I want to compare values of two rows in one table,
The table is like follows.
I want to find record where -F sku greater than normal one
SKU ASIN Price
CT0144 B013VNZNYU 20.99
CT0144-F B013VNZNYU 17.64
Try like this,
DECLARE #table TABLE (
SKU VARCHAR(50)
,ASIN VARCHAR(50)
,Price FLOAT
)
INSERT INTO #table
VALUES (
'CT0144'
,'B013VNZNYU'
,'20.99'
)
,(
'CT0144-F'
,'B013VNZNYU'
,'17.64'
)
,(
'CT0144'
,'B013VNZNU'
,'10.99'
)
,(
'CT0144-F'
,'B013VNZNU'
,'18.64'
)
SELECT *
FROM #table
SELECT A.ASIN
,A.FPrice
,B.Normal
FROM (
SELECT ASIN
,MAX(PRICE) AS FPrice
FROM #table t1
WHERE SKU LIKE '%F'
GROUP BY ASIN
) A
INNER JOIN (
SELECT ASIN
,MAX(PRICE) AS Normal
FROM #table t1
WHERE SKU NOT LIKE '%F'
GROUP BY ASIN
) B ON A.ASIN = B.ASIN
WHERE A.FPrice > B.Normal
Try this
select t1.SKU,t1.ASIN,t1.Price from table as t1 inner join
(
select ASIN, max(price) as price from table group by ASIN
) as t2
on t1.ASIN=t2.ASIN and t1.price=t2.price
where t1.SKU like '%-F'
Related
I have a table that has 3 columns.
create table myTable
(
ID int Primary key,
Detail_ID int references myTable(ID) null, -- reference to self
Master_Value varchar(50) -- references to master table
)
this table has the follow records:
insert into myTable select 100,null,'aaaa'
insert into myTable select 101,100,'aaaa'
insert into myTable select 102,101,'aaaa'
insert into myTable select 103,102,'aaaa' ---> last record
insert into myTable select 200,null,'bbbb'
insert into myTable select 201,200,'bbbb'
insert into myTable select 202,201,'bbbb' ---> last record
the records is saved In the form of relational with ID and Detail_ID columns.
I need to select the last record each Master_Value column. follow output:
lastRecordID Master_Value Path
202 bbbb 200=>201=>202
103 aaaa 100=>101=>102=>103
tips:
The records are not listed in order in the table.
I can not use the max(ID) keyword. beacuse data is not sorted.(may
be the id column updated manually.)
attempts:
I was able to Prepare follow query and is working well:
with Q as
(
select ID ,Detail_ID, Master_Value , 1 RowOrder, CAST(id as varchar(max)) [Path] from myTable where Detail_ID is null
union all
select R.id,R.Detail_ID , r.Master_Value , (q.RowOrder + 1) RowOrder , (q.[Path]+'=>'+CAST(r.id as varchar(max))) [Path] from myTable R inner join Q ON Q.ID=R.Detail_ID --where r.Dom_ID_RowType=1010
)
select * into #q from Q
select Master_Value, MAX(RowOrder) lastRecord into #temp from #Q group by Master_Value
select
q.ID lastRecordID,
q.Master_Value,
q.[Path]
from #temp t
join #q q on q.RowOrder = t.lastRecord
where
q.Master_Value = t.Master_Value
but I need to simple way (one select) and optimal method.
Can anyone help me?
One method uses a correlated subquery to get the last value (which is how I interpreted your question):
select t.*
from mytable t
where not exists (select 1
from mytable t2
where t2.master_value = t.master_value and
t2.id = t.detail_id
);
This returns rows that are not referred to by another row.
For the path, you need a recursive CTE:
with cte as (
select master_value, id as first_id, id as child_id, convert(varchar(max), id) as path, 1 as lev
from mytable t
where detail_id is null
union all
select cte.master_value, cte.first_id, t.id, concat(path, '->', t.id), lev + 1
from cte join
mytable t
on t.detail_id = cte.child_id and t.master_value = cte.master_value
)
select cte.*
from (select cte.*, max(lev) over (partition by master_value) as max_lev
from cte
) cte
where max_lev = lev
Here is a db<>fiddle.
how to find products that are within the same package, given the constraints of physics, it must be present at the same location within the warehouse.
sample schema
CREATE TABLE stock (
id SERIAL,
product_id integer NOT NULL REFERENCES products ( id ),
location_id integer NOT NULL REFERENCES locations ( id ),
package_id integer REFERENCES packages ( id ),
qty integer
);
insert into stock values (1,1,1,1,1) ;
insert into stock values (2,2,1,1,1) ;
insert into stock values (3,3,2,1,1) ;
insert into stock values (4,4,2,1,1) ;
insert into stock values (5,1,2,1,1) ;
insert into stock values (6,1,3,1,1) ;
my query
select package_id from (
select count(*), t2.product_id, t2.package_id
from stock t2
group by t2.product_id, t2.package_id
having count(*)>1
) t3 ;
select t4.* from stock t4,
(
select count(*), t1.package_id, t1.location_id
from stock t1
where t1.package_id in (select package_id from (
select count(*), t2.product_id, t2.package_id
from stock t2
group by t2.product_id, t2.package_id
having count(*)>1
) t3 )
group by t1.package_id, t1.location_id
having count(*)>1) t5
where t5.package_id = t4.package_id and t5.location_id = t4.location_id;
You can use exists:
select s.*
from stock s
where exists (select 1
from stock s2
where s2.package_id = s.package_id and
s2.location_id <> s.location_id
);
If you want just the packages, aggregation is easy:
select package_id
from stock s
group by package_id
having min(location_id) <> max(location_id);
I have a table like this
Date----- ----------Value--------- Group <br>
2017-01-01--------10--------------1--<br>
2017-01-02---------9---------------1--<br>
2017-01-03 --------5---------------2--<br>
2017-01-04 --------4---------------2--<br>
i want to update all value column in the table such that it is set to minimum date's value in that group
like this
Date----- ----------Value--------- Group <br>
2017-01-01--------10--------------1--<br>
2017-01-02---------10---------------1--<br>
2017-01-03 --------5---------------2--<br>
2017-01-04 --------5---------------2--<br>
Here you go, 2 sub-queries, the first to calculate min date per group then join back to original table to get the associated value. Then finally join this to the original table to update all associated groups with that value:
UPDATE M SET M.Value = RESULT.Value FROM MyTable M
INNER JOIN (
SELECT MV.Group, M.Value FROM MyTable M
INNER JOIN (
SELECT MIN(Date) as MinDateValue, Group FROM MyTable
GROUP BY Group
) MV ON MV.MinDateValue = M.Date AND MV.Group = M.Group
) RESULT ON RESULT.Group = M.Group
First get min date and value from sub query.Based on this result update main table
CREATE TABLE #Table(_Date Date,value INT,_Group INT)
INSERT INTO #Table(_Date ,value ,_Group)
SELECT '2017-01-01',10,1 UNION ALL
SELECT '2017-01-02',9,1 UNION ALL
SELECT '2017-01-03',5,2 UNION ALL
SELECT '2017-01-04',4,2
UPDATE #Table SET value = _Output._Value
FROM
(
SELECT A._Date , A._Group , T.value _Value
FROM #Table T
JOIN
(
SELECT MIN(_Date) _Date ,_Group
FROM #Table
GROUP BY _Group
) A ON A._Date = T._Date
) _Output WHERE _Output._Group = #Table._Group
SELECT * FROM #Table
You can also use a CTE.
Query
;with cte as(
select [rn] = row_number() over(
partition by [Group]
order by [Date]
), *
from [your_table_name]
)
update t1
set t1.[Value] = t2.[Value]
from cte t1
join cte t2
on t1.[Group] = t2.[Group]
and t1.[rn] > t2.[rn];
I have this table:
I am trying to pull all records from this table for the max value in the DIST_NO column for every distinct ID in the left most column, but I still want to pull every record for each ID in which there are different Product_ID's as well.
I tried partitioning and using row_number, but I am having trouble at the moment.
Here are my desired results:
This is what my code looks like currently:
select *
from
(SELECT *,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY DIST_NO DESC) RN
FROM Table) V
WHERE RN<=3
you want the max(DIST_NO) for each ID, product_ID?
If so, you can:
SELECT
ID, product_ID, max(DIST_NO)
from table
group by ID, product_ID
If you want the detail rows related to the max row, you just need to join it back to your table:
Select
t.ID, max_dist_no, TRANSaction_ID , LINE_NO , PRODUCT_ID
from
table t inner join
(SELECT
ID, max(DIST_NO) as max_dist_no
from table
group by ID) mx on
t.ID = mx.ID and
t.DIST_NO = max_DIST_NO
Try
SELECT MT.ID
, MT.DIST_NO
, MT.TRANS_ID
, MT.LINE_NO
, MT.PRODUCT_ID
FROM MYTABLE MT
INNER JOIN (
SELECT T.ID, MAX(T.DIST_NO) as DIST_NO FROM MYTABLE T
GROUP BY T.ID
) MAX_MT ON MT.Id = MAX_MT.ID AND MT.DIST_NO = MAX_MT.DIST_NO
The sub query returns each combination of ID and Max value of DIST_NO:
SELECT T.ID, MAX(T.DIST_NO) as DIST_NO FROM MYTABLE T
GROUP BY T.ID
Joining this back to your original table will basically filter your original data-set by only these combinations of values.
Tested on PostgreSQL:
WITH t1 AS (
SELECT id, product_id, MAX(dist_no) AS dist_no
FROM test
GROUP BY 1,2)
SELECT t1.id, t1.dist_no, t2.trans_id, t2.line_no, t1.product_id
FROM test t2, t1
WHERE t1.id=t2.id AND t1.product_id=t2.product_id AND t1.dist_no=t2.dist_no
Use rank() or dense_rank():
select t.*
from (SELECT t.*
RANK() OVER (PARTITION BY ID ORDER BY DIST_NO DESC) as seqnum
FROM Table t
) t
WHERE seqnum = 1;
This is almost a literal translation of your request:
I am trying to pull all records from this table for the max value in
the DIST_NO column for every distinct ID in the left most column.
you can try something like this one :). (But is your result correct? I think there is little mistake in TRANS_ID...)
DECLARE #ExampleTable TABLE
(ID INT,
DIST_NO INT,
TRANS_ID INT,
LINE_NO INT,
PRODUCT_ID INT)
INSERT INTO #ExampleTable
( ID, DIST_NO, TRANS_ID,LINE_NO, PRODUCT_ID )
VALUES ( 102657, 1, 1105365, 1, 109119 ),
( 102657, 1, 1105366, 2, 109114 ),
( 102657, 2, 1105365, 1, 109119 ),
( 102657, 2, 1105366, 2, 109114 ),
( 104371, 1, 1190538, 1, 110981 ),
( 104371, 2, 1190538, 1, 110981 )
;WITH CTE AS ( SELECT DISTINCT ID, LINE_NO
FROM #ExampleTable)
SELECT a.ID,
x.DIST_NO,
x.TRANS_ID,
x.LINE_NO,
x.PRODUCT_ID
FROM CTE a
CROSS APPLY (SELECT TOP 1 *
FROM #ExampleTable f
WHERE a.ID = f.ID AND
a.LINE_NO = f. LINE_NO
ORDER BY DIST_NO DESC) x
I have a question
If I have one row that looks like this
|ordernumber|qty|articlenumber|
| 123125213| 3 |fffff111 |
How can I split this into three rows like this:
|ordernumber|qty|articlenumber|
| 123125213| 1 |fffff111 |
| 123125213| 1 |fffff111 |
| 123125213| 1 |fffff111 |
/J
You can use recursive CTE:
WITH RCTE AS
(
SELECT
ordernumber, qty, articlenumber, qty AS L
FROM Table1
UNION ALL
SELECT
ordernumber, 1, articlenumber, L - 1 AS L
FROM RCTE
WHERE L>0
)
SELECT ordernumber,qty, articlenumber
FROM RCTE WHERE qty = 1
SQLFiddleDEMO
EDIT:
Based on Marek Grzenkowicz's answer and MatBailie's comment, whole new idea:
WITH CTE_Nums AS
(
SELECT MAX(qty) n FROM dbo.Table1
UNION ALL
SELECT n-1 FROM CTE_Nums
WHERE n>1
)
SELECT ordernumber ,
1 AS qty,
articlenumber
FROM dbo.Table1 t1
INNER JOIN CTE_Nums n ON t1.qty >= n.n
Generating number from 1 to max(qty) and join table on it.
SQLFiddle DEMO
Here's a quick hack using an additional table populated with a number of rows suitable for the qty values you are expecting:
-- helper table
CREATE TABLE qty_splitter (qty int)
INSERT INTO qty_splitter VALUES (1)
INSERT INTO qty_splitter VALUES (2)
INSERT INTO qty_splitter VALUES (3)
INSERT INTO qty_splitter VALUES (4)
INSERT INTO qty_splitter VALUES (5)
....
-- query to produce split rows
SELECT t1.ordernumber, 1, t1.articlenumber
FROM table1 t1
INNER JOIN qty_splitter qs on t.qty >= qs.qty
You can do it using CTE
declare #t table (ordername varchar(50), qty int)
insert into #t values ('ord1',5),('ord2',3)
;with cte as
(
select ordername, qty, qty-1 n
from #t
union all
select ordername, qty, n-1
from cte
where n>0
)
select ordername,1
from cte
order by ordername
Also you can use option with master..spt_values system table.
SELECT t.ordernumber, o.qty, t.articlenumber
FROM dbo.SplitTable t CROSS APPLY (
SELECT 1 AS qty
FROM master..spt_values v
WHERE v.TYPE = 'P' AND v.number < t.qty
) o
However, for this purpose is preferable to use its own sequence table
See demo on SQLFiddle