VARCHAR Column contains both decimal or Money - sql

I have a varchar column that can either be a money or decimal data type. Sample values stored are 500 & .02 for each example.
How can I test to see if it's Money or a decimal and if it is a decimal add a leading 0 in front of it so the result will be 0.02?
Thanks in advance

Here is how you could convert all of the data to be consistently displayed as the Money datatype.
DECLARE #BadDesign TABLE (
BadDataTyping VARCHAR(100)
)
INSERT INTO #BadDesign (BadDataTyping) VALUES ('500')
INSERT INTO #BadDesign (BadDataTyping) VALUES ('.02')
SELECT * FROM #BadDesign
SELECT CONVERT(MONEY,BadDataTyping) FROM #BadDesign
UPDATE #BadDesign
SET BadDataTyping=CONVERT(MONEY,BadDataTyping)
SELECT * FROM #BadDesign

Maybe it will be helpful for you:
SELECT REPLACE(REPLACE('500 & .02','&',''),' ','')::DECIMAL(15,2); -- result: 500.02 (decimal)

Maybe this is what you're looking for? It takes all values with a leading "." and adds a "0". The search pattern in the 3rd row can be adjusted if you want to identify you're decimal values somehow differently.
SELECT
CASE TRUE
WHEN LEFT( col1, 1 ) = "." THEN CONCAT('0', col1 )
ELSE col1
END AS col1_formatted
FROM tab1

Related

'LIKE' issues with FLOAT: SQL query needed to find values >= 4 decimal places

I have a conundrum....
There is a table with one NVARCHAR(50) Float column that has many rows with many numbers of various decimal lengths:
'3304.063'
'3304.0625'
'39.53'
'39.2'
I need to write a query to find only numbers with decimal places >= 4
First the query I wrote was:
SELECT
Column
FROM Tablename
WHERE Column LIKE '%.[0-9][0-9]%'
The above code finds all numbers with decimal places >= 2:
'3304.063'
'3304.0625'
'39.53'
Perfect! Now, I just need to increase the [0-9] by 2...
SELECT
Column
FROM Tablename
WHERE Column LIKE '%.[0-9][0-9][0-9][0-9]%'
this returned nothing! What?
Does anyone have an explanation as to what went wrong as well and/or a possible solution? I'm kind of stumped and my hunch is that it is some sort of 'LIKE' limitation..
Any help would be appreciated!
Thanks.
After your edit, you stated you are using FLOAT which is an approximate value stored as 4 or 8 bytes, or 7 or 15 digits of precision. The documents explicitly state that not all values in the data type range can be represented exactly. It also states you can use the STR() function when converting it which you'll need to get your formatting right. Here is how:
declare #table table (columnName float)
insert into #table
values
('3304.063'),
('3304.0625'),
('39.53'),
('39.2')
--see the conversion
select * , str(columnName,20,4)
from #table
--now use it in a where clause.
--Return all values where the last digit isn't 0 from STR() the conversion
select *
from #table
where right(str(columnName,20,4),1) != 0
OLD ANSWER
Your LIKE statement would do it, and here is another way just to show they both work.
declare #table table (columnName varchar(64))
insert into #table
values
('3304.063'),
('3304.0625'),
('39.53'),
('39.2')
select *
from #table
where len(right(columnName,len(columnName) - charindex('.',columnName))) >= 4
select *
from #table
where columnName like '%.[0-9][0-9][0-9][0-9]%'
One thing that could be causing this is a space in the number somewhere... since you said the column type was VARCHAR this is a possibility, and could be avoided by storing the value as DECIMAL
declare #table table (columnName varchar(64))
insert into #table
values
('3304.063'),
('3304. 0625'), --notice the space here
('39.53'),
('39.2')
--this would return nothing
select *
from #table
where columnName like '%.[0-9][0-9][0-9][0-9]%'
How to find out if this is the case?
select *
from #table
where columnName like '% %'
Or, anything but numbers and decimals:
select *
from #table
where columnName like '%[^.0-9]%'
The following is working fine for me:
declare #tab table (val varchar(50))
insert into #tab
select '3304.063'
union select '3304.0625'
union select '39.53'
union select '39.2'
select * from #tab
where val like '%.[0-9][0-9][0-9][0-9]%'
Assuming your table only has numerical data, you can cast them to decimal and then compare:
SELECT COLUMN
FROM tablename
WHERE CAST(COLUMN AS DECIMAL(19,4)) <> CAST(COLUMN AS DECIMAL(19,3))
You'd want to test the performance of this against using the character data type solutions that others have already suggested.
You can use REVERSE:
declare #vals table ([Val] nvarchar(50))
insert into #vals values ('3304.063'), ('3304.0625'), ('39.53'), ('39.2')
select [Val]
from #Vals
where charindex('.',reverse([Val]))>4

SQL automatically rounding off values

I have two table. First table(Table1) use to get the records and second table(Table2) used to insert first table record into it. But I am little bit confused after getting result.
In table 1 and table 2 column "Amount" have same data type i.e nvarchar(max)
Table1
Id Amount
1 Null
2 -89437.43
2 -533.43
3 22403.88
If I run this query
Insert into Table2(Amount)
Select Amount from Table1
Then get result like this, I don't know why values are automatically rounded off
Table2
Id Amount
1 Null
2 -89437.4
2 -533.43
3 22403.9
SQL Server will round float values when converting back and to from string types.
And then you have the fun bits of empty string being 0, as well other strange effects
SELECT CAST(CAST('' AS float) AS nvarchar(MAX))
SELECT CAST(CAST('0.E0' AS float) AS nvarchar(MAX))
Use decimal.
If you need to store "blank" (how does this differ from NULL?) use a separate bit column to allow that extra value
Here is good explanation about your question.
Eigher you explicitly give float or decimal or numeric(xx,x) (x means numeric value)
Then it will convert as the data, other wise it round off the last value.
Insert into Table2(Amount)
Select cast(Amount as numeric(18,2) --or , cast (Amount as float)
from Table1
Check this link:-
TSQL Round up decimal number
In my case I was doing the conversion to the correct data type but had decimal(18,0) for the column in the table. So make sure the decimal places are represented properly for the column decimal(18,2).
Perhaps it's your query tool that's truncating to 8 characters.
Check the actual fields lengths to see if the problem is really in the database:
SELECT LEN(Amount)
FROM Table2
WHERE Amount LIKE '%-89437.%'
Unreproducible. Running this script on SQL Server 2012:
DECLARE #T1 TABLE ([Amount] nvarchar(max) NULL);
DECLARE #T2 TABLE ([Amount] nvarchar(max) NULL);
INSERT INTO #T1 ([Amount])
VALUES (NULL),('-89437.43'),('-533.43'),('22403.88');
Insert into #T2(Amount)
Select Amount from #T1;
SELECT * FROM #T2;
Produces this result:
Amount
NULL
-89437.43
-533.43
22403.88
The problem you describe does not exist.
This will show you the problem:
DECLARE #T1 TABLE ([Amount123456789] money NULL);
DECLARE #T2 TABLE ([Amount123456789] nvarchar(max) NULL);
INSERT INTO #T1 ([Amount123456789])
VALUES (NULL),('-89437.43123'),('-533.43456'),('22403.88789'),(22403.88789);
Insert into #T2(Amount123456789)
Select Amount123456789 from #T1;
SELECT * FROM #T1;
SELECT * FROM #T2;

Varchar to Number in sql

i have written a query in which i am fetching an amount which is a number like '50,000','80,000'.
select Price_amount
from per_prices
As these values contain ',' these are considered to be varchar.Requirement is to to print these as 'number' with ','
that is how can '50,000' be considered as number and not varchar
If a value has anything other than numbers in it, it is not an integer it is string containing characters. in your case you have a string containing character 5, 0 and ,.
If this is what is stored in your database and this is what you want to display then go ahead you do not need to change it to Integer or anything else. But if you are doing some calculations on these values before displaying them, Yes then you need to change them to an Integer values. do the calculation. Change them back to the varchar datatype to show , between thousands and hundred thousands and display/select them.
Example
DECLARE #TABLE TABLE (ID INT, VALUE VARCHAR(100))
INSERT INTO #TABLE VALUES
(1, '100,000'),(2, '200,000'),(3, '300,000'),(4, '400,000'),
(1, '100,000'),(2, '200,000'),(3, '300,000'),(4, '400,000')
SELECT ID, SUM(
CAST(
REPLACE(VALUE, ',','') --<-- Replace , with empty string
AS INT) --<-- Cast as INT
) AS Total --<-- Now SUM up Integer values
FROM #TABLE
GROUP BY ID
SQL Fiddle
you could combine the Replace and cast function
SELECT CAST(REPLACE(Price_amount, ',', '') AS int) AS Price_Number FROM per_prices
for more information visit 'replace', 'cast'
SQLFiddle

Using SQL 2005 trying to cast 16 digit Varchar as Bigint error converting

First, thanks for all your help! You really make a difference, and I GREATLY appreciate it.
So I have a Varchar column and it holds a 16 digit number, example: 1000550152872026
select *
FROM Orders
where isnumeric([ord_no]) = 0
returns: 0 rows
select cast([ord_no] as bigint)
FROM Progression_PreCall_Orders o
order by [ord_no]
returns: Error converting data type varchar to bigint.
How do I get this 16 digit number into a math datatype so I can add and subtract another column from it?
UPDATE: Found scientific notation stored as varchar ex: 1.00054E+15
How do I convert that back into a number then?
DECIMAL datatype seems to work fine:
DECLARE #myVarchar AS VARCHAR(32)
SET #myVarchar = '1000550152872026'
DECLARE #myDecimal AS DECIMAL(38,0)
SET #myDecimal = CAST(#myVarchar AS DECIMAL(38,0))
SELECT #myDecimal + 1
Also, here's a quick example where IsNumeric returns 1 but converting to DECIMAL fails:
DECLARE #myVarchar AS VARCHAR(32)
SET #myVarchar = '1000550152872026E10'
SELECT ISNUMERIC(#myVarchar)
DECLARE #myDecimal AS DECIMAL(38,0)
SET #myDecimal = CAST(#myVarchar AS DECIMAL(38,0)) --This statement will fail
EDIT
You could try to CONVERT to float if you're dealing with values written in scientific notation:
DECLARE #Orders AS TABLE(OrderNum NVARCHAR(64), [Date] DATETIME)
INSERT INTO #Orders VALUES('100055015287202', GETDATE())
INSERT INTO #Orders VALUES('100055015287203', GETDATE())
INSERT INTO #Orders VALUES('1.00055015287E+15', GETDATE()) --sci notation
SELECT
CONVERT(FLOAT, OrderNum, 2) +
CAST(REPLACE(CONVERT(VARCHAR(10), GETDATE(), 120), '-', '') AS FLOAT)
FROM #Orders
WITH validOrds AS
(
SELECT ord_no
FROM Orders
WHERE ord_no NOT LIKE '%[^0-9]%'
)
SELECT cast(validOrds.ord_no as bigint) as ord_no
FROM validOrds
LEFT JOIN Orders ords
ON ords.ord_no = validOrds.ord_no
WHERE ords.ord_no is null
Take a look at this link for an explanation of why isnumeric isn't functioning the way you are assuming it would: http://www.sqlservercentral.com/articles/IsNumeric/71512/
Take a look at this link for an SO post where a user has a similar problem as you:
Error converting data type varchar
hence, you should always use the correct datatype for each column unless you have a very specific reason to do so otherwise... Even then, you'll need to be extra careful when saving values to the column to ensure that they are indeed valid values

SQL Server Concatenate string column value to 5 char long

Scenario:
I have a table1(col1 char(5)); A value in table1 may '001' or '01' or '1'.
Requirement:
Whatever value in col1, I need to retrive it in 5 char length concatenate with leading '0' to make it 5 char long.
Technique I applied:
select right(('00000' + col1),5) from table1;
I didn't see any reason, why it doesn't work? but it didn't.
Can anyone help me, how I can achieve the desired result?
Since you're using a fixed width column, it's already of size 5 (with whitespace). You need to trim it:
DECLARE #table1 TABLE (col1 char(5))
INSERT INTO #table1 (col1) VALUES ('12345')
INSERT INTO #table1 (col1) VALUES ('1')
SELECT RIGHT('00000'+RTRIM(col1),5) FROM #table1
-- Output:
-- 12345
-- 00001
Or use varchar instead:
DECLARE #table2 TABLE (col1 varchar(5))
INSERT INTO #table2 (col1) VALUES ('12345')
INSERT INTO #table2 (col1) VALUES ('1')
SELECT RIGHT('00000'+col1,5) FROM #table2
-- Output:
-- 12345
-- 00001
If you are storing the data in a CHAR field you are probably getting right spaces buffered with blanks. e.g. 01 = "01 ". If your do a RIGHT("00000" + value, 5) it'll still be the original value. You need to do a RTRIM() on the value or store the data in a VARCHAR field.
The problem is that the char(5) field is always 5 characters long, not matter what you put into it. If you insert '01' into the field, the value stored is actually '01 ' (note the trailing spaces).
Try this:
select right(('00000' + replace(col1, ' ', '')), 5)
Edit: I will leave my answer here as an example, but Michael's answer using rtrim is better.
you need to store your data in a consistent manner, so you don't need to write queries to format the data each time. this will fix your existing data:
UPDATE table1
SET col1= RIGHT('00000'+ISNULL(RTRIM(col1),''),5)
now every time you select you only have to do this:
SELECT col1 FROM table1
however, you must make sure that the data is formatted properly (leading zeros) every time it is inserted. I'd add a check constraint just to make sure:
ALTER TABLE table1 ADD CONSTRAINT
CK_table1_col1 CHECK (LEN(col1)=5)
and when you insert do this:
INSERT INTO table1
(col1, ...
VALUES
(RIGHT('00000'+ISNULL(RTRIM(#col1),''),5)