I want to make a short version on my DATEDIFF function on my SQL Query. In my code, I created two temporary tables then there, I select and use the DATEDIFF funtion.
I would want this code to be simplified and only use ONE SELECT statement that will provide the same results. Is it possible?
Here is my result:
This is my SQL Query
DECLARE #Temp TABLE (ID int, Stamp datetime)
INSERT INTO #Temp (ID, Stamp) VALUES (1, '2016-08-17')
INSERT INTO #Temp (ID, Stamp) VALUES (1, GETDATE())
INSERT INTO #Temp (ID, Stamp) VALUES (1, GETDATE()+0.5)
INSERT INTO #Temp (ID, Stamp) VALUES (2, '2016-08-16')
INSERT INTO #Temp (ID, Stamp) VALUES (2, GETDATE())
INSERT INTO #Temp (ID, Stamp) VALUES (2, GETDATE()+3)
SELECT ROW_NUMBER() OVER (ORDER BY ID) as c, ID, Stamp INTO #Temp2
FROM #Temp
SELECT ROW_NUMBER() OVER (ORDER BY ID) as d, ID, Stamp INTO #Temp3
FROM #Temp
SELECT temp2.ID, temp2.Stamp, ISNULL(DATEDIFF(day, temp3.Stamp, temp2.Stamp),0) as DateDiff
FROM #Temp2 as temp2
LEFT JOIN #Temp3 as temp3 on temp2.ID = temp3.ID and temp2.c = temp3.d + 1
Thanks!
If you are using SQL Server 2012:
select * ,isnull(datediff(day,lag(stamp) over(partition by id order by stamp),stamp) ,0)
from #temp t1
Else use this..
;with cte
as
(select * ,row_number() over (partition by id order by stamp ) as rownum
from #temp t1
)
select c1.id,c1.stamp,isnull(datediff(day,c2.stamp,c1.stamp),0) as datee
from cte c1
left join
cte c2
on c1.id=c2.id and c1.rownum=c2.rownum+1
You could remove insert into the temp-tables and use subselects within the final query:
DECLARE #Temp TABLE (ID int, Stamp datetime)
INSERT INTO #Temp (ID, Stamp) VALUES (1, '2016-08-17')
INSERT INTO #Temp (ID, Stamp) VALUES (1, GETDATE())
INSERT INTO #Temp (ID, Stamp) VALUES (1, GETDATE()+0.5)
INSERT INTO #Temp (ID, Stamp) VALUES (2, '2016-08-16')
INSERT INTO #Temp (ID, Stamp) VALUES (2, GETDATE())
INSERT INTO #Temp (ID, Stamp) VALUES (2, GETDATE()+3)
SELECT temp2.ID, temp2.Stamp, ISNULL(DATEDIFF(day, temp3.Stamp, temp2.Stamp),0) as DateDiff
FROM (SELECT ROW_NUMBER() OVER (ORDER BY ID) as c, ID, Stamp FROM #Temp) as temp2
LEFT JOIN (SELECT ROW_NUMBER() OVER (ORDER BY ID) as d, ID, Stamp FROM #Temp) as temp3
on temp2.ID = temp3.ID and temp2.c = temp3.d + 1
In SQL Server 2012+, you would just use lag():
select t.*
isnull(datediff(day, lag(stamp) over (partition by id order by stamp), stamp), 0)
from #temp t;
In earlier versions, I would use outer apply:
select t.*,
isnull(datediff(day, t2.stamp, t.stamp), 0)
from #temp t outer apply
(select top 1 t2.*
from #temp t2
where t2.id = t.id and t2.stamp < t.stamp
order by t2.stamp desc
) t2;
try a cte,
DECLARE #Temp TABLE (ID int, Stamp datetime)
INSERT INTO #Temp (ID, Stamp) VALUES (1, '2016-08-17')
INSERT INTO #Temp (ID, Stamp) VALUES (1, GETDATE())
INSERT INTO #Temp (ID, Stamp) VALUES (1, GETDATE()+0.5)
INSERT INTO #Temp (ID, Stamp) VALUES (2, '2016-08-16')
INSERT INTO #Temp (ID, Stamp) VALUES (2, GETDATE())
INSERT INTO #Temp (ID, Stamp) VALUES (2, GETDATE()+3)
;WITH CTE AS
(
SELECT ROW_NUMBER() OVER (ORDER BY ID) as RowNo, ID, Stamp
FROM #Temp
)
SELECT temp2.ID, temp2.Stamp, ISNULL(DATEDIFF(day, temp3.Stamp, temp2.Stamp),0) as DateDiff
FROM CTE as temp2
LEFT JOIN CTE as temp3 on temp2.ID = temp3.ID
AND temp2.RowNo = temp3.RowNo + 1
Related
The question is, how do I write a statement that would return all customers with NO Orders TODAY using sql join?
Tables : tbl_member ,tbl_order
tbl_member consist of id,name,
tbl_order consist of id, date, foodOrdered
If you left join, the select where the table on the right is nulkl, it limits to the rows that DO NOT meet the join condition:
select t1.*
from tbl_member t1
left join tbl_member t2
on t1.id = t2.id -- assuming that t2.id relates to t1.id
and t2.date = current_date() -- today's date in mysql
where t2.id is null
Assuming tbl_order date is a datetime (it probably should be) for sql server you could use something like:
declare #tbl_member table
(
id int,
fullname varchar(50)
)
declare #tbl_order table
(
id int,
orderdate datetime,
foodOrdered varchar(50)
)
INSERT INTO #tbl_member VALUES (1, 'George Washington')
INSERT INTO #tbl_member VALUES (2, 'Abraham Lincoln')
INSERT INTO #tbl_member VALUES (3, 'Mickey Mouse')
INSERT INTO #tbl_member VALUES (3, 'Donald Duck')
INSERT INTO #tbl_order VALUES (1, '2017-07-01 13:00:00', 'Fish and Chips')
INSERT INTO #tbl_order VALUES (2, '2017-07-03 08:00:00', 'Full English')
INSERT INTO #tbl_order VALUES (3, '2017-07-25 08:00:00', 'Veggie Burger')
INSERT INTO #tbl_order VALUES (3, '2017-07-25 12:00:00', 'Bangers and Mash')
SELECT id, fullname FROM #tbl_member WHERE id NOT IN
(SELECT id FROM #tbl_order
WHERE CAST(orderDate as date) = CAST(GETDATE() as Date))
It helps if you specify what flavour database you are using as the syntax is often subtly different.
Please consider the following table...
DECLARE #tmp TABLE
(
ID int,
userID int,
testID int,
someDate datetime
)
...containing the following values:
INSERT INTO #tmp (ID, userID, testID, someDate) VALUES (1, 1, 50, '2010-10-01')
INSERT INTO #tmp (ID, userID, testID, someDate) VALUES (2, 1, 50, '2010-11-01')
INSERT INTO #tmp (ID, userID, testID, someDate) VALUES (3, 1, 50, '2010-12-01')
INSERT INTO #tmp (ID, userID, testID, someDate) VALUES (4, 2, 20, '2010-10-01')
INSERT INTO #tmp (ID, userID, testID, someDate) VALUES (5, 2, 30, '2010-11-01')
INSERT INTO #tmp (ID, userID, testID, someDate) VALUES (6, 2, 20, '2012-11-01')
I need to retrieve the maximum date for each userID/testID combination of values, and also the accompanying ID value. The results should be:
ID userID testID someDate
-------------------------------
3 1 50 2010-12-01
5 2 30 2010-11-01
6 2 20 2012-11-01
When I try the following query, the result set becomes incorrect and all rows are shown. I cannot omit ID from the GROUP BY clause because it causes and error. Can anyone help please? It seems long-winded to join the table to itself to get these values.
SELECT ID, userID, testID, MAX(someDate)
FROM #tmp
GROUP BY testId,userID,ID;
http://www.sqlfiddle.com/#!6/d41d8/5219
Please try:
select * from (
select
*,
ROW_NUMBER() over (partition by userID, testID order by SomeDate desc) Rnum
From #tmp
)x where Rnum=1
I have a table as follows:
DECLARE #tmp TABLE
(
userID int,
testID int,
someDate datetime
)
Within it I store dates along with two ID values, e.g.
INSERT INTO #tmp (userID, testID, someDate) VALUES (1, 50, '2010-10-01')
INSERT INTO #tmp (userID, testID, someDate) VALUES (1, 50, '2010-11-01')
INSERT INTO #tmp (userID, testID, someDate) VALUES (1, 50, '2010-12-01')
INSERT INTO #tmp (userID, testID, someDate) VALUES (2, 20, '2010-10-01')
INSERT INTO #tmp (userID, testID, someDate) VALUES (2, 20, '2010-11-01')
I need to select the latest date per userID/testID combination. So, the result would be
userID testID someDate
1 50 2010-12-01
2 20 2010-11-01
It sounds really easy but I can't figure it out. SQL Fiddle Here.
SELECT userID, testID, MAX(someDate)
FROM #tmp
GROUP BY testId,userID;
fiddle
Try
SELECT t1.* FROM #tmp t1
INNER JOIN (SELECT userId, MAX(someDate) someDate
FROM #tmp
GROUP BY userId) t2
ON t1.userId = t2.userId
AND t1.someDate = t2.someDate
SELECT userId, testId, MAX(someDate)
FROM #tmp
GROUP BY testId, userId
http://www.sqlfiddle.com/#!6/d41d8/5205
I have a table like this:
CREATE TABLE #TEMP(id int, name varchar(100))
INSERT INTO #TEMP VALUES(1, 'John')
INSERT INTO #TEMP VALUES(1, 'Adam')
INSERT INTO #TEMP VALUES(1, 'Robert')
INSERT INTO #TEMP VALUES(1, 'Copper')
INSERT INTO #TEMP VALUES(1, 'Jumbo')
INSERT INTO #TEMP VALUES(2, 'Jill')
INSERT INTO #TEMP VALUES(2, 'Rocky')
INSERT INTO #TEMP VALUES(2, 'Jack')
INSERT INTO #TEMP VALUES(2, 'Lisa')
INSERT INTO #TEMP VALUES(3, 'Amy')
SELECT *
FROM #TEMP
DROP TABLE #TEMP
I am trying to remove all but some records for those that have more than 3 names with the same id. Therefore, I am trying to get something like this:
id name
1 Adam
1 Copper
1 John
2 Jill
2 Jack
2 Lisa
3 Amy
I am not understanding how to write this query. I have gotten to the extent of preserving one record but not a threshold of records:
;WITH FILTER AS
(
SELECT id
FROM #TEMP
GROUP BY id
HAVING COUNT(id) >=3
)
SELECT id, MAX(name)
FROM #TEMP
WHERE id IN (SELECT * FROM FILTER)
GROUP BY id
UNION
SELECT id, name
FROM #TEMP
WHERE id NOT IN (SELECT * FROM FILTER)
Gives me:
1 Robert
2 Rocky
3 Amy
Any suggestions? Oh by the way, I don't care what records are preserved while merging.
You can do it using CTE
CREATE TABLE #TEMP(id int, name varchar(100))
INSERT INTO #TEMP VALUES(1, 'John')
INSERT INTO #TEMP VALUES(1, 'Adam')
INSERT INTO #TEMP VALUES(1, 'Robert')
INSERT INTO #TEMP VALUES(1, 'Copper')
INSERT INTO #TEMP VALUES(1, 'Jumbo')
INSERT INTO #TEMP VALUES(2, 'Jill')
INSERT INTO #TEMP VALUES(2, 'Rocky')
INSERT INTO #TEMP VALUES(2, 'Jack')
INSERT INTO #TEMP VALUES(2, 'Lisa')
INSERT INTO #TEMP VALUES(3, 'Amy')
SELECT *
FROM #TEMP;
WITH CTE(N) AS
(
SELECT ROW_NUMBER() OVER(PARTITION BY id ORDER BY id)
FROM #Temp
)
DELETE CTE WHERE N>3;
SELECT *
FROM #TEMP;
DROP TABLE #TEMP
I will change your select like this (not tested)
select name from #temp group by name having count(id) > 3
then you can implement your query in a delete statement using your select as a where clause
in inner query you can use row_number function over (partition by id)
and then in outer query you have to give condition like below
select id,name from (
SELECT id,name, row_number() over (partition by id order by 1) count_id FROM #test
group by id, name )
where count_id <=3
If i got your question right, you need to get rows when id occurrence 3 or more times
select t1.name,t1.id from tbl1 t1
inner join tbl1 t2 on t1.id = t2.id
group by t1.name, t1.id
having count(t1.id) > 2
I have the following table:
CREATE TABLE #TEMP (id int, name varchar(255), startdate datetime, enddate datetime)
INSERT INTO #TEMP VALUES(1, 'John', '2011-01-11 00:00:00.000','2011-01-11 00:01:10.000')
INSERT INTO #TEMP VALUES(2, 'John', '2011-01-11 00:00:20.000','2011-01-11 00:01:50.000')
INSERT INTO #TEMP VALUES(3, 'John', '2011-01-11 00:01:40.000','2011-01-11 00:01:50.000')
INSERT INTO #TEMP VALUES(4, 'Adam', '2011-01-11 00:00:40.000','2011-01-11 00:01:20.000')
INSERT INTO #TEMP VALUES(5, 'Adam', '2011-01-11 00:00:10.000','2011-01-11 00:01:30.000')
SELECT * FROM #TEMP
DROP TABLE #TEMP
I am trying to merge all records with the same name within a range of 60 seconds to each other to get the following:
John 2011-01-11 00:00:00.000 2011-01-11 00:01:10.000
John 2011-01-11 00:01:40.000 2011-01-11 00:01:50.000
Adam 2011-01-11 00:00:10.000 2011-01-11 00:01:20.000
Any suggestions on how to do this on a table with about 50K records? Currently, I managed to get to this:
SELECT * FROM #TEMP
CREATE TABLE #Merge(id1 int, id2 int)
INSERT INTO #Merge
SELECT id, uuid
FROM
(
SELECT t.id, u.uuid, t.name, t.startdate, t.enddate, u.ustartdate, u.uenddate,
(CASE WHEN (DATEDIFF(second, t.startdate, u.ustartdate) <= 60 AND DATEDIFF(second, t.startdate, u.ustartdate) >= 0) then 1 else 0 END) Flag
FROM #Temp t
INNER JOIN
(SELECT id AS uuid, name, startdate AS ustartdate, enddate AS uenddate
FROM #Temp) u
ON t.name = u.name AND t.startdate != u.ustartdate AND t.id != u.uuid
) w
WHERE Flag = 1
SELECT * FROM #Merge
-- Insert non-mergable records
CREATE TABLE #TEMP2 (id int, name varchar(255), membergroup varchar(255), startdate datetime, enddate datetime)
INSERT INTO #TEMP2
SELECT * FROM #TEMP
WHERE id NOT IN (SELECT id1 FROM #Merge UNION SELECT id2 FROM #Merge)
SELECT * FROM #TEMP2
Of course, I am not sure how to proceed from here. The #Merge table gives me rows that are to be merged. What I did was to insert non-mergable rows first into #Temp2 first.
EDIT:
Updated set of rows, just in case:
INSERT INTO #TEMP VALUES(1, 'John', 'A', '2011-01-11 00:00:00.000','2011-01-11 00:01:10.000')
INSERT INTO #TEMP VALUES(2, 'John', 'A', '2011-01-11 00:00:01.000','2011-01-11 00:01:10.000')
INSERT INTO #TEMP VALUES(3, 'John', 'B', '2011-01-11 00:00:20.000','2011-01-11 00:01:50.000')
INSERT INTO #TEMP VALUES(4, 'John', 'C', '2011-01-11 00:01:40.000','2011-01-11 00:01:50.000')
INSERT INTO #TEMP VALUES(5, 'John', 'C', '2011-01-11 00:01:50.000','2011-01-11 00:02:20.000')
INSERT INTO #TEMP VALUES(6, 'Adam', 'A', '2011-01-11 00:00:40.000','2011-01-11 00:01:20.000')
INSERT INTO #TEMP VALUES(7, 'Adam', 'B', '2011-01-11 00:00:10.000','2011-01-11 00:01:30.000')
INSERT INTO #TEMP VALUES(8, 'Adam', 'B', '2011-01-11 00:03:10.000','2011-01-11 00:04:30.000')
The code below manage's to show both merged rows (rows 1-2,4-5) and unique rows (row 3)
SELECT DISTINCT a.id,a.name,a.startdate,a.enddate
FROM temp a
LEFT JOIN temp b ON a.name = b.name AND a.id < b.id AND DATEDIFF(s,a.startdate,b.startdate)<=60
LEFT JOIN temp c ON c.name = a.name AND c.id < a.id AND DATEDIFF(s,c.startdate,a.startdate)<=60
WHERE (b.id IS NOT NULL OR c.id IS NULL) AND a.id <= COALESCE(c.id,a.id)
Given you haven't said how to use the 60 second interval and your sample code showed only a startdate comparison, here you go
SELECT
*
FROM
#Temp t1
CROSS APPLY
(SELECT TOP 1*
FROM #Temp t2
WHERE t1.name = t2.name AND DATEDIFF(second, t1.startdate, t2.startdate) < 60 AND t1.id < t2.id
ORDER BY id DESC
) t2x
Based on startdate only, row pairs 1/2 and 4/5 make it into the output. Row 3 doesn't so you'll have to explain why you added it.
That is, row id = 3 is not within 60 seconds of row 1 or 2 based on startdate. So it shouldn't be in the output.
This assumes that id and startdate are both increasing.
Edit, after chat:
SELECT
*
FROM
#Temp t1
CROSS APPLY
(SELECT TOP 1 *
FROM #Temp t2
WHERE t1.name = t2.name AND DATEDIFF(second, t1.startdate, t2.startdate) < 60 AND t1.id < t2.id
ORDER BY t2.id DESC
) t2x
UNION ALL
SELECT
t1.*, t1.*
FROM
#Temp t1
WHERE NOT EXISTS
(
SELECT
t1ZZ.id, t2xZZ.id
FROM
#Temp t1ZZ
CROSS APPLY
(SELECT TOP 1 *
FROM #Temp t2ZZ
WHERE t1ZZ.name = t2ZZ.name AND DATEDIFF(second, t1ZZ.startdate, t2ZZ.startdate) < 60 AND t1ZZ.id < t2ZZ.id
ORDER BY t2ZZ.id DESC
) t2xZZ
WHERE
t1.id IN (t1ZZ.id, t2xZZ.id)
)