I want to find duplicate of IRN # entered into a table in database. Here are the unique attributes (logically unique) of the IRN.
ProjectNo, DrawingNo, DrawingRev, SpoolNo, WeldNo
An IRN can have multiple WeldNos meaning the above unique attributes may repeat for one IRN # (with of course one of the 5 attribute values must be unique).
Now I am trying to find out whether there are any duplicate IRNs entered into the system or not? How can I find that through a sql query?
P.S: Due to bad design of database, there is no primary key in the table..
Here is what I have tried so far but this does not give the correct results.
select * from WeldInfo a, WeldInfo b
where a.ProjectNo = b.ProjectNo and
a.DrawingNo = b.DrawingNo and
a.DrawingRev = b.DrawingRev and
a.SpoolNo = b.SpoolNo and
a.WeldNo = b.WeldNo and
a.IrnNo <> b.IrnNo;
But i'm not sure, have i understood your question.
select * from (
select count(*) over ( partition by ProjectNo, DrawingNo, DrawingRev, SpoolNo, WeldN) rr,t.* from WeldInfo t)
where rr > 1;
Explanation.
with tab as (
select 1 as id, 'a' as a , 'b' as b , 'c' as c from dual
union all
select 2 , 'a', 'b', 'c' from dual
union all
select 3 , 'x', 'b', 'c' from dual
union all
select 3 , 'x', 'b', 'c' from dual
union all
select 3 , 'x', 'd', 'c' from dual
)
select t.*
, count(*) over (partition by a,b,c) cnt1
, count(distinct id) over (partition by a,b,c) cnt2
from tab t;
Related
I have a table with two columns
type
TXT
A
this is some text for %1 and %2
B
this is another step for %1
in a translation table I have the signification of the variables %X that looks like
Type
variable
descr
A
%1
#person1#
A
%2
#person2#
B
%1
#manager#
I want to replace in my first table all the variables by the description, so the result has to looks like this:
type
TXT
A
this is some text for #person1# and #person2#
B
this is another step for #manager#
I tried with a replace, but I didn't figured out how to make it work
To replace all variables you could use a recursive algorithm:
with data(typ, txt) as (
select 'A', 'this is some text for %1 and %2' from dual union all
select 'B', 'this is another step for %1' from dual
),
translations(typ, var, description) as (
select 'A', '%1', '#person1#' from dual union all
select 'A', '%2', '#person2#' from dual union all
select 'B', '%1', '#manager#' from dual -- union all
),
rtranslations(typ, var, description,rn) as (
select t.*, row_number() over(partition by typ order by var) as rn
from translations t
),
replacecte(typ, txt, replaced_txt, rn) as (
select d.typ, d.txt, replace(d.txt, t.var, t.description), t.rn
from data d
join rtranslations t on t.typ = d.typ
where t.rn = 1
union all
select r.typ, r.txt, replace(r.replaced_txt, t.var, t.description), t.rn
from replacecte r
join rtranslations t on t.typ = r.typ and t.rn = r.rn + 1
)
select r.typ, r.txt, replaced_txt from replacecte r
where rn = length(txt) - length(replace(txt,'%',''))
;
You can also do it this way without recursion. data and descr are of course just mock ups for your tables, you would not need any WITH clauses. This method uses the steps (1) break up the sentences into words, (2) outer join using those words to your description table, replacing any matches with the description values, (3) reassemble the words back into sentences using LISTAGG.
WITH data AS(SELECT 'A' type, 'this is some text for %1 and %2' txt FROM dual
UNION ALL
SELECT 'B' type, 'this is another step for %1' txt FROM dual
),
descr AS (SELECT 'A' type, '%1' variable,'#person1#' description FROM dual
UNION ALL
SELECT 'A' type, '%2' variable,'#person2#' description FROM dual
UNION ALL
SELECT 'B' type, '%1' variable,'#manager#' description FROM dual)
SELECT type,
LISTAGG(new_word,' ') WITHIN GROUP (ORDER BY seq) txt
FROM (SELECT x.type,
NVL(descr.description,x.word) new_word,
seq
FROM (SELECT type,SUBSTR(' '||txt,INSTR(' '||txt,' ',1,seq)+1,INSTR(' '||txt||' ',' ',1,seq+1) - (INSTR(' '||txt,' ',1,seq)+1)) word,seq
FROM data,
(SELECT ROWNUM seq FROM dual CONNECT BY LEVEL <= 50) x) x,
descr
WHERE x.type = descr.type(+)
AND x.word = descr.variable(+))
GROUP BY type
You could use PIVOT to get the var values from rows into columns (geting all vars in the same row with text) and then do multiple replaces depending on number of var values:
SELECT t.A_TYPE,
CASE WHEN d.V3 Is Not Null THEN REPLACE(REPLACE(REPLACE(t.TXT, '%1', d.V1), '%2', d.V2), '%3', d.V3)
WHEN d.V2 Is Not Null THEN REPLACE(REPLACE(t.TXT, '%1', d.V1), '%2', d.V2)
WHEN d.V1 Is Not Null THEN REPLACE(t.TXT, '%1', d.V1)
ELSE t.TXT
END "TXT"
FROM tbl t
INNER JOIN ( SELECT *
FROM ( Select A_TYPE, VAR, DESCRIPTION FROM descr )
PIVOT ( MAX(DESCRIPTION) For VAR IN('%1' "V1", '%2' "V2", '%' "V3") )
) d ON(d.A_TYPE = t.A_TYPE)
With sample data as:
WITH
tbl (A_TYPE, TXT) AS
(
Select 'A', 'this is some text for %1 and %2' From Dual Union All
Select 'B', 'this is another step for %1' From dual
),
descr (A_TYPE, VAR, DESCRIPTION) AS
(
Select 'A', '%1', '#person1#' From Dual UNION ALL
Select 'A', '%2', '#person2#' From Dual UNION ALL
Select 'B', '%1', '#manager#' From Dual
)
... the result should be
A_TYPE TXT
------ -----------------------------------------------
A this is some text for #person1# and #person2#
B this is another step for #manager#
I have this table
Id
item
type
A
itemA1
X
A
itemA2
X
B
itemA1
X
B
itemA2
X
B
itemA3
Y
And i would like to create new indicator which contains the information about if the Id contains only item of type X or only tpye Y or both like this :
Id
Indicator
A
Only X
B
Both
EDIT: It's possible to have more than 2 kind of types
Thanks in advance for your help
Consider below generic approach
select id,
if(count(distinct type)=1,'Only ','') || string_agg(distinct type) indicator
from your_table
group by id
This will cover if both item are 'Y' as well:
with table_with_sample_data as (
select 'A' as Id ,'itemA1' as item, 'X' as type union all
select 'A', 'itemA2', 'X' union all
select 'B', 'itemA1', 'X' union all
select 'B', 'itemA2', 'X' union all
select 'B', 'itemA3', 'Y' union all
select 'C', 'itemA1', 'Y' union all
select 'C', 'itemA2', 'Y'
)
select id,
if(count(distinct type)=1,'Only '|| max(type), 'Both') indicator from table_with_sample_data
group by id
Say that I have the following table:
with data as (
select 'John' "name", 'A' "tag", 10 "count"
union all select 'John', 'B', 20
union all select 'Jane', 'A', 30
union all select 'Judith', 'A', 40
union all select 'Judith', 'B', 50
union all select 'Judith', 'C', 60
union all select 'Jason', 'D', 70
)
I know there are a number of distinct tag values, namely (A, B, C, D).
I would like to select the unique names that only have the tag A
I can get close by doing
-- wrong!
select
distinct("name")
from data
group by "name"
having count(distinct tag) = 1
however, this will include unique names that only have 1 distinct tag, regardless of what tag is it.
I am using PostgreSQL, although having more generic solutions would be great.
You're almost there - you already have groups with one tag, now just test if it is the tag you want:
select
distinct("name")
from data
group by "name"
having count(distinct tag) = 1 and max(tag)='A'
(Note max could be min as well - SQL just doesn't have single() aggregate function but that's different story.)
You can use not exists here:
select distinct "name"
from data d
where "tag" = 'A'
and not exists (
select * from data d2
where d2."name" = d."name" and d2."tag" != d."tag"
);
This is one possible way of solving it:
select
distinct("name")
from data
where "name" not in (
-- create list of names we want to exclude
select distinct name from data where "tag" != 'A'
)
But I don't know if it's the best or most efficient one.
I have 2 lists which I need to compare. I need to find if at least one element from List A is found in List B. I know IN doesn't work with 2 lists. What are my other options?
Basically something like this :
SELECT
CASE WHEN ('A','B','C') IN ('A','Z','H') THEN 1 ELSE 0 END "FOUND"
FROM DUAL
Would appreciate any help!
You are probably looking for something like this. The WITH clause is there just to simulate your "lists" (whatever you mean by that); they are not really part of the solution. The query you need is just the last three lines (plus the semicolon at the end).
with
first_list (str) as (
select 'A' from dual union all
select 'B' from dual union all
select 'C' from dual
),
second_list(str) as (
select 'A' from dual union all
select 'Z' from dual union all
select 'H' from dual
)
select case when exists (select * from first_list f join second_list s
on f.str = s.str) then 1 else 0 end as found
from dual
;
FOUND
----------
1
In Oracle you can do:
select
count(*) as total_matches
from table(sys.ODCIVarchar2List('A', 'B', 'C')) x,
table(sys.ODCIVarchar2List('A', 'Z', 'H')) y
where x.column_value = y.column_value;
You need to repeat the conditions:
SELECT (CASE WHEN 'A' IN ('A', 'Z', 'H') OR
'B' IN ('A', 'Z', 'H') OR
'C' IN ('A', 'Z', 'H')
THEN 1 ELSE 0
END) as "FOUND"
FROM DUAL
If you are working with collection of String you can try Multiset Operators.
create type coll_of_varchar2 is table of varchar2(4000);
and:
-- check if exits
select * from dual where cardinality (coll_of_varchar2('A','B','C') multiset intersect coll_of_varchar2('A','Z','H')) > 0;
-- list of maching elments
select * from table(coll_of_varchar2('A','B','C') multiset intersect coll_of_varchar2('A','Z','H'));
Additionally:
-- union of elemtns
select * from table(coll_of_varchar2('A','B','C') multiset union distinct coll_of_varchar2('A','Z','H'));
select * from table(coll_of_varchar2('A','B','C') multiset union all coll_of_varchar2('A','Z','H'));
-- eelemnt from col1 not in col2
select * from table(coll_of_varchar2('A','A','B','C') multiset except all coll_of_varchar2('A','Z','H'));
select * from table(coll_of_varchar2('A','A','B','C') multiset except distinct coll_of_varchar2('A','Z','H'));
-- check if col1 is subset col2
select * from dual where coll_of_varchar2('B','A') submultiset coll_of_varchar2('A','Z','H','B');
I am trying to do something very similar but the first list is another field on the same query created with listagg and containing integer numbers like:
LISTAGG(my_first_list,', ') WITHIN GROUP(
ORDER BY
my_id
) my_first_list
and return this with all the other fields that I am already returning
SELECT
CASE WHEN my_first_list IN ('1,2,3') THEN 1 ELSE 0 END "FOUND"
FROM DUAL
I have a script that extracts transactions and their details from a database. But my users complain that the file size being generated is too large, and so they asked for certain transactions to be just summed up/consolidated instead if they are of a certain classification, say Checking Accounts. That means there should only be one line in the result set named "Checking" which contains the sum of all transactions under Checking Accounts. Is there a way for an SQL script to go like:
CASE
WHEN Acct_class = 'Checking'
then sum(tran_amount)
ELSE tran_amount
END
I already have the proper GROUP BY and ORDER BY statements, but I can't seem to get my desired output. There is still more than one "Checking" line in the result set. Any ideas would be very much appreciated.
Try This,
Select sum(tran_amount) From tran_amount Where Acct_class = 'Checking'
You can try to achieve this using UNION ALL
SELECT tran_amount, .... FROM table WHERE NOT Acct_class = 'Checking'
UNION ALL
SELECT SUM(tran_amount), .... FROM table WHERE Acct_class = 'Checking' GROUP BY Acct_class, ...;
hi you can try below sql
select account_class,
case when account_class = 'saving' then listagg(trans_detail, ',') within group (order by emp_name) -- will give you all details transactions
when account_class = 'checking' then to_char(sum(trans_detail)) -- will give you only sum of transactions
end as trans_det from emp group by account_class;
Or, if your desired output is getting either the sum, either the actual column value based on another column value, the solution would be to use an analytical function to get the sum together with the actual value:
select
decode(acct_class, 'Checking', tran_amount_sum, tran_amount)
from (
select
sum(tran_amount) over (partition by acct_class) as tran_amount_sum,
tran_amount,
acct_class
from
YOUR_TABLE
)
You can try something like the following, by keeping single rows for some classes, and aggregating for some others:
with test (id, class, amount) as
(
select 1, 'a' , 100 from dual union all
select 2, 'a' , 100 from dual union all
select 3, 'Checking', 100 from dual union all
select 4, 'Checking', 100 from dual union all
select 5, 'c' , 100 from dual union all
select 6, 'c' , 100 from dual union all
select 7, 'c' , 100 from dual union all
select 8, 'd' , 100 from dual
)
select sum(amount), class
from test
group by case
when class = 'Checking' then null /* aggregates elements of class 'b' */
else id /* keeps elements of other classes not aggregated */
end,
class