Copying a specfic line within a cell into another cell - vba

I have a spreadsheet that has multiple lines within a cell, all with line breaks.
e.g.
Name: a
Age: 1
University: 1
Degree: 3
Year: 3
I am looking to extract (in this example) the University infomation that is contained within the cell and copy it into another cell in another column.
There are about 1000 records in my document so to copy and paste by hand will be time consuming.
Any help will be appreciated
Cheers
Joe

You could do this with an Excel formula.
Assuming your data is in column A, and you want the extraction in column B, and assuming you put a title in row 1, you could do as in the following image:
(Note that I have a semi-colon in the formula as list separator, use comma instead)
The formula in B2 is:
=MID($A2, FIND(B$1, $A2) + LEN(B$1),
FIND(CHAR(10), $A2 & CHAR(10), FIND(B$1, $A2)) - FIND(B$1, $A2) - LEN(B$1))
The formula has some duplication; here are some of the parts explained:
FIND(B$1, $A2) returns the position of the title in the text
FIND(B$1, $A2) + LEN(B$1) returns the position of what follows that title in the text
FIND(CHAR(10), $A2 & CHAR(10), FIND(B$1, $A2)) returns the position of a newline character following the title, making sure that if none is present, a position beyond the string length is returned
As long as you put the column titles to whatever sub-string you are looking for, you can copy/drag the same formula to other columns and rows.

If there is a single break between each line, then in B1 enter:
=TRIM(MID(SUBSTITUTE($A1,CHAR(10),REPT(" ",999)),COLUMNS($A:C)*999-998,999))
This assumes that:
the university line is the third line
you want the entire line

I'm providing an answer even though you haven't provided what attempts you've made so far, which is how questions on this site usually work...but today I'm feeling generous :)
Use a combination of MID and FIND formulas, like the following:
=MID(A1,FIND("University",A1),FIND("Degree",A1)-FIND("University",A1)-2)
I put your example text in Cell A1 for my test, and it returned University: 1. This however will only work if University is always followed by Degree in the text strings.
The other method would be to replace the last part of your MID statement (the part asking for length to return) with the exact number of characters to return, which in this case would be 13, like the following:
=MID(A1,FIND("University",A1),13)
This assumes that the integer associated with University is always 1 character in length.
Either way, a combination of the above two formulas should get you what you need. VBA should not be necessary in this case.

Lines in a cell value are separated by the line feed character vbLf, so to extract the information out of the cell value you can use String-Functions Mid(...) and InStr(...):
Dim cellValue as String
Dim extracedValue as String
Dim keyWord as String
Dim posStart as Integer, posEnd as Integer
extractedValue = "" ' Not necessary, but I prefer initialized variables
cellValue = ActiveSheet.Cells(1,1).Value ' Put your cell here
keyWord = "University" ' Put your keyword here
posStart = InStr(1, cellValue, keyWord) ' Find keyword in the string
If (posStart > 0) Then
posEnd = InStr(posStart, cellValue, vbLf) ' Find next line feed after the keyword
If (posEnd > 0) Then
extractedValue = Mid(cellValue, posStart, posEnd - posStart) ' Extract the value
End If
End If
I haven't tested the code, but you should get the idea.

Related

extract airlines from flight numbers strings in excel

I have problem of extracting two-character code from the string format like:
"VA198-VA200-VA197"
I just want to get the string:
"VA-VA-VA"
Also the data I have are not just in one format, some data is like:
"DL123-DL245"
or
"DL123-VA345-HU12-OZ123"
Does anyone know how to do it fast in excel? Thanks.
With data in A1, in B1 enter the array formula:
=TEXTJOIN("",TRUE,IF(ISERR(MID(A1,ROW(INDIRECT("1:100")),1)+0),MID(A1,ROW(INDIRECT("1:100")),1),""))
NOTE:
The formula strips out all numeric characters, leaving only the alphas and the dash.
Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key. If this is done correctly, the formula will appear with curly braces around it in the Formula Bar.
There are a couple of ways you can approach this depending on how many possible segments their are in your string. If we assume your flight number is in A1:
First Segment: =LEFT(A1,2)
Second Segment: =MID(A1,FIND("-",A1)+1,2)
Third Segment: =MID(A1,FIND("-",A1,FIND("-",A1)+1)+1,2)
You could then concatenate the three expressions together and add a fourth with some conditionals. The problem is that based on your information you can have anywhere from 1 to 4 (at least) names which means you'll need a conditional:
Second Segment: =IF(ISERR(FIND("-",A1)),"",MID(A1,FIND("-",A1)+1,2))
Adding in the separators we end up with something like this for up to four segements:
=CONCATENATE(LEFT(A1,2),IF(ISERR(FIND("-",A1)),"",CONCATENATE("-",MID(A1,FIND("-",A1)+1,2))),IF(ISERR(FIND("-",A1,FIND("-",A1)+1)),"",CONCATENATE("-",MID(A1,FIND("-",A1,FIND("-",A1)+1)+1,2))),IF(ISERR(FIND("-",A1,FIND("-",A1,FIND("-",A1)+1)+1)),"",CONCATENATE("-",MID(A1,FIND("-",A1,FIND("-",A1,FIND("-",A1)+1)+1)+1,2))))
This will give you everything in one field.
Here is a VBA type answer.Assuming all strings are structured in the same way. Meaning Two letters followed by numbers and separated with "-". If one such string is A1, and you want to write the result to B1:
Sub BreakStrings()
d = Split(Range("A1"), "-")
For i = LBound(d) To UBound(d)
d(i) = Left(d(i), 2)
Next i
strg = Join(d, "-")
Range("B1") = strg
End Sub
User-defined function (UDF):
Function GetVal(cell)
With CreateObject("VBScript.RegExp")
.Global = True: .Pattern = "(\w{2})(.+?)(?=-|$)"
GetVal = .Replace(cell, "$1")
End With
End Function

How to put character if there is one digit in cell in VBA Macro?

I would like to ask, how to put character, in this case 0 to cell, if the cell already contains digit in it.
To clarify what do I mean, if on the cell is number 5, I would like to put before the number 5, number 0 to have the result 05.
As far as I know, cell format should be TEXT to avoid automatic Excel correction. But, this question is specific due to several different characters in the cells. In some point I got in the same column different characters in the cells (1, 2, 3, AV, AR, IX etc.).
For example: I would like to select column K, find the numeric characters with one digit (1, 2, 3, -9) and paste there 0 before it to have two space digit like 01, 02, 03, …
Of course, with macro. I know how to put Text format to it, but do not know how to manage the whole macro function to select column K, format whole column as text, find one digit number in the column and paste 0 before it.
Does anybody know how to do that?
Many thanks in advance.
There are 2 solutions:
Format the numbers
Convert numbers to text and format them
1. Format the numbers
The advantage of this solution is that the numbers will still be numbers (not text) but formatted with leading zeros. Therefore you still can calculate with these numbers as before.
Public Sub ChangeNumberFormat()
ThisWorkbook.Worksheets("YourDesiredSheetName").Columns("K").NumberFormat = "00"
'this will keep them numbers but only change the format of them
End Sub
Note that you don't need to do this necessarily with VBA you can just set a user defined cell format 00 for column K (open format cells with Ctrl + 1).
2. Convert numbers to text and format them
If you really need to convert them to text this would be a possible solution. But I really don't recommend that because you cannot calculate with these "numbers" anymore because they are converted to text.
The trick would be to format the number with numberformat first and then convert it to text (see comments in the code).
Option Explicit 'force variable declaring
Public Sub FixLeadingZerosInText()
Dim ws As Worksheet
Set ws = ThisWorkbook.Worksheets("YourDesiredSheetName") '<-- change your sheet name here
Dim lRow As Long
lRow = ws.Cells(ws.Rows.Count, "K").End(xlUp).Row 'find last used row in column K
Dim iCell As Range
For Each iCell In ws.Range("K1:K" & lRow) 'loop from row 1 to last used in column K
If iCell.Value < 10 And iCell.Value > -10 Then 'check if it is a one digit number
Dim tmpText As String
tmpText = Format(iCell.Value, "00") 'format the one digit number
iCell.NumberFormat = "#" 'convert number to text
iCell.Value = tmpText 're-write formatted number
End If
iCell.NumberFormat = "#" 'make all other numbers in column K formatted as text too
Next iCell
End Sub

How to sort excel values with numbers in end

I have a macro which reads file names from a folder. The problem is that when file names are in series like A1,A2.....A200.pdf, as in this image:
then it reads in Excel as A1,A10,A100,A101.....A109,A11,A110.....A119,A20, as in this image:
How can I sort this so that the value in Excel comes as same as folder file names, or is there a way I can sort in Excel itself?
You can sort this in Excel with a helper column. Create a new column and calculate the length of your filenames in that "=LEN(A1)". Then use two-level sort to sort your filenames. Data -> Sort: Use length in the first level and the filenames in the second level.
Another option, you can use the RegEx object to extract the Numeric digits "captured" inside the file name.
Option Explicit
Sub SortFileNames()
Dim i As Long
With Sheets("Sheet1") ' replaces "Sheet1| with your sheet's name
For i = 1 To .Cells(.Rows.Count, "A").End(xlUp).Row
.Range("B" & i).Value = RetractNumberwithRegex(.Range("A" & i)) ' call the Regex function
Next i
End With
End Sub
'========================================================================
Function RetractNumberwithRegex(Rng As Range) As String
' function uses the Regex object to substract the Numeric values inside
Dim Reg1 As Object
Dim Matches As Object
Set Reg1 = CreateObject("vbscript.regexp")
With Reg1
.Global = True
.MultiLine = True
.IgnoreCase = False
.Pattern = "[0-9]{1,20}" ' any size numeric string (up to 20 digits length)
End With
Set Matches = Reg1.Execute(Rng.Value2)
If Matches.Count <> 0 Then
RetractNumberwithRegex = Matches.Item(0)
End If
End Function
This is happening ofcourse of because different sorting algorithm in both these cases (Windows Explorer and Excel) Refer to this article if you want to understand.
To solve your problem, one of the ways is to pull out only the numeric part of file names in a different cell (say column B) and then sort based on those numbers.
If I can assume that the pattern of the files names is AXXX.pdf i.e. one letter A, then number, and 4 characters for file extension. You can use this function
=VALUE(MID(A1,2,LEN(A1)-5))
This works by pulling out some number of characters from in between the string. As per assumption, the number starts from 2nd place that's why the second parameter is 2. Then to decide, how many characters you pull, you know that all the characters except 'A' (1 char) and '.pdf' (4 chars) make the number. So, take the lenght of the whole name and reduce 5 characters. You get your number part which you can sort.
This will be your result:
The best way is to change the file names in your Excel list to have leading zeroes. Instead of A19, refer to the file as A019 and it will sort correctly. Convert the file names using this formula in a helper column.
=Left($A2, 1) & Right("000" & Mid($A2, 2, 3), 3)
Note that the 3 zeroes and string lengths of 3 are all related to each other. To create fixed length numbers of 4 digits, just use 4 zeroes and increase both string lengths to 4.
Copy the formula down from row 2 to the end. Copy the helper column, paste Values in place and, when everything is perfect, replace the original column with the helper.
In order to accommodate a fixed number of digits following the number the above formula may be tweaked. The formula below will accommodate 4 extra characters which follow the number, for example ".pdf" (including the period).
=Left($A2, 1) & Right("000" & Mid($A2, 2, 7), 7)

Use a VBA macro to replace individual characters in a word 2007 document

I need to write a macro that will replace specific characters in a selected string with other specific characters. That is, for example, I may want to replace all a's with b's, all b's with c's, and so on.
I wrote this test macro just to see if I could replace characters. It gets stuck in an infinite loop replacing the first character in the selection with "1".
Dim obChar As Range 'Define a range variable
For Each obChar In Selection.Characters
obChar.Text = "1"
Next obChar
What am I doing wrong?
Try a reversed loop:
Dim i As Integer
For i = Selection.Characters.Count To 1 Step -1
Selection.Characters(i).Text = "1"
Next i

Extract 5-digit number from one column to another

I need help with extracting 5-digit numbers only from one column to another in Excel 2010. These numbers can be in any position of the string (beginning of the string, anywhere in the middle, or at the end). They can be within brackets or quotes like:
(15478) or "15478" or '15478' or [15478]
I need to ignore any numbers that are less than 5 digits and include numbers that start with 1 or more leading zeros (like 00052, 00278, etc.) and ensure that leading zeros are copied over to the next column. Could someone help me with either creating a formula or UDF?
Here is a formula-based alternative that will extract the first 5 digit number found in cell A1. I tend to prefer reasonably simple formula solutions over VBA in most situations as formulas are more portable. This formula is an array formula and thus must be entered with Ctrl+Shift+Enter. The idea is to split the string up into every possible 5 character chunk and test each one and return the first match.
=MID(A1,MIN(IF(NOT(ISERROR(("1"&MID(A1,ROW(INDIRECT("R1C[1]:R"&(LEN(A1)-4)&"C[1]",FALSE)),5)&".1")*1))*ISERROR(MID(A1,ROW(INDIRECT("R1C[1]:R"&(LEN(A1)-4)&"C[1]",FALSE))+5,1)*1)*ISERROR(MID(A1,ROW(INDIRECT("R1C[1]:R"&(LEN(A1)-4)&"C[1]",FALSE))-1,1)*1),ROW(INDIRECT("R1C[1]:R"&(LEN(A1)-4)&"C[1]",FALSE)),9999999999)),5)
Let's break this down. First we have an expression I used twice to return an array of numbers from 1 up to 4 less than the length of your initial text. So if you have a string of length 10 the following will return {1,2,3,4,5,6}. Hereafter the below formula will be referred to as rowlist. I used R1C1 notation to avoid potential circular references.
ROW(INDIRECT("R1C[1]:R"&(LEN(A1)-4)&"C[1]",FALSE))
Next we will use that array to split the text into an array of 5 letter chunks and test each chunk. The test being performed is to prepend a "1" and append ".1" then verify the chunk is numeric. The prepend and append eliminate the possibility of white space or decimals. We can then check the character before and the character after to make sure they are not numbers. Hereafter the below formula will be referred to as isnumarray.
NOT(ISERROR(("1"&MID(A1,rowlist,5)&".1")*1))
*ISERROR(MID(A1,rowlist+5,1)*1)
*ISERROR(MID(A1,rowlist-1,1)*1)
Next we need to find the first valid 5 digit number in the string by returning the current index from a duplicate of the rowlist formula and returning a large number for non-matches. Then we can use the MIN function to grab that first match. Hereafter the below will be referred to as minindex.
MIN(IF(isnumarray,rowlist,9999999999))
Finally we need to grab the numeric string that started at the index returned by the MIN function.
MID(A1,minindex,5)
The following UDF will return the first five digit number in the string, including any leading zero's. If you need to detect if there is more than one five digit number, the modifications are trivial. It will return a #VALUE! error if there are no five-digit numbers.
Option Explicit
Function FiveDigit(S As String, Optional index As Long = 0) As String
Dim RE As Object
Set RE = CreateObject("vbscript.regexp")
With RE
.Pattern = "(?:\b|\D)(\d{5})(?:\b|\D)"
.Global = True
FiveDigit = .Execute(S)(index).submatches(0)
End With
End Function
As you may see from the discussion between Mark and myself, some of your specifications are unclear. But if you would want to exclude decimal numbers, when the decimal portion has five digits, then the regex pattern in my code above should be changed:
.Pattern = "(?:\d+\.\d+)|(?:\b|\D)(\d{5})(?:\b|\D)"
I just wrote this UDF for you , basic but will do it...
It will find the first 5 consecutive numbers in a string, very crude error checking so it just says Error if anything isn't right
Public Function GET5DIGITS(value As String) As String
Dim sResult As String
Dim iLen As Integer
sResult = ""
iLen = 0
For i = 1 To Len(value)
If IsNumeric(Mid(value, i, 1)) Then
sResult = sResult & Mid(value, i, 1)
iLen = iLen + 1
Else
sResult = ""
iLen = 0
End If
If iLen = 5 Then Exit For
Next
If iLen = 5 Then
GET5DIGITS = Format(sResult, "00000")
Else
GET5DIGITS = "Error"
End If
End Function