I'm trying to return the second most recent date for a set of projects in SQL, but I'm getting the error 'Only one expression can be specified in the select list when the subquery is not introduced with EXISTS.'
Here is my code:
SELECT ProjectId, max(CreatedDateTime)
FROM NTNote.dbo.nProjectReference P
INNER JOIN NTNote.dbo.nJournal J
ON J.JournalID = P.JournalID
Where CreatedDateTime < (SELECT max(CreatedDateTime), projectid
FROM NTNote.dbo.nProjectReference P
INNER JOIN NTNote.dbo.nJournal J
ON J.JournalID = P.JournalID
Group by ProjectId)
Group by ProjectId
Any help would be greatly appreciated!
use the below code for desired output ( sql server).
with cte_grp
as
(SELECT ProjectId,CreatedDateTime,ROW_NUMBER () OVER(PARTITION BY ProjectId ORDER BY CreatedDateTime desc) RNo
FROM NTNote.dbo.nProjectReference P
INNER JOIN NTNote.dbo.nJournal J
ON J.JournalID = P.JournalID)
SELECT *
FROM cte_grp
WHERE RNO=2
You can use
Row_Number() over (partition by ProjectId order by CreatedDateTime desc) as rownum
and use 2 as predicate to get the output.
Related
I would like to get the average of the top2 limit1 per policyid. I need my resulting table to also have objectid.
Limit1 and objectid come from the table p_coverage.
Policyid comes from the table p_risk.
The table p_item is a linking table between p_risk and p_coverage.
The way I thought I should build my query is: create a ranking of limit1 within each policyid. Then take the avg top2.
However the ranking doesn't work and give wrong result. My query works if I take columns from ONE table, but as soon as I add joins between them it gives false ranking.
SELECT policyid, limit1, /*pcob,*/ RANK() OVER(PARTITION BY policyid ORDER BY limit1 DESC) AS rn
FROM (SELECT policyid, limit1/*, pc.objectid ASpcob*/
FROM p_risk pr
LEFT JOIN p_item
ON pr.objectid=p_item.riskobjectid
LEFT JOIN p_coverage pc
ON p_item.objectid=pc.insuranceitemid) AS s
) AS SubQueryAlias
GROUP BY
policyid, limit1/*, pcob*/, rn
ORDER BY rn,policyid,limit1 DESC
The table at the end of the picture is what I'd like to have. The first table is the result of the query of Golden Linoff
If I understand correctly, you want the ROW_NUMBER() in the subquery and then to aggregate and filter in the outer query:
SELECT policyid, AVG(limit1) as avg_top2_limit1
FROM (SELECT policyid, limit1,
DENSE_RANK() OVER (PARTITION BY policyid ORDER BY limit1 DESC) as seqnum
FROM p_risk pr LEFT JOIN
p_item i
ON pr.objectid = i.riskobjectid LEFT JOIN
p_coverage pc
ON i.objectid = pc.insuranceitemid) AS s
) p
WHERE seqnum <= 2
GROUP BY policyid
thanks to previous comment! I succeed to do what I wanted. There is the query
select b.policyid, avg(b.limit1) as avg_top2_limit1 from(
SELECT distinct(policyid) policyid, limit1
FROM (SELECT policyid, limit1,
Dense_rank() OVER (PARTITION BY policyid ORDER BY limit1 DESC) as
seqnum
FROM p_risk pr LEFT JOIN
p_item i
ON pr.objectid = i.riskobjectid LEFT JOIN
p_coverage pc
ON i.objectid = pc.insuranceitemid) AS s
WHERE seqnum <= 2 ) as b
GROUP BY policyid`
I need to pull the second last record in a date column called OrderDate. However, I need to bring only one date (I am making the search into a table with all the purchases orders, dates and costs, in which a have to bring only the second last and its cost). The way its query is written today (and working) is pulling me the the newest date.
select distinct
a.PurchaseNum, a.ItemID, a.SupplierNum, a.Location, a.OrderDate, a.Cost
from
PurchaseOrder a
inner join
(select
l.SupplierNum, l.ItemID, l.Location, maxdate = max(l.OrderDate)
from
PurchaseOrder l
where
l.Cost <> 0
group by
l.SupplierNum, l.itemid, l.Location) l on a.SupplierNum = l.SupplierNumand a.itemid = l.itemid
and l.Location = a.Location
and a.OrderDate = l.maxdate
I have tried to use lag(), offset (but with limitations once is within a join, forcing me to use the order by and include the dateOrder column which is not what I want because we need only one date)
A bit of context: I have a report in which I need to show the last and second last cost of a purchase order for each supplier. Bring the last cost of an order is easy, the problem is go back to the second last... and it is where I am stuck right now.
Any thought?
If I'm understanding you correctly, here's one option using row_number to return the 2 highest orderdate records:
select *
from (
select *,
row_number() over (partition by SupplierNum, ItemID, Location
order by OrderDate desc) rn
from PurchaseOrder
where cost <> 0
) t
where rn <= 2
Inner query does order by desc and outside query does order by asc.
select distinct top 1 a.*
from PurchaseOrder a
inner join
(
select Top 2 l.*
from PurchaseOrder l
where
l.Cost <> 0
group by l.SupplierNum, l.itemid, l.Location order by orderdate desc) l
on a.SupplierNum= l.SupplierNumand a.itemid = l.itemid and l.Location=a.Location and a.OrderDate = l.Orderdate
order by a.orderdate
or
SELECT TOP 1 * FROM (SELECT * FROM PurchaseOrder a
EXCEPT SELECT TOP (SELECT (COUNT(*)-2) FROM PurchaseOrder a where
l.Cost <> 0
group by l.SupplierNum, l.itemid, l.Location) * FROM PurchaseOrder) A
or
SELECT *
FROM PurchaseOrder a
WHERE OrderDate = ( SELECT MAX(OrderDate)
FROM PurchaseOrder
WHERE Orderdate < ( SELECT MAX(OrderDate)
FROM PurchaseOrder l where
l.Cost <> 0
group by l.SupplierNum, l.itemid, l.Location
)
) ;
or
SELECT TOP (1) *
FROM PurchaseOrder
WHERE OrderDate < ( SELECT MAX(OrderDate)
FROM PurchaseOrder where ....
)
ORDER BY OrderDate DESC ;
I have 2 tables as seen below:
Now the question is :
How can I have a view which shows the details of the last Owner? in other words I need the details of person who has MAX(StartDate) in tbl_Owners table?
I want to find the latest owner of each apartment.
I tried different approaches but I couldn't find the way to do that.
I know I need to get the personID in a Group By clause which groups records by AppID but I can't do that
Thank you
Try this
select t1.* from tbl_persons as t1 inner join
(
select t1.* from tbl_owners as t1 inner join
(
select appid,max(startdate) as startdate from tbl_owners group by appid
) as t2
on t1.appid=t2.appid and t1.startdate=t2.startdate
) as t2
on t1.personid=t2.personid
Add this to your query:
JOIN (select AppId, MAX(StartDate) as MAxStartDate
from dbo.tbl_Owners
group by PersonId) o2
ON dbo.tbl_Owners.AppId= o2.AppId and
dbo.tbl_Owners.StartDate = o2.MAxStartDate
The sub-query above returns every AppId together with it's latest StartDate. Self-joining with that result will give you what you want.
You can USE CTE for this purpose
;WITH CTE AS
(
SELECT AppID,PersonID,StartDate,
ROW_NUMBER() OVER (PARTITION BY AppID ORDER BY StartDate DESC) RN
FROM TableNAme
GROUP BY AppID,PersonID,StartDate
)
SELECT * FROM CTE
WHERE RN=1
Using row_number
select t.*, p.* -- change as needed
from (select *, rn= row_number() over(partition by AppID order by StartDate desc)
from dbo.tbl_Owners
) t
join dbo.tbl_Persons p on t.rn=1 and t.PersonId = p.PersonId
using cross apply
select t.*, p.* -- change as needed
from dbo.tbl_Persons p
cross apply (
select top(1) *
from dbo.tbl_Owners o
where o.PersonId = p.PersonId
order by o.StartDate desc
) t
SELECT dbo.tbl_Owners.*,dbo.tbl_Persons.PersonFullname FROM dbo.tbl_Owners
INNER JOIN
dbo.tbl_Persons ON dbo.tbl_Owners.PersonID=dbo.tbl_Persons.PersonID
GROUP BY dbo.tbl_Owners.StartDate HAVING MAX(StartDate);
Use GROUP BY on StartDate instead on PersonID.
I'm having an absolute brain fade
SELECT p.ProductCategory, f.ProductSubCategory, COUNT(*) AS Cnt
FROM Sales f
JOIN Products p ON f.ProductSubCategory = p.ProductSubCategory
GROUP BY p.ProductCategory, f.ProductSubCategory
ORDER BY 1,3 DESC
This shows me the count for each ProductSubCategory, I would like to see only the highest ProductSubCategory per ProductCategory.
I wish to see (I don't care about the Count value)
There are a couple of different ways to do this. One involves joining the results back to themselves and using the max aggregate. But since you are using SQL Server, you can use ROW_NUMBER to achieve the same result:
with cte as (
select p.productcategory, p.ProductSubCategory, COUNT(*) cnt,
ROW_NUMBER() over (partition by p.productcategory order by count(*) desc) rn
from products p
join sales s on p.ProductSubCategory = s.ProductSubCategory
group by p.productcategory, p.ProductSubCategory
)
select *
from cte
where rn = 1
You already got the answer, Please see the following code to. It may help you.
SELECT p.ProductCategory,
f.ProductSubCategory,
COUNT(*) AS Cnt
FROM Sales f
JOIN Products p ON f.ProductSubCategory = p.ProductSubCategory
JOIN (
SELECT p.ProductCategory,
f.ProductSubCategory,
ROW_NUMBER() OVER ( PARTITION BY p.ProductCategory,
f.ProductSubCategory
ORDER BY COUNT(*) DESC) [Row]
FROM Sales f
JOIN Products p ON f.ProductSubCategory = p.ProductSubCategory) Lu
ON P.ProductCategory = Lu.ProductCategory
AND f.ProductSubCategory = Lu.ProductSubCategory
WHERE Lu.Row = 1
GROUP By p.ProductCategory,
f.ProductSubCategory
I want to only select the highlighted records. how can i do it in sql and preferably in linq. there is a separate table Emp with EmployeeID as PK.
here is the schema for my tables
I could be way off but I believe following statement satisfies your requirements
SELECT *
FROM (
SELECT e.EmployeeID, h.FromDate, h.ToDate
, rn = ROW_NUMBER() OVER (PARTITION BY e.EmployeeID ORDER BY DesignationID DESC)
FROM employee e
INNER JOIN history h ON h.EmployeeID = e.EmployeeID
) eh
WHERE rn = 1
Try:
select * from
(select t.*,
row_number() over (partition by EmployeeID order by FromDate) as rn) sq
where rn = 1
Can't see exactly what you're asking for. The highlighted ID's are just unique occurrences. So you can do this easily with:
SELECT DISTINCT EmployeeID FROM MyTable
Not sure what you're looking for, but try something like this (no subqueries needed and should work on most DBMS, although it looks like your running SQL Server):
select t1.DisignationHistoryIDs, t1.employeeId, t1.fromDate from history t1
left join history t2
on t1.employeeId = t2.employeeId and t1.fromDate > t2.fromDate
where t2.fromDate is null
This should work to get the oldest fromDate. To get the newest from date just change the > for a <.