i want to pass 1 variables from a view to another view with post method. use this redirect code but its not working
Yii::$app->getResponse()->redirect('home','id'=>$id)->send();
try this
Yii::$app->getResponse()->redirect(['home','id' => $id])->send();
For the sake of completeness in a controller context you may use:
class MyController extends \yii\web\Controller
{
public function actionIndex()
{
return $this->redirect(['home', 'id' => 123]);
}
}
Where the array parameter of redirect() is equal to yii\helpers\Url::to().
Related
Am having a problem passing an array from Laravel's AuthController to auth.login view. What am trying to do is retrieve data from News model and send it to the view. I know how to use eloquent to retrieve data, passing from the controller to the view is my problem as I cannot see the how/where Laravel is rendering the view.
Add an array as second parameter to the view method when returning it in the controller.
return view('greetings', ['name' => 'Victoria']); // in controller
Then in your view, you should be able to access the variable $name which should be equal to Victoria
var_dump($name); // in view
More in the documentation
I solved it by passing the variable through the Controller on the redirect method.
I am not entirely sure what the objective is here, but you said:
I cannot see the how/where Laravel is rendering the view.
So to answer that:
Laravel's AuthController pulls in a trait AuthenticatesAndRegistersUsers which itself pulls in a few other traits, one being AuthenticatesUsers and another being RegistersUsers.
In AuthenticatesUsers you will find a method like so:
/**
* Show the application login form.
*
* #return \Illuminate\Http\Response
*/
public function showLoginForm()
{
$view = property_exists($this, 'loginView')
? $this->loginView : 'auth.authenticate';
if (view()->exists($view)) {
return view($view);
}
return view('auth.login');
}
There is likewise a similar method in the RegistersUsers trait.
This is where the AuthController returns its views.
If you need to tweak this behavior, or return the view with some data, you could override these methods in your controller, if this is really the best solution to your given situation.
Meanwhile I found a better way to do that.
You can override the showRegistrationForm() method in AuthController.php and pass along the data you want to use in the view. Ex.:
public function showRegistrationForm()
{
$results = Model::all();
return view('auth.register', ['results' => $results]);
}
I'm writing an api in Laravel 4. I'd like to pass query string parameters to my controllers. Specifically, I want to allow something like this:
api/v1/account?fields=email,acct_type
where the query params are passed along to the routed controller method which has a signature like this:
public function index($cols)
The route in routes.php looks like this:
Route::get('account', 'AccountApiController#index');
I am manually specifying all my routes for clarity and flexibility (rather than using Route::controller or Route::resource) and I am always routing to a controller and method.
I made a (global) helper function that isolates the 'fields' query string element into an array $cols, but calling that function inside every method of every controller isn't DRY. How can I effectively pass the $cols variable to all of my Route::get routes' controller methods? Or, more generally, how can I efficiently pass one or more extra parameters from a query string through a route (or group of routes) to a controller method? I'm thinking about using a filter, but that seems a bit off-label.
You might want to implement this in your BaseController. This is one of the possible solutions:
class BaseController extends Controller {
protected $fields;
public function __construct(){
if (Input::has('fields')) {
$this->fields = Input::get('fields');
}
}
}
After that $fields could be accessed in every route which is BaseController child:
class AccountApiController extends \BaseController {
public function index()
{
dd($this->fields);
}
}
I'm not sure I am using the proper terminology, so I will describe what I want to achieve.
I have a controller called ControllerA and want a "virtual" controller called ControllerB to function exactly the same as ControllerA.
Basically I just want the url site.com/ControllerB to load up the same page as site.com/ControllerA (but not redirect).
Hope my description is clear enough.
You can achieve what you want with a simple URL rule:
'controllerA/<a>' => 'controllerA/<a>',
'controllerB/<a>' => 'controllerA/<a>',
Read more about URL rules here: http://www.yiiframework.com/doc/guide/1.1/en/topics.url#user-friendly-urls
You can extend ControllerA with ControllerB and provide extended controller name. Next override getViewPath method. Attribute extendedControler give us basic controller name.
class ControllerBController extends ControllerAController
{
private $extendedControler = 'ControllerA';
public function getViewPath() {
$nI = Yii::app()->createController($this->extendedControler);
return $nI[0]->getViewPath();
}
}
Of course you can use some string modification. Like str_ireplace:
class Klient2Controller extends KlientController
{
public function getViewPath() {
//We must extract parent class views directory
$c = get_parent_class($this);
$c = str_ireplace('Controller', '', $c); //Extract only controller name
$nI = Yii::app()->createController($c);
return $nI[0]->getViewPath();
}
}
let's say i have model A..then this model A is being used by many controllers...
now I want to implement the afterSave method, only in one of the controllers that uses
model A . e.g in Controller C it calls the save() function, so I want the afterSave to be called in that function only.how is that ?
protected function afterSave()
{
parent::afterSave();
if($this->isNewRecord)
{
echo "hello";
exit;
}
}
BECAUSE: afterSave() affects all the save() call of all the controllers that uses the Model A
You can try this in you afterSave function :
if (Yii::app()->controller->id!=='yourcontroller')
{
// do what you want
}
If needed, you can also test value of Yii::app()->controller->action->id.
EDIT : or take a look at Jelle de Fries answer.
I don't get why you would need an afterSave() method for this.
In your action you are calling $model->save().
Can't you just do what you have to do after calling this?
like so:
public function actionMyAction(){
$model=new myModel;
$model->attribute = 5;
$model->save();
$model->doLogicAfterSave(); //<-this
$this->render('myView',array(
'model'=>$model,
));
}
Since it's only for 1 controller.
I'm new to Yii. I have a controller like this:
<?php
class EventsController extends Controller
{
public function actionIndex()
{
$this->render('index');
}
}
How can i make the following url render the correct view. eg.
localhost/events/intaglio -> $this->render('intaglio');
localhost/events/burrito-> $this->render('burrito');
localhost/events/jerrito -> $this->render('jerrito');
Worse case, I'll have to have separate actions for each
public function actionIntagio {...}
public function actionBurrito {...}
public function actionJerrito {...}
Is there a smarter way of doing this?
Setup URL rules (in protected/config/main.php) to handle those URL's dynamically, eg:
events/<event_name:.+> => events/myaction
This points any URL with events/whatever to the Controller/Action events/myaction. You can then access the event_name portion of the URL with a $_GET variable, eg:
echo $_GET['event_name'];