Display city with second highest number of stores in sql - sql

Question

Display city with second highest number of stores.
here is table toy_store with data IN IMAGETOY_STORE

Answer 1

Remember this is not service to complete your assignments, you should try it first, show some efforts, for now you could get ans for you question and there are number of way to do this.
SELECT TOP(1),*
FROM
(
SELECT TOP(2) CITY,COUNT(CITY)
FROM TableName
GROUP BY CITY
ORDER BY CITY DESC
)M

Answer 2

The question as I and #jaydip-jadhav have mentioned lacks details. It's also very old at this point but since it came back up via your comments I decided to take another look.
However, the above should work with minimal changes depending on what you're using (again, more details would help such as what DBMS your using and what version, etc).
That said you could also google what you're after and find a variety of solutions.
An Example solution
But here's 2 working basic examples you can view, run and use with this SQL Fiddle.
If the fiddle stops working here's the details you could use to recreate on your own somewhere.
This is using MySQL 5.6 (old, but so's this question).
Schema based on your image (next time, type it out):
CREATE TABLE IF NOT EXISTS `toy_store` (
`toy_store_id` int(6) NOT NULL,
`toy_store_name` varchar(200) NOT NULL,
`city` varchar(200) NOT NULL,
`phone_number` varchar(200) NOT NULL,
`store_opening_time` varchar(200) NOT NULL,
`store_closing_time` varchar(200) NOT NULL,
PRIMARY KEY (`toy_store_id`)
) DEFAULT CHARSET=utf8;
INSERT INTO `toy_store` (`toy_store_id`, `toy_store_name`, `city`, `phone_number`, `store_opening_time`, `store_closing_time`) VALUES
('1', 'kids cave', 'Delhi', '9912312312', '2014-04-01 09:10:12', '2014-04-01 21:42:05'),
('2', 'kids corner', 'Mumbai', '9912312312', '2014-04-01 09:10:12', '2014-04-01 21:42:05'),
('3', 'play and grow', 'Mumbai', '9912312312', '2014-04-01 09:10:12', '2014-04-01 21:42:05'),
('4', 'puzzles and more', 'Delhi', '9912312312', '2014-04-01 09:10:12', '2014-04-01 21:42:05'),
('5', 'uncle same toys den', 'Delhi', '9912312312', '2014-04-01 09:10:12', '2014-04-01 21:42:05'),
('6', 'mickey toys', 'Delhi', '9912312312', '2014-04-01 09:10:12', '2014-04-01 21:42:05'),
('7', 'mickey toys', 'Somewhere Else', '9912312312', '2014-04-01 09:10:12', '2014-04-01 21:42:05');
2 basic queries that work against the above schema:
SELECT * FROM (
SELECT city, count(city) as count_city
FROM toy_store
GROUP BY city
ORDER BY COUNT(city) desc
LIMIT 2
) as top2
ORDER BY top2.count_city asc
LIMIT 1;
-- RESULT
-- city count_city
-- Mumbai 2
SELECT DISTINCT city, count(city) as count_city
FROM toy_store
GROUP BY city
ORDER BY COUNT(city)
LIMIT 1,1;
-- RESULT
-- city count_city
-- Mumbai 2