How to handle exception twice - error-handling

Question

I have extended the ExceptionHandler class:
import {Injectable, ExceptionHandler} from '#angular/core';
export class FirstError extends Error {
handle() {
console.log("This is firstError handler");
}
}
export class AnotherError extends Error {
handle() {
console.log("This is AnotherError handler");
}
}
export class _ArrayLogger {
res = [];
log(s: any): void { this.res.push(s); }
logError(s: any): void { this.res.push(s); }
logGroup(s: any): void { this.res.push(s); }
logGroupEnd() {};
}
#Injectable()
export class CustomExceptionHandler extends ExceptionHandler {
constructor() {
super (new _ArrayLogger(), true);
}
call(exception: any, stackTrace = null, reason = null) {
// I want to have original handler log exceptions to console
super.call(exception, stackTrace, reason);
// If exception is my type I want to do some additional actions
if (exception.originalException instanceof Error) {
exception.originalException.handle();
}
}
}
My goal is to have super.call log the error to the console as original Angular2 ExceptionHandler, and additionally do my own exception handle. Unfortunately, in such a scenario super gets called only the first time the error is thrown. When the second, third .. occurs, the super is not get called. How to make it work so the original console.log logs the error to console, and additionaly error processing is also done?

Answer 1

I had the same problem but was able to get it working by passing false in the constructor for the second parameter (rethrowException).
constructor() {
super (new _ArrayLogger(), false);
}
The name of the parameter would suggest that the correct value is indeed true; seems a bit backward to me but it works.