crawling inside a for loop is not synchronous - scrapy

Question

Source Code
for hotel in response.xpath('//div[contains(#class,"sr_item")]'):
hotelName = hotel.xpath('.//span[contains(#class,"sr-hotel__name")]//text()')
print hotelName.extract()
hotel_image = hotel.xpath('.//img[contains(#class, "hotel_image")]//#src')
print hotel_image.extract()
hotelLink = hotel.xpath('.//a[contains(#class,"hotel_name_link")]//#href')
yield scrapy.Request(response.urljoin(hotelLink[0].extract()), self.parseHotel)
next_page = response.xpath('//a[contains(#class,"paging-next")]//#href')
My code can be seen attached as an image. As, you can see, inside the for loop. I want Scrapy to return from the function "hotelParse", then continue, executing the for loop.
However, now, it firsts prints all the hotel names, meaning, the for loop get executed completely, then "hotelParse" starts yielding.
This would mess up my output, once, I start assigning values to the item object.

Answer 1

Almost definitely what you're trying to do is the "Passing additional data to callback functions" from the Scrapy documentation. Here's how it would look for your case:
def parse_item(self, response):
for hotel in response.xpath('//div[contains(#class,"sr_item")]'):
item = HotelItem()
hotelName = hotel.xpath('.//span[contains(#class,"sr-hotel__name")]//text()')
print hotelName.extract()
item["hotelName"] = hotelName
hotel_image = hotel.xpath('.//img[contains(#class, "hotel_image")]//#src')
print hotel_image.extract()
item["hotel_image"] = hotel_image
hotelLink = hotel.xpath('.//a[contains(#class,"hotel_name_link")]//#href')
request = scrapy.Request(response.urljoin(hotelLink[0].extract()), self.parseHotel)
request.meta['item'] = item
yield request
next_page = response.xpath('//a[contains(#class,"paging-next")]//#href')
yield scrapy.Request(response.urljoin(next_page.extract()), self.parse_item)
def parseHotel(self, response):
item = response.meta['item']
item["extra_1"] = response.xpath('/example/text()').extract_first()
item["extra_2"] = response.xpath('/example2/text()').extract_first()
yield item