SQL Query of 2 tables finding missing value in table 2 - sql

I have 2 tables in SQL.
-Table 1-
Name
ID
-Table 2-
ID
Program
Table 1 only holds a single record for each company. In table 2, there can be multiple entries for a record in table 1. So I could join the two tables together on ID = ID and get anywhere from 0 to 7 results. I need to query the 2 tables where I am looking for any company from table 1 who is not in a specific program but they can be in other programs. I know this is easy to do but I just can't get it to work for me.

SELECT *
FROM
Table1 t1
LEFT JOIN Table2 t2
ON t1.id = t2.id
AND t2.program = 'asdf'
WHERE
t2.id IS NULL
Just use an OUTER JOIN place the program requirement on the join condition and then say where a record for the Table2 doesn't exist.
Trying to make this a little less ambiguous and adapting to your specific companies and programs:
SELECT *
FROm
Companies c
LEFT JOIN Programs p
ON c.Id = p.CompanyId
AND p.Program = 'some title'
WHERE
p.Program IS NULL
And the NOT exists method:
SELECT *
FROM
Companies c
WHERE
NOT EXISTS (SELECT 1
FROM Programs p
WHERE
p.CompanyId = c.Id
AND p.Program = 'some title')
I don't show the NOT IN method because I don't recommend it typically.

You want to get companies where they aren't in a program that you specify in the query? This is what I came up with:
select t1.*
from Table1 t1
left join Table2 t2 on t1.ID = t2.ID
where coalesce(t2.Program, '') <> 'Name of Program'
or
where coalesce(t2.Program, '') not in (<comma-delimited list of programs>)

SELECT t1.Name
FROM Table1 t1
LEFT JOIN
Table2 t2
ON t1.id = t2.id
WHERE t2.program IS NULL;

Related

SQL query to get output from referring data in single table

I have 3 tables and the expected result like this:
This is the example table:
This is the expected output from the table:
To get the result I must refer the id and parentid from table2.
How to write a SQL query based on the pictures above?
You must join table1 to 2 copies of table2, the first is directly linked to the id of table1 and the 2nd is linked to the parentid of table2.
Then join to table3.
SELECT t1.*, t3.city
FROM table1 t1
INNER JOIN table2 c ON c.id = t1.id
INNER JOIN table2 p ON p.id = c.parentid
INNER JOIN table3 t3 ON t3.id = p.parentid

How to fetch * records from a table which are not present in other two tables

I want to fetch all records with all columns of a table, Records which are not in the other 2 tables. Please help.
I have tried below query, it is working fine for comparing one column. But I want to compare 5 columns.
select * from A
WHERE NOT EXISTS
(select * from B b where b.id=a.id) AND
NOT EXISTS
(select * from C c where c.id=a.id)
A general solution might look like:
SELECT t1.*
FROM table1 t1
WHERE NOT EXISTS (SELECT 1 FROM table2 t2 WHERE t2.id = t1.t2_id) AND
NOT EXISTS (SELECT 1 FROM table3 t3 WHERE t3.id = t1.t3_id);
This assumes that you want to target table1 for records, ensuring that no matches can found in table2 and table3.
I prefer this approach:
SELECT t1.*
FROM table1 AS t1
LEFT JOIN table2 AS t2
ON t1.id = t2.t1_id
LEFT JOIN table3 AS t3
ON t1.id = t3.t1_id
WHERE t2.id IS NULL
AND t3.id IS NULL;
While this might be a bit less intuitive than using sub queries I think odds of making mistakes with aliases are less likely as in the example below, which happens more often than you might expect:
SELECT *
FROM table1
WHERE NOT EXISTS (SELECT 1 FROM table2 WHERE id = id) AND
NOT EXISTS (SELECT 1 FROM table3 WHERE id = id);
To your question about checks on 5 columns, that can still be done using either of these methods by adding conditions either in the left joins or in the where clause of each sub query.

MS Access 2007 Inner Join on Same Table

I have a table t1. It has columns [id] and [id2].
Select count(*) from t1 where id=1;
returns 31,189 records
Select count(*) from t1 where id=2;
returns 31,173 records
I want to know the records where id2 is in id=1 but not in id=2.
So, I use the following:
Select * from t1 a left join t1 b on a.id2=b.id2
Where a.id=2 And b.id=1
And b.id2 Is Null;
It returns zero records.
Using an inner join to see how many records have id2 in common, I do...
Select * from t1 a inner join t1 b on a.id2=b.id2
Where a.id=2 And b.id=1;
And that returns 31,060. So where are the extra records in my first query that don't match?
I am sure I must be missing something obvious.
Sample Data
id id2
1 101
1 102
1 103
2 101
2 102
My expected results is to find the record with '103' in it. 'id2' not shared.
Thanks for any help.
Jeff
You are attempting to do what is generally called an exclude join. This involves doing a LEFT JOIN between two tables, then using a WHERE clause to only select rows where the right table is null, i.e. there was no record to join. In this way, you select everything from the left table except what exists in the right table.
With this data, it would look something like this:
SELECT
t1.id,
t1.id2
FROM test_table t1
LEFT JOIN
(SELECT
id,
id2
FROM test_table
WHERE id = 2) t2
ON t2.id2 = t1.id2
WHERE t1.id = 1
AND t2.id IS NULL --This is what makes the exclude join happen
And here is a SQLFiddle demonstrating this in MySQL 5.7 with the sample data you provided.
I think maybe Access changes the left join to an inner join when you add a where clause to filter rows (I know SQL Server does this), but if you do the filtering in derived tables it should work:
select
a.*
from
(select * from t1 where id = 1) a
left join
(select * from t1 where id = 2) b
on a.id2 = b.id2
where b.id2 is null

SQL query - filter with cascading conditions

I've two tables T1 and T2 with the following columns -
T1
Project_ID
Category
Column_X
Column_Y
Column_Z
T2
Proj_ID
Category
Parent_Project_ID
I want to write a query to get records from T1 with the following condition -
Get Projects with Category = "A" from T1
Get child projects of the above filtered projects
I'm not sure how to check the second condition only with the results coming out of first condition.
What is needed?
Projects from T1 where Category is A
Child projects of projects obtained from condition 1
Adding sample data and desired results as requested -
To get all records from second table then you can use the following query.
SELECT
t2.*
FROM T1 t1
RIGHT OUTER JOIN T2 t2 ON t1.Project_ID = t2.Project_ID
WHERE t1.Category = "A"
SELECT * FROM T2 WHERE T2.Proj_ID IN ( SELECT Project_ID FROM T1 WHERE Category = 'A' )
This should do the job needed.
SELECT * from T2 as d
WHERE EXISTS ( SELECT * from T1 as d1 where d1.Category = 'A' and d1.Project_ID = d.Proj_ID )
SELECT * from T1 as d1 right join T2 as d2 on d1.Project_ID = d2.Proj_ID
WHERE d1.CodTert = 500
I've made an update, these query give the same result, one uses the JOIN one doesn't.
I'm assuming that T2.Parent_Project_ID and T1.Project_ID are related. If so, you can use this:
Select T3.*
From T1
Join T2 On T2.Parent_Project_ID = T1.Project_ID
Join T1 T3 On T3.Project_ID = T2.Proj_ID
Where T1.Category = 'A'
This would get only child projects of projects that have a category of 'A'.
EDIT:
Based on the output format that has been added to the question, the following query, which uses a LEFT OUTER JOIN would render the exact result required:
SELECT
T2.PROJ_ID Project_ID,
T2.Category,
T1.Column_X,
T1.Column_Y,
T1.Column_Z,
T2.Parent_Project_ID
FROM T1 T1_PARENTS
INNER JOIN T2
ON T2.Parent_Project_ID = T1.Project_ID and T1.Category = 'A'
INNER JOIN T2 T2_CHILDREN
ON T2_CHILDREN.PROJ_ID = T2.Parent_Project_ID OR T2_CHILDREN.Parent_Project_ID = T2.Parent_Project_ID
LEFT OUTER JOIN T1
ON T2_CHILDREN.PROJ_ID = T1.Project_ID;

Tsql select from related table with AND condition

I've two related tables:
Table1
Id
-----
1
2
3
Table2
Id Feature
--------------
1 Car
1 Moto
1 Camper
2 Moto
2 Scooter
3 Apple
I want to select Ids which have, for example, both 'Car' AND 'Moto'.
So in the example i want to get only Id = 1.
Use the INTERSECT operator:
select id from table2 where feature = 'Car'
intersect
select id from table2 where feature = 'Moto'
This:
WITH features AS
(
SELECT feature
FROM (
VALUES
('Car'),
('Moto')
) q (feature)
)
SELECT *
FROM table1 t1
WHERE NOT EXISTS
(
SELECT feature
FROM features
EXCEPT
SELECT feature
FROM table2 t2
WHERE t2.id = t1.id
)
or this:
SELECT *
FROM table t1
WHERE (
SELECT COUNT(*)
FROM table2 t2
WHERE t2.id = t1.id
AND t2.feature IN ('Car', 'Moto')
) = 2
Which query is more efficient depends on how many records you have in both tables and how many matches there are.
This select does two LEFT OUTER JOINs to table2 (one based on 'Car' and the other based on 'Moto') and makes sure that each JOIN returned a result. The DISTINCT ensures that you get each ID only once.
SELECT DISTINCT t1.id
FROM table2 t2
LEFT OUTER JOIN table2 t2_2 ON t2.id = t2_2.id AND t2_2.feature = 'Moto'
WHERE t2.feature = 'Car'
AND t2_2.id IS NOT NULL
Edit: Removed join to table1 since it really isn't needed.