I have a SQL Server table that looks like this:
ID | Club Name | Booking Date | Submission Date
---+-------------+-------------------------+-------------------------
1 | Basketball | 2015-10-21 00:00:00.000 | 9/18/2015 3:23:42 PM
2 | Tennis | 2015-10-14 00:00:00.000 | 9/28/2015 1:50:25 PM
3 | Basketball | 2015-10-06 00:00:00.000 | 9/29/2015 11:08:20 AM
1 | Other | 2015-10-21 00:00:00.000 | 9/29/2015 11:08:39 AM
I want to know how many times each club did a submission less than 15 days from the booking date..
The solution I came up with was adding a new column and running a the datefiff function and storing the value in the new column.. Then just grouping by club name and adding a parameter for > 15 on the new column..
The question I have is: can this be done on the fly with out having to create the new column? how much would that affect performance if its done on the fly?
Yes, this can be done inline, in a query. In a database, you almost never want to store a calculated column, which is what that datediff column would be. Instead, you can do the math in the WHERE clause.
SELECT
*
FROM
myTable
WHERE
DATEDIFF(day, -15, BookingDate) >= SubmissionDate
I wrote that pretty quickly, so the date math might be going in the wrong direction (checking in the future instead of in the past) but playing with the above query should set you on the right path. Just keep in mind that, if this table gets very big, you're going to be doing a TON of DATEDIFFs and that can have a performance impact.
Something like this?
Declare #Table table (Id int,Club_Name varchar(50),Booking_Date datetime,Sumbission_Date datetime)
Insert #Table values
(1,'Basketball','2015-10-21 00:00:00.000','9/18/2015 3:23:42 PM'),
(2,'Tennis ','2015-10-14 00:00:00.000','9/28/2015 1:50:25 PM'),
(3,'Basketball','2015-10-06 00:00:00.000','9/29/2015 11:08:20 AM'),
(1,'Other ','2015-10-21 00:00:00.000','9/29/2015 11:08:39 AM')
Select Club_Name
,Submissions= count(*)
,Early = sum(case when datediff(DD,Sumbission_Date,Booking_Date)<15 then 1 else 0 end)
From #Table
Group By Club_Name
Returns
Club_Name Submissions Early
Basketball 2 1
Other 1 0
Tennis 1 0
Try this.
SELECT ID,
ClubName,
Sum(Value) As Ttle
FROM
(
SELECT ID,
ClubName,
COUNT(*) AS Value
FROM TableName
GROUP BY ID,
ClubName,
RecordDate
HAVING DATEDIFF(D, BookingDate, SubmissionDate) > 15
) Data
GROUP BY ID,
ClubName,
ORDER BY ttle DESC
Related
I have data structured like this:
ID | Enrolment_Date | Appointment1_Date | Appointment2_Date | .... | Appointment150_Date |
112 01/01/2015 01/02/2015 01/03/2018 01/08/2018
113 01/06/2018 01/07/2018 NULL NULL
114 01/04/2018 01/05/2018 01/06/2018 NULL
I need a new variable which counts the number of months between the enrolment_date and the most recent appointment. The challenge is is that all individuals have a different number of appointments.
Update: I agree with the comments that this is poor table design and it needs to be reformatted. Could proposed solutions please include suggested code on how to transform the table?
Since the OP is currently stuck with this bad design, I will point out a temporary solution. As others have suggested, you really must change the structure here. For now, this will suffice:
SELECT '['+ NAME + '],' FROM sys.columns WHERE OBJECT_ID = OBJECT_ID ('TableA') -- find all columns, last one probably max appointment date
SELECT ID,
Enrolment_Date,
CASE WHEN Appointment150_Date IS NOT NULL THEN DATEDIFF (MONTH, Enrolment_Date, Appointment150_Date)
WHEN Appointment149_Date IS NOT NULL THEN DATEDIFF (MONTH, Enrolment_Date, Appointment149_Date)
WHEN Appointment148_Date IS NOT NULL THEN DATEDIFF (MONTH, Enrolment_Date, Appointment148_Date)
WHEN Appointment147_Date IS NOT NULL THEN DATEDIFF (MONTH, Enrolment_Date, Appointment147_Date)
WHEN Appointment146_Date IS NOT NULL THEN DATEDIFF (MONTH, Enrolment_Date, Appointment146_Date)
WHEN Appointment145_Date IS NOT NULL THEN DATEDIFF (MONTH, Enrolment_Date, Appointment145_Date)
WHEN Appointment144_Date IS NOT NULL THEN DATEDIFF (MONTH, Enrolment_Date, Appointment144_Date) -- and so on
END AS NumberOfMonths
FROM TableA
This is a very ugly temporary solution and should be considered as such.
You will need to restructure your data, the given structure is poor database design. Create two separate tables - one called users and one called appointments. The users table contains the user id, enrollment date and any other specific user information. Each row in the appointments table contains the user's unique id and a specific appointment date. Structuring your tables like this will make it easier to write a query to get days/months since last appointment.
For example:
Users Table:
ID, Enrollment_Date
1, 2018-01-01
2, 2018-03-02
3, 2018-05-02
Appointments Table:
ID, Appointment_Date
1, 2018-01-02
1, 2018-02-02
1, 2018-02-10
2, 2018-05-01
You would then be able to write a query to join the two tables together and calculate the difference between the enrollment date and min value of the appointment date.
It is better if you can create two tables.
Enrolment Table (dbo.Enrolments)
ID | EnrolmentDate
1 | 2018-08-30
2 | 2018-08-31
Appointments Table (dbo.Appointments)
ID | EnrolmentID | AppointmentDate
1 | 1 | 2018-09-02
2 | 1 | 2018-09-03
3 | 2 | 2018-09-01
4 | 2 | 2018-09-03
Then you can try something like this.
If you want the count of months from Enrolment Date to the final appointment date then use below query.
SELECT E.ID, E.EnrolmentDate, A.NoOfMonths
FROM dbo.Enrolments E
OUTER APPLY
(
SELECT DATEDIFF(mm, E.EnrolmentDate, MAX(A.AppointmentDate)) AS NoOfMonths
FROM dbo.Appointments A
WHERE A.EnrolmentId = E.ID
) A
And, If you want the count of months from Enrolment Date to the nearest appointment date then use below query.
SELECT E.ID, E.EnrolmentDate, A.NoOfMonths
FROM dbo.Enrolments E
OUTER APPLY
(
SELECT DATEDIFF(mm, E.EnrolmentDate, MIN(A.AppointmentDate)) AS NoOfMonths
FROM dbo.Appointments A
WHERE A.EnrolmentId = E.ID
) A
Try this on sqlfiddle
You have a lousy data structure, as others have noted. You really one a table with one row per appointment. After all, what happens after the 150th appointment?
select t.id, t.Enrolment_Date,
datediff(month, t.Enrolment_Date, m.max_Appointment_Date) as months_diff
from t cross apply
(select max(Appointment_Date) as max_Appointment_Date
from (values (Appointment1_Date),
(Appointment2_Date),
. . .
(Appointment150_Date)
) v(Appointment_Date)
) m;
I have a table of data which stores scans into a building, and this contains well over a million rows of data. I am attempting to add a temporary status column within this query, which counts the scans on a daily basis. For the purpose of this question lets use this as the main data table:
CREATE TABLE DataTable (DataTableID INT IDENTITY(1,1) NOT NULL,
User VARCHAR(50),
EventTime DATETIME)
from this I have narrowed it down to show only the scans for today:
SELECT * FROM DataTable
WHERE CONVERT(DATE,EventTime) = CONVERT(DATE, SYSDATETIME())
It is at this point in which I want to add a status column to this query above. The Status column:
WHEN ODD - will mean that the person is in the building
WHEN EVEN - will mean that the person is not in the building
(This is simply an integer field which starts on 1, and will increment by 1 per scan on that day, PER USER). How would I go about doing this?
I do want to make this a view after so its worth mentioning in case this affects the query syntax
Also its worth mentioning that I cant add a status column to the main table as this would prevent the door access program working, otherwise I would add something in here to control that.
EXAMPLE DATA:
DataTableID User EventTime Status
1 Joe 30/08/2016 09:00:00 1
2 Alan 30/08/2016 08:45:00 1
3 John 30/08/2016 09:02:00 1
4 Steven 30/08/2016 07:30:00 1
5 Joe 30/08/2016 11:00:00 2
6 Mike 30/08/2016 17:30:00 1
7 Joe 30/08/2016 12:00:00 3
You want a simple windowing function for this. Take a look at the query below and let me know if you have any questions. This is ordered by EventTime rather than DataTableID for the windowing, it's then ordered by DataTableID in the final query. This is going to make sure you don't have any issues if your data isn't in the correct order in the table.
Temp table for testing;
CREATE TABLE #DataTable
(DataTableID INT IDENTITY(1,1) NOT NULL,
[User] VARCHAR(50),
EventTime DATETIME)
Fill it with sample data;
INSERT INTO #DataTable
VALUES
('Joe', '2016-08-30 09:00:00')
,('Alan', '2016-08-30 08:45:00')
,('John', '2016-08-30 09:02:00')
,('Steven', '2016-08-30 07:30:00')
,('Joe', '2016-08-30 11:00:00')
,('Mike', '2016-08-30 17:30:00')
,('Joe', '2016-08-30 12:00:00')
Query
SELECT
DataTableID
,[User]
,EventTime
,ROW_NUMBER() OVER(PARTITION BY [User] ORDER BY EventTime) Status
FROM #DataTable
WHERE CONVERT(DATE,EventTime) = CONVERT(DATE, SYSDATETIME())
ORDER BY DataTableID
Output
DataTableID User EventTime Status
1 Joe 2016-08-30 09:00:00.000 1
2 Alan 2016-08-30 08:45:00.000 1
3 John 2016-08-30 09:02:00.000 1
4 Steven 2016-08-30 07:30:00.000 1
5 Joe 2016-08-30 11:00:00.000 2
6 Mike 2016-08-30 17:30:00.000 1
7 Joe 2016-08-30 12:00:00.000 3
Something like:
select *, row_number() over(partition by user, cast(eventtime as date) order by eventtime) as status
from datatable
should do the trick.
However, I'd suggest to create a calculated column as cast(eventtime as date), and compound index on this and user column and the original eventtime column as well for performance reasons.
Hello I'm stuck trying to calculate the difference in time between each transaction for each ID.
The data looks like
Customer_ID | Transaction_Time
1 00:30
1 00:35
1 00:37
1 00:38
2 00:20
2 00:21
2 00:23
I'm trying to get the result to look something like
Customer_ID | Time_diff
1 5
1 2
1 1
2 1
2 2
I would really appreciate any help.
Thanks
Most databases support the LAG() function. However, the date/time functions can depend on the database. Here is an example for SQL Server:
select t.*
from (select t.*,
datediff(second,
lag(transaction_time) over (partition by customer_id order by transaction_time),
transaction_time
) as diff
from t
) t
where diff is not null;
The logic would be similar in most databases, although the function for calculating the time difference varies.
SQL command: get min date and hour from table
TblAzmon:
Acode(pk) | Aname | Adate | Ahour | ADcode_fk
----------------------------------------------------------------------------
1 system 1358/05/05 08:00 2
2 graphic 1389/05/05 08:00 1
3 simulation 1392/05/06 07:30 1
4 math 1389/05/05 09:00 1
I want the output date and time for the manager (ADcode) to get the smallest.
Desired output: [Where ADcode_fk='1']
Acode | Adate | Ahour
----------------------------------
2 1389/05/05 08:00
SQL command:
select Acode,Adate,Ahour from TblAzmon<br>
where Adate in (select min(Adate) from TblAzmon where ADcode_fk='1')
And Ahour in (select min(Ahour) from TblAzmon where ADcode_fk='1')
Output:---------->0 rows - NULL
Tip: All columns are of type text. Apart from the column Acode.
Please write the SQL code.
You could made it like that, using order by and top:
select top 1 *
from tblAzmon a
order by Adate, Ahour
Assuming you mean the earliest combination of date and hour, You can do this with order by and top:
select top 1 *
from tblAzmon a
order by Adate, Ahour
Your SQL doesnt work, because u select the minHour and minDate at once, and since the min(Date) doesnt have the min(Hour) you get 0 rows back.
U need to brake them apart and select them one by one like this. With that u should be able to do it on your own =)
SELECT Acode,Adate,min(Ahour)
FROM (Select Acode,min(Adate),Ahour FROM TblAzmon WHERE ADcode_fk='1') t
WHERE ADcode_fk='1'
I have followed many of the excellent pieces of advise on this site about selecting the MAX from a group of rows.
I have a history file and I only want the top date and comments for each project number. I am creating a derived table in a Boxi universe from this information. It all goes pretty well but if there are two entries for the same day but with different times they are both returned. This duplicates that entry on the subsequent report. Is there some way to make the MAX command go down to the time level of the date field?
Database is SQL Server 2005
-------------Sql used for derived table
Select
Projectno, Comment, CreatedOn
from
ReportHistory
Where
ReportHistory.ItemName=('ProjectCode1')
and
CreatedOn in(Select max(CreatedOn) FROM ReportHistory group by Projectno)
-------------------Example database
Projectno Comment Created on
1 Started 2013-01-04 11:04:00
2 Late 2013-01-06 11:22:00
3 Late 2013-01-07 11:06:00
1 On Time 2013-01-08 11:01:00 *these two both get selected*
1 Late 2013-01-08 12:05:00 *these two both get selected*
3 Back on schedule 2013-01-08 14:20:00
2 Still overdue 2013-01-09 09:01:00
MAX on a DATETIME data type do obviously take the time into account, that is not what's wrong with your query. The problem is that you are not ensuring that the max value for CreatedOn is for the correct ProjectNo. You could use analytical functions for this:
;WITH CTE AS
(
SELECT Projectno,
Comment,
CreatedOn,
ROW_NUMBER() OVER(PARTITION BY ProjectNo ORDER BY CreatedOn DESC) RN
FROM ReportHistory
WHERE ReportHistory.ItemName = 'ProjectCode1'
)
SELECT Projectno, Comment, CreatedOn
FROM CTE
WHERE RN = 1
Query if there are no same projectno with the same date:
SQLFIDDLEExample
SELECT h.Projectno,
h.Comment,
h.[Created on]
FROM ReportHistory h
WHERE h.[Created on] =(Select max(h2.[Created on])
FROM ReportHistory h2
WHERE h2.Projectno = h.Projectno )
ORDER BY h.Projectno
Result:
| PROJECTNO | COMMENT | CREATED ON |
-----------------------------------------------------------------
| 1 | Late | January, 08 2013 12:05:00+0000 |
| 2 | Still overdue | January, 09 2013 09:01:00+0000 |
| 3 | Back on schedule | January, 08 2013 14:20:00+0000 |
Query if there are same projectno with the same date:
SELECT h.Projectno,
MAX(h.Comment) AS Comment,
h.[Created on]
FROM ReportHistory h
WHERE h.[Created on] =(Select max(h2.[Created on])
FROM ReportHistory h2
WHERE h2.Projectno = h.Projectno )
GROUP BY h.Projectno,
h.[Created on]
ORDER BY h.Projectno
I think you receive copies when dates at different projects are identical.
For eg. add in your data (4, 'On Time', '2013-01-08 11:01:00')
Then result will be SQLFiddle
But you need this result SQLFiddle
SELECT *
FROM ReportHistory t
WHERE t.ItemName=('ProjectCode1')
AND EXISTS (
SELECT 1
FROM ReportHistory
WHERE projectNo = t.projectNo
GROUP BY projectNo
HAVING MAX(CreatedOn) = t.CreatedOn
)