Good day,
I have an SQL code that return to me all quantities that I received over time, but I want to display only the latest one
SELECT * FROM
(SELECT DISTINCT
[dbo].[ttcibd001110].[t_cmnf] AS [Manufacturer],
[dbo].[ttcibd001110].[t_item] AS [Item code],
[dbo].[ttcibd001110].[t_dsca] AS [Description],
[dbo].[ttcibd001110].[t_seak] AS [Search key 1],
[dbo].[twhinr110110].[t_trdt] AS [Transaction date],
[dbo].[twhinr110110].[t_cwar] AS [Warehouse],
[dbo].[twhinr110110].[t_qstk] AS [Quantity Inventory Unit]
FROM [dbo].[twhinr110110] LEFT JOIN [dbo].[ttcibd001110]
ON [dbo].[twhinr110110].[t_item]=[dbo].[ttcibd001110].[t_item]
WHERE [dbo].[twhinr110110].[t_koor]='2' AND [dbo].[ttcibd001110].[t_cmnf]='ManufacturerX') AS tabel
WHERE ltrim(tabel.[Item code])='1000045'
Now, from this selection I want to select only the line with the latest Transaction date, but I am stuck.
Can somebody help me in this way?
Thank you!
Change your beginning to
SELECT TOP 1
and after where use
ORDER BY [Transaction date] DESC
Related
I need to make a report for weekly changes.
This is the code for todays amount
SELECT
[Entry No_],
[Customer No_],
[Posting Date],
[Description],
[Currency Code],
Trans_type = case when [Deposit]=1 then 'Deposit'
when [Imprest]=1 then 'Imprest'
else 'Other' end,
A.Amount
FROM Table1
LEFT JOIN
(
SELECT Distinct [Cust_ Ledger Entry No_],
SUM ([Amount EUR]) as 'amount'
FROM Table2
group by [Cust_ Ledger Entry No_]
having
SUM ([Amount EUR]) <> '0'
)A
on [Entry No_] = A.[Cust_ Ledger Entry No_]
Where
A.Amount is not NULL
Code to generate data for previous week is here (adding only where clause):
SELECT
[Entry No_],
[Customer No_],
[Posting Date],
[Description],
[Currency Code],
Trans_type = case when [Deposit]=1 then 'Deposit'
when [Imprest]=1 then 'Imprest'
else 'Other' end,
A.Amount
FROM Table1
LEFT JOIN
(
SELECT Distinct [Cust_ Ledger Entry No_],
SUM ([Amount EUR]) as 'amount'
FROM Table2
where [posting Date] < '2020-11-23'
group by [Cust_ Ledger Entry No_]
having
SUM ([Amount EUR]) <> '0'
)A
on [Entry No_] = A.[Cust_ Ledger Entry No_]
Where
A.Amount is not NULL
It would be enough to union both queries and then export to Excel and make pivot, but problem is that I need results of last 50 weeks. Is there any smart way to avoid union 50 tables and run one simple code to generate weekly report?
Thanks
it might be easier with sample, but I don't know how to paste table here..
Maybe it is true, i dont need union here, and group by would be enough, but it stills sounds difficult for me :)
Ok. Lets say table has such headers: Project | Country | date | amount
The code below returns amount for todays date
Select
Project,
SUM(amount)
From Table
Group by Project
I actually need todays date and also the results of previous weeks (What was the result on November 22 (week 47), November 15 (week 46) and so on.. total 50 weeks from todays date).
Code for previous week amount is here:
Select
Project,
SUM(amount)
From Table
Where Date < '2020.11.23'
Group by Project
So my idea was to create create 50 codes and join the results together, but i am sure it is a better way to do this. Besides i dont want to edit this query every week and add a new date for it.
So any ideas, to make my life easier?
if I have understood your requirement correctly, all you need to do is extract the week from the date e.g.
Select
Project,
datepart(week, date),
SUM(amount)
From Table
Where Date < '2020.11.23'
Group by Project, datepart(week, date)
I am running SQL Server 2008 R2 (RTM).
I have a SQL query that pulls Dates, Products, Customers and Units:
select
[Transaction Date] as Date,
[SKU] as Product,
[Customer Name] as Customer,
sum(Qty) as Units
from dataset
where [Transaction Date] < '2019-03-01' and [Transaction Date] >= '2016-01-01'
group by [Transaction Date], [SKU], [Customer Name]
order by [Transaction Date]
This pulls hundreds of thousands of records and I wanted to determine if a certain transaction was a new order or reorder based on the following logic:
Reorder: That specific Customer has ordered that specific product in the last 6 months
New Order: That specific Customer hasn’t ordered that specific product in the last 6 months
For that I have this formula in Excel that seems to be working:
=IF(COUNTIFS(A$1:A1,">="&DATE(YEAR(A2),MONTH(A2)-6,DAY(A2)),C$1:C1,C2,B$1:B1,B2),"Reorder","New Order")
The formula works when I paste it individually or in a smaller dataset, but when I try to copy paste it to all 500K+ rows, Excel gives up because it loops for each calculation.
This could probably be done in SQL, but I don’t have the knowledge on how to convert this excel formula to SQL, I just started studying it.
You're doing pretty well with the start of your query there. There are three additional functions you're looking to add to your query.
The first thing you'll need is the easiest. GETDATE() simply returns the current date. You'll need that when you're comparing the current date to the transaction date.
The second function is DATEDIFF, which will give you a unit of time between two dates (months, days, years, quarters, etc). Using DATEDIFF, you can say "is this date within the last 6 months". The format for this is pretty easy. It's DATEDIFF(interval, date1, date2).
The thrid function you're looking for is CASE, which allows you to tell SQL to give you one answer if one condition is met, but a different answer if a different condition is met. For your example, you can say "if the difference in days is < 60, return 'Reorder', if not give me 'New Order'".
Putting it all together:
SELECT CASE
WHEN DATEDIFF(MONTH, [Transaction Date], GETDATE()) <= 6
THEN 'Reorder'
ELSE 'New Order'
END as ORDER_TYPE
,[Transaction Date] AS DATE
,[SKU] AS PRODUCT
,[Customer Name] AS CUSTOMER
,Qty AS UNITS
FROM DATASET
For additonal examples on CASE, take a look at this site: https://www.w3schools.com/sql/sql_ref_case.asp
For additional examples on DATEDIFF, take a look here: See the
following webpage for examples and a chance to try it out:
https://www.w3schools.com/sql/func_sqlserver_datediff.asp
SELECT CASE
WHEN Datediff(day, [transaction date], Getdate()) <= 180 THEN 'reorder'
ELSE 'Neworder'
END,
[transaction date] AS Date,
[sku] AS Product,
[customer name] AS Customer,
qty AS Units
FROM datase
If I understand correctly, you want to peak at the previous date and make a comparison. This suggests lag():
select (case when lag([Transaction Date]) over (partition by SKU, [Customer Name] order by [Transaction Date]) >
dateadd(month, -6, [Transaction Date])
then 'Reorder'
else 'New Order'
end) as Order_Type
[Transaction Date] as Date,
[SKU] as Product,
[Customer Name] as Customer,
sum(Qty) as Units
from dataset d
group by [Transaction Date], [SKU], [Customer Name];
EDIT:
In SQL Server 2008, you can emulate the LAG() using OUTER APPLY:
select (case when dprev.[Transaction Date] >
dateadd(month, -6, d.[Transaction Date])
then 'Reorder'
else 'New Order'
end) as Order_Type
d.[Transaction Date] as Date,
d.[SKU] as Product,
d.[Customer Name] as Customer,
sum(d.Qty) as Units
from dataset d outer apply
(select top (1) dprev.*
from dataset dprev
where dprev.SKU = d.SKU and
dprev.[Customer Name] = d.[Customer Name] and
dprev.[Transaction Date] < d.[Transaction Date]
order by dprev.[Transaction Date] desc
) dprev
group by d.[Transaction Date], d.[SKU], d.[Customer Name];
I'm using Advantage Database Server by Sybase. I need to elimiate duplicate addbatch's from my report, but having trouble pulling up just distinct records. Any idea what I am missing?
here is what I am using
SELECT DISTINCT
SI.[addbatch] as [Batch#],
SI.[current account #] as [Account],
SI.[status date] as [Status Date],
SI.[SKU] as [SKU],
AC.[email address] as [Email]
FROM salesinventory SI, accounts AC
WHERE AC.[account #]=SI.[current account #] and [Status Date] > '6/1/2015'
I still get duplicate addbatch's though. I'm not sure where I am going wrong! Thanks in advance! Wasn't even sure how to google this question!
The problem is that you need to check uniqueness of a single column and that's not actually what your code is performing. Try this
SELECT *
FROM (SELECT SI.[addbatch] as [Batch#],
SI.[current account #] as [Account],
SI.[status date] as [Status Date],
ETC,
ROW_NUMBER() OVER (PARTITION BY [Batch#]) AS RowNumber
FROM salesinventory SI, accounts AC
WHERE AC.[account #]=SI.[current account #] and [Status Date] > '6/1/2015') as rec
WHERE rec.RowNumber = 1
-- The following code is generic to de-duplicate records, modify to suit your need.
select x.[Well_Name] as nameX
, x.[TestDate] as dateX
from (
SELECT count(*) as dup
,[Well_Name]
,[TestDate]enter code here
FROM [dbo].[WellTests]
group by [TestDate] ,[Well_Name] ) x
where dup > 1
If you want to have unique batch numbers in your result, you have to GROUP BY the batch field only.
Something like this should work:
SELECT
SI.[addbatch] as [Batch#],
MIN(SI.[current account #]) as [Account],
MIN(SI.[status date]) as [Status Date],
MIN(SI.[SKU]) as [SKU],
MIN(AC.[email address]) as [Email]
FROM salesinventory SI, accounts AC
WHERE AC.[account #]=SI.[current account #] and [Status Date] > '6/1/2015'
GROUP BY
SI.[addbatch]
You didn't say how you want to aggregate the other columns, just replace MIN with something that makes more sense for you, like SUM or COUNT, etc.
There is a topic about grouping in the documentation.
PS: SELECT DISTINCT is (basically) just a shorter way to GROUP BY on all columns without any aggregation.
I have this SQL line
SELECT No_, sum(Quantity) AS Sold, [Shipment Date] AS SoldDate, [Item Category Code],
Description, [Description 2] FROM dbo.[3S Company A_S$Sales Invoice Line]
WHERE [Item Category Code] = '5104' GROUP BY No_
But i got this error for my script.
Column 'dbo.3S Company A_S$Sales Invoice Line.Shipment Date' is invalid in the select
list because it is not contained in either an aggregate function or the GROUP BY clause.
Can anyone help me with why?
If you use GROUP BY in your query, only the columns used in your grouping clause and any aggregate functions like SUM are allowed in the select list. In your case, you specify GROUP BY No_, so that is the only column you can select without using an aggregate function.
If you want to get the remaining columns, you could select No_ and the other aggregate columns in a subquery and then select other columns by matching the No_ column with the corresponding column in subquery.
The error means you have a column which may have multiple values when grouped and SQL doesn't know which value to select in the column
You cn use e.g. min() to select min value. Like this
SELECT No_,
sum(Quantity) AS Sold,
min([Shipment Date]) AS SoldDate,
min([Item Category Code]),
min(Description),
min([Description 2])
FROM dbo.[3S Company A_S$Sales Invoice Line]
WHERE [Item Category Code] = '5104'
GROUP BY No_
Or read about aggregate functions to choose proper one
BWT it's not MySQL but rather MS SQL (MySQL does not complain the column usages)
TRY THIS
SELECT No_, sum(Quantity) AS Sold, [Shipment Date] AS SoldDate, [Item Category Code],
Description, [Description 2] FROM dbo.[3S Company A_S$Sales Invoice Line]
WHERE [Item Category Code] = '5104' GROUP BY No_,[Shipment Date],
[ItemCategoryCode], Description,[Description 2]
IN SQL IF YOU USE ANY COLUMN NAME IN SELECT CLAUSE EXCEPT AGGREGRATE FUNCTION THEN YOU NEED TO ADD ALL THE COLUMNS IN GROUP BY ALSO OTHER WISE IT WILL SHOW EXCEPTION
IF YOU WANT SUM ONLY BY NO_ Column then you have to write a subquery with the aggregarte function and join it to you other columns as folows
SELECT No_ ,quant.sold, [Shipment Date] AS SoldDate, [Item Category Code],
Description, [Description 2] FROM dbo.[3S Company A_S$Sales Invoice Line] INV,
(SELECT No_, sum(Quantity) AS Sold from dbo.[3S Company A_S$Sales Invoice Line] where
WHERE [Item Category Code] = '5104' group by No_) quant
WHERE [Item Category Code] = '5104' and
inv.no_=quant.no_
The columns (Other than aggregate functions) that exists in select clause should also present in the group by clause. This is what the error message states.
Select Productid, Sum(Saled) from product
Group by ProductId
In the above example, ProductId is in the group by clause. So that query is valid. If you introduce one more column that should also be in the group by clause to avoid error.
You have to put columns not using the aggregate functions in your GROUP BY :
GROUP BY
No_
, [Shipment Date]
, [Item Category Code]
, Description
, [Description 2]
I have a query, where I need the MIN of a DateTime field and then I need the value of a corresponding field in the same row.
Now, I have something like this, however I cannot get Price field without putting it also in an aggregate clause, which is not what I want.
SELECT MIN([Registration Time]), Price FROM MyData WHERE [Product Series] = 'XXXXX'
I need the MIN of the Registration Time field and then I just want the corresponding Price field for that row, however how do I show that?
I do also need my WHERE clause as shown.
I'm sure I've overlooked something really obvious. Using SQL Server 2008
If you want just one record with [Registration Time], Price, it'd be as simple as this:
select top 1 [Registration Time], Price
from MyData
where [Product Series] = 'XXXXX'
order by [Registration Time]
If you want minimum [Registration Time] and corresponding Price for all [Product Series], then there's a few approaches, for example, using row_number() function:
with cte as (
select
[Registration Time], Price,
row_number() over(partition by [Product Series] order by [Registration Time]) as rn
from MyData
)
select
[Registration Time], Price, [Product Series]
where rn = 1