Extract hyperlink target from a cell in different workbook - vba

Question

I have a workbook with a custom right click function that extracts cell values from another workbook depending on what the user chooses. It works very well, I just take in the cell's value from the other workbook. Some cells contain hyperlinks though, and I'd like to import the functional hyperlink, not the value of what's shown in the cell. For example, the following image contains a hyperlink in cell (Y216) of sheet BOS of the input workbook.:
This is an image of the cell I want to copy. It is indeed a hyperlink.
?application.Workbooks(2).Sheets("BOS").Range("Y216").value
returns MKB 70-203 Wicket Shear Pin Detection System, which is indeed correct.
But how do I take the hyperlink's destination? I tried several things including
?application.Workbooks(2).Sheets("BOS").Range("Y216").Hyperlinks.count
returns 0 even though you can see in the image that the hyperlink does have an address. In the same fashion the following sub doesn't enter the For Each because it counts 0 hyperlinks.
Sub HLtester()
Dim HL As Hyperlink
For Each HL In Application.Workbooks(2).Sheets("BOS").Range("Y216").Hyperlinks
Debug.Print HL.Address
Next
End Sub
Expected output would be the link's target J:\SOUM\3191.... as shown in image.
EDIT
If it's important the cell's formula is
=LIEN_HYPERTEXTE("J:\SOUM\3191 M - Old Hickory Dam\11_BOS_FT\02_FT_MECT\21-200 Headcover";"21-200 Headcover")
That's the =HYPERLINK function of French Excel, by the way. I guess in last resort I can take the formula and cut off the function parts to retrieve the link part?

Answer 1

Your command works for me, I don't know why you set the range if you want to loop through all the hyperlinks in the sheet -neither why you set as application. workbooks-, anyways, this worked fine for me:
Sub HLtester()
Dim HL As Hyperlink
For Each HL In Sheets("Sheet1").UsedRange.Hyperlinks
Debug.Print HL.Address
Next
End Sub
You may get it as well within range methods with the following
ActiveCell.Hyperlinks(1).Address
You may get more info here
Edit:
Probably the count is wrong because of the "application.workbook", try to declare it as a variable instead of using it all over the code
Sub HLtester()
Dim HL As Hyperlink
Dim WBAnalyzed As Workbook: Set WBAnalyzed = Workbooks("MyWB.xlsm")
For Each HL In WBAnalyzed.Sheets("Sheet1").UsedRange.Hyperlinks
Debug.Print HL.Address
Next
End Sub
Edit 2:
This is the approach suggested when the hyperlink it's given by its formula
Sub test()
On Error Resume Next 'means no formula
x = Evaluate(Range("A1").Formula)
x1 = Sheets("Sheet1").UsedRange.Hyperlinks.Count
Debug.Print x
Debug.Print x1
End Sub
PS: I saved my variable declaration -just cause-, but, you should always have a neat control for them and use option explicit at the beginning of the module.