The question is stated in the title and below is an example of the data
insert into table A values('a','b', {'key':'value'});
And I would like to be able to select this row based on the key-value pair using the WHERE clause. How can I do that?
Use JSON_VALUE:
SELECT t.*
FROM tableA t
WHERE JSON_VALUE(col3, '$.key') LIKE 'some_value'
This assumes that the column which contains the JSON value {'key':'value'} is called col3.
If you are using PostgreSQL then use below query
select * from table_name where column_name->>'key_name' = 'value_name';
Here is solution that's work for me:
column_name->'$.key'
Tested with mysql server 5.7.27
Related
I have written a query like this :
select *
from DATASYNCH_HA_TO_TRG_AUDIT_HIST
where PSX_BATCH_ID IN (select PSX_BATCH_ID
from DATASYNCH_HA_TO_TRG_AUDIT_T
);
Here,when I execute the sub-query alone, it results some values and when I put those values in the place of sub-query the main query also returns some values.But,when I use this whole query ,it does not result any values.How is it possible?
Hope PSX_BATCH_ID column datatype is integer. if it is varchar filed, then trim the value.
SELECT *
FROM DATASYNCH_HA_TO_TRG_AUDIT_HIST
WHERE TRIM(PSX_BATCH_ID) IN
(SELECT TRIM(PSX_BATCH_ID) FROM DATASYNCH_HA_TO_TRG_AUDIT_T);
Instead of using IN query, use JOIN
SELECT *
FROM DATASYNCH_HA_TO_TRG_AUDIT_HIST A
INNER JOIN DATASYNCH_HA_TO_TRG_AUDIT_T B
ON (A.PSX_BATCH_ID = B.PSX_BATCH_ID)
Really Sorry guys,I found out it was actually a database issue.I ran the query recently in a procedure,it is working fine.
I am currently working with a MS SQL database on Windows 2012 Server
I need to query only 1 column from a table that I only have access to read, not make any kind of changes.
Problem is that the name of the column is "Value"
My code is this:
SELECT 'Value' FROM table
If I add
`ORDER BY 'Value'`
The issue is that the query is returning an empty list of results.
Things I've tried already
I tried replacing ' with `"' but this didn't work either.
I also tried writing SELECT * instead of SELECT VALUE
Using the table name in the SELECT or ORDER clauses again didn't help
You are claiming that this query:
SELECT 'Value'
FROM table
ORDER BY 'Value'
Is returning no rows. That's not quite correct. It is returning an error because SQL Server does not allow constant expressions as keys for ORDER BY (or GROUP BY for that matter).
Do not use single quotes. In this case:
SELECT 'Value' as val
FROM table
ORDER BY val;
Or, if value is a column in the table:
SELECT t.Value
FROM table t
ORDER BY t.Value;
Value is not a reserved word in SQL Server, but if it were, you could escape it:
SELECT t.[Value]
FROM table t
ORDER BY t.[Value];
it looks like your table has null values. and because of the order by all null values come first.
try to add filter like this
select Value FROM table
where Value is not null and Value <> ''
order by Value
how to
select name,family from student where name="X"
without its column name.
for example :
select "column1","column2" from student where "column1"="x"
or for example
select "1","2" from student where "1"="x"
"1" is column1
"2" is column2
i dont want to say columns name. i want to say just its number or other....
idont tired from select *. but it just for that i dont know the columns name but i know where they are. my columns name are change every i want to read the file but its data are same, and the data are in the same columns in each file.
Although you can not use field positions specifiers in the SELECT statement, the SQL standard includes the INFORMATION_SCHEMA where the dictionary of your tables is defined. This includes the COLUMNS view where all the fields of all tables are defined. And in this view, there is a field called ORDINAL_POSITION which you can use to assist in this problem.
If you query
SELECT ORDINAL_POSITION, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'TABLE'
ORDER BY ORDINAL_POSITION
then you can obtain the column names for the ordinal positions you want. From there you can prepare a SQL statement.
You could use temp table as:
DECLARE #TB TABLE(Column1 NVARCHAR(50),...)
INSERT #TB
SELECT * FROM student
Then use it:
SELECT Column1 FROM #TB WHERE Column1='aa'
If it's a string you can do this :
Select Column1 + '' From Table
If it's a number you can do this :
Select Column1 + 0 From Table
If it's a datetime you can do this :
Select dateadd(d, 0, Column1) From Table
And similarly for other data types..
No, you can not use the ordinal (numeric) position in the SELECT clause. Only in Order by you can.
however you can make your own column alias...
Select Column1 as [1] From Table
You can use alias:
SELECT name AS [1], family AS [2] FROM student WHERE name="X"
It's just not possible. Unfortunately, they didn't think about table-valued functions, for which information_schema is not available, so good luck with that.
Is there any shorter way to look for multiple matches:
SELECT *
from table
WHERE column LIKE "AAA%"
OR column LIKE "BBB%"
OR column LIKE "CCC%"
This questions applies to PostgreSQL 9.1, but if there is a generic solution it would be even better.
Perhaps using SIMILAR TO would work ?
SELECT * from table WHERE column SIMILAR TO '(AAA|BBB|CCC)%';
Use LIKE ANY(ARRAY['AAA%', 'BBB%', 'CCC%']) as per this cool trick #maniek showed earlier today.
Using array or set comparisons:
create table t (str text);
insert into t values ('AAA'), ('BBB'), ('DDD999YYY'), ('DDD099YYY');
select str from t
where str like any ('{"AAA%", "BBB%", "CCC%"}');
select str from t
where str like any (values('AAA%'), ('BBB%'), ('CCC%'));
It is also possible to do an AND which would not be easy with a regex if it were to match any order:
select str from t
where str like all ('{"%999%", "DDD%"}');
select str from t
where str like all (values('%999%'), ('DDD%'));
You can use regular expression operator (~), separated by (|) as described in Pattern Matching
select column_a from table where column_a ~* 'aaa|bbb|ccc'
Following query helped me. Instead of using LIKE, you can use ~*.
select id, name from hosts where name ~* 'julia|lena|jack';
You might be able to use IN, if you don't actually need wildcards.
SELECT *
from table
WHERE column IN ('AAA', 'BBB', 'CCC')
I am trying to find a way, if possible, to use IN and LIKE together. What I want to accomplish is putting a subquery that pulls up a list of data into an IN statement. The problem is the list of data contains wildcards. Is there any way to do this?
Just something I was curious on.
Example of data in the 2 tables
Parent table
ID Office_Code Employee_Name
1 GG234 Tom
2 GG654 Bill
3 PQ123 Chris
Second table
ID Code_Wildcard
1 GG%
2 PQ%
Clarifying note (via third-party)
Since I'm seeing several responses which don't seems to address what Ziltoid asks, I thought I try clarifying what I think he means.
In SQL, "WHERE col IN (1,2,3)" is roughly the equivalent of "WHERE col = 1 OR col = 2 OR col = 3".
He's looking for something which I'll pseudo-code as
WHERE col IN_LIKE ('A%', 'TH%E', '%C')
which would be roughly the equivalent of
WHERE col LIKE 'A%' OR col LIKE 'TH%E' OR col LIKE '%C'
The Regex answers seem to come closest; the rest seem way off the mark.
I'm not sure which database you're using, but with Oracle you could accomplish something equivalent by aliasing your subquery in the FROM clause rather than using it in an IN clause. Using your example:
select p.*
from
(select code_wildcard
from second
where id = 1) s
join parent p
on p.office_code like s.code_wildcard
In MySQL, use REGEXP:
WHERE field1 REGEXP('(value1)|(value2)|(value3)')
Same in Oracle:
WHERE REGEXP_LIKE(field1, '(value1)|(value2)|(value3)')
Do you mean somethign like:
select * FROM table where column IN (
SELECT column from table where column like '%%'
)
Really this should be written like:
SELECT * FROM table where column like '%%'
Using a sub select query is really beneficial when you have to pull records based on a set of logic that you won't want in the main query.
something like:
SELECT * FROM TableA WHERE TableA_IdColumn IN
(
SELECT TableA_IdColumn FROM TableB WHERE TableA_IDColumn like '%%'
)
update to question:
You can't combine an IN statement with a like statement:
You'll have to do three different like statements to search on the various wildcards.
You could use a LIKE statement to obtain a list of IDs and then use that in the IN statement.
But you can't directly combine IN and LIKE.
Perhaps something like this?
SELECT DISTINCT
my_column
FROM
My_Table T
INNER JOIN My_List_Of_Value V ON
T.my_column LIKE '%' + V.search_value + '%'
In this example I've used a table with the values for simplicity, but you could easily change that to a subquery. If you have a large list (like tens of thousands) then performance might be rough.
select *
from parent
where exists( select *
from second
where office_code like trim( code_wildcard ) );
Trim code_wildcard just in case it has trailing blanks.
You could do the Like part in a subquery perhaps?
Select * From TableA Where X in (Select A from TableB where B Like '%123%')
tsql has the contains statement for a full-text-search enabled table.
CONTAINS(Description, '"sea*" OR "bread*"')
If I'm reading the question correctly, we want all Parent rows that have an Office_code that matches any Code_Wildcard in the "Second" table.
In Oracle, at least, this query achieves that:
SELECT *
FROM parent, second
WHERE office_code LIKE code_wildcard;
Am I missing something?