parse const char* argv[] - objective-c

Question

Code:-
#import <Foundation/Foundation.h>
int main(int argc, const char* argv[]){
NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init];
char* charString = argv[1];
printf("%s", charString);
[pool drain];
return 0;
}
Problem:-
But the above line is printing null, how to get the array of integers;

Answer 1

argv[0] is the name of your program. If you want to read your parameters, start by reading argv[1]. Of course, you should also check that there are actually some parameters using argc > 1.
Or you could use [[NSProcessInfo processInfo] arguments]
int main(int argc, const char* argv[]){
#autoreleasepool {
for (NSInteger i = 0; i < argc; i++) {
NSString *stringArgument = [NSString stringWithFormat:#"%s", argv[i]];
NSLog(#"%#", stringArgument);
NSLog(#"Integer value: %i", [stringArgument intValue]);
}
}
return 0;
}
or
int main(int argc, const char* argv[]){
#autoreleasepool {
for (NSString *argument in [NSProcessInfo processInfo].arguments) {
NSLog(#"%#", argument);
NSLog(#"Integer value: %i", [argument intValue]);
}
}
return 0;
}
Arguments: 10 20
Output:
ObjcTest[65709:1964435] /Projects/ObjcTest/Build/Products/Debug/ObjcTest
ObjcTest[65709:1964435] Integer value: 0
ObjcTest[65709:1964435] 10
ObjcTest[65709:1964435] Integer value: 10
ObjcTest[65709:1964435] 20
ObjcTest[65709:1964435] Integer value: 20
Note the first argument cannot be converted to an integer therefore the printed value is 0.