I have a very specific business requirement to hide certain characters within an email address when returned from SQL and I have hit the limit of my ability with SQL to achieve this. I was wondering if someone out there would be able to point me in the right direction. Essentially, my business is asking for the following:
test#email.com to become t*\*t#e**l.com
or
thislong#emailaddress.com to become t******h#e**********s.com
I am aware that if either portion of the email before of after the # are less than 3 characters, then this won't work, but I intend on checking for this and dealing with it appropriately. I have tried a mixture of SUBSTRING, STUFF, LEFT/RIGHT etc but I can't quite get it right.
DECLARE #String VARCHAR(100) = 'example#gmail.com'
SELECT LEFT(#String, 1) + '*****#'
+ REVERSE(LEFT(RIGHT(REVERSE(#String) , CHARINDEX('#', #String) +1), 1))
+ '******'
+ RIGHT(#String, 5)
result will be
e******e#g***l.com
Very interesting and very much tough to generate generic solution try this
this may help you
DECLARE #String VARCHAR(100) = 'sample#gmail.com'
SELECT STUFF(STUFF(#STring,
CHARINDEX('#',#String)+2,
(CHARINDEX('.',#String, CHARINDEX('#',#String))-CHARINDEX('#',#String)-3),
REPLICATE('*',CHARINDEX('.',#String, CHARINDEX('#',#String))-CHARINDEX('#',#String)))
,2
,CHARINDEX('#',#String)-3
,REPLICATE('*',CHARINDEX('#',#String)-3))
OUTPUT will be
s****e#g******l.com
Similar way for thislong#emailaddress.com
OUTPUT will be
t******g#e*************s.com
You could also use regular expressions. Something like this (not completely finished):
select regexp_replace('test#email.com', '^(.?).*#(.?).*', '\1***#\2***')
from dual
Results in:
t***#e***
Could be a useful solution if you can only use SELECT statements.
CREATE FUNCTION dbo.EmailObfuscate
( #Email VARCHAR(255)
) RETURNS TABLE AS RETURN
(
SELECT adr.email
, LEFT (adr.email, 1)
+ REPLICATE ('*', AtPos-3)
+ SUBSTRING (adr.Email, AtPos-1, 3)
+ REPLICATE ('*', Length-DotPos - AtPos - 2)
+ SUBSTRING (adr.Email, Length - DotPos, 10) AS hide
FROM ( VALUES ( #Email) ) AS ADR (EMail)
CROSS APPLY ( SELECT CHARINDEX ('#', adr.Email)
, CHARINDEX ('.', REVERSE(Adr.Email))
, LEN (Adr.Email)
) positions ( AtPos
, dotpos
, Length
)
);
GO
-- Calling
SELECT Emails.*
FROM ( Values ( 'this.long#emailaddress.com')
, ( 'test#email.com' )
, ( 'sample#gmail.com' )
, ( 'test#gmx.de' )
) AS adr (email)
CROSS APPLY dbo.EmailObfuscate (Adr.Email) AS Emails
SELECT
-- Email here is the name of the selected Column from your Table
--Display the First Character
SUBSTRING(Email,1,1)+
--Replace selected Number of *
REPLICATE('*',10)+
--Display the One Character before # along with # & One Character after #
SUBSTRING(Email,CHARINDEX('#',Email)-1,3)+
--Replace selected Number of *
REPLICATE('*',10)+
--Display. Character along with the rest selected Number of Characters
SUBSTRING(Email,CHARINDEX('.',Email)-1, LEN(Email) -
CHARINDEX('.',Email)+12)
--NameEmail is the Table Name
FROM NameEmail
Result is:
j**********l#a**********a.co.uk
I've found this answer, but was searching for PostgreSQL version (and have not found it)
So I've made my own for PGSQL
SELECT
-- Email here is the name of the selected Column from your Table
--Display the First Character
SUBSTRING('g40gj30m#my-email.co.uk', 1, 1) ||
--Replace selected Number of *
REPEAT('*', 10) ||
--Display the One Character before # along with # & One Character after #
SUBSTRING('g40gj30m#my-email.co.uk', strpos('g40gj30m#my-email.co.uk', '#') - 1, 3) ||
--Replace selected Number of *
REPEAT('*', 10) ||
--Display. Character along with the rest selected Number of Characters
SUBSTRING(
'g40gj30m#my-email.co.uk',
strpos('g40gj30m#my-email.co.uk', '.') - 1,
length('g40gj30m#my-email.co.uk') - strpos('g40gj30m#my-email.co.uk', '.') + 12
);
the result will be
?column?
---------------------------------
g**********m#m**********l.co.uk
(1 row)
Related
I am working with a field called codes that is a delimited list of values, separated by commas. Within each item there is a title ending in a colon and then a code number following the colon. I want a list of only the code numbers after each colon.
Example Value:
name-form-na-stage0:3278648990379886572,rules-na-unwanted-sdfle2:6886328308933282817,us-disdg-order-stage1:1273671130817907765
Desired Output:
3278648990379886572,6886328308933282817,1273671130817907765
The title does always start with a letter and the end with a colon so I can see how REGEXP_REPLACE might work to replace any string between starting with a letter and ending with a colon with '' might work but I am not good at REGEXP_REPLACE patterns. Chat GPT is down fml.
Side note, if anyone knows of a good guide for understanding pattern notation for regular expressions it would be much appreciated!
I tried this and it is not working REGEXP_REPLACE(REPLACE(REPLACE(codes,':', ' '), ',', ' ') ,' [^0-9]+ ', ' ')
This solution assumes a few things:
No colons anywhere else except immediately before the numbers
No number at the very start
At a high level, this query finds how many colons there are, splits the entire string into that many parts, and then only keeps the number up to the comma immediately after the number, and then aggregates the numbers into a comma-delimited list.
Assuming a table like this:
create temp table tbl_string (id int, strval varchar(1000));
insert into tbl_string
values
(1, 'name-form-na-stage0:3278648990379886572,rules-na-unwanted-sdfle2:6886328308933282817,us-disdg-order-stage1:1273671130817907765');
with recursive cte_num_of_delims AS (
select max(regexp_count(strval, ':')) AS num_of_delims
from tbl_string
), cte_nums(nums) AS (
select 1 as nums
union all
select nums + 1
from cte_nums
where nums <= (select num_of_delims from cte_num_of_delims)
), cte_strings_nums_combined as (
select id,
strval,
nums as index
from cte_nums
cross join tbl_string
), prefinal as (
select *,
split_part(strval, ':', index) as parsed_vals
from cte_strings_nums_combined
where parsed_vals != ''
and index != 1
), final as (
select *,
case
when charindex(',', parsed_vals) = 0
then parsed_vals
else left(parsed_vals, charindex(',', parsed_vals) - 1)
end as final_vals
from prefinal
)
select listagg(final_vals, ',')
from final
Using SQL, how can I retrieve the 2 words from the right end of a CHAR(30) field?
namefield = "My name is Bill Smith"
results = Bill Smith
This is untested, but maybe something like:
SELECT REVERSE(SUBSTRING(REVERSE(namefield) , 0, CHARINDEX(' ', REVERSE(namefield), CHARINDEX(' ', REVERSE(namefield), 0)+1))) FROM TABLE
Replace table with your table. Let me know if it works!
If you use LOCATE_IN_STRING you can say -X to search backwards - as op. to charindex which only only look forward.
select
-- locate_in_string(str,' ',-1),
-- substr(str,1,locate_in_string(str,' ',-1)-1),
-- length(str) - locate_in_string(str,' ',-1),
-- locate_in_string(str,' ',-7),
-- locate_in_string(str,' ',(-1* (length(str) - locate_in_string(str,' ',-1))) -2 ),
-- substr(str,1,11) || '<-',
-- substr(str,1,locate_in_string(str,' ',(-1* (length(str) - locate_in_string(str,' ',-1))) -2 )-1),
substr(str,locate_in_string(str,' ',(-1* (length(str) - locate_in_string(str,' ',-1))) -2 ))
FROM (
VALUES('My name is Bill Smith')
) AS T(str)
Here I start at the point of the last space and search for the prior space and then pass that to substr.
https://www.ibm.com/support/knowledgecenter/en/SSEPGG_9.7.0/com.ibm.db2.luw.sql.ref.doc/doc/r0054098.html
I've included my testing code above -- you can see how I test various parts by removing the comment for that line. This technique my prove useful in your testing.
I need to do a select in a column that contains a query string like:
user_id=300&company_id=201503&status=WAITING OPERATION&count=1
I want to perform a select and break each value in a new column, something like:
user_id | company_id | status | count
300 | 201503 | WAITING OPERATION | 1
How can i do it in SQL Server without use procs?
I've tried a function:
CREATE FUNCTION [xpto].[SplitGriswold]
(
#List NVARCHAR(MAX),
#Delim1 NCHAR(1),
#Delim2 NCHAR(1)
)
RETURNS TABLE
AS
RETURN
(
SELECT
Val1 = PARSENAME(Value,2),
Val2 = PARSENAME(Value,1)
FROM
(
SELECT REPLACE(Value, #Delim2, '&') FROM
(
SELECT LTRIM(RTRIM(SUBSTRING(#List, [Number],
CHARINDEX(#Delim1, #List + #Delim1, [Number]) - [Number])))
FROM (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
FROM sys.all_objects) AS x
WHERE Number <= LEN(#List)
AND SUBSTRING(#Delim1 + #List, [Number], LEN(#Delim1)) = #Delim1
) AS y(Value)
) AS z(Value)
);
GO
Execution:
select QueryString
from User.Log
CROSS APPLY notifier.SplitGriswold(REPLACE(QueryString, ' ', N'ŏ'), N'ŏ', '&') AS t;
But it returns me only one column with all inside:
QueryString
user_id=300&company_id=201503&status=WAITING OPERATION&count=1
Thanks in advance.
I've had to do this many times before, and you're in luck! Since you only have 3 delimiters per string, and that number is fixed, you can use SQL Server's PARSENAME function to do it. That's far less ugly than the best alternative (using the XML parsing stuff). Try this (untested) query (replace TABLE_NAME and COLUMN_NAME with the appropriate names):
SELECT
PARSENAME(REPLACE(COLUMN_NAME,'&','.'),1) AS 'User',
PARSENAME(REPLACE(COLUMN_NAME,'&','.'),2) AS 'Company_ID',
PARSENAME(REPLACE(COLUMN_NAME,'&','.'),3) AS 'Status',
PARSENAME(REPLACE(COLUMN_NAME,'&','.'),4) AS 'Count',
FROM TABLE_NAME
That'll get you the results in the form "user_id=300", which is far and away the hard part of what you want. I'll leave it to you to do the easy part (drop the stuff before the "=" sign).
NOTE: I can't remember if PARSENAME will freak out over the illegal name character (the "=" sign). If it does, simply nest another REPLACE in there to turn it into something else, like an underscore.
You need to use SQL SUBSTRING as part of your select statement. You would first need to build the first row, then use a UNION to return the second row.
I have a column with value
AAA_ZZZZ_7890_10_28_2014_123456.jpg
I need to replace the middle underscores so that it displays it as date i.e.
AAA_ZZZZ_7890_10-28-2014_123456.jpg
Can some one please suggest a simple update query for this.
The Number of Underscores would be same for all the values in the column but the length will vary for example some can have
AAA_q10WRQ_001_10_28_2014_12.jpg
The following should do it:
http://sqlfiddle.com/#!3/d41d8/30384/0
declare #filename varchar(64) = 'AAA_ZZZZ_7890_10_28_2014_123456.jpg'
declare #datepattern varchar(64) = '%[_][0-1][0-9][_][0-3][0-9][_][1-2][0-9][0-9][0-9][_]%'
select
filename,
substring(filename,1,datepos+2)+'-'+
substring(filename,datepos+4,2)+'-'+
substring(filename,datepos+7,1000)
from
(
select
#filename filename,
patindex(#datepattern,#filename)
as datepos
) t
;
Resulting in
AAA_ZZZZ_7890_10-28-2014_123456.jpg
Caveats to watch out for:
It is important to exactly define how you find the date. In my definition it is MM_DD_YYYY surrounded by further two underscores, and I check that the first digits of M,D,Y are 0-1,0-3,1-2 respectively (i.e. I do NOT check if month is e.g. 13.) -- of course we assume that there is only one such string in any file name.
datepos actually finds the position of the underscore before the date -- this is not an issue if taken into account in the indexing of substring.
in the 3rd substring the length cannot be NULL or infinity and I couldn't get LEN() to work in SQL Fiddle so I dirty hardcoded a large enough number (1000). Corrections to this are welcome.
Try this (assuming that the DATE portion always starts at the same character index)
declare #string varchar(64) = 'AAA_ZZZZ_7890_10_28_2014_123456.jpg'
select replace(#string, reverse(substring(reverse(#string), charindex('_', reverse(#string), 0) + 1, 10)), replace(reverse(substring(reverse(#string), charindex('_', reverse(#string), 0) + 1, 10)), '_', '-'))
If there are exactly 6 _ then for the first
select STUFF ( 'AAA_ZZZZ_7890_10_28_2014_123456.jpg' , CHARINDEX ( '_' ,'AAA_ZZZZ_7890_10_28_2014_123456.jpg', CHARINDEX ( '_' ,'AAA_ZZZZ_7890_10_28_2014_123456.jpg', CHARINDEX ( '_' ,'AAA_ZZZZ_7890_10_28_2014_123456.jpg', CHARINDEX ( '_' ,'AAA_ZZZZ_7890_10_28_2014_123456.jpg', 0 ) + 1 ) + 1 ) + 1 ) , 1 , '-' )
I've got a column in a database table (SQL Server 2005) that contains data like this:
TQ7394
SZ910284
T r1534
su8472
I would like to update this column so that the first two characters are uppercase. I would also like to remove any spaces between the first two characters. So T q1234 would become TQ1234.
The solution should be able to cope with multiple spaces between the first two characters.
Is this possible in T-SQL? How about in ANSI-92? I'm always interested in seeing how this is done in other db's too, so feel free to post answers for PostgreSQL, MySQL, et al.
Here is a solution:
EDIT: Updated to support replacement of multiple spaces between the first and the second non-space characters
/* TEST TABLE */
DECLARE #T AS TABLE(code Varchar(20))
INSERT INTO #T SELECT 'ab1234x1' UNION SELECT ' ab1234x2'
UNION SELECT ' ab1234x3' UNION SELECT 'a b1234x4'
UNION SELECT 'a b1234x5' UNION SELECT 'a b1234x6'
UNION SELECT 'ab 1234x7' UNION SELECT 'ab 1234x8'
SELECT * FROM #T
/* INPUT
code
--------------------
ab1234x3
ab1234x2
a b1234x6
a b1234x5
a b1234x4
ab 1234x8
ab 1234x7
ab1234x1
*/
/* START PROCESSING SECTION */
DECLARE #s Varchar(20)
DECLARE #firstChar INT
DECLARE #secondChar INT
UPDATE #T SET
#firstChar = PATINDEX('%[^ ]%',code)
,#secondChar = #firstChar + PATINDEX('%[^ ]%', STUFF(code,1, #firstChar,'' ) )
,#s = STUFF(
code,
1,
#secondChar,
REPLACE(LEFT(code,
#secondChar
),' ','')
)
,#s = STUFF(
#s,
1,
2,
UPPER(LEFT(#s,2))
)
,code = #s
/* END PROCESSING SECTION */
SELECT * FROM #T
/* OUTPUT
code
--------------------
AB1234x3
AB1234x2
AB1234x6
AB1234x5
AB1234x4
AB 1234x8
AB 1234x7
AB1234x1
*/
UPDATE YourTable
SET YourColumn = UPPER(
SUBSTRING(
REPLACE(YourColumn, ' ', ''), 1, 2
)
)
+
SUBSTRING(YourColumn, 3, LEN(YourColumn))
UPPER isn't going to hurt any numbers, so if the examples you gave are completely representative, there's not really any harm in doing:
UPDATE tbl
SET col = REPLACE(UPPER(col), ' ', '')
The sample data only has spaces and lowercase letters at the start. If this holds true for the real data then simply:
UPPER(REPLACE(YourColumn, ' ', ''))
For a more specific answer I'd politely ask you to expand on your spec, otherwise I'd have to code around all the other possibilities (e.g. values of less than three characters) without knowing if I was overengineering my solution to handle data that wouldn't actually arise in reality :)
As ever, once you've fixed the data, put in a database constraint to ensure the bad data does not reoccur e.g.
ALTER TABLE YourTable ADD
CONSTRAINT YourColumn__char_pos_1_uppercase_letter
CHECK (ASCII(SUBSTRING(YourColumn, 1, 1)) BETWEEN ASCII('A') AND ASCII('Z'));
ALTER TABLE YourTable ADD
CONSTRAINT YourColumn__char_pos_2_uppercase_letter
CHECK (ASCII(SUBSTRING(YourColumn, 2, 1)) BETWEEN ASCII('A') AND ASCII('Z'));
#huo73: yours doesn't work for me on SQL Server 2008: I get 'TRr1534' instead of 'TR1534'.
update Table set Column = case when len(rtrim(substring (Column , 1 , 2))) < 2
then UPPER(substring (Column , 1 , 1) + substring (Column , 3 , 1)) + substring(Column , 4, len(Column)
else UPPER(substring (Column , 1 , 2)) + substring(Column , 3, len(Column) end
This works on the fact that if there is a space then the trim of that part of string would yield length less than 2 so we split the string in three and use upper on the 1st and 3rd char. In all other cases we can split the string in 2 parts and use upper to make the first two chars to upper case.
If you are doing an UPDATE, I would do it in 2 steps; first get rid of the space (RTRIM on a SUBSTRING), and second do the UPPER on the first 2 chars:
// uses a fixed column length - 20-odd in this case
UPDATE FOO
SET bar = RTRIM(SUBSTRING(bar, 1, 2)) + SUBSTRING(bar, 3, 20)
UPDATE FOO
SET bar = UPPER(SUBSTRING(bar, 1, 2)) + SUBSTRING(bar, 3, 20)
If you need it in a SELECT (i.e. inline), then I'd be tempted to write a scalar UDF