My Goal is to load a monthly-daily tabular presentation of sales data with sum total and other average computation at the bottom,
I have one data result set with one column that is named as 'Day' which corresponds to the days of the month, with automatic datatype of int.
select datepart(day, a.date ) as 'Day'
On my second result set, is the loading of the sum at the bottom, it happens that the word 'Sum' is aligned to the column of Day, and I used Union All TO COMBINE the result set together, expected result set is something to this like
day sales
1 10
2 20
3 30
4 10
5 20
6 30
.
.
.
31 10
Sum 130
What I did is to convert the day value, originally in int to varchar datatype. this is to successfully join columns and it did, the new conflict is the sorting of the number
select * from #SalesDetailed
UNION ALL
select * from #SalesSum
order by location, day
Assuming your union query returns the correct results, just messes up the order, you can use case with isnumeric in the order by clause to manipulate your sort:
SELECT *
FROM
(
SELECT *
FROM #SalesDetailed
UNION ALL
SELECT *
FROM #SalesSum
) u
ORDER BY location,
ISNUMERIC(day) DESC,
CASE WHEN ISNUMERIC(day) = 1 THEN cast(day as int) end
The isnumeric will return 1 when day is a number and 0 when it's not.
Try this
select Day, Sum(Col) as Sales
from #SalesDetailed
Group by Day With Rollup
Edit (Working Sample) :
select
CASE WHEN Day IS NULL THEN 'SUM' ELSE STR(Day) END as Days,
Sum(Sales) from
(
Select 1 as Day , 10 as Sales UNION ALL
Select 2 as Day , 20 as Sales
) A
Group by Day With Rollup
EDIT 2:
select CASE WHEN Day IS NULL THEN 'SUM' ELSE STR(Day) END as Days,
Sum(Sales) as Sales
from #SalesDetailed
Group by Day With Rollup
Related
Hi I am trying to calculate the average of previous 4 Tuesdays. I have daily sales data and I am trying to calculate what the average for previous 4 weeks were for the same weekday.
Attached is a snapshot of how my dataset looks like
Now for March 6, I would like to know what is the average for the previous 4 weeks were, (namely Feb 6, Feb 13, Feb 20 and Feb 27). This value needs to be assigned to Monthly Average column
I am using a PostGres DB.
Thanks
You can use window functions:
select t.*,
avg(dailycount) over (partition by seller_name, day
order by date
rows between 3 preceding and current row
) as avg_4_weeks
from t
where day = 'Tuesday';
This assumes that "previous 4 weeks" is the current date plus the previous three weeks. If it starts the week before, only the windowing clause needs to change:
select t.*,
avg(dailycount) over (partition by seller_name, day
order by date
rows between 4 preceding and 1 preceding
) as avg_4_weeks
from t
where day = 'Tuesday';
I decided to post my answer also, for anyone else searching. My answer will allow you to put in any date and get the average for the previous 4 weeks ( current day + previous 3 weeks matching the day).
SQL Fiddle
PostgreSQL 9.3 Schema Setup:
CREATE TABLE sales (sellerName varchar(10), dailyCount int, saleDay date) ;
INSERT INTO sales (sellerName, dailyCount, saleDay)
SELECT 'ABC',10,to_date('2018-03-15','YYYY-MM-DD') UNION ALL /* THIS ONE */
SELECT 'ABC',11,to_date('2018-03-14','YYYY-MM-DD') UNION ALL
SELECT 'ABC',12,to_date('2018-03-12','YYYY-MM-DD') UNION ALL
SELECT 'ABC',13,to_date('2018-03-11','YYYY-MM-DD') UNION ALL
SELECT 'ABC',14,to_date('2018-03-10','YYYY-MM-DD') UNION ALL
SELECT 'ABC',15,to_date('2018-03-09','YYYY-MM-DD') UNION ALL
SELECT 'ABC',16,to_date('2018-03-08','YYYY-MM-DD') UNION ALL /* THIS ONE */
SELECT 'ABC',17,to_date('2018-03-07','YYYY-MM-DD') UNION ALL
SELECT 'ABC',18,to_date('2018-03-06','YYYY-MM-DD') UNION ALL
SELECT 'ABC',19,to_date('2018-03-05','YYYY-MM-DD') UNION ALL
SELECT 'ABC',20,to_date('2018-03-04','YYYY-MM-DD') UNION ALL
SELECT 'ABC',21,to_date('2018-03-03','YYYY-MM-DD') UNION ALL
SELECT 'ABC',22,to_date('2018-03-02','YYYY-MM-DD') UNION ALL
SELECT 'ABC',23,to_date('2018-03-01','YYYY-MM-DD') UNION ALL /* THIS ONE */
SELECT 'ABC',24,to_date('2018-02-28','YYYY-MM-DD') UNION ALL
SELECT 'ABC',25,to_date('2018-02-22','YYYY-MM-DD') UNION ALL /* THIS ONE */
SELECT 'ABC',26,to_date('2018-02-15','YYYY-MM-DD') UNION ALL
SELECT 'ABC',27,to_date('2018-02-08','YYYY-MM-DD') UNION ALL
SELECT 'ABC',28,to_date('2018-02-01','YYYY-MM-DD')
;
Now For The Query:
WITH theDay AS (
SELECT to_date('2018-03-15','YYYY-MM-DD') AS inDate
)
SELECT AVG(dailyCount) AS totalCount /* 18.5 = (10(3/15)+16(3/8)+23(3/1)+25(2/22))/4 */
FROM sales
CROSS JOIN theDay
WHERE extract(dow from saleDay) = extract(dow from theDay.inDate)
AND saleDay <= theDay.inDate
AND saleDay >= theDay.inDate-INTERVAL '3 weeks' /* Since we want to include the entered
day, for the INTERVAL we need 1 less week than we want */
Results:
| totalcount |
|------------|
| 18.5 |
Just wondering if I have two fields in a table named modified date and created date, they either have a date populate or is null. What I would like to know is the best way to count the number of occurrences and group them into a particular range like for example 0-7 days, 8-14 days, 15- 30 days etc.
I was thinking about using
sum(case when modifieddate between getdate()-7 and getdate() then 1 else 0 end)
Is this the best way to do it or is there a better way for each date range specified above. Same would go for the created date
Build a table containing the ranges on the fly, then access your table and count:
select
mindays,
maxdays,
(
select count(*)
from mytable t
where datediff(day, coalesce(t.modifieddate, t.createddate), getdate() )
between ranges.mindays and ranges.maxdays
) as cnt
from
(
select 0 as mindays, 7 as maxdays
union all
select 8 as mindays, 14 as maxdays
union all
select 15 as mindays, 30 as maxdays
) ranges;
Please help me to solve this issue. I have to write a query to get the sum of previous month values and current month values but not able to get the solution.
Here is an image for your reference sum of actual count column values I need the result.
In Oracle you would use the following, could be not completely correct on the case statement:
Select
Site,
sum(value * (case (date_transaction > trunc(sysdate, 'MM') then 1 else 0 end))
volume_current_month
from myTable
where date_transaction between add_months(trunc(sysdate,'MM'),-1) and sysdate
group by site
The previous month is more or less the same using another case statement and ADD_MONTHS.
There are two ways to do this in Tableau :
First Way .
Under Analysis --> Total --> Add All SubTotals .
Second Way :
Create a calc field Total_event as :
WINDOW_SUM(SUM([Event Count]))
Compute the Window_sum as COMPUTE USING EVENT NAME .
If you CAN USE sql AND YOU actually need the previous month and not just all months summed by EventName then you could use LAG. I made the assumption that you are summing by EventName and you only want the current EventName and previous EventNAme
WITH Summed
AS
(
SELECT * ,
LAG(EventCount) OVER (Partition BY EventName ORDER BY trialmonth) as PrevEvent
FROM dbo.Table1
)
SELECT *,
SUM(PrevEvent+EventCount) AS SummedCount
FROM summed
GROUP BY Site
,TrialMonth
,EventName
,EventCount
, PrevEvent
This will produce output like this
Site TrialMonth EventName EventCount PrevEvent SummedCount
12101 2001-10-15 Actual Count 4 NULL NULL
12101 2001-10-15 Projected Count 8 NULL NULL
12101 2001-11-15 Actual Count 6 4 10
12101 2001-11-15 Projected Count 9 8 17
12101 2001-12-15 Actual Count 0 6 6
12101 2001-12-15 Projected Count 10 9 19
http://sqlfiddle.com/#!6/8253f0/2
In tableau -> Create a calculated field ->
// This is for previous month
if [date] >= DATE("01" +"-" + (Month(TODAY())-1) +"-" + YEAR(TODAY()))
and [date] <= DATE("31" +"-" + (Month(TODAY())-1) +"-" + YEAR(TODAY()))
//if the month has 30 or 28 days it will check that there is no 31 and return null
then
sum([Value])
end
//For current month ->
if Month([date]) = Month(TODAY()) then
sum([Value])
end
You will 2 fields returning previous month's sum and current month's sum, You can then use them as you wish.
On sql end you may use
For Previous Month ->
select sum(value) from table_name t where DATE_PART('month',t.date)=DATE_PART('month',TIMESTAMPADD(mm,-1,GETDATE()))
For current Month ->
select sum(value) from table_name t where DATE_PART('month',t.date)=DATE_PART('month',GETDATE()))
I have this query in sql server 2012
select sum(user_number),
sum(media_number),
month_name from (
select TOP 100
count(distinct a.answer_group_guid) as 'user_number',
count(distinct a.media_guid) as 'media_number',
datename(mm,answer_datetime) as 'month_name' ,year(answer_datetime) as 'year'
from
tb_answers as a
left outer join
tb_media as m ON m.user_guid = 'userguid' and m.media_guid=a.media_guid
where
m.user_guid = 'userguid'
group by concat(year(answer_datetime),'',month(answer_datetime)),datename(mm,answer_datetime),year(answer_datetime)
order by year(answer_datetime) desc) as aa
group by month_name,year
order by month_name desc,year desc;
it get this result
Out
user_number media_number month_name
5 1 September
2 1 October
1 1 October
1 1 August
But I need only the first occurence of octuber month
as
user_number media_number month_name
5 1 September
2 1 October
1 1 August
You simply need to use a ranking function like ROW_NUMBER(). Use it to number the records partitioning by month_name, and select only the records which are number 1 in each partition, i.e.
Add this to the select list of your query:
ROW_NUMBER() OVER(PARTITION BY month_name ORDER By XXX) as RowNumber
This will number the rows which have the same month_name with consecutive numbers, starting by 1, and in the order specified by XXX.
NOTE: specify the order in XXX to decide which of the month rows is number one and will be returned by the query
And then, do a select from the resulting query, filtering by RowNumber = 1
SELECT Q.user_number, Q.media_number, Q.month_name
FROM(
-- your query + RowNumber) Q
WHERE Q.RowNumber = 1
NOTE: if you need some ordering in your result, you'll have to move the ORDER BY out of the subselect, and write it beside the WHERE Q.RowNumber=1
I am trying to create a statement in SQL (for a table which holds stock symbols and price on specified date) with avg of 5 day price and avg of 15 days price for each symbol.
Table columns:
symbol
open
high
close
date
The average price is calculated from last 5 days and last 15 days. I tried this for getting 1 symbol:
SELECT avg(close),
avg(`trd_qty`)
FROM (SELECT *
FROM cashmarket
WHERE symbol = 'hdil'
ORDER BY `M_day` desc
LIMIT 0,15 ) s
but I couldn't get the desired list for showing avg values for all symbols.
You can either do it with row numbers as suggested by astander, or you can do it with dates.
This solution will also take the last 15 days if you don't have rows for every day while the row number solution takes the last 15 rows. You have to decide which one works better for you.
EDIT: Replaced AVG, use CASE to avoid division by 0 in case no records are found within the period.
SELECT
CASE WHEN SUM(c.is_5) > 0 THEN SUM( c.close * c.is_5 ) / SUM( c.is_5 )
ELSE 0 END AS close_5,
CASE WHEN SUM(c.is_5) > 0 THEN SUM( c.trd_qty * c.is_5 ) / SUM( c.is_5 )
ELSE 0 END AS trd_qty_5,
CASE WHEN SUM(c.is_15) > 0 THEN SUM( c.close * c.is_15 ) / SUM( c.is_15 )
ELSE 0 END AS close_15,
CASE WHEN SUM(c.is_15) > 0 THEN SUM( c.trd_qty * c.is_15 ) / SUM( c.is_15 )
ELSE 0 END AS trd_qty_15
FROM
(
SELECT
cashmarket.*,
IF( TO_DAYS(NOW()) - TO_DAYS(m_day) < 15, 1, 0) AS is_15,
IF( TO_DAYS(NOW()) - TO_DAYS(m_day) < 5, 1, 0) AS is_5
FROM cashmarket
) c
The query returns the averages of close and trd_qty for the last 5 and the last 15 days. Current date is included, so it's actually today plus the last 4 days (replace < by <= to get current day plus 5 days).
Use:
SELECT DISTINCT
t.symbol,
x.avg_5_close,
y.avg_15_close
FROM CASHMARKET t
LEFT JOIN (SELECT cm_5.symbol,
AVG(cm_5.close) 'avg_5_close',
AVG(cm_5.trd_qty) 'avg_5_qty'
FROM CASHMARKET cm_5
WHERE cm_5.m_date BETWEEN DATE_SUB(NOW(), INTERVAL 5 DAY) AND NOW()
GROUP BY cm_5.symbol) x ON x.symbol = t.symbol
LEFT JOIN (SELECT cm_15.symbol,
AVG(cm_15.close) 'avg_15_close',
AVG(cm_15.trd_qty) 'avg_15_qty'
FROM CASHMARKET cm_15
WHERE cm_15.m_date BETWEEN DATE_SUB(NOW(), INTERVAL 15 DAY) AND NOW()
GROUP BY cm_15.symbol) y ON y.symbol = t.symbol
I'm unclear on what trd_qty is, or how it factors into your equation considering it isn't in your list of columns.
If you want to be able to specify a date rather than the current time, replace the NOW() with #your_date, an applicable variable. And you can change the interval values to suit, in case they should really be 7 and 21.
Have a look at How to number rows in MySQL
You can create the row number per item for the date desc.
What you can do is to retrieve the Rows where the rownumber is between 1 and 15 and then apply the group by avg for the selected data you wish.
trdqty is the quantity traded on particular day.
the days are not in order coz the market operates only on weekdays and there are holidays too so date may not be continuous