Query:
select *
from etm
where emp_id LIKE '009090%'
AND directnumber LIKE '111 123 12345x 67%'
AND cellnumber LIKE '123456789%'
AND phone LIKE '111 123 12345x 67';
database: oracle 11g
Select query doesn't return any records when the LIKE operator has small X character (12345x) in it.
When I replace it with any other character (small/capital) it works ((12345Y)), but replacing it with the small x also does not work.
I cannot modify the query, is there anything can be done at database level while inserting the data?
we are importing data in bulk.
I can't see an issue - here's a test case to demonstrate:
with sample_data as (select '123x 456' str from dual union all
select '123 456' str from dual union all
select '123x' str from dual union all
select 'abcx 93s' str from dual)
select *
from sample_data
where str like '123x%';
STR
--------
123x 456
123x
So, you can see my search has pulled back rows where the str column starts with 123x.
However, if I search for rows starting with 123y then no rows are returned:
with sample_data as (select '123x 456' str from dual union all
select '123 456' str from dual union all
select '123x' str from dual union all
select 'abcx 93s' str from dual)
select *
from sample_data
where str like '123y%';
no rows selected.
since there are no rows where the str column starts with 123y.
Is it a similar case with your data, where there aren't any rows that match all the filter conditions when you have an x in one or more of the like conditions?
I haven't verified this query but it should work.
select *
from etm
where emp_id LIKE '009090%'
AND (directnumber LIKE '111%' or directnumber LIKE '123%' .....)
AND cellnumber LIKE '123456789%'
AND (phone LIKE '111' or phone LIKE '123' .......);
Reference :
https://community.oracle.com/thread/1096523?start=0&tstart=0
Related
I have to test a column of a sql table for invalid values and for NULL.
Valid values are: Any number and the string 'n.v.' (with and without the dots and in every possible combination as listed in my sql command)
So far, I've tried this:
select count(*)
from table1
where column1 is null
or not REGEXP_LIKE(column1, '^[0-9,nv,Nv,nV,NV,n.v,N.v,n.V,N.V]+$');
The regular expression also matches the single character values 'n','N','v','V' (with and without a following dot). This shouldn't be the case, because I only want the exact character combinations as written in the sql command to be matched. I guess the problem has to do with using REGEXP_LIKE. Any ideas?
I guess this regexp will work:
NOT REGEXP_LIKE(column1, '^([0-9]+|n\.?v\.?)$', 'i')
Note that , is not a separator, . means any character, \. means the dot character itself and 'i' flag could be used to ignore case instead of hard coding all combinations of upper and lower case characters.
No need to use regexp (performance will increase by large data) - plain old TRANSLATE is good enough for your validation.
Note that the first translate(column1,'x0123456789','x') remove all numeric charcters from the string, so if you end with nullthe string is OK.
The second translate(lower(column1),'x.','x') removes all dots from the lowered string so you expect the result nv.
To avoid cases as n.....v.... you also limit the string length.
select
column1,
case when
translate(column1,'x0123456789','x') is null or /* numeric string */
translate(lower(column1),'x.','x') = 'nv' and length(column1) <= 4 then 'OK'
end as status
from table1
COLUMN1 STATUS
--------- ------
1010101 OK
1012828n
1012828nv
n.....v....
n.V OK
Test data
create table table1 as
select '1010101' column1 from dual union all -- OK numbers
select '1012828n' from dual union all -- invalid
select '1012828nv' from dual union all -- invalid
select 'n.....v....' from dual union all -- invalid
select 'n.V' from dual; -- OK nv
You can use:
select count(*)
from table1
WHERE TRANSLATE(column1, ' 0123456789', ' ') IS NULL
OR LOWER(column1) IN ('nv', 'n.v', 'nv.', 'n.v.');
Which, for the sample data:
CREATE TABLE table1 (column1) AS
SELECT '12345' FROM DUAL UNION ALL
SELECT 'nv' FROM DUAL UNION ALL
SELECT 'NV' FROM DUAL UNION ALL
SELECT 'nV' FROM DUAL UNION ALL
SELECT 'n.V.' FROM DUAL UNION ALL
SELECT '...................n.V.....................' FROM DUAL UNION ALL
SELECT '..nV' FROM DUAL UNION ALL
SELECT 'n..V' FROM DUAL UNION ALL
SELECT 'nV..' FROM DUAL UNION ALL
SELECT 'xyz' FROM DUAL UNION ALL
SELECT '123nv' FROM DUAL;
Outputs:
COUNT(*)
5
or, if you want any quantity of . then:
select count(*)
from table1
WHERE TRANSLATE(column1, ' 0123456789', ' ') IS NULL
OR REPLACE(LOWER(column1), '.') = 'nv';
Which outputs:
COUNT(*)
9
db<>fiddle here
I'm looking to modify an existing query to use REGEXP_LIKE but falling foul of some syntax I'm not understanding properly. We've currently a CF query into an Oracle DB using the following:
result = QueryExecute("
SELECT paramOne, paramTwo FROM someTable WHERE fieldOne = :PUBLISHER
", {PUBLISHER=publisherId}, {datasource="someDB"});
which works. However, I want to modify the underlying query to be:
result = QueryExecute("
SELECT paramOne, paramTwo FROM someTable WHERE REGEXP_LIKE(fieldOne, '(^|,)(:PUBLISHER)($|,)', 'i')
", {PUBLISHER=publisherId}, {datasource="someDB"});
but it's not delivering the expected results. A few things I've noted as I try to debug...
The underlying query(without using a variable) works and has been verified in Oracle SQL
If I go to the source code and replace :PUBLISHER with a 'hard coded' value the things work as expected.
I've tried escaping the ':' but that's not the answer.
I fell there's something I'm not understanding about passing variables into a REGEX expression within queryExecute(), so would appreciate any thoughts.
Any input gratefully received,
Phil
SQL>
with t (fieldOne) as (
select 'abc, def' from dual union all
select 'def cba' from dual union all
select ':publisher' from dual
)
select * from t where REGEXP_LIKE(fieldOne, '(^|,)(:PUBLISHER)($|,)', 'i');
FIELDONE
----------
:publisher
SQL>
with t (fieldOne) as (
select 'abc, def' from dual union all
select 'def cba' from dual union all
select ':publisher' from dual
)
select * from t where REGEXP_LIKE(fieldOne, '(^|,)(' || :PUBLISHER || ')($|,)', 'i');
FIELDONE
----------
abc, def
Let's say i have following data:
fjflka, kdjf
ssssllkjf fkdsjl
skfjjsld, kjl
jdkfjlj, ksd
lkjlkj hjk
I want to cut out everything after ',' but in case the string doesn't contain this character, it wont do anything, if i use substr and cut everything after ',' the string which doesn't contain this character shows as null. How do i achieve this? Im using oracle 11g.
This should work. Simply use regexp_substr
with t_view as (
select 'fjflka, kdjf' as text from dual union
select 'ssssllkjf fkdsjl' from dual union
select 'skfjjsld, kjl' from dual union
select 'jdkfjlj, ksd' from dual union
select 'lkjlkj hjk' from dual
)
select text,regexp_substr(text,'[^,]+',1,1) from t_view;
Assuming your table :
SQL> desc mytable
s varchar2(100)
you may use:
select decode(instr(s,','),0,s,substr(s,1,instr(s,',')-1)) from mytable;
demo
Well the below query works as per your requirement.
with mytable as
(select 'aaasfasf wqwe' s from dual
union all
select 'aaasfasf, wqwe' s from dual)
select s,substr(s||',',1,instr(s||',',',')-1) from mytable;
I have a table in oracle in which we have one column having data as B12345, means first alphabet always B and followed by numeric. I want to replace all such instances with BH that will become BH12345
So if already there is a value called BH45678 in that column don't update.
Only where find B followed by numeric need updates.
Get the rows which have B followed by digits using regexp_like. Then use replace to replace B with BH for those rows.
select replace(col,'B','BH')
from tablename
where regexp_like(col,'^B\d+$')
with
inputs( str ) as (
select 'B123' from dual union all
select 'BONE' from dual union all
select 'BH55' from dual union all
select 'Z123' from dual union all
select 'B13H' from dual
)
select str, regexp_replace(str, '^B(\d)', 'BH\1') as new_str
from inputs
;
STR NEW_STR
---- -------
B123 BH123
BONE BONE
BH55 BH55
Z123 Z123
B13H BH13H
5 rows selected.
I am working on below query, I am expected to select exact 7 or 10 digit values columns using regular expression, I have used express in regexp_like() function of oracle, but its not working, please help
Query :
select * from
(select '1234567CELL' "a" from dual
union
select '123CaLLAsasd12' "a" from dual
union
select 'as9960488188CELLas12' "a" from dual
union
select '1234567' "a" from dual
union
select '9960488188' "a" from dual
union
select 'asdCELLqw' "a" from dual) b
where b."a" like '%CELL%' and regexp_like(b."a",'^(\d{7}|\d{10})$');
Expected output
"1234567"
"9960488188"
as above two rows, please check
^ and $ match the start and end of a string and the value cannot contain the string CELL and be solely a 7- or 10-digit number. Instead you could use the regular expression (^|\D)(\d{7}|\d{10})($|\D) which will match either the start of the string or a not digit character (^|\D) then either 7- or 10- digits and then either the end of the string or a non digit character ($|\D).
Like this:
WITH data ( a ) AS (
select '1234567CELL' from dual union
select '123CaLLAsasd12' from dual union
select 'as9960488188CELLas12' from dual union
select '1234567' from dual union
select '9960488188' from dual union
select 'asdCELLqw' from dual
)
SELECT a,
REGEXP_SUBSTR( a, '(^|\D)(\d{7}|\d{10})($|\D)', 1, 1, NULL, 2 ) AS val
FROM data
WHERE a LIKE '%CELL%'
AND REGEXP_LIKE( a, '(^|\D)(\d{7}|\d{10})($|\D)');
Output:
A VAL
-------------------- ----------
1234567CELL 1234567
as9960488188CELLas12 9960488188
You may just use
where regexp_like(b."a",'^([[:digit:]]{7}|[[:digit:]]{10})$')
Since the pattern is anchored (^ matches the start of the string and $ matches the end of the string) there can't be CELL inside the entries you fetch, and you can remove where b."a" like '%CELL%' from the query.