Is it possible to check if a specific substring which is in SQL Server column, is contained in a user provided string?
Example :
SELECT * FROM Table WHERE 'random words to check, which are in a string' CONTAINS Column
From my understanding, CONTAINS can't do such kind of search.
EDIT :
I have a fully indexed text and would like to search (by the fastest method) if a string provided by me contains words that are present in a column.
You can use LIKE:
SELECT * FROM YourTable t
WHERE 'random words ....' LIKE '%' + t.column + '%'
Or
SELECT * FROM YourTable t
WHERE t.column LIKE '%random words ....%'
Depends what did you mean, first one select the records that the column has a part of the provided string. The second one is the opposite.
Just use the LIKE syntax together with % around the string you are looking for:
SELECT
*
FROM
table
WHERE
Column LIKE '%some random string%'
This will return all rows in the table table in which the column Column contains the text "some random string".
1) If you want to get data starting with some letter you can use % this operator like this in your where clause
WHERE
Column LIKE "%some random string"
2) If you want to get data contains any letter you can use
WHERE
Column LIKE "%some random string%"
3)if you want to get data ending with some letter you can use
WHERE
Column LIKE "some random string%"
Related
In REGEX you can do something like [a-c]+, which will match on
aaabbbccc
abcccaabc
cbccaa
b
aaaaaaaaa
In SQL LIKE it seems that one can either do the equivalent of ".*" which is "%", or [a-c]. Is it possible to use the +(at least one) quantifier in SQL to do [a-c]+?
EDIT: Just to clarify, the desired end-query would look something like
SELECT * FROM table WHERE column LIKE '[a-c]+'
which would then match on the list above, but would NOT match on e.g "xxxxxaxxxx"
As a general rule, SQL Server's LIKE patterns are much weaker than regular expressions. For your particular example, you can do:
where col not like '%[^a-c]%'
That is, the column contains no characters that are not a, b, or c.
You can use regex in SQL with combination of LIKE e.g :
SELECT * FROM Table WHERE Field LIKE '%[^a-z0-9 .]%'
This works in SQL
Or in your case
SELECT * FROM Table WHERE Field LIKE '%[^a-c]%'
I seems you want some data from database, That is you don't know exactly, You must show your column and the all character that you want in that filed.
I am trying to figure out some commands/code in SQL.
I have database with names, addresses IDs etc, but I have to convert firstname values ending in “jnr” to “(Jnr)” and those ending in “snr” to “(Snr)”.
How do I do this?
update table TABLE_NAME set NAMES = '*xyz*Jnr' where NAMES like '%jnr'
Update or select:
PASTE(column, CHAR_LENGTH(column)-3, 1, UPPER(SUBSTRING(column FROM CHAR_LENGTH(column)-3 FOR 1)
WHERE column LIKE '%jnr' OR column LIKE '%snr'
PASTE is used to put in one character at position 3 from end,
CHAR_LENGTH to get length of column value,
UPPER converts character to upper case,
SUBSTRING is used to pick one character here (j or s),
LIKE is used to find values ending with jnr, or snr.
All ANSI SQL (no dbms specified!)
I have a column of data in my database that has a project number the numbers are formatted like this, YYYYnnnn.ee (for example 20140124.00). Since there are three distinct parts of the number, the user could search by either the YYYY or the nnnn. I have written a query that searches by the YYYY. I need to write a query for the nnnn.
How would you write a query to search for a specific string in a specific location of another string?
You can use SUBSTRING for that.
The first paramter to SUBSTRING should be the columname, the next parameter is the index of the start character and the last parameter is the number of characters.
The example below will return the nnnn part from your column. In the example below we are searching for records where the nnnn equals 1234.
SELECT *
FROM tablename
WHERE
(SUBSTRING(columnName, 5, 4) = '1234')
Please note, if your column is a number (decimal). You will need to first cast it as a varchar (string). For example:
SELECT *
FROM tablename
WHERE
(SUBSTRING(CAST(columnName AS VARCHAR(20)), 5, 4) = '1234')
ok so I have a table that looks something like this...(using pipe symbol to separate columns)
example1 url|0
example2 url|0
example3 url|1
example4 url|1,2
example5 url|1,3,6
What I am trying to do is to select all rows where column 2 does NOT contain a 1.
I cannot use != because if you look all but one of those would return data because the last 2 rows don't equal 1. I tried scouring SQLite documentation for how to go about writing the statement, but I can't find it. This is what I have so far.
select * from table_name where table_column_name[something needed here]'1';
Give that "1,2,3" et al are strings, you probably need the LIKE keyword.
select * from table_name where table_column_name NOT LIKE '%1%'
For matching a list item separated by ,, use:
SELECT * FROM table WHERE `,`||column||`,` NOT LIKE '%,1,%';
this will match entire item (ie, only 1, not 11, ...), whether it is at list beginning, middle or end.
If I have a query to return all matching entries in a DB that have "news" in the searchable column (i.e. SELECT * FROM table WHERE column LIKE %news%), and one particular row has an entry starting with "In recent World news, Somalia was invaded by ...", can I return a specific "chunk" of an SQL entry? Kind of like a teaser, if you will.
select substring(column,
CHARINDEX ('news',lower(column))-10,
20)
FROM table
WHERE column LIKE %news%
basically substring the column starting 10 characters before where the word 'news' is and continuing for 20.
Edit: You'll need to make sure that 'news' isn't in the first 10 characters and adjust the start position accordingly.
You can use substring function in a SELECT part. Something like:
SELECT SUBSTRING(column, 1,20) FROM table WHERE column LIKE %news%
This will return the first 20 characters from column column
I had the same problem, I ended up loading the whole field into C#, then re-searched the text for the search string, then selected x characters either side.
This will work fine for LIKE, but not full text queries which use FORMS OF INFLECTION because that may match "women" when you search for "woman".
If you are using MSSQL you can perform all kinds VB-like of substring functions as part of your query.