we have attendance db data as follows (sql server)
empid date type
1 01-Jan In
1 01-Jan Out
2 01-Jan In
3 01-Jan In
3 01-Jan Out
How can we get records that have only 1 record per date per employee (in above case empid 2 for 01-jan)?
The query should simply list all records of employees that have only single type for a day.
EDIT
The result set should be a bit more specific: show all employee who only have "In" for a date but no "Out"
Use Having
select empid, date, count(*)
from Mytable
group by empid, date
having count(*) = 1
You can use this to get the full line:
select t1.*
from MyTable t1
inner join
(
select empid, date, count(*)
from Mytable
group by empid, date
having count(*) = 1
) t2
on t1.empid = t2.empid
and t1.date = t2.date
You can use window functions:
select t.*
from (select t.*,
count(*) over (partition by empid, date) as cnt
from t
) t
where cnt = 1;
You can also use aggregation:
select empid, date, max(type) as type
from t
group by empid, date
having count(*) = 1;
Use a correlated subquery
select * from tablename a
where not exists (select 1 from tablename b where a.empid=b.empid and a.date=b.date and type='Out')
OR
select empid, date,count(distinct type)
from tablename
group by empid,date
having count(distinct type)=1
The Solution is Very Simple, You can use 'DISTINCT' function.
Query Should be as,
SELECT DISTINCT empid FROM attendance
This will return only 1 record per date per employee.
For Your Reference, Check it out- https://www.techonthenet.com/sql_server/distinct.php
This will work if we have ID with 1 IN OR 1 OUT as well
Declare #t table (empid int,date varchar(50),types varchar(50))
insert into #t values (1,'01-Jan','IN')
insert into #t values (1,'01-Jan','OUT')
insert into #t values (2,'01-Jan','IN')
insert into #t values (3,'01-Jan','OUT')
insert into #t values (4,'01-Jan','OUT')
select * from #t a
where not exists (select 1 from #t b where a.empid=b.empid and a.types!=b.types)
I need to find duplicate records (ID) which have different dates, however the duplicate has to be on the day before/after the original. Essentially I am trying to find if the same ID's were used on a different day.
I am able to find the duplicates but cannot get the date part correct, is there a simpler way to perform the above?
I have been trying the following but feel I am over complicating things:
SELECT *
FROM table
WHERE ID IN (
SELECT ID
FROM Table
Where [DATE] < DATEADD(day, +1, [DATE]) and ID=ID
GROUP BY ID
HAVING COUNT(*) > 1 )
ORDER BY Name,[DATE], ID ASC
My data is similar to:
Name Date ID
A 3/30/2018 6.26
B 3/31/2018 6.26
C 4/1/2018 7.85
D 4/2/2018 11.88
E 4/3/2018 11.88
F 4/4/2018 9.48
The query should only pick up names AB and DE.
Any help would be appreciated.
SELECT NAME,
DATE,
ID
FROM TABLE1
WHERE ID IN (SELECT ID
FROM TABLE1
GROUP BY ID
HAVING COUNT(*) > 1)
Output
NAME DATE ID
A 2018-03-30 6.26
B 2018-03-31 6.26
D 2018-04-02 11.88
E 2018-04-03 11.88
Demo
http://sqlfiddle.com/#!18/15edb/1
You can use exists:
select t.*
from t
where exists (select 1
from t t2
where t2.id = t.id and
t2.date = dateadd(day, -1, t1.date)
);
This selects the later duplicate. For the earlier one, use 1 instead of -1.
You may try the following Method
DECLARE #T TABLE
(
Nm VARCHAR(50),
Mydate DATE,
Id FLOAT
)
INSERT INTO #T
VALUES('A','3/30/2018',6.26),
('B','3/31/2018',6.26),
('C','4/1/2018',7.85),
('D','4/2/2018',11.88),
('E','4/3/2018',11.88),
('F','4/4/2018',9.48)
SELECT
*
FROM #T T
WHERE EXISTS
(
SELECT 1 FROM #T WHERE ID = T.Id GROUP BY Id HAVING COUNT(1)>1
)
I am sure this is a very stupid question and I am having a dumb moment.
Consider the following basic scenario (this is a very small scenario compared with reality which has many many dimensions and measures):
What I need to get to is the expected output.
So ALL costs between the input_Date and output_date defined in the params are included. However only the latest PID is included- defined as either:
1- where PIDs run sequentially, or overlap the latest one based on date_to as long as both aren't active at the # output date
2- where there are two PID active at the # output date show both
I can't for the life of me work out how to do this in SQL, note that is has to be non dynamic and not use any CTE unfortunately, just your basic SQL with subqueries
Obviously returning the necessary list of ID and PID is easy:
declare #input_date date ='2006-01-01'
declare #output_date date ='2006-12-31'
select a.PID, a.ID
from #tmp a
where date_from <=#output_date and date_to >=#input_date
But I can't figure out how to join this back to return the correct cost values
drop table tmp
CREATE TABLE [dbo].[tmp](
[date_from] [datetime] NOT NULL,
[date_to] [datetime] NOT NULL,
[ID] [nvarchar](25) NOT NULL,
[PID] [nvarchar](25) NOT NULL,
[cost] [float] NULL
) ON [PRIMARY]
INSERT tmp VALUES('2005-1-1','2005-1-31','10001','X123',1254.32)
INSERT tmp VALUES('2000-10-10','2006-8-21','10005','TEST01',21350.9636378758)
INSERT tmp VALUES('2006-8-22','2099-12-31','10005','TEST02',22593.4926163943)
INSERT tmp VALUES('2006-1-1','2099-12-31','10006','X01',22458.3342354444)
INSERT tmp VALUES('2006-2-8','2099-12-31','10006','X02',22480.3772331959)
INSERT tmp VALUES('2006-1-1','2006-2-7','10007','AB01',565.416874152212)
INSERT tmp VALUES('2006-2-8','2006-7-31','10007','AA05',19108.3206482165)
I've made some progress using a CTE so you can see how I would do it this way if I could:
drop table #tmp
CREATE TABLE #tmp (
[date_from] [datetime] NOT NULL,
[date_to] [datetime] NOT NULL,
[ID] [nvarchar](25) NOT NULL,
[PID] [nvarchar](25) NOT NULL,
[cost] [float] NULL
) ON [PRIMARY]
INSERT #tmp VALUES('2005-1-1','2005-1-31','10001','X123',1254.32)
INSERT #tmp VALUES('2000-10-10','2006-8-21','10005','TEST01',21350.9636378758)
INSERT #tmp VALUES('2006-8-22','2099-12-31','10005','TEST02',22593.4926163943)
INSERT #tmp VALUES('2006-1-1','2099-12-31','10006','X01',22458.3342354444)
INSERT #tmp VALUES('2006-2-8','2099-12-31','10006','X02',22480.3772331959)
INSERT #tmp VALUES('2006-1-1','2006-2-7','10007','AB01',565.416874152212)
INSERT #tmp VALUES('2006-2-8','2006-7-31','10007','AA05',19108.3206482165)
declare #input_date date ='2006-01-01'
declare #output_date date ='2006-12-31'
;with cte as (
select t.id,t.PID,t.cost,t.date_from,t.date_to ,
iif(date_To >= #output_date OR max_date_To is not null,PID,NULL) as PID2,
b.total_id_cost
from #tmp t
left join (select ID,max(date_to) as max_date_to
from #tmp
where date_from <=#output_date and date_to >=#input_date
group by ID) a
on t.ID = a.ID and t.date_to = a.max_date_to
left join (Select ID, sum(cost) as total_id_cost
from #tmp
where date_from <=#output_date and date_to >=#input_date
group by ID) b
on t.ID = b.ID
where date_from <=#output_date and date_to >=#input_date )
select distinct ID,PID2,
iif(ID in (
select ID
from cte
where PID2 IS NULL)
and ID not in (select ID
from cte
where PID IS NOT NULL
group by ID
having count (distinct PID2) >1 ), cte.total_id_cost, cost) as cost
from cte
where PID2 is not null;
so it looks like there's several problems to solve within 1 query.
We want the PID that matches the latest date. This wasn't too difficult and can be solved by joining the data with an aggregate of itself that finds the latest date
Where both PID is active i.e. overlapping from and to dates, then both must show. I found this to be more tricky. in the end I did a query to find the ones that do overlap and meet the dates, and did a count on that. then used this count as a criteria for the join on 1. so that it can conditionally pick the PID that matches the latest date
Then finally using the results from above, you can do the sum to get the cost. The resulting query is a bit of a monster, but here it is.
if it doesn't cover other scenarios not detailed, do let me know.
DECLARE #Data TABLE (date_from DATETIME, date_to DATETIME, ID INT, PID NVARCHAR(50), COST MONEY)
INSERT #Data VALUES('2005-1-1','2005-1-31','10001','X123',1254.32)
INSERT #Data VALUES('2000-10-10','2006-8-21','10005','TEST01',21350.9636378758)
INSERT #Data VALUES('2006-8-22','2099-12-31','10005','TEST02',22593.4926163943)
INSERT #Data VALUES('2006-1-1','2099-12-31','10006','X01',22458.3342354444)
INSERT #Data VALUES('2006-2-8','2099-12-31','10006','X02',22480.3772331959)
INSERT #Data VALUES('2006-1-1','2006-2-7','10007','AB01',565.416874152212)
INSERT #Data VALUES('2006-2-8','2006-7-31','10007','AA05',19108.3206482165)
declare #input_date date ='2006-01-01'
declare #output_date date ='2006-12-31'
select
a.ID,
PIDForMaxDateThatMatches.PID,
SUM(a.cost) as cost
from
#Data a
inner join (
-- number of PIDs for dates that overlap grouped by ID
select
a.ID,
-- where there's no overlap then we want the count to be 1 so that later we can use it as condition
COUNT(DISTINCT ISNULL(b.PID,'')) as NumberOfPID
from
#Data a
-- may or may not find overlaps
LEFT JOIN #data b ON
b.date_from <=#output_date and
b.date_to >=#input_date and
a.date_from <= b.date_to and
a.date_to >= b.date_from and
a.ID = b.ID and
a.PID <> b.PID
where
a.date_from <=#output_date and
a.date_to >=#input_date
group by
a.ID) as PIDCountForOverlappingMatches ON
a.ID = PIDCountForOverlappingMatches.ID
left join (
-- get the PID that matches the max date_to
select
DataForMaxDate.ID,
DataForMaxDate.date_from,
DataForMaxDate.date_to,
DataForMaxDate.PID
from
#Data as DataForMaxDate
inner join (
-- get the max date_to that matches the criteria
select
ID,
MAX(date_to) as maxDateTo
from
#Data a
where
date_from <=#output_date and
date_to >=#input_date
group by
ID) as MaxToDatePerID on
DataForMaxDate.ID = MaxToDatePerID.ID and
DataForMaxDate.date_to = MaxToDatePerID.maxDateTo) as PIDForMaxDateThatMatches on
a.ID = PIDForMaxDateThatMatches.ID AND
-- if there's no overlapping dates the PID count would be 1, which we'll take the PID that matches the max(date_to)
-- but if there is overlap, then we want both dates to show, thus the from date must also match before we take the PID
(PIDCountForOverlappingMatches.NumberOfPID = 1 OR a.date_from = PIDForMaxDateThatMatches.date_from)
where
a.date_from <= #output_date and
a.date_to >= #input_date
GROUP BY
a.ID,
PIDForMaxDateThatMatches.PID
ORDER BY
a.ID
EDIT: DB Fiddle http://dbfiddle.uk/?rdbms=sqlserver_2014&fiddle=d43cb4b9765da1bca035531e78a2c77d
Results:
ID PID cost
10005 TEST02 43944.4562
10006 X01 22458.3342
10006 X02 22480.3772
10007 AA05 19673.7375
Hello you can try the following query :
select a.resource_id ID, max(a.post_id) PID, SUM(a.cost) Cost
from #tmp a
where date_from <=#output_date and date_to >=#input_date
group by a.resource_id
order by a.resource_id;
I think this might work:
SELECT
t1.ID,
q1.PID,
SUM(t1.cost)
FROM
Table AS t1
JOIN
(
SELECT
q2.ID,
t2.PID
FROM
(
SELECT
ID,
MAX(date_to) AS maxdate
FROM
Table
GROUP BY
ID
) AS q2
JOIN
table AS t2
ON
q2.ID = t2.ID
AND
q2.maxdate = t2.date_to
) AS q1
ON
t1.ID = q1.ID
AND
t1.PID = q1.PID
GROUP BY
t1.ID,
q1.PID
Here is a query without CTE. Idea of query:
1) Find consecutive dates and make different groups within each id
2) Find min and max date, sum of costs for each group
3) Limit by input parametres
declare #date_from date = '20060101'
declare #date_to date = '20061231'
declare #myTable table(
date_from date
, date_to date
, id int
, pid varchar(30)
, cost decimal(10,2)
)
insert into #myTable values
('20050101', '20050201', 10001, 'x123', 1254.32)
, ('20001010', '20060821', 10005, 'test01', 21350.96)
, ('20060822', '20991231', 10005, 'test02', 22593.49)
, ('20060101', '20991231', 10006, 'x01', 22548.33)
, ('20060208', '20991231', 10006, 'x02', 22480.38)
, ('20060101', '20060207', 10007, 'abo1', 565.42)
, ('20060208', '20060731', 10007, 'abo2', 19108.32)
select
date_from = min(date_from), date_to = max(date_to)
, id, pid = max(case when date_to = max_date_to then pid end)
, cost = sum(cost)
from (
select
a.date_from, a.date_to, a.id, a.pid, a.cost, a.rn, grp = sum(b.ss)
, max_date_to = max(a.date_to) over (partition by a.id, sum(b.ss))
from
(
select
a.*, ss = case when datediff(dd, b.date_to, a.date_from) = 1 then 0 else 1 end
from
(
select
*, rn = row_number() over (partition by id order by date_from)
from
#myTable
) a
left join (
select
*, rn = row_number() over (partition by id order by date_from)
from
#myTable
) b on a.id = b.id and a.rn - 1 = b.rn
) a
left join (
select
a.*, ss = case when datediff(dd, b.date_to, a.date_from) = 1 then 0 else 1 end
from
(
select
*, rn = row_number() over (partition by id order by date_from)
from
#myTable
) a
left join (
select
*, rn = row_number() over (partition by id order by date_from)
from
#myTable
) b on a.id = b.id and a.rn - 1 = b.rn
) b on a.id = b.id and a.rn >= b.rn
group by a.date_from, a.date_to, a.id, a.pid, a.cost, a.rn
) t
group by id, grp, max_date_to
having min(date_from) <= #date_from and max(date_to) >= #date_to
order by id
Output
date_from date_to id pid cost
------------------------------------------------
2000-10-10 2099-12-31 10005 test02 43944.45
2006-01-01 2099-12-31 10006 x01 22548.33
Result is a bit different than your provided output. But:
1) For id = 10006 and pid = X02 date_from = 08/02/2006 while input is 01/01/2006
2) For id = 10007 date_to = 31/07/2006 while input is 31/12/2006
So, I think query works correctly
Rextester demo in more readable format with cte
I have a table example like this:
date id status
01/01/2013 55555 high
01/01/2014 55555 low
01/01/2010 44444 high
01/01/2011 33333 low
I need in order: group by id and select most recent date.
this is the result I want.
date id status
01/01/2014 55555 low
01/01/2010 44444 high
01/01/2011 33333 low
I do not care the order of the rows.
you need to join your table with a subquery that "links" the record date with the greatest date for each id:
select a.*
from your_table as a
inner join (
select id, max(date) as max_date
from your_table
group by id
) as b on a.id = b.id and a.date = b.max_date;
I think you will need a subquery to get the MAX(Date) and then inner join. Try this:
SELECT A.[Date], A.[Id], A.[Status]
FROM Table A
INNER JOIN(SELECT Id, MAX([Date]) AS MaxDate
FROM Table
GROUP BY [Id]) B ON
A.[Id] = B.[Id] AND
A.[Date] = B.[MaxDate]
--return the group id and the latest date in that group
select id
, MAX([date]) [latestDateInGroup]
from tbl
group by id
--return the group id, and the related status and date for the record with the latest date in that group
select id
, [status] [latestDateInGroup'sStatus]
, [date] [latestDateInGroup]
from
(
select id
, [status]
, [date]
, row_number() over (partition by id order by [date] desc) r
from tbl
) x
where x.r = 1
--return all ids and statuses, along with the latest date in that group's group (requires SQL 2012+)
select id
, [status]
, max([date]) over (partition by id order by [date] desc) [latestDateInGroup]
from tbl
SQL Fiddle's offline at the moment; once back up the following code should allow you to build a table to test the above queries with
http://sqlfiddle.com
create table tbl ([date] date, id bigint, [status] nvarchar(4))
go
insert tbl select '2013-01-01', 55555, 'high'
insert tbl select '2014-01-01', 55555, 'low'
insert tbl select '2010-01-01', 44444, 'high'
insert tbl select '2011-01-01', 33333, 'low'
I have a table which is not sorted by any of column. Is there any way to select next/previous record if I know only Id of current? (I'm using mssql)
Id Label Date
---------------------
1 label1 2011-01-10
7 label2 2011-01-15 -- how to get previous?
5 label3 2011-01-12 -- I know id of this record
10 label10 2011-01-25 -- how to get next?
12 label8 2011-01-13
2 label5 2011-01-29
Thanks in advance!
try this:
VALUES (1, 'label1', '2011-01-10'), (7, 'label2', '2011-01-15'),
(5, 'label3', '2011-01-12'), (10, 'label10', '2011-01-25'),
(12, 'label8', '2011-01-13'), (2, 'label5', '2011-01-29')
select * from table007;
Declare #inptID int=12;
;WITH CTE
as
(
select *, ROW_NUMBER() over (order by (select 0)) as rn
from table007
)
select *
from CTE
where rn in( select rn-1 from CTE where id = #inptID)
union all
select * from CTE where rn in(select rn + 1 from CTE where id = #inptID);
SQL Fiddle Demo
DEMO
If it is not sorted by any column, there is no definitive next or previous record. Data in SQL Server has no order, other than that specified by an ORDER BY clause.
If you really want the previous from the list you enclosed, here is a way.
declare #t table(Id int, Label varchar(10), Date date, s int identity(1,1))
insert #t (id, label, date)
values(1,'label1','2011-01-10'),(7,'label2','2011-01-15'),
(5,'label3','2011-01-12'),(10,'label10','2011-01-25'),
(12,'label8','2011-01-13'),(2,'label5','2011-01-29')
--select the data with a self join
select t1.id as previous_id, t2.id, t2.Label, t2.Date, t3.id, t3.id as next_id
from #t t1
right join
#t t2 on t1.s + 1 = t2.s
left join
#t t3 on t2.s = t3.s - 1