Whenever I want to find out a grade in the program I made.
It highlights the statement k = k + 1 and says:
Arithmetic operation resulted in an overflow
Can someone help?
Sub SearchStudentData()
Dim Sname, G As String
Dim Lname, Lgradetext, position, j, k, position1 As Integer
Dim gradefile As IO.StreamReader
Dim Valid As Boolean
Valid = False
Console.WriteLine("Enter the name of the student of whom you want the grade!")
Sname = Console.ReadLine()
Lname = Len(Sname)
gradefile = New IO.StreamReader("D:\Grades.txt")
Do Until gradefile.EndOfStream
gradetext = gradefile.ReadLine()
Lgradetext = Len(gradetext)
j = 0
k = 0
Do
k = k + 1 'It highlights this line of code
position1 = k
Loop Until Mid(gradetext, k, 1) = ":"
Do
j = j + 1
position = j
Loop Until Mid(Lgradetext, j, 1) = ","
If Sname = Right(gradetext, position1 + 1) And Sname = Left(gradetext, position - 1) Then
Valid = True
End If
If Valid = True Then
G = Right(Lgradetext, Lgradetext - 1)
Console.WriteLine(G)
Else
Valid = False
Console.WriteLine("Ypu have failed this PROGRAM")
End If
Loop
gradefile.Close()
End Sub
Your input is not what you expected. The line from your file has no ":" or "," in it, resulting in an infinite loop, and eventually the error when the counter goes past the max. You could use String.IndexOf() to determine if the value is present, instead of a loop. When the value is not present, -1 will be returned. Here's an example:
Dim indexOfColon As Integer = gradetext.IndexOf(":")
Dim indexOfComma As Integer = gradetext.IndexOf(",")
If indexOfColon <> -1 AndAlso indexOfComma <> -1 Then
' ... both ":" and "," were present in the string, do something with those values ...
End If
I have a set which has an unknown number of objects. I want to associate a label to each one of these objects. Instead of labeling each object with a number I want to label them with letters.
For example the first object would be labeled A the second B and so on.
When I get to Z, the next object would be labeled AA
AZ? then BA, BB, BC.
ZZ? then AAA, AAB, AAC and so on.
I'm working using Mapbasic (similar to VBA), but I can't seem to wrap my head around a dynamic solution. My solution assumes that there will be a max number of objects that the set may or may not exceed.
label = pos1 & pos2
Once pos2 reaches ASCII "Z" then pos1 will be "A" and pos2 will be "A". However, if there is another object after "ZZ" this will fail.
How do I overcome this static solution?
Basically what I needed was a Base 26 Counter. The function takes a parameter like "A" or "AAA" and determines the next letter in the sequence.
Function IncrementAlpha(ByVal alpha As String) As String
Dim N As Integer
Dim num As Integer
Dim str As String
Do While Len(alpha)
num = num * 26 + (Asc(alpha) - Asc("A") + 1)
alpha = Mid$(alpha, 2,1)
Loop
N = num + 1
Do While N > 0
str = Chr$(Asc("A") + (N - 1) Mod 26) & str
N = (N - 1) \ 26
Loop
IncrementAlpha = str
End Function
If we need to convert numbers to a "letter format" where:
1 = A
26 = Z
27 = AA
702 = ZZ
703 = AAA etc
...and it needs to be in Excel VBA, then we're in luck. Excel's columns are "numbered" the same way!
Function numToLetters(num As Integer) As String
numToLetters = Split(Cells(1, num).Address(, 0), "$")(0)
End Function
Pass this function a number between 1 and 16384 and it will return a string between A and XFD.
Edit:
I guess I misread; you're not using Excel. If you're using VBA you should still be able to do this will the help of an reference to an Excel Object Library.
This should get you going in terms of the logic. Haven't tested it completely, but you should be able to work from here.
Public Function GenerateLabel(ByVal Number As Long) As String
Const TOKENS As String = "ZABCDEFGHIJKLMNOPQRSTUVWXY"
Dim i As Long
Dim j As Long
Dim Prev As String
j = 1
Prev = ""
Do While Number > 0
i = (Number Mod 26) + 1
GenerateLabel = Prev & Mid(TOKENS, i, 1)
Number = Number - 26
If j > 0 Then Prev = Mid(TOKENS, j + 1, 1)
j = j + Abs(Number Mod 26 = 0)
Loop
End Function
Good people of Stackland
I'm analysing strings comprised of 5 alpha chars which in their raw format look like this;
A2) BCDBE
A3) TLDPP
A4) FGGFC
A5) BBGBB
I need a way of evaluating each character to identify patterns within the strings themselves, eg repeating letters. I want to represent these patterns as follows, where the 1st letter is always given as "A", the 2nd "B"...;
A2) BCDBE --> ABCAD
A3) TLDPP --> ABCDD
A4) FGGFC --> ABBAC
A5) BBGBB --> AABAA
Now, I have achieved this with some pretty inelegant conditional formulae but had to do this to evaluate each character individually, as follows;
1) =IF(LEFT(A2,1)>0,"A")
2) =IF(MID(A2,2,1)=LEFT(A2,1),"A","B")
3) =IF(MID(A2,3,1)=LEFT(A2,1),"A",IF(MID(A2,3,1)=MID(A2,2,1),M2,CHAR(CODE(M2)+1)))
4) =IF(MID(A2,4,1)=LEFT(A2,1),"A",IF(MID(A2,4,1)=MID(A2,2,1),M2,IF(MID(A2,4,1)=MID(A2,3,1),N2,CHAR(MAX(CODE(L2:N2)+1)))))
5) =IF(MID(A2,5,1)=LEFT(A2,1),"A",IF(MID(A2,5,1)=MID(A2,2,1),M2,IF(MID(A2,5,1)=MID(A2,3,1),N2,IF(MID(A2,5,1)=MID(A2,4,1),O2,CHAR(MAX(CODE(L2:O2)+1))))))
Translated...
1) Call the first character "A"
2) If the 2nd character is the same as the same as the 1st call it "A", otherwise cause it "B"
3) If the 3rd character is the same as the 1st call it "A", if it's the same as the 2nd call it whatever the 2nd is, if not give it the value of the next letter, ie "C"
4) If the 4th character is the same as the 1st, call it "A", if it's the sames as the 2nd call it whatever the 2nd is, if it's the same as the 3rd call it whatever the 3rd is, if not then call it the next letter in the alphabet, ie "D"
5) If the 5th character is the same as the 1st, call it "A", if it's the same as the 2nd call it whatever the 2nd is, if it's the same as the 3rd call it whatever the 3rd is called, if it's the same as the 4th call it whatever the 4th is called, if not then call it the next letter in the alphabet, ie "E"
I'm doing this over 5 cols, one formula per col, and the concatenating the 5 results into one cell to get AABAA or whatever.
I just need to know if there's a nice, clean VBA solution to this.
Any ideas?
Here is the a Function to do the letter instead of numbers:
Function findPattern(inputStr As String) As String
Dim i As Integer
Dim t As Integer
t = 1
For i = 1 To 5 Step 1
If Asc(Mid(inputStr, i, 1)) > 54 Then
inputStr = Replace(inputStr, Mid(inputStr, i, 1), t)
t = t + 1
End If
Next i
For i = 1 To 5
inputStr = Replace(inputStr, i, Chr(i + 64))
Next i
findPattern = inputStr
End Function
Put it in a module attached to the workbook, and you can call it thus:
=findPattern(A2)
Driectly from the worksheet where A2 is the cell you want tested.
Or from vba:
Sub test()
Dim str as string
str = findPattern(Range("A2").value)
debug.print str
End Sub
Edit: By your Comment I assume you have more than just the first 5 characters that you want left original. If that is the case use this:
Function findPattern(Str As String) As String
Dim inputStr As String
Dim i As Integer
Dim t As Integer
inputStr = Left(Str, 5)
t = 1
For i = 1 To 5 Step 1
If Asc(Mid(inputStr, i, 1)) > 54 Then
inputStr = Replace(inputStr, Mid(inputStr, i, 1), t)
t = t + 1
End If
Next i
For i = 1 To 5
inputStr = Replace(inputStr, i, Chr(i + 64))
Next i
'This is the return line. As is it will only return 5 characters.
'If you want the whole string with only the first five as the pattern
'Remove the single quote in the middle of the string.
findPattern = inputStr '& Mid(Str, 6, (Len(Str)))
End Function
This seems like an easy approach:
's is the input string
dim pos, c, s_new, s_old
pos = 1 : c = 49
s_new = mid(s, 1, 5) ' take only first five characters
do while pos <= 5
s_old = s_new
s_new = replace(s_new, mid(s, pos, 1), chr(c))
if s_new <> s_old then c = c + 1
loop
s_new = replace(s_new, "1", "A")
s_new = replace(s_new, "2", "B")
s_new = replace(s_new, "3", "C")
s_new = replace(s_new, "4", "D")
s_new = replace(s_new, "5", "E")
'm assuming that you don't have any numeric characters in your input.
This has a certain elegance:
Function Pattern(r As Range)
Dim c&, i&, a
Const FORMULA = "iferror(find(mid(~,{2,3,4,5},1),left(~,{1,2,3,4})),)"
a = Evaluate(Replace(FORMULA, "~", r.Address))
c = 1: Pattern = "A"
For i = 1 To 4
If a(i) = 0 Then c = c + 1: a(i) = c
Pattern = Pattern & Chr$(64 + a(i))
Next
End Function
I had this for a while (it's handy for cryptograms), so I'll post it:
Function Pattern(ByVal sInp As String) As String
' shg 2012
' Returns the pattern of a string as a string of the same length
' First unique letter and all repeats is a, second is b, …
' E.g., Pattern("mississippi") returns "abccbccbddb"
Dim iChr As Long ' character index to sInp & Pattern
Dim sChr As String ' character in sInp
Dim iPos As Long ' position of first appearance of sChr in sInp
sInp = LCase(Trim(sInp))
If Len(sInp) Then
sChr = Chr(64)
Pattern = sInp
For iChr = 1 To Len(sInp)
iPos = InStr(sInp, Mid(sInp, iChr, 1))
If iPos = iChr Then ' it's new
sChr = Chr(Asc(sChr) + 1)
Mid(Pattern, iChr) = sChr
Else
Mid(Pattern, iChr) = Mid(Pattern, iPos, 1)
End If
Next iChr
End If
End Function
I am banging my head against the wall for a while now trying different techniques.
None of them are working well.
I have two strings.
I need to compare them and get an exact percentage of match,
ie. "four score and seven years ago" TO "for scor and sevn yeres ago"
Well, I first started by comparing every word to every word, tracking every hit, and percentage = count \ numOfWords. Nope, didn't take into account misspelled words.
("four" <> "for" even though it is close)
Then I started by trying to compare every char in each char, incrementing the string char if not a match (to count for misspellings). But, I would get false hits because the first string could have every char in the second but not in the exact order of the second. ("stuff avail" <> "stu vail" (but it would come back as such, low percentage, but a hit. 9 \ 11 = 81%))
SO, I then tried comparing PAIRS of chars in each string. If string1[i] = string2[k] AND string1[i+1] = string2[k+1], increment the count, and increment the "k" when it doesn't match (to track mispellings. "for" and "four" should come back with a 75% hit.) That doesn't seem to work either. It is getting closer, but even with an exact match it is only returns 94%. And then it really gets screwed up when something is really misspelled. (Code at the bottom)
Any ideas or directions to go?
Code
count = 0
j = 0
k = 0
While j < strTempName.Length - 2 And k < strTempFile.Length - 2
' To ignore non letters or digits '
If Not strTempName(j).IsLetter(strTempName(j)) Then
j += 1
End If
' To ignore non letters or digits '
If Not strTempFile(k).IsLetter(strTempFile(k)) Then
k += 1
End If
' compare pair of chars '
While (strTempName(j) <> strTempFile(k) And _
strTempName(j + 1) <> strTempFile(k + 1) And _
k < strTempFile.Length - 2)
k += 1
End While
count += 1
j += 1
k += 1
End While
perc = count / (strTempName.Length - 1)
Edit: I have been doing some research and I think I initially found the code from here and translated it to vbnet years ago. It uses the Levenshtein string matching algorithm.
Here is the code I use for that, hope it helps:
Sub Main()
Dim string1 As String = "four score and seven years ago"
Dim string2 As String = "for scor and sevn yeres ago"
Dim similarity As Single =
GetSimilarity(string1, string2)
' RESULT : 0.8
End Sub
Public Function GetSimilarity(string1 As String, string2 As String) As Single
Dim dis As Single = ComputeDistance(string1, string2)
Dim maxLen As Single = string1.Length
If maxLen < string2.Length Then
maxLen = string2.Length
End If
If maxLen = 0.0F Then
Return 1.0F
Else
Return 1.0F - dis / maxLen
End If
End Function
Private Function ComputeDistance(s As String, t As String) As Integer
Dim n As Integer = s.Length
Dim m As Integer = t.Length
Dim distance As Integer(,) = New Integer(n, m) {}
' matrix
Dim cost As Integer = 0
If n = 0 Then
Return m
End If
If m = 0 Then
Return n
End If
'init1
Dim i As Integer = 0
While i <= n
distance(i, 0) = System.Math.Max(System.Threading.Interlocked.Increment(i), i - 1)
End While
Dim j As Integer = 0
While j <= m
distance(0, j) = System.Math.Max(System.Threading.Interlocked.Increment(j), j - 1)
End While
'find min distance
For i = 1 To n
For j = 1 To m
cost = (If(t.Substring(j - 1, 1) = s.Substring(i - 1, 1), 0, 1))
distance(i, j) = Math.Min(distance(i - 1, j) + 1, Math.Min(distance(i, j - 1) + 1, distance(i - 1, j - 1) + cost))
Next
Next
Return distance(n, m)
End Function
Did not work for me unless one (or both) of following are done:
1) use option compare statement "Option Compare Text" before any Import declarations and before Class definition (i.e. the very, very first line)
2) convert both strings to lowercase using .tolower
Xavier's code must be correct to:
While i <= n
distance(i, 0) = System.Math.Min(System.Threading.Interlocked.Increment(i), i - 1)
End While
Dim j As Integer = 0
While j <= m
distance(0, j) = System.Math.Min(System.Threading.Interlocked.Increment(j), j - 1)
End While
I need to calculate the median of a set of measurements where in some cases a value was measured, and in some cases the value was below detection (indicated by "<" sign followed by the detection limit, e.g. <1)
Here are some examples of cases that I'm encountering:
2.0; 3.0; <1.0; 4.0 --> median = 2.5
1.0; <0.5; <0.5 --> median = <0.5
1.0; 1.0; <0.5; <0.5 --> median = <0.75
I'm a little stumped about doing this in excel VBA.
How can I do math with the values that have a "<" sign while still keeping track of the "<"?
Any input is much appreciated -- thanks!
Here's something I use:
Public Function DoAvg(rng As Range)
DoAvg = Parse(rng, "Average")
End Function
Public Function DoMedian(rng As Range)
DoMedian = Parse(rng, "Median")
End Function
'This does the work...
Private Function Parse(rng As Range, CalcType As String)
Dim rv, arr() As Single, mods As String, i As Long
Dim c As Range
Dim tmp, m
For Each c In rng.Cells
tmp = Replace(Trim(c.Value), " ", "")
If tmp Like "<*" Or tmp Like ">*" Then
m = Left(tmp, 1)
If Not InStr(mods, m) > 0 Then mods = mods & m
tmp = Right(tmp, Len(tmp) - 1)
End If
If IsNumeric(tmp) And tmp <> "" Then
i = i + 1
ReDim Preserve arr(1 To i)
arr(i) = tmp
End If
Next c
If i > 1 Then
rv = CallByName(Application.WorksheetFunction, CalcType, VbGet, arr)
Parse = IIf(mods <> "", mods, "") & rv
Else
Parse = ""
End if
End Function