaleDate < DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
THEN DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, DATEADD(day,-7,s.SaleDate) ),DATEADD(day,-7,s.SaleDate) )), 0)
ELSE DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
END
Note that the AccountingMonth return field actually contains the date of the first Monday of the month. In actual practice, you probably want to wrap this entire query in another query that reformats AccountingMonth to whatever you like... "2011-07", "2011-08", etc.
Here's how it works: This bit of code is the important part:
DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
It takes any date and returns the first Monday of the month in which that date occurred. In your case, however, you have to do a little more work because a sale might have occurred in the window between the first of the month and the first Monday of the month. The CASE statement detects that scenario and, if it's true, subtracts a week off of the date before calculating the first Monday.
Good luck!
-Michael
I have some code that takes in a year and month and returns the fiscal start and end dates. Perhaps this will give you something to go by:
DECLARE #yr int;
DECLARE #mo int;
SELECT #yr = 2011
SELECT #mo = 7
DECLARE #FiscalMonthStartDate datetime
DECLARE #FiscalMonthEndDate datetime
DECLARE #startOfMonth datetime
DECLARE #startOfNextMonth datetime
select #startOfMonth = CAST((CAST(#yr AS VARCHAR(4)) + '-' + CAST(#mo AS VARCHAR(2)) + '-' + '01') as DATE)
select #startOfNextMonth = CAST((CAST(#yr AS VARCHAR(4)) + '-' + CAST((#mo + 1) AS VARCHAR(2)) + '-' + '01') as DATE)
SELECT #FiscalMonthStartDate =
CASE
WHEN DATEPART(DW,#startOfMonth) = 0
THEN DATEADD(DD, 1, #startOfMonth)
ELSE
DATEADD(DD, 8 - DATEPART(DW,#startOfMonth), #startOfMonth)
END
SELECT #FiscalMonthEndDate =
CASE
WHEN DATEPART(DW,#startOfNextMonth) = 0
THEN DATEADD(DD, 1, #startOfNextMonth)
ELSE
DATEADD(DD, 8 - DATEPART(DW,#startOfNextMonth), #startOfNextMonth)
END
-- subtract one day to get end of fiscal month (not start of next fiscal month)
SELECT #FiscalMonthEndDate = DATEADD(DD, -1, #FiscalMonthEndDate)
SELECT #FiscalMonthStartDate, #FiscalMonthEndDate