RxJava timeout without emiting error? - operators

Question

Is there an option to have variant of timeout that does not emit Throwable?
I would like to have complete event emited.

Answer 1

You don't need to map errors with onErrorResumeNext. You can just provide a backup observable using:
timeout(long,TimeUnit,Observable)
It would be something like:
.timeout(500, TimeUnit.MILLISECONDS, Observable.empty())

Answer 2

You can resume from an error with another Observable, for example :
Observable<String> data = ...
data.timeout(1, TimeUnit.SECONDS)
.onErrorResumeNext(Observable.empty())
.subscribe(...);

Answer 3

A simpler solution that does not use Observable.timeout (thus it does not generate an error with the risk of catching unwanted exceptions) might be to simply take until a timer completes:
Observable<String> data = ...
data.takeUntil(Observable.timer(1, TimeUnit.SECOND))
.subscribe(...);

Answer 4

You can always use onErrorResumeNext which will get the error and you can emit whatever item you want-
/**
* Here we can see how onErrorResumeNext works and emit an item in case that an error occur in the pipeline and an exception is propagated
*/
#Test
public void observableOnErrorResumeNext() {
Subscription subscription = Observable.just(null)
.map(Object::toString)
.doOnError(failure -> System.out.println("Error:" + failure.getCause()))
.retryWhen(errors -> errors.doOnNext(o -> count++)
.flatMap(t -> count > 3 ? Observable.error(t) : Observable.just(null)),
Schedulers.newThread())
.onErrorResumeNext(t -> {
System.out.println("Error after all retries:" + t.getCause());
return Observable.just("I save the world for extinction!");
})
.subscribe(s -> System.out.println(s));
new TestSubscriber((Observer) subscription).awaitTerminalEvent(500, TimeUnit.MILLISECONDS);
}