Running Distinct Count with a Partition - sql

Question

I'd like a running distinct count with a partition by year for the following data:
DROP TABLE IF EXISTS #FACT;
CREATE TABLE #FACT("Year" INT,"Month" INT, "Acc" varchar(5));
INSERT INTO #FACT
values
(2015, 1, 'A'),
(2015, 1, 'B'),
(2015, 1, 'B'),
(2015, 1, 'C'),
(2015, 2, 'D'),
(2015, 2, 'E'),
(2015, 3, 'E'),
(2016, 1, 'A'),
(2016, 1, 'A'),
(2016, 2, 'B'),
(2016, 2, 'C');
SELECT * FROM #FACT;
The following returns the correct answer but is there a more concise way that is also performant?
WITH
dnsRnk AS
(
SELECT
"Year"
, "Month"
, DenseR = DENSE_RANK() OVER(PARTITION BY "Year", "Month" ORDER BY "Acc")
FROM #FACT
),
mxPerMth AS
(
SELECT
"Year"
, "Month"
, RunningTotal = MAX(DenseR)
FROM dnsRnk
GROUP BY
"Year"
, "Month"
)
SELECT
"Year"
, "Month"
, X = SUM(RunningTotal) OVER (PARTITION BY "Year" ORDER BY "Month")
FROM mxPerMth
ORDER BY
"Year"
, "Month";
The above returns the following - the answer should also return exactly the same table:

Answer 1

If you want a running count of distinct accounts:
SELECT f.*,
sum(case when seqnum = 1 then 1 else 0 end) over (partition by year order by month) as cume_distinct_acc
FROM (
SELECT
f.*
,row_number() over (partition by account order by year, month) as seqnum
FROM #fact f
) f;
This counts each account during the first month when it appears.
EDIT:
Oops. The above doesn't aggregate by year and month and then start over for each year. Here is the correct solution:
SELECT
year
,month
,sum( sum(case when seqnum = 1 then 1 else 0 end)
) over (partition by year order by month) as cume_distinct_acc
FROM (
SELECT
f.*
,row_number() over (partition by account, year order by month) as seqnum
FROM #fact f
) f
group by year, month
order by year, month;
And, SQL Fiddle isn't working but the following is an example:
with FACT as (
SELECT yyyy, mm, account
FROM (values
(2015, 1, 'A'),
(2015, 1, 'B'),
(2015, 1, 'B'),
(2015, 1, 'C'),
(2015, 2, 'D'),
(2015, 2, 'E'),
(2015, 3, 'E'),
(2016, 1, 'A'),
(2016, 1, 'A'),
(2016, 2, 'B'),
(2016, 2, 'C')) v(yyyy, mm, account)
)
SELECT
yyyy
,mm
,sum(sum(case when seqnum = 1 then 1 else 0 end)) over (partition by yyyy order by mm) as cume_distinct_acc
FROM (
SELECT
f.*
,row_number() over (partition by account, yyyy order by mm) as seqnum
FROM fact f
) f
group by yyyy, mm
order by yyyy, mm;

Answer 2

Demo Here:
;with cte as (
SELECT yearr, monthh, count(distinct acc) as cnt
FROM #fact
GROUP BY yearr, monthh
)
SELECT
yearr
,monthh
,sum(cnt) over (Partition by yearr order by yearr, monthh rows unbounded preceding ) as x
FROM cte