To_char for Oracle SQL not working - sql

i have the following query which does not retrieve data even though there is:
select *
from INTERFACE_RUN
where TO_CHAR(INTERFACE_RUN.START_TIME, 'dd-mon-yy') = '04-MAY-10';
The start_time field is a timestamp field. Hence I converted it using to_char and compared with the user passed value of 04-MAY-10. But it did not fetch any data.
Any help please. Thanks in advance

to_char() pays attention to the case of the pattern. So, you are producing `04-may-10', which is not the same.
So, try this:
where TO_CHAR(INTERFACE_RUN.START_TIME, 'DD-MON-YY') = '04-MAY-10';
That said, I much prefer:
where trunc(INTERFACE_RUN.START_TIME) = date '2010-05-04'
or:
where INTERFACE_RUN.START_TIME >= date '2010-05-04' AND
INTERFACE_RUN.START_TIME < (date '2010-05-04') + 1
Why? For two reasons. First, the column is a date, so I prefer date comparisons. Second, I prefer the ANSI/ISO standard date formats. The second version can also readily take advantage of an index on the START_TIME column.

Oracle will convert the date to lowercase, thus generating '04-may-10'
Try with 'DD-MON-YY' (uppercase)
select TO_CHAR(sysdate, 'dd-mon-yy') from dual
union all
select TO_CHAR(sysdate, 'dd-MON-yy') from dual;
TO_CHAR(S
---------
13-jun-16
13-JUN-16

Related

Sql Change Time in Query

I currently have the following Problem, working on an Oracle Database:
I have 2 columns of an appointment I want to read: date_from and date_to. They have both DateTime as the datatype.
I need to adjust the time of the value though (and only the time, the date should stay the same).
date_from for example contains 10.10.2017 14:21:00 as a value,
but should be changed to the "start of the day" --> 10.10.2017 00:00:00
date_to for example contains 11.10.2017 11:47:00 as a value,
but should be changed to the "end of the day" --> 10.10.2017 23:59:59
Is this somehow possible to manipulate it this way? I can not do an Update or permanent change to the data. This Format is only needed for a Gantt Diagramm, I dont have an other way to change it.
Thank you in Advance!
Yes, you can achieve that with Oracle's TO_DATE and TO_CHAR functions. It will only depend if you need the result as a DATE or as a VARCHAR. The syntax would look like this for VARCHAR output:
TO_CHAR(date_from, 'DD.MM.YY') || ' 00:00:00'
TO_CHAR(date_to, 'DD.MM.YY') || ' 23:59:59'
If you need the DATE value from this, just add the TO_DATE funtion around it:
TO_DATE((TO_CHAR(date_from, 'DD.MM.YY') || ' 00:00:00'), 'DD.MM.YY HH24:MI:SS')
TO_DATE((TO_CHAR(date_to, 'DD.MM.YY') || ' 23:59:59'), 'DD.MM.YY HH24:MI:SS')
I did not test it, but it's pretty much it.
Does this helps?
Cheers
Nikao
If you need to show the result, try this:
select to_char(date_from, 'DD.MM.YYYY') ||' 00:00:00' as date_from,
to_char(date_to, 'DD.MM.YYYY') ||' 23:59:59' as date_to
from table_name
But you may need to compare intervals. In this case, you could discarts the time using trunc function:
select *
from table_dates t,
other_table o
where trunc(o.some_date) between trunc(t.date_from) and trunc(t.date_to)
UPD: First, I did an implicit conversion of dates to string using TRUNC. But it can lead to inexpected result. Instead, explicitly use TO_CHAR with the format model you are expecting for your output and you do not need to use TRUNC. (Thank you #MT0 )
So you want to return the start and end of the day?
select trunc(start_date) as day_start, -- Strips off the time part of the date
trunc(end_date) + 1 - (1/86400) as day_end -- As above, but we add 1 day and minus 1 second
from My_Table
Also, Oracle has date formats of Date and Timestamp, no datetime
this might be some help to you:
SELECT to_char(current_timestamp,'yyyy-mm-dd hh:mm:ss') FROM dual;
SELECt trunc(current_timestamp)||' 23:59:59' FROM dual;

SQL time and date formatting against dual table

I am trying to only display the date and time of a table in a certain format. This format is DD-MON-YYYY and the time HH24:MI:SS. I don't understand how to make both formats work together. I can get them to function separately.
select to_char(sysdate, 'DD-MON-YYYY', systimestamp,'HH24:MI:SS') from dual;
My error is 'too many arguments'. I want to understand why it isn't working.
From the documentation TO_CHAR takes three arguments when using dates
a date or date time
a format model
optional NLS parameter for the localization
You can concatenate the two results together with this.
select to_char(sysdate, 'DD-MON-YYYY')||' '|| TO_CHAR(systimestamp,'HH24:MI:SS') from dual;
But why would when you do it one call
SELECT TO_CHAR(systimestamp,'DD-MON-YYYY HH24:MI:SS') from dual;
NB SQL is not case sensitive in regards to keywords. Upper or lower case both work.
Try:
select to_char(sysdate, 'DD-MON-YYYY HH24:MI:SS') from dual;

Oracle query concatenate date

I have the following query:
select *
from mytable
where to_char(mydate,'mm/dd/yyyy') between ('05/23/2013')
and ('06/22/2013')
I need to change it to make dynamically so that I won't modify it every month from 05/23/2013 to 06/23/2013 for example:
('05/23/' + (select to_char(sysdate, 'yyyy') from dual))
but this is giving an error. Any suggestions?
What I need to do: Every month I need to run this query to get the records between 23rd of this month and 23rd of the last month.
Oracle uses || as the concatenation operator:
('05/23/' || (select to_char(sysdate, 'yyyy') from dual))
BTW, David is right. If you really want to compare string representations of dates (but why?), use a date format that is ordered the same way as dates:
to_char(mydate,'yyyy/mm/dd')
You're performing a comparison on strings, not on dates, so your code doesn't work the way you think it does.
Based on the string logic, "05/23/2000" is between "05/22/2013" and "06/24/2000".
Keep the data types as date and Oracle will get the comparison right.
Possibly what you want is:
select *
from my_table
where mydate >= add_months(trunc(sysdate,'MM'),-1)+22 and
mydate < trunc(sysdate,'MM')+22
but it's difficult to tell without a description of what the requirement actually is.
How about this one?
SELECT '(''05/23/'''||to_char(sysdate, 'yyyy')||'''' FROM DUAL
Have not testet because I have no Oracle database right now, needs checking for quote escapes...
Do you need exact days from the month? You can also substract days from sysdate:
SELECT (sysdate - 30) FROM DUAL
You may also use concat function
concat('05/23/', (select to_char(sysdate, 'yyyy') from dual))

store dates in oracle

I have a table as
create table Dummy (date_created date)
in oracle.I want to store date in 'dd-mon-yyyy' (12-dec-2010) format.
How should i do this.
Please help.
In Oracle a column created with the DATE datatype just stores the date. It doesn't have a particular format, it just stores the day, month, year, hour, minute, and second. You need to convert from whatever format you have using the TO_DATE function. If you have a text string with the date in 'dd-mon-yyyy' format and you want to put this date into your table you'd use something like
INSERT INTO DUMMY (DATE_CREATED)
VALUES (TO_DATE('01-FEB-2011', 'DD-MON-YYYY');
Going the other way (from DATE column value to character string) you'd use the TO_CHAR function. If you were retrieving a value from your table and wanted to convert it to 'DD-MON-YYYY' format you'd use something like
SELECT TO_CHAR(DATE_CREATED, 'DD-MON-YYYY')
FROM DUMMY;
Share and enjoy.
Use to_date() function. In your case, the syntax would be
insert into Dummy values (to_date('08-09-2010', 'dd-mm-yyyy'));
Here is a link to the detailed help.
The DATE datatype will store date and time information (century, year, month, day, hours, minutes, and seconds) in an internal format in the database. When you get it out of the database, you can choose to display it in whatever format you like.
This information is either created using implicit conversion from a string or explicitly using either the TO_DATE function or the ANSI date literal. If you look in the v$nls_parameters view, this will tell you what the NLS_DATE_FORMAT is which is generally used for the implicit conversion. This may often be defined as DD-MON-RR, which might be why the date will come out as 23-DEC-10 when the query select sysdate from dual is run. (Not entirely sure I'm right about the nls stuff. Correct me if I'm wrong.)
However, all the date information is available if you know how to get it. The query select to_char(sysdate, 'dd-mon-yyyy hh24:mi:ss') from dual will return all the date fields.
Likewise, the insert statement shown below will create a row with a date value in it.
insert into dummy (date_created)
values (to_date('12-dec-2010 12:34:56', 'dd-mon-yyyy hh24:mi:ss'))`
This data can then be retrieved.
select date_created from dummy
This will implicitly convert the date to a character string using the NLS_DATE_FORMAT, providing the output below.
DATE_CREA
---------
23-DEC-10
The full date information is available by explicitly converting the date to a character string.
select to_char(date_created, 'DD-MON-YYYY') as date_created from dummy;
select to_char(date_created, 'DD-MON-YYYY HH24:MI:SS') as date_created
from dummy;
This will provide output in the format you require:
DATE_CREATE
-----------
23-DEC-2010
If you always use the TO_DATE and TO_CHAR functions to convert to/from a date datatype, then you will have fewer problems. Implicit conversion is useful but can cause some confusion or problems.
You can keep and eye here
http://www.techonthenet.com/oracle/functions/to_date.php
use to_date function to save a data with the format you need. I suggest to use SYSDATE updating table and when you need to read data from table use something like that:
dbms_output.put_line(TO_CHAR(SYSDATE, 'DD-MON-YYYY HH24:MI:SS'));
to solve your problem use:
to_date('08/JAN/2010', 'DD/MON/YYYY')
Just use TRUNC(YourDate) if date have time part, it will be truncate time part. Oracle have not just 'DATE' type, 'DATE' always have time part.
However if you do not specify time - it will 00:00:00.
SELECT TRUNC(SYSDATE) from dual
Result:
23-12-2010
Oracle does not support DATE without time part.
You can make it always be an integer date by adding a CHECK constraint:
CREATE TABLE dummy (date_created date CHECK (date_created = TRUNC(date_created)))
, insert it in any format you want:
INSERT
INTO dummy (date_created)
VALUES (TO_DATE('23-DEC-2010', 'dd-mon-yyyy'))
and select it in any format you want:
SELECT TO_CHAR(date_created, 'dd-mon-yyyy')
FROM dummy

how to use = assignment operator with timestamp date column in oracle

I'm using timestamp in dat column in table r3. when I fire command
select dat from r3 where dat='16-nov-09';
it shows "no rows selected" but when i fire command
select dat from r3 where dat>'15-nov-09';
it shows the whole data of 16-nov-09. Tell me what is wrong in my first command or what i have to do.
Quering on oracle date columns is always confusing. The date columntype is always a datetime. Storing the current date from sysdate stores always the time component too.
There good and evil ways quering the date columns. I show and vote some.
where to_char(DAT, 'DD-MON-YYYY') = '16-NOV-2009'
where trunc(DAT) = to_date('16-NOV-2009', 'DD-MON-YYYY')
Both bad, because they do not use any index. To avoid this, you can define a function based index on the expression.
The trick of both is to cut off the time component. If time is not needed, than it is a good advise to cut off the time in INSERT and UPDATE trigger. The function based index can convert to a normal index.
where DAT between to_date('16-NOV-2009', 'DD-MON-YYYY')
and to_date('16-NOV-2009 23:59:59', 'DD-MON-YYYY HH24:MI:SS')
where DAT >= to_date('16-NOV-2009', 'DD-MON-YYYY') and DAT < to_date('16-NOV-2009', 'DD-MON-YYYY')+1
This two are always my favorites.
Its a good advice to use to_date and to_char to convert the values between string and datetime.
As DAT is timestamp you can use as below
select DAT from R3
where DAT between to_date('16-NOV-09' , 'dd-MON-yy') and to_date('16-NOV-09 23:59:59', 'DD-MON-YY hh24:mi:ss')
Timestamp has time and date components, so query
select dat from r3 where dat='16-nov-09';
will work only for records where time component is midnight: '00:00:00'
Beside formatting (to_date function), you can truncate timestamp to get only date:
select dat from r3 where trunc(dat)='16-nov-09';
Beware that this will not use index on field dat (if there is any).
TIMESTAMP and DATE are different data types in oracle and both store time components. If you really do need to store subsecond times then you use TIMESTAMP, otherwise DATE is your best choice.
The ANSI timestamp and date literal syntaxes are quite handy:
create table ts_test (ts1 timestamp);
select *
from ts_test
where ts1 > timestamp '2009-10-11 00:00:00'
/
select *
from ts_test
where ts1 > timestamp '2009-10-11 00:00:00.1'
/
select *
from ts_test
where ts1 > timestamp '2009-10-11 00:00:00.001'
/
select *
from ts_test
where ts1 = date '2009-10-11'
/
use the below format for a date field in where condition.
where to_char(DAT,'mmddyyyy') = '11152009';
In Oracle the date fields also contain a time component, so 16-nov-09 is actually midnight of Nov 16th.
Two different ways to handle this:
where to_char(DAT,'mmddyyyy') = '11152009'
as john suggested, but I like the following version more:
where trunc(dat) = to_date ('11152009', 'mmddyyyy')
TRUNCfor a date "removes" the time component (or to be more specific, truncates it to midnight), and to_date is the proper way to construct a date value in Oracle SQL. (I prefer to do the comparisons in the right domain - DATEs as in the second example- over another - STRINGs as in the first example. With strings you may run into some weird month issues, sorting is easier in dates etc.)
Just to add to it , An easy way out when you are not bothered about the time-stamp but just want to compare the date is to use the 'like' operator.
for example
select dat from r3 where dat LIKE '16-nov-09%'
will give you desired output.