I am trying to keep the date of some event occurrence. I am having trouble with the way my data has been defined. Instead of showing the actual date the output is showing in 1900 format (like 10/1/1900)
Here is my code:
Dim Arr_rate As Date
Dim D(528) As Date
for i = 3 to 500
Arr_rate = -3.7 * Log(Rnd) '<~~ Arrival interval
D(2) = CDate(1 / 1 / 2006)
D(i) = D(i - 1) + Arr_rate
Worksheets("A").Cells(i, "E").Value = Cdate(D(i))
next i
I tried to have the sdate format in my code but it will not give me the numbers in a proper format (1/1/2006). How can I print in the proper format? I have read some post in stackover flow but was not helpful!
Without quotes 1\1\12006 is just a mathematical expression and not a date.
Sub test()
Dim Arr_rate As Date
Dim D(528) As Date
For i = 3 To 500
Arr_rate = -3.7 * Log(Rnd) '<~~ Arrival interval
'<~~ Using Cdate, then use string. Otherwise 1 / 1 / 2006 evaluates to 4.98504486540379E-04
D(2) = CDate("1 / 1 / 2006")
D(i) = D(i - 1) + Arr_rate
Worksheets("Sheet1").Cells(i, "E").Value = CDate(D(i))
Next i
End Sub
Related
I am trying to auto filter datasets pertaining to a set date array which are stored in the UK format - for ex: 11/04/2019 (April 11, 2019), 15/04/2019 (April 15, 2019). The macro is converting the UK date format to US format, however, it is filtering only those dates which are under 12 and is discarding those above 12. The code I used is shown below:
i = 0
For Each iCell In Control.Range(Cells(5, 3), Cells(99, 3))
If iCell.Value <> "" Then
'CONVERT DATE TO US FORMAT FOR VBA
iDte = Format(iCell, "mm/dd/yyyy")
i = i + 2
ReDim Preserve DteAry(1 To i)
DteAry(i - 1) = 2
DteAry(i) = iDte
End If
Next iCell
[Dates to be filtered][1]
If you store true date values, not text, these carry no format, so:
iDte = iCell
i = i + 2
ReDim Preserve DteAry(1 To i)
DteAry(i - 1) = 2
DteAry(i) = iDte
All,
I have written a little procedure which I would like a for each loop to insert the current month into the first cell "01"/MM/YY and then add one month to the date as it goes through the loop. Using the example below;
K1 = 01/06/2018
L1 = 01/07/2018
M1 = 01/08/2018 etc
The code I am using is below - The error is on the DateAdd line.
Sub test()
Dim dt As date
dt = "01/" & Application.Text(Now(), "MM/YY")
Dim i As Double
i = 1
For Each c In Range("K1:XFD1")
If c.Value = "" Then Exit For
c.Value = dt
'change date to one months time
dt = DateAdd(m, i, dt)
i = i + 1
Next c
End Sub
Any help regarding this would be much appreciated.
Put "m" not m. m would be a variable. "m" is a literal string representing the argument being "month".
dt = DateAdd("m", i, dt)
I have 2 tables, Table 1 and Table 2. Both the tables have one date column each. I am inserting the first Monday of the month on top of the table 1 and Table 2, both. I will fetch date value from each row of the table 2, and if it is more than the value on top of the table, I will insert 0. If the date value in the table 2 is "16/02/2018", and it is not a Monday, I will insert the Monday after it, and the value 1 for that record.How can I proceed with it? Please help.
Dim col_tab2_dat as Date
first_day = DateSerial(Year(Date), Month(Date), 1)
last_day = DateSerial(Year(Date), Month(Date) + 1, 1)
curr_month= Format(first_day, "mmm")
w = Weekday(first_day , vbMonday)
FirstMonday = first_day + IIf(w <> 1, 8 - w, 0)
tab1_last_lin = ws.Columns(2).Find("Total(T1)").Row
tab2_last_lin = ws.Columns(2).Find("Total(T2)").Row
find_tab2 = ws.Columns(1).Find("Table 2").Row
last_lin = Range("B" & Rows.Count).End(xlUp).Row
last_col_tab1 = ws.Cells(tab1_last_lin, ws.Columns.Count).End(xlToLeft).Column
last_col_tab2 = ws.Cells(tab2_last_lin, ws.Columns.Count).End(xlToLeft).Column
last_dat = ws.Cells(2, last_col_tab1 - 1).Value
new_date = last_dat + 7
For i = find_tab2 + 3 to tab2_last_lin
ws.Cells(find_tab2 + 3, 1).Value = col_tab2_dat
If col_tab2_dat > last_dat Then
I am stuck here. What to do next?
End If
Next i
Here is a function that will return the next Monday:
Public Function GetNextMonday(dt As Date) As Date
Do Until Weekday(dt, vbSunday) = 2
dt = DateAdd("d", 1, dt)
Loop
GetNextMonday = dt
End Function
Here's a function that will work for any day of the week.
NextWeekday Function:
Function NextWeekday(FromDate As Date, vbWeekday As VbDayOfWeek) As Date
If Weekday(FromDate) < vbWeekday Then
NextWeekday = FromDate + vbWeekday - Weekday(FromDate)
Else
NextWeekday = FromDate + 7 + vbWeekday - Weekday(FromDate)
End If
End Function
It takes two arguments:
FromDate: The Date of which you are wanting to find the next weekday of. You can simply use "Date" as the argument for today's Date.
vbWeekday: The upcoming day of the week you are wanting the date for.
VBA Example:
Once you've added the above function to your code module, it's easy to get its value:
Sub Main()
Dim NextThursday As Date
NextThursday = NextWeekday(Date, vbThursday)
End Sub
Worksheet Formula Example:
Or you can use it as a worksheet function:
=NextWeekday(Today(), 5)
Worksheet Formula Considerations:
Notice in the worksheet formula we had to remove the vbThursday constant as worksheet functions doesn't have this functionality built-in. However, if you want to still use these constant values in your worksheet, you can create them yourself by using the Name Manager.
Click on the Formulas Tab, then on Define Name
Start creating your constants starting at vbSunday = 1 through vbSaturday = 7 by placing the Constant Name in the Name: field, and the value in the Refers to: field:
And there you have it! You can now refer to them using your named values:
Additional Example Usage:
Comments:
The benefit of using the VbDayOfWeek Type is that you will now gain IntelliSense when using the function:
I have infinite rows with with a single column assigned to define date and time in the following 'General Format' "2016.08.10 06:00:00.066". I am aware that you can't convert every single cell in this column "mm/dd/yyyy hh:mm:ss.000 AM/PM". Therefore I would a single column assigned to "mm/dd/yyyy" and another column assigned to "hh:mm:ss.000 AM/PM". The time is currently 6 hours behind as well so I would like to add 6 hours to it.
I am struggling with this as although the cells are in general or text format the time and date is being displayed as "yyyy.mm.dd hh:mm:ss.000". And can't find a way to split the two in this format
Any help is appreciated
To convert the text to a format that Excel will change to a data/time use this:
=--SUBSTITUTE(SUBSTITUTE(A1,".","/",1),".","/",1)
Then to add 6 hours you would use:
+ TIME(6,0,0)
So to get the date/time is:
=--SUBSTITUTE(SUBSTITUTE(A1,".","/",1),".","/",1) + TIME(6,0,0)
Then simply format the new cell:
mm/dd/yyyy hh:mm:ss.000 AM/PM
You can also split it into the date and time:
Date:
=INT(--SUBSTITUTE(SUBSTITUTE(A1,".","/",1),".","/",1) + TIME(6,0,0))
And format it mm/dd/yyyy
Time:
=MOD(--SUBSTITUTE(SUBSTITUTE(A1,".","/",1),".","/",1) + TIME(6,0,0)),1)
And format it hh:mm:ss.000 AM/PM
use text: =concatenate(text(a1,"MM"),text(a1,"DD"),text(a1,"YYYY") do the same for the other column =concatenate(text(a1,"HH"),text(a1,"MM"),text(a1,"SS")
That's pretty strange that you Excel will round off the milliseconds if you try and use a Date-Time format.
Enum DTValues
ReturnDate
ReturnTime
ReturnDateTime
End Enum
Function getDateTime(yyyymmdd_hh_mm_ss_000 As String, ReturnValue As DTValues) As Single
Dim arr
Dim mSecs As Single
yyyymmdd_hh_mm_ss_000 = Replace(yyyymmdd_hh_mm_ss_000, " ", ".")
yyyymmdd_hh_mm_ss_000 = Replace(yyyymmdd_hh_mm_ss_000, ":", ".")
arr = Split(yyyymmdd_hh_mm_ss_000, ".")
mSecs = arr(6) / 24 / 60 / 60 / 100
Select Case ReturnValue
Case ReturnDate
getDateTime = CSng(DateSerial(arr(0), arr(1), arr(2)))
Case ReturnTime
getDateTime = CSng(TimeSerial(arr(3), arr(4), arr(5))) + mSecs
Case ReturnDateTime
getDateTime = CSng(DateSerial(arr(0), arr(1), arr(2))) + CSng(TimeSerial(arr(3), arr(4), arr(5))) + mSecs
End Select
End Function
Sub ProcessDates()
Const WORKSHEET_NAME = "Sheet1"
Const FIRST_ROW = 2
Const SOURE_COLUMN = 1
Const DATE_COLUMN = 2
Const TIME_COLUMN = 3
Dim Target As Range
Dim arDate, arTime
Dim y As Long
With Worksheets(WORKSHEET_NAME)
Set Target = .Range(.Cells(FIRST_ROW, SOURE_COLUMN), .Cells(Rows.Count, SOURE_COLUMN).End(xlUp))
End With
arDate = Target.Value
arTime = Target.Value
For y = 1 To UBound(arDate)
arDate(y) = getDateTime(arDate(y), ReturnDate)
arTime(y) = getDateTime(arTime(y), ReturnTime)
Next
Target.EntireRow.Columns(DATE_COLUMN).Value = arDate
Target.EntireRow.Columns(TIME_COLUMN).Value = arTime
End Sub
If i have a string containing a date formatted like this:
1402-3
which means Year: 2014, Week: 02 and Day number 3 (monday is 1), how can i convert this to a normal date? (in this case the date above is today; 2014-01-08 - wednesday 8 jan 2014)
Edit: I came up with a function like this, can anyone tell if this is gonna fail or maybe have a better and better coded function/solution?
Private Function StrangeFormattedDateToRegularDate(ByVal StrangeDate As String) As Date
Dim Y As String = "20" & StrangeDate.Substring(0, 2) 'I'll be dead before this fails, haters gonna hate
Dim W As String = StrangeDate.Substring(2, 2)
Dim D As String = StrangeDate.Substring(5, 1)
'Get first day of this year
Dim RefDate As Date = New Date(CInt(Y), 1, 1)
'Get the first day of this week (can be the year before)
Dim daysOffSet As Integer = DayOfWeek.Monday - RefDate.DayOfWeek
RefDate = RefDate.AddDays(daysOffSet)
'Add as many days as the weeks is
RefDate = RefDate.AddDays(7 * CInt(W))
'now the date is the last day of this week (plus one day), remove the days that are ahead, and remove that extra day
Dim daysToRemove = ((7 - CInt(D)) * -1) - 1
RefDate = RefDate.AddDays(daysToRemove)
Return RefDate
End Function
This should be what you're looking for :) This looked challenging so I tried it. Tell me if it works for you or not :)
Function GetDate(InputDate As String) As DateTime
Dim FirstDayofYear As Date = CType("1/1/20" & Mid(InputDate, 1, 2), Date)
Dim LastDayofYear As Date = CType("12/31/20" & Mid(InputDate, 1, 2), Date)
Dim target As Date
For x = 0 To DateDiff(DateInterval.Day, FirstDayofYear, LastDayofYear)
Dim dfi = DateTimeFormatInfo.CurrentInfo
Dim calendar = dfi.Calendar
Dim weekOfyear = calendar.GetWeekOfYear(FirstDayofYear.AddDays(x), dfi.CalendarWeekRule, DayOfWeek.Sunday)
If CInt(Mid(InputDate, 3, 2)) = weekOfyear And CInt(Mid(InputDate, InStr(InputDate, "-") + 1)) = FirstDayofYear.AddDays(x).DayOfWeek Then
target = FirstDayofYear.AddDays(x)
GoTo skip
End If
Next x
skip:
Return target
End Function
This works up to Year 2099. We're probably all dead by then.