My table seems like this;
A B
1 100
1 102
1 105
2 100
2 105
3 100
3 102
I want output like this:
A Count(B)
1 3
1,2 2
1,2,3 3
2 2
3 2
2,3 2
How can i do this?
I try to use listagg but it didn't work.
I suspect that you want to count the number of sets of A that are in the data -- and that your sample results are messed up.
If so:
select grp, count(*)
from (select listagg(a, ',') within group (order by a) as grp
from t
group by b
) b;
This gives you the counts for the full combinations present in the data. The results would be:
1,2,3 1
1,3 1
1,2 1
You can get the original number of rows by doing:
select grp, sum(cnt)
from (select listagg(a, ',') within group (order by a) as grp, count(*) as cnt
from t
group by b
) b;
Oracle Setup:
CREATE TABLE table_name ( A, B ) AS
SELECT 1, 100 FROM DUAL UNION ALL
SELECT 1, 102 FROM DUAL UNION ALL
SELECT 1, 105 FROM DUAL UNION ALL
SELECT 2, 100 FROM DUAL UNION ALL
SELECT 2, 105 FROM DUAL UNION ALL
SELECT 3, 100 FROM DUAL UNION ALL
SELECT 3, 102 FROM DUAL;
Query:
SELECT A,
COUNT(B)
FROM (
SELECT SUBSTR( SYS_CONNECT_BY_PATH( A, ',' ), 2 ) AS A,
B
FROM table_name
CONNECT BY PRIOR B = B
AND PRIOR A + 1 = A
)
GROUP BY A
ORDER BY A;
Output:
A COUNT(B)
----- ----------
1 3
1,2 2
1,2,3 1
2 2
2,3 1
3 2
Related
I need to generate a running number / group sequence inside a select statement for a group of data.
For example
Group Name Sequence
1 a 1
1 b 2
1 c 3
2 d 1
2 e 2
2 f 3
So for each group the sequence should be a running number starting with 1 depending on the order of column"Name".
I already pleayed around with Row_Number() and Level but I couldn't get a solution.
Any idea how to do it?
Analytic functions help.
SQL> with test (cgroup, name) as
2 (select 1, 'a' from dual union all
3 select 1, 'b' from dual union all
4 select 1, 'c' from dual union all
5 select 2, 'd' from dual union all
6 select 2, 'e' from dual union all
7 select 2, 'f' from dual
8 )
9 select cgroup,
10 name,
11 row_number() over (partition by cgroup order by name) sequence
12 from test
13 order by cgroup, name;
CGROUP N SEQUENCE
---------- - ----------
1 a 1
1 b 2
1 c 3
2 d 1
2 e 2
2 f 3
6 rows selected.
SQL>
Try this
SELECT
"Group",
Name,
DENSE_RANK() OVER (PARTITION BY "Group" ORDER BY Name) AS Sequence
FROM table;
This is the table.
Id. Name
1 A
1 A
2 B
2 C
1 A
2 B
2 D
The output should be
Id. Name
1 A
2 B
2 C
2 D
please try
Select distinct id, name
from <name of you table>
order by name
Check this link.
Sample data:
create table demo (id, name) as
select 1, 'A' from dual union all
select 1, 'A' from dual union all
select 2, 'B' from dual union all
select 2, 'C' from dual union all
select 1, 'A' from dual union all
select 2, 'B' from dual union all
select 2, 'D' from dual;
select * from demo order by 1,2;
ID NAME
---------- ------------------------------
1 A
1 A
1 A
2 B
2 B
2 C
2 D
7 rows selected
Delete all but the first row in each (id, name) group:
delete demo where rowid in
( select lag(rowid) over (partition by id, name order by null) from demo );
3 rows deleted
select * from demo order by 1,2
ID N
---------- -
1 A
2 B
2 C
2 D
4 rows selected.
I have the following data (order of records as in the example):
A B
1 10
1 20
1 30
1 40
2 50
2 65
2 75
1 89
1 100
from SQL:
with x as (
select A, B
from (
select 1 as A, 10 as B from dual
union all
select 1 as A, 20 as B from dual
union all
select 1 as A, 30 as B from dual
union all
select 1 as A, 40 as B from dual
union all
select 2 as A, 50 as B from dual
union all
select 2 as A, 65 as B from dual
union all
select 2 as A, 75 as B from dual
union all
select 1 as A, 89 as B from dual
union all
select 1 as A, 100 as B from dual
)
)
select A, B
from X
I want to group the data for each change of value in column A,
I want to get the following result:
A MIN(B) MAX(B)
1 10 40
2 50 75
1 89 100
How to get such a result in the ORACLE 11. I would expect a simple implementation...
This is a gaps and islands problem, solved using row_number analytic function
SELECT a,
MIN(b),
MAX(b)
FROM (
SELECT x.*,
ROW_NUMBER() OVER(
ORDER BY b
) - ROW_NUMBER() OVER(
PARTITION BY a
ORDER BY b
) AS seq
FROM x
)
GROUP BY a,
seq;
Demo
in need Help with oracle SQL.
I have a table with
from to
F B
B R
R D
E X
X Q
and I need the list
F
B
R
D
E
X
Q
so my problem is the jump from R-->D to E-->X
Edit: It's a big list with from and to, seperatet with a annother column as citerium. Normaly there is every from in the to column, so i used
SELECT from,snr as Nr FROM list where StrAbsNr = 1
union all
SELECT to,snr + 1 as Nr FROM list
to create a ordered list. But there are gaps in some parts, in the example there is D-->E missing
has anybody an idea ?
for your example this work:
WITH ft AS
(SELECT 'f' vfrom, 'b' AS vto FROM dual UNION ALL
SELECT 'b' , 'r' FROM dual UNION ALL
SELECT 'r','d' FROM dual UNION ALL
SELECT 'e','x' FROM dual UNION ALL
SELECT 'x','q' FROM dual )
SELECT a.a, MAX(rn), MIN(ob)
FROM
( SELECT vfrom a , rownum rn, 1 ob FROM ft
UNION ALL
SELECT vto , rownum rn, 2 ob FROM ft
) a
GROUP BY a
ORDER BY MAX(rn), MIN(ob)
A MAX(RN) MIN(OB)
- ---------- ----------
f 1 1
b 2 1
r 3 1
d 3 2
e 4 1
x 5 1
q 5 2
7 rows selected
or analityc func row_number:
SELECT *
FROM
(SELECT a.a,
row_number() over (partition BY a order by rn, ob) rna,
ob,
rn
FROM
( SELECT vfrom a, rownum rn, 1 ob FROM ft
UNION ALL
SELECT vto , rownum rn, 2 ob FROM ft
) a
)
WHERE rna=1
ORDER BY rn,
ob
A RNA OB RN
- ---------- ---------- ----------
f 1 1 1
b 1 2 1
r 1 2 2
d 1 2 3
e 1 1 4
x 1 2 4
q 1 2 5
7 rows selected
select "from" as val from table
union
select to from table
And if you want to keep the order:
select distinct val
from (select "from" as val, rownum, 1 as valOrder from table
union
select to, rownum, 2 as valOrder from table)
order by rownum,valOrder
For example, I have table:
ID | Value
1 hi
1 yo
2 foo
2 bar
2 hehe
3 ha
6 gaga
I want my query to get ID, Value; meanwhile the returned set should be in the order of frequency count of each ID.
I tried the query below but don't know how to get the ID and Value column at the same time:
SELECT COUNT(*) FROM TABLE group by ID order by COUNT(*) desc;
The count number doesn't matter to me, I just need the data to be in such order.
Desire Result:
ID | Value
2 foo
2 bar
2 hehe
1 hi
1 yo
3 ha
6 gaga
As you can see because ID:2 appears most times(3 times), it's first on the list,
then ID:1(2 times) etc.
you can try this -
select id, value, count(*) over (partition by id) freq_count
from
(
select 2 as ID, 'foo' as value
from dual
union all
select 2, 'bar'
from dual
union all
select 2, 'hehe'
from dual
union all
select 1 , 'hi'
from dual
union all
select 1 , 'yo'
from dual
union all
select 3 , 'ha'
from dual
union all
select 6 , 'gaga'
from dual
)
order by 3 desc;
select t.id, t.value
from TABLE t
inner join
(
SELECT id, count(*) as cnt
FROM TABLE
group by ID
)
x on x.id = t.id
order by x.cnt desc
How about something like
SELECT t.ID,
t.Value,
c.Cnt
FROM TABLE t INNER JOIN
(
SELECT ID,
COUNT(*) Cnt
FROM TABLE
GROUP BY ID
) c ON t.ID = c.ID
ORDER BY c.Cnt DESC
SQL Fiddle DEMO
I see the question is already answered, but since the most obvious and most simple solution is missing, I'm posting it anyway. It doesn't use self joins nor subqueries:
SQL> create table t (id,value)
2 as
3 select 1, 'hi' from dual union all
4 select 1, 'yo' from dual union all
5 select 2, 'foo' from dual union all
6 select 2, 'bar' from dual union all
7 select 2, 'hehe' from dual union all
8 select 3, 'ha' from dual union all
9 select 6, 'gaga' from dual
10 /
Table created.
SQL> select id
2 , value
3 from t
4 order by count(*) over (partition by id) desc
5 /
ID VALU
---------- ----
2 bar
2 hehe
2 foo
1 yo
1 hi
6 gaga
3 ha
7 rows selected.