I have huge robot-files. In all this files a section of the code is the same. Because of DRY I want to shorten the files and put the code to an other file. How to call this 100 robot-code lines from an other file then?
file1.robot
MyTest1
<Content of other file>
Some other keywords
file2.robot
MyTest2
<Content of other file>
Some other keywords
Other file
Log to console 1
Log to console 2
Log to console 3
Log to console .
Log to console .
Log to console 100
The way to do this is to use keywords in a resource file. You can't include raw lines of code.
For example:
other.robot
*** Keywords ***
Do something
log to console 1
log to console 2
...
file1.robot
*** Settings ***
Resource other.robot
*** Test Cases ***
MyTest1
do something
Some other keywords
Related
I have a robot framework test automation product that runs in a docker container. All the configurations for the project are written in a .env file and all works perfectly in the docker environment.
Wat I want is to run this project out side the docker environment(in my laptop using VS code or any other supported IDE). But I don't know how to set the configuration environment when I run the project out side the docker environment.
Can someone please tell me the best way of doing this.
I found the soultion.
1.You create .env file as below and put all of your environment variables as below. This is the environment file that you are going to push in to the docker container.
HOST_ADDRESS="https://192.168.0.15"
DEFAULT_PORT="8056"
2.Create .yaml file called LocalConfig.yaml and place all your local configuration in that file as below.
LOCAL_HOST_ADDRESS: "https://192.168.0.10"
LOCAL_DEFAULT_PORT: "8055"
3.Create .resource file called Config.resource and read all the environment variables from the OS environment using % character and if the environment variable is not found in the OS, you can set the default value which is defined in the LocalConfig.yml file as below.
*** Settings ***
Variables LocalConfig.yaml
*** Variables ***
${CONFIG_HOST_ADDRESS} %{HOST_ADDRESS=${LOCAL_HOST_ADDRESS}}
${CONFIG_PORT} %{DEFAULT_PORT=${LOCAL_DEFAUL_PORT}}
4.Then you can reference this Config.resource file in any of your .robot files and retrieve the configuration values.
Example:
*** Settings ***
Resource ../Config.resource
*** Variables ***
*** Test Cases ***
Retrieve env variable Test
Log To Console ${CONFIG_HOST_ADDRESS}
Not sure why its not finding my csv header variables
Im using this Library I installed it
https://github.com/Snooz82/robotframework-datadriver
However, I keep getting error
Variable '${username}' not found.
Below is my robot file
*** Setting ***
Resource ../../../Resources/Common.robot
Library DataDriver ../../../DataFiles/LoginMultipleTimes2.csv
Suite Setup Open Browser and navigate
Suite Teardown Close All Browsers
Test Template CSVList
*** Variables ***
${URL} = https://myapplogin.com
*** Test Cases ***
Login Successfully ${username} ${password}
*** Keywords ***
Open Browser and navigate
I open a browser and nagivate to MyApp Login page
CSVList
[Arguments] ${username} ${password}
Input Text id=username ${username}
Input Text id=password ${password}
Click Button xpath=//*[#id="signin-button"]/input
My csv file looks like this
${username},${password}
jack2,T3sT123
jack3,T3sT123
Any suggestions?
I have tried putting double and single quotes around the variables.
If I type in the wrong name in the Library section it gives an error so I know the file path is correct.
Solved the issue by adding
Library DataDriver ../../../DataFiles/AddClients_002.csv reader_class=csv_reader encoding=utf_8
and making sure I saved the file as MS DOS Comma Seperated (im using a mac).
I want to use a resource file with the name clean_environment.robot on windows. It is in the same folder like my robot file (C:\Users\xxxxx\Desktop\git\src), which is callig the resource file.
Basic file 30.robot:
** Settings **
Resource clean_environment.robot
** Test Cases **
MyTestCase
Clean environment
I get the error:
[ ERROR ] Error in file
'C:\Users\xxxxx\Desktop\git\src\30.robot':
Resource file 'Clean environment' does not exist.
The resource file:
*** Settings ***
*** Test Cases ***
Clean environment
Log to console 111
Edit:
The computer said: Resource file 'Clean environment' does not exist! But 'Clean environment is not the resource file, it is the keyword right?
If the file has a test case in it, it is not considered to be a resource file by robot. Resource files can only have keywords, variables and settings.
If you expect Clean environment to be a keyword, put it in a keyword table:
*** Keywords ***
Clean environment
Log to console 1111
I have designed this architecture where all the test cases will be in Amazon.robot file and all low level keywords for robot framework will be in two separate files(AmazonGui.robot and Commons.robot)
Amazon.robot file that has all the test cases:
*** Settings ***
Documentation This is some basic infor the whole suite
Resource Resources/AmazonGui.robot
Resource Resources/Common.robot
*** Variables ***
*** Test Cases ***
User must sign in to check out
[Documentation] This is some basic info about test
[Tags] Smoke
Common.Begin Web Test
AmazonGui.Search for Products
AmazonGui.Select Product from Search Results
AmazonGui.Add Product to Cart
AmazonGui.Begin Checkout
Common.End Web Test
I have two other resources files that has the low keywords, so basically the test case(Amazon.robot) is calling the low level Keywords files(Common.robot and AmazonGui.robot). I have imported the Resources files to the test case file.
AmazonGui.robot file that has low level keywords for test cases
*** Settings ***
Library Selenium2Library
*** Keywords ***
Search for Products
go to http://www.amazon.com
wait until page contains Your Amazon.com
input text id=twotabsearchtextbox Ferrari 458
click button xpath=//*[#id='nav-search']/form/div[2]/div/input
wait until page contains results for "Ferrari 458"
Select Product from Search Results
click link css=#result_0 a.s-access-detail-page
wait until page contains Back to search results
Add Product to Cart
click button id=add-to-cart-button
wait until page contains Added to Cart
Begin Checkout
click link id=hlb-ptc-btn-native
page should contain element id=signInSubmit
Common.robot file that has common features just opening and closing browser
*** Settings ***
Library Selenium2Library
*** Keywords ***
Begin Web Test
open browser about:blank ff
End Web Test
close browser
When I am trying to run the script from terminal using :
C:\development\robot-scripts\amazon>pybot -d results tests/amazon.robot
I get the below error:
[ ERROR ] Error in file 'C:\development\robot-scripts\amazon\tests\amazon.robot': Resource file 'Resources\AmazonGui.robot' does not exist.
[ ERROR ] Error in file 'C:\development\robot-scripts\amazon\tests\amazon.robot': Resource file 'Resources\Common.robot' does not exist.
==============================================================================
Amazon :: This is some basic infor the whole suite
==============================================================================
User must sign in to check out :: This is some basic info about test | FAIL |
No keyword with name 'Common.Begin Web Test' found.
--------------------------------------------------------
Amazon :: This is some basic infor the whole suite | FAIL |
1 critical test, 0 passed, 1 failed
1 test total, 0 passed, 1 failed
Not really sure, where I should look to find out the issue.
You have your test cases inside a folder called tests. The Resource files are present in a different folder called Resources.
When you give
Resources/AmazonGui.robot
It will check for a directory named Resources in the directory tests, but actually the directory is present outside the tests directory.
../Resources/AmazonGui.robot
Here you are asking the framework to come outside of the tests directory and check for the directory named Resources.
This issue is do not set the right path for resource files. Try this codes replace old：
Resource ../Resources/AmazonGui.robot
Resource ../Resources/Common.robot
I have a Zim Database myfile file with the content:
output "hello world"
I want to execute the file from command line. But, when I try to call zimmu myfile from shell, I see the following error:
*** Error *** "myfile" is not a know name.
>
In order to work, 'myfile' must have been created in directory 'zim' and must be located in zim0001.ws (if compiled).
If not compiled, 'myfile' must be located in the database directory.