How to group a specific number of blocks in an xml based on number of tags - xslt-1.0

Question

I have a big xml like below and I would like to group a specific number of tags under one block; The expected input and output below will make my question clearer. Any help is greatly appreciated
The input file is
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<Root>
<ListABC>
<ABC name="name1" class="class1" age="age1" />
<ABC name="name2" class="class2" age="age2" />
<ABC name="name3" class="class3" age="age3" />
<ABC name="name4" class="class4" age="age4" />
<ABC name="name5" class="class5" age="age5" />
</ListABC>
<ListABC>
<EOF tag1="1" tag2="2" tag3="3"/>
</ListABC>
</Root>
I need to create a tag ListABC after every 2 ABC elements and at the same time, the last ListABC which contains EOF element should not be impacted at all. This is how I need the output
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<Root>
<ListABC>
<ABC name="name1" class="class1" age="age1" />
<ABC name="name2" class="class2" age="age2" />
</ListABC>
<ListABC>
<ABC name="name3" class="class3" age="age3" />
<ABC name="name4" class="class4" age="age4" />
</ListABC>
<ListABC>
<ABC name="name5" class="class5" age="age5" />
</ListABC>
<ListABC>
<EOF tag1="1" tag2="2" tag3="3"/>
</ListABC>
</Root>
Thanks much!

Answer 1

How about:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/Root">
<xsl:copy>
<xsl:for-each select="ListABC[not (EOF)]/ABC[position() mod 2 = 1]">
<ListABC>
<xsl:copy-of select=". | following-sibling::ABC[1]"/>
</ListABC>
</xsl:for-each>
<xsl:copy-of select="ListABC[EOF]"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>