I need to convert a 2-byte signed integer into a string of it's hex equivalent, but I need the string to be 4 characters. I've tried the Hex() function but when I convert 0 or say, 10, the result is 0 or A. I need the result to be 0000 or 000A. Any tips or advice?
It is just
Dim hexS As String = i.ToString("X4")
This is well explained in the The Hexadecimal (X) Format specifier.
The 4 after the X specifies how many chars you want in the output and if there are not enough chars, the missing ones are supplied as an appropriate number of "0".
Since you also tagged the question VBA, here is a VBA way to do it
Right("0000" & Hex(i), 4)
Use
Dim i As Integer = 10
Dim hexS As String = i.ToString("X4")
If you are deadset on using Hex as opposed to string formatting then you could use:
Dim Number As Integer
Dim Output As String
Number = 10
Output = ("000" & Hex(Number))
Output = Output.Substring(Output.Length - 4, 4)
Console.WriteLine(Output)
Alternatively make use of string formatting for numbers as so:
Output = Number.ToString("X4")
Console.WriteLine(Output)
The output in both cases with be 000A.
The VB way
Format(i, "X4")
or
Hex(i).PadLeft(4, "0"c)
In Visual Studio 2015:
s = $"{i:X4}"
Related
Need help in converting hex to dec in VB.NET
I use the code below in smaller number which returns the expected result.
leftPaddingHex = Val("&H" & "99000533")
but when using 99000533 it return negative result -1728051917. I am expecting to get 2566915379. I am using to get the correct result in ms sql. using the code below.
CONVERT(BIGINT,CONVERT(varbinary(4),(SELECT master.dbo.fn_cdc_hexstrtobin(#leftPadding))))
Need help on this. Thanks in advance.
Thank you.
Aze
I just thought that I'd post this alternate method.
The various integer type's Parse and TryParse methods allow you to specify a System.Globalization.NumberStyles parameter. You can specify the System.Globalization.NumberStyles.AllowHexSpecifier to parse a hexadecimal string. The only restriction is that the string can not be prefixed with "0x" or "&h".
Dim unsigned32 As UInt32
Dim itParsed As Boolean = UInt32.TryParse("99000533", System.Globalization.NumberStyles.AllowHexSpecifier, Nothing, unsigned32)
The Val method returns Double. This cannot be changed
One workaround would be to use Long data type in the final result (that is, your leftPaddingHex) and to check if the result in the intermediate stage is negative, we add it with UInt.MaxValue + 1 to correct it:
Dim leftPaddingHex As Long = Val("&H" & "99000533")
If leftPaddingHex < 0 Then
leftPaddingHex = leftPaddingHex + UInt32.MaxValue + 1
End If
For hexadecimal with even larger number, I suggest you to take a look on this
Perhaps this is a simple solution for most, but I can't get this to work like it should according to syntax.
I have this line of text "Part Number123456Price$50.00"
I want to pull the part number out of it, so I use this function...
str = Mid(str, str.IndexOf("Part Number") + 12, str.IndexOf("Price"))
My results are str = "123456Price$50.0" every time. I know the part number can vary in length so I need a solid solution of pulling this out.
It can be confusing to mix the legacy VB string methods (such as Mid) with the .Net string methods (like IndexOf). The VB methods use 1 as the index of the first character while the .Net methods use 0.
The following code will extract the part number from a string
Dim str As String = "Part Number123456Price$50.00"
Dim iPart As Integer = str.IndexOf("Part Number") + 11
Dim iPrice As Integer = str.IndexOf("Price")
str = str.Substring(iPart, iPrice - iPart).Trim
The Mid() function of Visual Basic is documented as having three arguments: (1) a string, (2) the beginning location in the string, and (3) the number of characters to copy.
So if your string is "Part Number123456Price$50.00" and you want to pull the part number as a series of digits, the "123456" part of the string, using the Mid() function then you need to find the beginning of the part number digit string and to then know the number of digits.
If your string is in the variable str then you can find the offset by something like str.IndexOf("Number") + len("Number") which will provide the offset to after the string "Number".
Next you need to find the number of digits so you would do something like str.IndexOf("Price") to find where the text "Price" begins and then subtract from that offset the offset of where the digits begin.
The result of all of this is you need a bit of code something like the following. I have not tested this source as I am not a VB programmer so it may need a tweak and you might want to put some checks on data validity as well.
Dim TextNumber as String = "Number"
Dim TextPrice as String = "Price"
iOffset = str.IndexOf(TextNumber) + len(TextNumber)
str = Mid(str, iOffset, str.IndexOf(TextPrice) - iOffset)
Alternatively, if Price is always the format $00.00, this will also work.
Dim str as String = "Part Number123456Price$50.00"
str = str.Remove(str.IndexOf("Price"))
I have an AD username called "lastname-132" in Textbox1, this string is 12 long, so i want to add the username in to Textbox2, but shortened, in the textbox2 i only have a string length of only 10 available due to other tools this program is using, so i don't want to convert it all the time manually and want to just convert it automatically with a onleave event.
Anyone any idea how to write this?
So the End Result should look like this.
'String length can be 20 max.
Textbox1.Text = "lastname-123"
'some code to convert it to this:
'String length 10 max. Numbers and the "-" should stay the same, but remove letters if necessary.
Textbox2.Text = "lastna-123"
Here's the concept:
Split string based on '-' into 2 strings
In the example above: 'lastname' and '123'.
Check the length of the first string and cut if it is too long
the program checks 'lastname' and finds that it is too long, then
cuts it into 'lastna'
Combine 'lastna' and '123' back into a string
I hope this helps
Without more information, this will assume that there can be multiple hyphens, the number can be of variable length, and you can change the maximum length of the string by changing one variable.
Dim username As String = "lastname-123"
Dim max As Integer = 10
Dim lindex As Integer = username.LastIndexOf("-")
Dim numberLength As Integer = username.Length - lindex
Dim number As String = username.Substring(lindex)
Dim justName As String = username.Substring(0, lindex)
If justName.Length + numberLength >= max Then
username = justName.Substring(0, max - numberLength) & number
End If
If you are concentrating only on the restriction of length of characters to be accepted then you can use
Maxlength
property of the Textbox.
Ex: Maxlength="10"
restricts the Textbox to accept only 10 characters.
Try to make it fit with for example substring manipulation. See http://msdn.microsoft.com/en-us/library/dd789093.aspx for more info.
i have a string "<PinX F='53mm'></PinX>", I want to access the 53 within the string and do some addition to it and then add the answer back into that string. I've been thinking about this and wasn't sure whether this can be done with regular expression or not? Can anybody help me out.
thanks
Yes, you can use a regular expression. This will get the digits, parse them to a number, add one to it, and put it back in the string (that is, the result is actually a new string as strings are immutable).
string s = Regex.Replace(
input,
#"(\d+)",
m => (Int32.Parse(m.Groups[1].Value) + 1).ToString()
);
Take a look at the HTML Agility Pack.
A regular expression looks like a good fit for this particular problem:
\d+
Will match one or more digits.
Int32.Parse(Regex.Match("<PinX F='53mm'></PinX>", #"\d+").Value)
Will return 53.
In this single case yes. "'(.*?)' then access the first group, but if this is part of a larger xml regular expressions should not be used. You should utilize the xml parser build into .net find the attribute with xsd and get the value.
Alternatively, here's a small routine...
' Set testing string
Dim s As String = "<PinX F='53mm'></PinX>"
' find first occurence of CHAR ( ' )
Dim a As Integer = s.IndexOf("'")
' find last occurence of CHAR ( ' )
Dim b As Integer = s.LastIndexOf("'")
' get substring "53mm" from string
Dim substring As String = s.Substring(a, b - a)
' get integer values from substring
Dim length As Integer = substring.Length
Dim c As Char = Nothing
Dim result As String = Nothing
For i = 1 To length - 1
c = substring.Chars(i)
If IsNumeric(c) Then
result = result & c
End If
Next
Console.WriteLine(Int32.Parse(result))
Console.ReadLine()
Dim phoneNumber As String = "077 47578 587(num)"
How do i strip the above string off every character which isnt a number. So only the numbers are left and then check to make sure it is 11 characters long?
dim number as string = Regex.Replace(phoneNumber,"[^0-9]","")
if number.length = 11 then
'valid number
else
'not valid
end if
You could loop on each character and check if it is a digit. While looping, check that the number of accepted characters (digits) is less than 11.
or
use a regex to remove all the alpha but you still will have to count at the end ....
Dim phoneNumber As String = "077 47578 587(num)"
Dim newPhoneNumber = String.Empty
For i = 0 To phoneNumber.Length - 1
If IsNumeric(phoneNumber(i)) Then
newPhoneNumber += phoneNumber(i)
End If
Next
Dim valid = newPhoneNumber.Length = 11
One possible solution is to treat the string as a character array, then retrieve only those characters with ascii codes within the paramaeters you define.
Ascii codes can be found at a resource such as: http://www.bolen.net/html/misc/ASCII-codes.html
Alternatively, you could use a regular expression to retrieve only the characters you want. My regex isn't so hot, so I can't give an example :)