I'm new to SQL could someone correct me this query ?!
CREATE TABLE AVION
(
AV int IDENTITY(100, 1) PRIMARY KEY,
AVMARQUE varchar(30) NOT NULL,
AVTYPE varchar(30) NOT NULL,
CAP int CHECK (CAP BETWEEN 100 AND 600),
LOC varchar(30)
)
CREATE TABLE PILOTE
(
PIL int IDENTITY(1,1) PRIMARY KEY,
PILNOM varchar(30) NOT NULL,
ADR varchar(30)
)
CREATE TABLE VOLE
(
VOL varchar(5) PRIMARY KEY CHECK(VOL LIKE 'IT'[1,9][0,9][0,9]),
PIL int FOREIGN KEY REFERENCES PILOTE(PIL),
AV int FOREIGN KEY REFERENCES AVION(AV),
VD varchar(30) NOT NULL,
VA varchar(30) NOT NULL,
HD TIME CHECK (HD BETWEEN '00:00' AND '23:59'),
HA TIME CHECK (HA BETWEEN '00:00' AND '23:59')
)
VOL is a string with 5 characters that start with 'IT' and the rest are numbers first number is different then 0
PIL FOREIGN KEY FROM PILOTE TABLE
AV FOREIGN KEY FROM AVION TABLE
VD is the departure city
VA is the destination city
HD is the departure time
HV is the arrival time
It might be as simple as moving the quotes. Try:
LIKE 'IT[1,9][0,9][0,9]'
Related
I'm trying to make a query in Oracle SQL Developer that must show the customer who has spend the biggest amount of money. So I have 4 tables: Cliente(Customer), Orden(Sale), Producto(Product) and a junction table to break many to many relationship between Orden and Producto.
CREATE TABLE Cliente(
id_cliente INT NOT NULL PRIMARY KEY,
Nombre VARCHAR(40) NOT NULL,
Apellido VARCHAR(40) NOT NULL,
Direccion VARCHAR(100) NOT NULL,
Telefono INT NOT NULL,
Tarjeta INT NOT NULL,
Edad INT NOT NULL,
Salario INT NOT NULL,
Genero VARCHAR(5) NOT NULL,
id_pais INT NOT NULL,
CONSTRAINT fk_cliente_pais FOREIGN KEY(id_pais) REFERENCES Pais(id_pais)
);
CREATE TABLE Producto(
id_producto INT NOT NULL PRIMARY KEY,
Nombre VARCHAR(40) NOT NULL,
Precio DECIMAL(10,2) NOT NULL,
id_categoria INT NOT NULL,
CONSTRAINT fk_categoria FOREIGN KEY(id_categoria) REFERENCES Categoria(id_categoria)
)
CREATE TABLE Orden(
id_orden INT NOT NULL,
linea_orden INT NOT NULL,
fecha_orden DATE NOT NULL,
id_cliente INT NOT NULL,
id_vendedor INT NOT NULL,
id_producto INT NOT NULL,
cantidad INT NOT NULL,
CONSTRAINT fk_orden_cliente FOREIGN KEY(id_cliente) REFERENCES Cliente(id_cliente),
CONSTRAINT fk_orden_vendedor FOREIGN KEY(id_vendedor) REFERENCES Vendedor(id_vendedor),
CONSTRAINT fk_orden_producto FOREIGN KEY(id_producto) REFERENCES Producto(id_producto),
CONSTRAINT pk_orden PRIMARY KEY(id_orden, linea_orden)
);
DROP TABLE Detalle;
CREATE TABLE Detalle(
id_detalle INT GENERATED ALWAYS AS IDENTITY,
id_producto INT NOT NULL,
id_orden INT NOT NULL,
linea_orden INT NOT NULL,
precio INT NOT NULL,
cantidad INT NOT NULL,
CONSTRAINT DETALLE_PRODUCTO
FOREIGN KEY (id_producto)
REFERENCES Producto (id_producto),
CONSTRAINT DETALLE_ORDEN
FOREIGN KEY (id_orden, linea_orden)
REFERENCES Orden (id_orden, linea_orden),
CONSTRAINT DETALLE_pk PRIMARY KEY(id_detalle, id_producto, id_orden)
);
On Table Detalle: precio (price), cantidad(quantity)
So I'm trying to get the Maximum total amount that a Customer has purchased by this query:
SELECT Cl.id_cliente, Cl.Nombre, Cl.Apellido,SUM( Detalle.precio * Detalle.cantidad) AS TOTAL
FROM Orden
INNER JOIN Cliente Cl ON Cl.id_cliente = Orden.id_cliente
INNER JOIN Detalle ON Detalle.id_orden = Orden.id_orden
GROUP BY Cl.id_cliente, Cl.Nombre, Cl.Apellido
ORDER BY TOTAL DESC;
But in the result, the TOTAL exceeds a lot from the right result, since I have another file with the result it should show.
I rewritten your query:
Select Cl.id_cliente, Cl.Nombre, Cl.Apellido,TOTAL
from(
SELECT Orden.id_cliente, SUM( Detalle.precio * Detalle.cantidad) AS TOTAL
FROM Detalle
JOIN Orden ON Detalle.id_orden = Orden.id_orden
GROUP BY Orden.id_cliente
) Orden
JOIN Cliente Cl ON Cl.id_cliente = Orden.id_cliente
ORDER BY TOTAL DESC
;
The data from details is summed multiple times, so calaculate them before joining
SELECT Cl.id_cliente, Cl.Nombre, Cl.Apellido,SUM(TOTAL ) AS TOTAL
FROM Orden
INNER JOIN Cliente Cl ON Cl.id_cliente = Orden.id_cliente
INNER JOIN (SELECT id_orden, SUM( Detalle.precio * Detalle.cantidad) AS TOTAL FROM Detalle GROUP BY id_orden) Detalle ON Detalle.id_orden = Orden.id_orden
GROUP BY Cl.id_cliente, Cl.Nombre, Cl.Apellido
ORDER BY TOTAL DESC;
I have a SQL table based on hotel data. I have two tables and a bridge table to relate them. I'm still learning so I'm sure some of this is not ideal or has potential risks.
Guest Table
CREATE TABLE Guest
(
Guest_ID INT PRIMARY KEY IDENTITY (1, 1),
GuestName NVARCHAR(60) NOT NULL,
Street NVARCHAR(50) NOT NULL,
City NCHAR(30) NOT NULL,
[State] CHAR(2) NOT NULL,
CONSTRAINT [State.State]
FOREIGN KEY ([State]) REFERENCES [State]([State]),
Zip CHAR(5) NOT NULL,
Phone VARCHAR(15) NOT NULL
);
Room Table
CREATE TABLE Room
(
Room_ID SMALLINT PRIMARY KEY,
Room_Type_ID SMALLINT NOT NULL,
CONSTRAINT Room_Type_ID
FOREIGN KEY (Room_Type_ID) REFERENCES Room_Type([Type_ID]),
Amenity_Type_ID SMALLINT NOT NULL,
CONSTRAINT Amenity_Type_ID
FOREIGN KEY (Amenity_Type_ID) REFERENCES Amenity_Type([Type_ID])
);
Bridge Table (Reservations)
CREATE TABLE Guest_Bridge_Rooms
(
Guest_ID INT NOT NULL,
CONSTRAINT Guest_ID
FOREIGN KEY (Guest_ID) REFERENCES Guest(Guest_ID),
Room_ID SMALLINT NOT NULL,
CONSTRAINT Room_ID
FOREIGN KEY (Room_ID) REFERENCES Room(Room_ID),
Date_Start DATE NOT NULL,
Date_End DATE NOT NULL,
Occ_Adults SMALLINT NOT NULL,
Occ_Children SMALLINT NOT NULL,
Price_Total DECIMAL(13,2) NOT NULL
);
Now with these tables, I would like to write a script to DELETE all rows where a reservation (bridged table) has a specific guest NAME by somehow relating the given Guest_ID to its GuestName in the related table. I could simply use Guest_ID but that is not the goal here.
For example something like
DELETE FROM Guest_Bridge_Rooms
WHERE Guest[ID].GuestName = 'John Doe';
Is there a simple way to do this?
You can use a subquery:
DELETE FROM Guest_Bridge_Rooms
WHERE Guest_ID = (SELECT g.Guest_Id FROM Guests g WHERE g.GuestName = 'John Doe');
Note: The exact syntax might vary, depending on the database. This also assumes that GuestName is unique in Guests.
I try to create three tables by using website suport compiler any code but I have a problem in the table of the bill.
When I run it I get to error show me it is near in foreign key
These are codes of three tables
CREATE TABLE patient (
Patient Id (5) Primary key,
Name Varchar (20) Not null ,
Age Int Not null ,
Weight Int Not null ,
Gender Varchar (10) Not null,
Address Varchar (50) Not null ,
Disease Varchar (20) Not null
);
CREATE TABLE doctors (
DoctorId Varchar (5) Primary key,
Doctorname Varchar (15) Not null,
Dept Varchar (15) Not null
);
CREATE TABLE bill (
Bill_no Varchar (50) Primary key,
Patient_Id Varchar (5) Foreign key,,
doctor_charge Int Not null,
patient_type Varchar (10) null,
no_of_days Int null,
lab_charge Int null,
bill Int Not null
);
Patient Table
CREATE TABLE patient
(
patient_id VARCHAR (5) PRIMARY KEY,
name VARCHAR (20) NOT NULL,
age INT NOT NULL,
weight INT NOT NULL,
gender VARCHAR (10) NOT NULL,
address VARCHAR (50) NOT NULL,
disease VARCHAR (20) NOT NULL
);
Errors
No data type has been assigned in Patient id column (Patient Id (5)
Primary key)
Patient id column name contains spaces. You need to
enclose the column name in double quotes or replace space with something else
(ex: _). It's not recommended to use spaces.
A column name with space
CREATE TABLE tablename ("column name" datatype);
Doctors Table
CREATE TABLE doctors
(
doctorid VARCHAR (5) PRIMARY KEY,
doctorname VARCHAR (15) NOT NULL,
dept VARCHAR (15) NOT NULL
);
Bill Table
CREATE TABLE bill
(
bill_no VARCHAR (50) PRIMARY KEY,
patient_id VARCHAR (5),
doctor_charge INT NOT NULL,
patient_type VARCHAR (10) NULL,
no_of_days INT NULL,
lab_charge INT NULL,
bill INT NOT NULL,
FOREIGN KEY (patient_id) REFERENCES patient(patient_id)
);
Errors
The way you have assigned foreign key is wrong. Please refer this and this article for more information. (Patient_Id Varchar (5) Foreign key,,)
There are two commans in the Patient_Id column (Patient_Id Varchar (5) Foreign key,,)
You have to provide reference of the table for which you want to use the reference key.
For example, you have table Persons which has Primary key PersonID, in that case if you want to use that as foreign key in another table, lets say Orders.
In Oracle
CREATE TABLE Orders (
OrderID numeric(10) not null,
OrderNumber numeric(10) not null,
PersonID numeric(10) not null,
CONSTRAINT fk_person_id
FOREIGN KEY (PersonID )
REFERENCES Persons(PersonID )
Your Case :
CREATE TABLE bill
( Bill_no Varchar (50) Primary key,
Patient_Id Varchar (5),
doctor_charge Int Not null,
patient_type Varchar (10) null,
no_of_days Int null,
lab_charge Int null,
bill Int Not null,
CONSTRAINT fk_patient_id
FOREIGN KEY (Patient_Id)
REFERENCES patient(Patient_Id)
);
Remove the 'Foreign Key' from the table creation script.
Add this to your SQL script:
ALTER TABLE [Bill] WITH CHECK ADD CONSTRAINT [FK_Bill_Patient] FOREIGN KEY([Patient_Id])
REFERENCES [Patient] ([Patient_Id])
GO
ALTER TABLE [Bill] CHECK CONSTRAINT [FK_Bill_Patient]
GO
The words FOREIGN KEY are only needed for introducing the name of the FK constraint. Since your other constraints are not named, you might as well skip that part and go straight to REFERENCES.
If you specify a foreign key constraint as part of the column definition, you can omit the datatype to allow it to inherit from its parent at the time of creation, which I think is good practice as the types will automatically match.
We use VARCHAR2 in Oracle, not VARCHAR.
You don't need to specify NULL for columns that are allowed to be null.
I am not sure a 5-character string is a good datatype for a unique ID. How will you generate the values? Normally an auto-incrementing sequence number simplifies this.
create table doctors
( doctorid varchar2(5) primary key
, doctorname varchar2(15) not null
, dept varchar2(15) not null );
create table patients
( patient_id varchar2(5) primary key
, name varchar2(20) not null
, age integer not null
, weight integer not null
, gender varchar2(10) not null
, address varchar2(50) not null
, disease varchar2(20) not null );
create table bills
( bill_no varchar2(50) primary key
, patient_id references patients -- Allow datatype to inherit from parent
, patient_type varchar2(10)
, no_of_days integer
, lab_charge integer
, bill integer not null );
can anyone help me with this sql statment
Create table doctor(
doctorId char(3),
doctorName varchar(20),
primary key (doctorId)
);
create table patient (
patient_id char(4) not null check (patient_id LIKE 'P[0-9][0-9][0-9]'),
doctorId char(3),
patientName varchar(60) not null,
dateOfBirth date not null,
gender char(1),
height decimal(4, 1) check (height > 0),
weight decimal(4, 1) check(weight > 0),
primary key (patient_id) FOREIGN KEY doctorId REFERENCES doctor(doctorId)
);
why 2nd table not created
put these below code instead of your own code:
Create table doctor(
doctorId char(3),
doctorName varchar(20),
primary key (doctorId)
);
create table patient (
patient_id char(4) not null check (patient_id LIKE 'P[0-9][0-9][0-9]'),
doctorId char(3),
patientName varchar(60) not null,
dateOfBirth date not null,
gender char(1),
height decimal(4, 1) check (height > 0),
weight decimal(4, 1) check(weight > 0),
primary key (patient_id) FOREIGN KEY doctorId REFERENCES doctor(doctorId)
);
Thats because you are missing a ,
create table patient (
patient_id char(4) not null check (patient_id LIKE 'P[0-9][0-9][0-9]'),
doctorId char(3),
patientName varchar(60) not null,
dateOfBirth date not null,
gender char(1),
height decimal(4, 1) check (height > 0),
weight decimal(4, 1) check(weight > 0),
primary key (patient_id) ,
FOREIGN KEY (doctorId) REFERENCES doctor(doctorId)
);
It should be like that.
Create table doctor(
doctorId Int Identity(1,1), --It's 'Primary Key' so it should be Int or Guid
doctorName varchar(20),
CONSTRAINT pk_doctorId PRIMARY KEY (doctorId) --It's better!
);
Create table patient (
patient_id Int IDENTITY(1,1), --It's 'Primary Key' so it should be Int or Guid
doctorId Int NOT NULL, --Every patient has a doctor, so it should be 'Not Null'
patientName varchar(60) not null,
dateOfBirth date not null,
gender char(1),
height decimal(4,1), -- I didnt see check operator, you should check > 0 in code.
weight decimal(4,1),
CONSTRAINT pk_patient_id PRIMARY KEY (patient_id),
CONSTRAINT fk_doctorId FOREIGN KEY (doctorId) REFERENCES doctor(doctorId)
);
I have the following problem to solve in SQL :
d) A query that provides management information on take up of the various types of activities on offer. For each type of activity, the query should show the total number of individuals who took that type of activity and the average number of individuals taking each type of activity.
Here are my tables :
CREATE TABLE accommodations
(
chalet_number int PRIMARY KEY,
chalet_name varchar(40) NOT NULL,
no_it_sleeps number(2) NOT NULL,
indivppw number(4) NOT NULL
)
CREATE TABLE supervisors
(
supervisor_number int PRIMARY KEY,
supervisor_forename varchar(30) NOT NULL,
supervisor_surname varchar(30) NOT NULL,
mobile_number varchar(11) NOT NULL
)
CREATE TABLE visitors
(
visitor_ID int PRIMARY KEY,
group_ID int NOT NULL,
forename varchar(20) NOT NULL,
surname varchar(20) NOT NULL,
dob date NOT NULL,
gender varchar(1) NOT NULL
)
CREATE TABLE activities
(
activity_code varchar(10) PRIMARY KEY,
activity_title varchar(20) NOT NULL,
"type" varchar(20) NOT NULL
)
CREATE TABLE "groups"
(
group_ID int PRIMARY KEY,
group_leader varchar(20) NOT NULL,
group_name varchar(30)
number_in_group number(2) NOT NULL
)
CREATE TABLE bookings
(
group_ID int NOT NULL,
start_date date NOT NULL,
chalet_number int NOT NULL,
no_in_chalet number(2) NOT NULL,
start_date date NOT NULL,
end_date date NOT NULL,
CONSTRAINT bookings_pk PRIMARY KEY(group_ID, chalet_number));
CREATE TABLE schedule
(
schedule_ID int PRIMARY KEY,
activity_code varchar(10) NOT NULL,
time_of_activity number(4,2) NOT NULL,
am_pm varchar(2) NOT NULL,
"date" date NOT NULL
)
CREATE TABLE activity_bookings
(
visitor_ID int NOT NULL,
schedule_ID int NOT NULL,
supervisor_number int NOT NULL,
comments varchar(200),
CONSTRAINT event_booking_pk PRIMARY KEY(visitor_ID, schedule_ID));
ALTER TABLE visitors
ADD FOREIGN KEY (group_ID)
REFERENCES "groups"(group_ID)
ALTER TABLE Schedule
ADD FOREIGN KEY (activity_code)
REFERENCES activities(activity_code)
ALTER TABLE bookings
ADD FOREIGN KEY (group_ID)
REFERENCES "groups"(group_ID)
ALTER TABLE bookings
ADD FOREIGN KEY (chalet_number)
REFERENCES accommodations(chalet_number)
ALTER TABLE activity_bookings
ADD FOREIGN KEY (visitor_ID)
REFERENCES visitors(visitor_ID)
ALTER TABLE activity_bookings
ADD FOREIGN KEY (schedule_ID)
REFERENCES schedule(schedule_ID)
ALTER TABLE activity_bookings
ADD FOREIGN KEY (supervisor_number)
REFERENCES supervisors(supervisor_number)
I have the following solution:
SELECT activities."type", 'overalltotal' AS OT, ('overalltotal' / 'activities') AS AVG
FROM activities, schedule
WHERE 'overalltotal' = (SELECT SUM(COUNT(schedule_ID))
FROM activities, schedule
WHERE schedule.activity_code = activities.activity_code
GROUP BY activities."type"
)
AND 'activities' = (SELECT COUNT(DISTINCT activities."type")
FROM activities
)
AND schedule.activity_code = activities.activity_code
GROUP BY activities."type";
I have implemented sample data and code to check the variables above:
SELECT SUM(COUNT(schedule_ID))
FROM activities, schedule
WHERE schedule.activity_code = activities.activity_code
GROUP BY activities."type";
Result : 20
SELECT COUNT(DISTINCT activities."type")
FROM activities;
Result : 5
However when running the code :
ORA-01722: invalid number
01722. 00000 - "invalid number"
*Cause:
*Action:
EDIT:
Using Dave's Code i have the following output:
Snowboarding 15
sledding 19
Snowmobiling 6
Ice Skating 5
Skiing 24
How would i do the final part of the question?
and the average number of individuals taking each type of activity.
You must use double quotes around column names in Oracle, not single quotes. For example, "overalltotal". Single quotes are for text strings, which is why you're getting an invalid number error.
EDIT: This is probably the type of query you want to use:
SELECT activities."type", COUNT(*) AS total, COUNT(*)/(COUNT(*) OVER ()) AS "avg"
FROM activities a
JOIN schedule s ON a.activity_code=s.activity_code
JOIN activity_bookings ab ON s.schedule_ID=ab.schedule_ID
GROUP BY activities."type";
Basically, because each activity booking has one visitor id, we want to get all the activity bookings for each activity. We have to go through schedule to do that. They we group the rows by the activity type and count how many activity bookings we have for each type.