I am writing a VBA code that goes through a defined matrix size and filling cells randomly within its limits.
I got the code here from a user on stackoverflow, but after testing it I realized that it does not fit for avoiding duplicate filling, and for instance when filling 5 cells, I could only see 4 cells filled, meaning that the random filling worked on a previously filled cell.
This is the code I'm working with:
Dim lRandom As Long
Dim sCells As String
Dim sRandom As String
Dim rMolecules As Range
Dim i As Integer, j As Integer
Dim lArea As Long
lArea = 400 '20x20
'Populate string of cells that make up the container so they can be chosen at random
For i = 1 To 20
For j = 1 To 20
sCells = sCells & "|" & Cells(i, j).Address
Next j
Next i
sCells = sCells & "|"
'Color the molecules at random
For i = 1 To WorksheetFunction.Min(5, lArea)
Randomize
lRandom = Int(Rnd() * 400) + 1
sRandom = Split(sCells, "|")(lRandom)
Select Case (i = 1)
Case True: Set rMolecules = Range(sRandom)
Case Else: Set rMolecules = Union(rMolecules, Range(Split(sCells, "|")(lRandom)))
End Select
sCells = Replace(sCells, "|" & sRandom & "|", "|")
lArea = lArea - 1
Next i
rMolecules.Interior.ColorIndex = 5
Using this same exact code which works perfectly, WHAT can I insert and WHERE do I do that so that the code would check if a cell is previously already filled with a string or a color?
I feel as though this code I'm looking for should be right before
rMolecules.Interior.ColorIndex = 5
But I'm not sure what to type.
EDIT
From the comments I realized that I should be more specific.
I am trying to randomly fill cells with the blue color (.ColorIndex = 5), but what I need to check first is if the randomizing hadn't marked a cell twice, so that for instance in this case, if I want to mark 5 different cells, it marks only 4 of them because of a duplicate and thus fills only 4 cells with the blue color. I need to avoid that and make it choose another cell to mark/fill.
I'd appreciate your help.
Keep the cells you use in a Collection and remove them as you fill the random cells:
Sub FillRandomCells(targetRange As Range, numberOfCells As Long)
' populate collection of unique cells
Dim c As Range
Dim targetCells As New Collection
' make sure arguments make sense
If numberOfCells > targetRange.Cells.Count Then
Err.Raise vbObjectError, "FillRandomCells()", _
"Number of cells to be changed can not exceed number of cells in range"
End If
For Each c In targetRange.Cells
targetCells.Add c
Next
' now pick random 5
Dim i As Long, randomIndex As Long
Dim upperbound As Long
Dim lowerbound As Long
For i = 1 To numberOfCells
lowerbound = 1 ' collections start with 1
upperbound = targetCells.Count ' changes as we are removing cells we used
randomIndex = Int((upperbound - lowerbound + 1) * Rnd + lowerbound)
Set c = targetCells(randomIndex)
targetCells.Remove randomIndex ' remove so we don't use it again!
c.Interior.Color = 5 ' do what you need to do here
Next
End Sub
Sub testFillRandomCells()
FillRandomCells ActiveSheet.[a1:t20], 5
FillRandomCells ActiveSheet.[b25:f30], 3
End Sub
EDIT: Changed to make the target range and number of changed cells configurable as arguments to a function. Also added error checking (always do that!).
Why not build a list of random numbers and place in a Scripting.Dictionary, one can use the Dictionary's Exist method to detect duplicates, loop through until you have enough then you can enter your colouring code confident that you have a unique list.
Related
I am creating a third party add in for my CAD program that has a sub in it that goes through a drawing and finds all the parts lists (BOMS), if any items in the parts list are shared between the BOM (1 part being used in 2 weldments for example) then it changes the item number of the second instance to be that of the first instance. It does this by comparing full file names between the two values. When they match change the number to that of the matcher. I have got this to work but it runs a little slow because for a 100 item BOM each item is compared to 100 and thus that takes a little longer then I would like (about 60seconds to run). After thinking about it I realized I did not need to compare each item to all the items, I just needed to compare until it found a duplicate and then exit the search loop and go to the next value. Example being Item 1 does not need to compare to the rest of the 99 values because even if it does have a match in position 100 I do not want to change item 1s number to that of item 100. I want to change item 100 to that of 1(ie change the duplpicate to that of the first encountered double). For my code however I am having trouble exiting the comparison for loops which is causing me trouble. An example of the trouble is this:
I have 3 BOMs, each one shares Part X, and is numbered 1 in BOM 1, 4 in BOM 2, and 7 in BOM 3. when I run my button because I cannot get it to leave the comparison loop once it finds it first match all the Part X's ended up getting item number 7 from BOM 3 because it is the last instance. (I can get this to do what I want by stepping through my for loops backwards and thus everything ends up as the top most occurrence, but I would like to get my exit fors working because it saves me on unnecessary comparisons)
How do I go about breaking out of the nested for loops using an if conditional?
Here is my current code:
Public Sub MatchingNumberR1()
Debug.Print ThisApplication.Caption
'define active document as drawing doc. Will produce an error if its not a drawing doc
Dim oDrawDoc As DrawingDocument
Set oDrawDoc = ThisApplication.ActiveDocument
'Store all the sheets of drawing
Dim oSheets As Sheets
Set oSheets = oDrawDoc.Sheets
Dim oSheet As Sheet
'Loop through all the sheets
For Each oSheet In oSheets
Dim oPartsLists As PartsLists
Set oPartsLists = oSheet.PartsLists
'Loop through all the part lists on that sheet
Dim oPartList As PartsList
'For every parts list on the sheet
For Each oPartList In oPartsLists
For i3 = 1 To oPartList.PartsListRows.Count
'Store the Item number and file referenced in that row to compare
oItem = FindItem(oPartList)
oDescription = FindDescription(oPartList)
oDescripCheck = oPartList.PartsListRows.Item(i3).Item(oDescription).Value
oNumCheck = oPartList.PartsListRows.Item(i3).Item(oItem).Value
'Check to see if the BOM item is a virtual component if it is do not try and get the reference part
If oPartList.PartsListRows.Item(i3).ReferencedFiles.Count = 0 Then
oRefPart = " "
End If
'Check to see if the BOM item is a virtual component if it is try and get the reference part
If oPartList.PartsListRows.Item(i3).ReferencedFiles.Count > 0 Then
oRefPart = oPartList.PartsListRows.Item(i3).ReferencedFiles.Item(1).FullFileName
End If
MsgBox (" We are comparing " & oRefPart)
'''''Create a comparison loop to go through the drawing that checks the oRefPart against other BOM items and see if there is a match.'''''
'Store all the sheets of drawing
Dim oSheets2 As Sheets
Set oSheets2 = oDrawDoc.Sheets
Dim oSheet2 As Sheet
'For every sheet in the drawing
For Each oSheet2 In oSheets2
'Get all the parts list on a single sheet
Dim oPartsLists2 As PartsLists
Set oPartsLists2 = oSheet2.PartsLists
Dim oPartList2 As PartsList
'For every parts list on the sheet
For Each oPartList2 In oPartsLists2
oItem2 = FindItem(oPartList2)
oDescription2 = FindDescription(oPartList2)
'Go through all the rows of the part list
For i6 = 1 To oPartList2.PartsListRows.Count
'Check to see if the part is a not a virtual component, if not, get the relevent comparison values
If oPartList2.PartsListRows.Item(i6).ReferencedFiles.Count > 0 Then
oNumCheck2 = oPartList2.PartsListRows.Item(i6).Item(oItem2).Value
oRefPart2 = oPartList2.PartsListRows.Item(i6).ReferencedFiles.Item(1).FullFileName
'Compare the file names, if they match change the part list item number for the original to that of the match
If oRefPart = oRefPart2 Then
oPartList.PartsListRows.Item(i3).Item(1).Value = oNumCheck2
''''''''This is where I want it to exit the loop and grab the next original value'''''''
End If
'For virtual components get the following comparison values
ElseIf oPartList2.PartsListRows.Item(i6).ReferencedFiles.Count = 0 Then
oNumCheck2 = oPartList2.PartsListRows.Item(i6).Item(oItem2).Value
oDescripCheck2 = oPartList2.PartsListRows.Item(i6).Item(oDescription2).Value
'Compare the descriptions and if they match change the part list item number for the original to that of the match
If oDescripCheck = oDescripCheck2 Then
oPartList.PartsListRows.Item(i3).Item(1).Value = oNumCheck2
''''''''This is where I want it to exit the loop and grab the next original value'''''''
End If
Else
''''''''This is where if no matches were found I want it to continue going through the comparison loop'''''''
End If
Next
Next
Next
Next
Next
Next
'MsgBox ("Matching Numbers has been finished")
End Sub
For escape from nested for loop you can use GoTo and specify where.
Sub GoToTest()
Dim a, b, c As Integer
For a = 0 To 1000 Step 100
For b = 0 To 100 Step 10
For c = 0 To 10
Debug.Print vbTab & b + c
If b + c = 12 Then
GoTo nextValueForA
End If
Next
Next
nextValueForA:
Debug.Print a + b + c
Next
End Sub
Here are a few examples that demonstrate (1) breaking out of (exiting) a loop and (2) finding the values in arrays.
The intersection of 2 arrays example can be modified to meet your need to "Create a comparison loop to go through the drawing that checks the oRefPart against other BOM items and see if there is a match." Note, you may find multiple matches between 2 arrays.
Option Explicit
Option Base 0
' Example - break out of loop when condition met.
Public Sub ExitLoopExample()
Dim i As Integer, j As Integer
' let's loop 101 times
For i = 0 To 100:
j = i * 2
'Print the current loop number to the Immediate window
Debug.Print i, j
' Let's decide to break out of the loop is some
' condition is met. In this example, we exit
' the loop if j>=10. However, any condition can
' be used.
If j >= 10 Then Exit For
Next i
End Sub
' Example - break out of inner loop when condition met.
Public Sub ExitLoopExample2()
Dim i As Integer, j As Integer
For i = 1 To 5:
For j = 1 To 5
Debug.Print i, j
' if j >= 2 then, exit the inner loop.
If j >= 2 Then Exit For
Next j
Next i
End Sub
Public Sub FindItemInArrayExample():
' Find variable n in array arr.
Dim intToFind As Integer
Dim arrToSearch As Variant
Dim x, y
intToFind = 4
arrToSearch = Array(1, 2, 3, 4, 5, 6, 7, 8, 9)
x = FindItemInArray(FindMe:=intToFind, _
ArrayToSearch:=arrToSearch)
If IsEmpty(x) Then
Debug.Print intToFind; "not found in arrToSearch"
Else
Debug.Print "found "; x
End If
intToFind = 12
y = FindItemInArray(FindMe:=intToFind, _
ArrayToSearch:=arrToSearch)
If IsEmpty(y) Then
Debug.Print intToFind; "not found in arrToSearch"
Else
Debug.Print "found "; y
End If
End Sub
Public Function FindItemInArray(FindMe, ArrayToSearch As Variant):
Dim i As Integer
For i = LBound(ArrayToSearch) To UBound(ArrayToSearch)
If FindMe = ArrayToSearch(i) Then
FindItemInArray = ArrayToSearch(i)
Exit For
End If
Next i
End Function
' Create a comparison loop to go through the drawing that checks
' the oRefPart against other BOM items and see if there is a match.
Public Sub ArrayIntersectionExample():
Dim exampleArray1 As Variant, exampleArray2 As Variant
Dim arrIntersect As Variant
Dim i As Integer
' Create two sample arrays to compare
exampleArray1 = Array(1, 2, 3, 4, 5, 6, 7)
exampleArray2 = Array(2, 4, 6, 8, 10, 12, 14, 16)
' Call our ArrayIntersect function (defined below)
arrIntersect = ArrayIntersect(exampleArray1, exampleArray2)
' Print the results to the Immediate window
For i = LBound(arrIntersect) To UBound(arrIntersect)
Debug.Print "match " & i + 1, arrIntersect(i)
Next i
End Sub
Public Function ArrayIntersect(arr1 As Variant, arr2 As Variant) As Variant:
' Find items that exist in both arr1 and arr2 (intersection).
' Return the intersection as an array (Variant).
Dim arrOut() As Variant
Dim matchIndex As Long
Dim i As Long, j As Long
' no matches yet
matchIndex = -1
' begin looping through arr1
For i = LBound(arr1) To UBound(arr1)
' sub-loop for arr2 for each item in arr1
For j = LBound(arr2) To UBound(arr2)
' check for match
If arr1(i) = arr2(j) Then
' we found an item in both arrays
' increment match counter, which we'll
' use to size our output array
matchIndex = matchIndex + 1
' resize our output array to fit the
' new match
ReDim Preserve arrOut(matchIndex)
' now store the new match our output array
arrOut(matchIndex) = arr1(i)
End If
Next j
Next i
' Have the function return the output array.
ArrayIntersect = arrOut
End Function
I've got a series of .csv files that I'm importing, which contain color information I need to apply to the imported data. The color column is colon-delimited, and the data is pipe-delimited:
:::::65535::|ADAM 14-22TGH|CHERRY|twu|Diesel Fuel (RIG)|Fuel||
::::14994616:::|MARCO 41-12G|CRYSTAL|HVA|Diesel Fuel (RIG)|Rig Fuel|gal us|
:::65535:65535:65535:65535:|MARCO 41-12G|CRYSTAL|||||
The excel sheet contains defined colors for various data states (missing data, wrong data, too high, too low, etc.), so I loop through the imported data building a cell union, which I eventually apply colorization to:
Dim ds As Worksheet
Dim i As Long, j As Long, k As Long
Dim iUsedCol As Long, iUsedRow As Long, clrRequired As Long, color as Long
Dim rngRequired As Range
Dim colorMap As Variant
Dim colors() As String
clrRequired = CLng(GetSetting("Failed Required Field Check"))
' Get the values of the color column
iusedRow = ds.UsedRange.Rows.Count
colorMap = Range(ds.Cells(1, 1), Cells(iUsedRow, 1)).Value
' Delete the color map column
ds.Columns(1).EntireColumn.Delete
' Skip the first two rows
For i = 3 To iusedRow
colors = Split(colorMap(i, 1), ":")
' Offset by one column since we're deleting column 1 after
For j = 2 To UBound(colors) + 1
If colors(j - 1) = "" Then
Else
color = CLng(colors(j - 1))
' Required
If color = clrRequired Then
If rngRequired Is Nothing Then
Set rngRequired = ds.Cells(i, j)
Else
Set rngRequired = Application.Union(rngRequired, ds.Cells(i, j))
End If
End If
End If
Next j
Next i
' Set the colors
If Not rngRequired Is Nothing Then
rngRequired.Interior.color = clrRequired
End If
For simplicity I removed the three other identical checks for the other colors, but this is the pattern. Depending on the data this can be 50 rows or 12000 rows, with varying columns based on what is being checked. I have a report that takes over 20 minutes to run, and when I remove this coloring code it finishes in about 10 seconds.
Additionally here is what I am disabling while running the code:
Calculations
CancelKey
PrintCommunication
ScreenUpdating
Events
StatusBar
Alerts
Try the following code:
Dim ds As Worksheet
Dim i As Long, j As Long, k As Long
Dim iUsedCol As Long, iUsedRow As Long, clrRequired As Long, color As Long
'...
'Set ds = .....
'...
iUsedRow = ds.UsedRange.Rows.Count
' Skip the first two rows
For i = 3 To iUsedRow
colors = Split(ds.Cells(i, 1).Value, ":")
' Offset by one column since we're deleting column 1 after
For j = 2 To UBound(colors) + 1
If colors(j - 1) <> "" Then
ds.Cells(i, j).Interior.color = CLng(colors(j - 1))
End If
Next j
Next i
' Delete the color map column
ds.Columns(1).EntireColumn.Delete
That will process all colours in one loop. (That may be a problem if you are only trying to set certain colours, as defined by your GetSetting calls. If so, you may need to include an If statement to avoid processing if the colour specified isn't one of the colours you want to deal with.)
Let me start by first thanking everyone for the help/intention to help. This community is phenomenal. Second: I'm pretty new at this- before this week I'd learned basic in highschool a decade ago but no other programming experience outside of theory.
Without further ado, here's my issue:
Working on code to find unique variables (I know there's a lot of opensource stuff out there, need to customize this though). When I go to populate the array with the very first string I run into an 'out of range' error at array(1), which I had explicity set (1 TO UB), with UB being the upper bound. I've also double checked the value of UB with msgbox and it's at 15 with my dummy data, so that shouldn't be an issue. I've set the values in the array to empty (have also done so with 0, to no avail).
The error occurs at "ResultArray(1) = CurrentArray(1)"
I'm at a loss; any assistance would be much appreciated.
Option Explicit
Sub unque_values()
'''''''''Variable declaration
'
' CurrentArray() is the array taken from the worksheet
' Comp is the method of comparing inputs (either case sensitive or case insensitive)
' resultarray() is the array that unique values are placed
' UB is the upper bound of Result Array
' resultindex is the variable that keeps track of which cells are unique and which are not
' n is a helped variable that assists with resizing the array
Dim currentarray() As Variant
Dim comp As VbCompareMethod
Dim resultarray() As Variant
Dim UB As Long
Dim resultindex As Long
Dim n As Long
Dim v As Variant
Dim inresults As Boolean
Dim m As Long
' set variables to default values
Let comp = vbTextCompare
Let n = 0
' count the number of cells included in currentarray and populate with values
Let n = ActiveWorkbook.Worksheets("Data").Range("A:A").Count
Let UB = ActiveWorkbook.Worksheets("Data").Range("A" & n).End(xlUp).Row
' dimension arrays
ReDim resultarray(1 To UB)
ReDim currentarray(1 To UB)
' don't forget to change to named ranges
Let currentarray() = Range("f2", "f" & UB)
' populate resultarray with empty values
For n = LBound(resultarray) To UBound(resultarray)
resultarray(n) = Empty
Next n
MsgBox (n)
'check for invalid values in array
For Each v In currentarray
If IsNull(n) = True Then
resultarray = CVErr(xlErrNull)
Exit Sub
End If
Next v
' assumes the first value is unique
resultindex = 1
'''''''''''''''''''''''''''''''''''''''''error is this line''''''''''''''
resultarray(1) = currentarray(1)
' Search for duplicates by cycling through loops
' n = index of value being checked
' m = index of value being checked against
For n = 2 To UB
Let inresults = False
For m = 1 To n
If StrComp(CStr(resultarray(m)), CStr(currentarray(n)), comp) = 0 Then
inresults = True
Exit For
End If
Next m
If inresults = False Then
resultindex = resultindex + 1
resultarray(resultindex) = currentarray(n)
End If
Next n
ReDim Preserve resultarray(1 To resultindex)
End Sub
You've assigned to currentArray a range array. These are always two-dimensional arrays.
You should be able to resolve it with:
resultarray(1) = currentarray(1, 1)
You would need to modify a few more lines in your code to refer to both dimensions of the array.
Alternatively, with the least manipulation to your existing code, transpose the array which turns it to a one-dimensional array. This should require no other changes to your code.
Let currentArray() = Application.Transpose(Range("f2", "f" & UB))
Try with ActiveWorkbook.Worksheets("Data").UsedRange.Columns(1).cells.Count
I'm working in VBA for excel. I have an array called "aKey" (1 by 137,000 strings but exact size is subject to change so making code generic is a neccesity). I need to paste aKey to the first column of a a worksheet. So far i have tried
Range(.Offset(1,0),.Offset(UBound(aKey)+1,0)).Value = aKey
but this seems to only paste 137,000 versions of the first entry of the array.
I have also tried
Range(.Offset(1,0),.Offset(UBound(aKey)+1,0)).Value = WorksheetFunction.Transpose(aKey)
which also didn't work. Through a google search I did find that the Transpose function has a limited pasting size which may very well be the problem there. Does anybody know of a method to avhieve my goal? Thanks
Sub Tester()
Dim a1(), a2(), i As Long, ub As Long
ReDim a1(1 To 1, 1 To 137000)
'load source array ("wrong" shape)
For i = 1 To 137000
a1(1, i) = i
Next i
ub = UBound(a1, 2)
ReDim a2(1 To ub, 1 To 1) 'resize a2 ("right" shape) to match a1
' "flip" the a1 array into a2
For i = 1 To ub
a2(i, 1) = a1(1, i)
Next i
'drop a2 to worksheet
ActiveSheet.Range("a1").Resize(ub, 1).Value = a2
End Sub
Here is an example of creating an array for a single column and placing it in a column:
Sub qwerty()
Dim aKey(1 To 137000, 1 To 1) As Variant
For i = 1 To 137000
aKey(i, 1) = Rnd
Next i
Range("A1:A137000") = aKey
End Sub
I have two bits of code. First a standard copy paste from cell A to cell B
Sheets(sheet_).Cells(x, 1).Copy Destination:=Sheets("Output").Cells(startrow, 2)
I can do almost the same using
Sheets("Output").Cells(startrow, 2) = Sheets(sheet_).Cells(x, 1)
Now this second method is much faster, avoiding copying to clipboard and pasting again. However it does not copy across the formatting as the first method does. The Second version is almost instant to copy 500 lines, while the first method adds about 5 seconds to the time. And the final version could be upwards of 5000 cells.
So my question can the second line be altered to included the cell formatting (mainly font colour) while still staying fast.
Ideally I would like to be able to copy the cell values to a array/list along with the font formatting so I can do further sorting and operations on them before I "paste" them back on to the worksheet..
So my ideal solution would be some thing like
for x = 0 to 5000
array(x) = Sheets(sheet_).Cells(x, 1) 'including formatting
next
for x = 0 to 5000
Sheets("Output").Cells(x, 1)
next
is it possible to use RTF strings in VBA or is that only possible in vb.net, etc.
Answer*
Just to see how my origianl method and new method compar, here are the results or before and after
New code = 65msec
Sheets("Output").Cells(startrow, 2) = Sheets(sheet_).Cells(x, 1)
Sheets("Output").Range("B" & startrow).Font.ColorIndex = Sheets(sheet_).Range("A" & x).Font.ColorIndex 'copy font colour as well
Old code = 1296msec
'Sheets("Output").Cells(startrow, 2).Value = Sheets(sheet_).Cells(x, 1)
'Sheets(sheet_).Cells(x, 1).Copy
'Sheets("Output").Cells(startrow, 2).PasteSpecial (xlPasteFormats)
'Application.CutCopyMode = False
You could have simply used Range("x1").value(11)
something like below:
Sheets("Output").Range("$A$1:$A$500").value(11) = Sheets(sheet_).Range("$A$1:$A$500").value(11)
range has default property "Value" plus value can have 3 optional orguments 10,11,12.
11 is what you need to tansfer both value and formats. It doesn't use clipboard so it is faster.- Durgesh
For me, you can't. But if that suits your needs, you could have speed and formatting by copying the whole range at once, instead of looping:
range("B2:B5002").Copy Destination:=Sheets("Output").Cells(startrow, 2)
And, by the way, you can build a custom range string, like Range("B2:B4, B6, B11:B18")
edit: if your source is "sparse", can't you just format the destination at once when the copy is finished ?
Remember that when you write:
MyArray = Range("A1:A5000")
you are really writing
MyArray = Range("A1:A5000").Value
You can also use names:
MyArray = Names("MyWSTable").RefersToRange.Value
But Value is not the only property of Range. I have used:
MyArray = Range("A1:A5000").NumberFormat
I doubt
MyArray = Range("A1:A5000").Font
would work but I would expect
MyArray = Range("A1:A5000").Font.Bold
to work.
I do not know what formats you want to copy so you will have to try.
However, I must add that when you copy and paste a large range, it is not as much slower than doing it via an array as we all thought.
Post Edit information
Having posted the above I tried by own advice. My experiments with copying Font.Color and Font.Bold to an array have failed.
Of the following statements, the second would fail with a type mismatch:
ValueArray = .Range("A1:T5000").Value
ColourArray = .Range("A1:T5000").Font.Color
ValueArray must be of type variant. I tried both variant and long for ColourArray without success.
I filled ColourArray with values and tried the following statement:
.Range("A1:T5000").Font.Color = ColourArray
The entire range would be coloured according to the first element of ColourArray and then Excel looped consuming about 45% of the processor time until I terminated it with the Task Manager.
There is a time penalty associated with switching between worksheets but recent questions about macro duration have caused everyone to review our belief that working via arrays was substantially quicker.
I constructed an experiment that broadly reflects your requirement. I filled worksheet Time1 with 5000 rows of 20 cells which were selectively formatted as: bold, italic, underline, subscript, bordered, red, green, blue, brown, yellow and gray-80%.
With version 1, I copied every 7th cells from worksheet "Time1" to worksheet "Time2" using copy.
With version 2, I copied every 7th cells from worksheet "Time1" to worksheet "Time2" by copying the value and the colour via an array.
With version 3, I copied every 7th cells from worksheet "Time1" to worksheet "Time2" by copying the formula and the colour via an array.
Version 1 took an average of 12.43 seconds, version 2 took an average of 1.47 seconds while version 3 took an average of 1.83 seconds. Version 1 copied formulae and all formatting, version 2 copied values and colour while version 3 copied formulae and colour. With versions 1 and 2 you could add bold and italic, say, and still have some time in hand. However, I am not sure it would be worth the bother given that copying 21,300 values only takes 12 seconds.
** Code for Version 1**
I do not think this code includes anything that needs an explanation. Respond with a comment if I am wrong and I will fix.
Sub SelectionCopyAndPaste()
Dim ColDestCrnt As Integer
Dim ColSrcCrnt As Integer
Dim NumSelect As Long
Dim RowDestCrnt As Integer
Dim RowSrcCrnt As Integer
Dim StartTime As Single
Application.ScreenUpdating = False
Application.Calculation = xlCalculationManual
NumSelect = 1
ColDestCrnt = 1
RowDestCrnt = 1
With Sheets("Time2")
.Range("A1:T715").EntireRow.Delete
End With
StartTime = Timer
Do While True
ColSrcCrnt = (NumSelect Mod 20) + 1
RowSrcCrnt = (NumSelect - ColSrcCrnt) / 20 + 1
If RowSrcCrnt > 5000 Then
Exit Do
End If
Sheets("Time1").Cells(RowSrcCrnt, ColSrcCrnt).Copy _
Destination:=Sheets("Time2").Cells(RowDestCrnt, ColDestCrnt)
If ColDestCrnt = 20 Then
ColDestCrnt = 1
RowDestCrnt = RowDestCrnt + 1
Else
ColDestCrnt = ColDestCrnt + 1
End If
NumSelect = NumSelect + 7
Loop
Debug.Print Timer - StartTime
' Average 12.43 secs
Application.Calculation = xlCalculationAutomatic
End Sub
** Code for Versions 2 and 3**
The User type definition must be placed before any subroutine in the module. The code works through the source worksheet copying values or formulae and colours to the next element of the array. Once selection has been completed, it copies the collected information to the destination worksheet. This avoids switching between worksheets more than is essential.
Type ValueDtl
Value As String
Colour As Long
End Type
Sub SelectionViaArray()
Dim ColDestCrnt As Integer
Dim ColSrcCrnt As Integer
Dim InxVLCrnt As Integer
Dim InxVLCrntMax As Integer
Dim NumSelect As Long
Dim RowDestCrnt As Integer
Dim RowSrcCrnt As Integer
Dim StartTime As Single
Dim ValueList() As ValueDtl
Application.ScreenUpdating = False
Application.Calculation = xlCalculationManual
' I have sized the array to more than I expect to require because ReDim
' Preserve is expensive. However, I will resize if I fill the array.
' For my experiment I know exactly how many elements I need but that
' might not be true for you.
ReDim ValueList(1 To 25000)
NumSelect = 1
ColDestCrnt = 1
RowDestCrnt = 1
InxVLCrntMax = 0 ' Last used element in ValueList.
With Sheets("Time2")
.Range("A1:T715").EntireRow.Delete
End With
StartTime = Timer
With Sheets("Time1")
Do While True
ColSrcCrnt = (NumSelect Mod 20) + 1
RowSrcCrnt = (NumSelect - ColSrcCrnt) / 20 + 1
If RowSrcCrnt > 5000 Then
Exit Do
End If
InxVLCrntMax = InxVLCrntMax + 1
If InxVLCrntMax > UBound(ValueList) Then
' Resize array if it has been filled
ReDim Preserve ValueList(1 To UBound(ValueList) + 1000)
End If
With .Cells(RowSrcCrnt, ColSrcCrnt)
ValueList(InxVLCrntMax).Value = .Value ' Version 2
ValueList(InxVLCrntMax).Value = .Formula ' Version 3
ValueList(InxVLCrntMax).Colour = .Font.Color
End With
NumSelect = NumSelect + 7
Loop
End With
With Sheets("Time2")
For InxVLCrnt = 1 To InxVLCrntMax
With .Cells(RowDestCrnt, ColDestCrnt)
.Value = ValueList(InxVLCrnt).Value ' Version 2
.Formula = ValueList(InxVLCrnt).Value ' Version 3
.Font.Color = ValueList(InxVLCrnt).Colour
End With
If ColDestCrnt = 20 Then
ColDestCrnt = 1
RowDestCrnt = RowDestCrnt + 1
Else
ColDestCrnt = ColDestCrnt + 1
End If
Next
End With
Debug.Print Timer - StartTime
' Version 2 average 1.47 secs
' Version 3 average 1.83 secs
Application.Calculation = xlCalculationAutomatic
End Sub
Just use the NumberFormat property after the Value property:
In this example the Ranges are defined using variables called ColLetter and SheetRow and this comes from a for-next loop using the integer i, but they might be ordinary defined ranges of course.
TransferSheet.Range(ColLetter & SheetRow).Value = Range(ColLetter & i).Value
TransferSheet.Range(ColLetter & SheetRow).NumberFormat = Range(ColLetter & i).NumberFormat
Does:
Set Sheets("Output").Range("$A$1:$A$500") = Sheets(sheet_).Range("$A$1:$A$500")
...work? (I don't have Excel in front of me, so can't test.)