i have to two tables in sql:
tbl_Rooms(Room_Id, Room_Beds);
tbl_AllocatedRooms(Room_Id, Bed_No);
i want to get the result as:
1: List of all the rooms in which no bed is allocated.
2: List of rooms in which one or more beds are allocated also the number of remaining beds(for example if i have a room_id = 2 in tbl_Rooms with Beds = 5 and 2 of these beds are allocated i want to get the remaining number of beds)
i have done the first one but cant figure how to get the second one.
Here is my query for the first one:
SELECT * INTO #tempUnAllocated FROM tbl_Rooms WHERE Room_Id NOT IN
(SELECT Room_Id FROM tbl_Allocation);
SELECT A.room_id,A.room_beds,count(B.bed_no) as allocated_beds,
(A.room_beds - count(B.bed_no)) as remaining_beds
from tbl_rooms A LEFT JOIN tbl_AllocatedRooms B
ON A.room_id = B.room_id
group by A.room_id,A.room_beds
having allocated_beds < room_beds
You can refer the solution here.
This should do it, although a solution using a CTE might be more readable, if your RDBMS supports them.
SELECT a.Room_Id, (SELECT Room_Beds FROM tbl_Rooms r WHERE r.Room_Id=a.Room_Id)-COUNT(*) AS unallocatedBeds
FROM tbl_allocatedRooms a
GROUP BY a.Room_Id
Related
I have a table named Ticket Numbers, which (for this example) contain the columns:
Ticket_Number
Assigned_Group
Assigned_Group_Sequence_No
Reported_Date
Each ticket number could contain 4 rows, depending on how many times the ticket changed assigned groups. Some of these rows could contain an assigned group of "Desktop Support," but some may not. Here is an example:
Example of raw data
What I am trying to accomplish is to get the an output that contains any ticket numbers that contain 'Desktop Support', but also the assigned group of the max sequence number. Here is what I am trying to accomplish with SQL:
Queried Data
I'm trying to use SQL with the following query but have no clue what I'm doing wrong:
select ih.incident_number,ih.assigned_group, incident_history2.maxseq, incident_history2.assigned_group
from incident_history_public as ih
left join
(
select max(assigned_group_seq_no) maxseq, incident_number, assigned_group
from incident_history_public
group by incident_number, assigned_group
) incident_history2
on ih.incident_number = incident_history2.incident_number
and ih.assigned_group_seq_no = incident_history2.maxseq
where ih.ASSIGNED_GROUP LIKE '%DS%'
Does anyone know what I am doing wrong?
You might want to create a proper alias for incident_history. e.g.
from incident_history as incident_history1
and
on incident_history1.ticket_number = incident_history2.ticket_number
and incident_history1.assigned_group_seq_no = incident_history2.maxseq
In my humble opinion a first error could be that I don't see any column named "incident_history2.assigned_group".
I would try to use common table expression, to get only ticket number that contains "Desktop_support":
WITH desktop as (
SELECT distinct Ticket_Number
FROM incident_history
WHERE Assigned_Group = "Desktop Support"
),
Than an Inner Join of the result with your inner table to get ticket number and maxSeq, so in a second moment you can get also the "MAXGroup":
WITH tmp AS (
SELECT i2.Ticket_Number, i2.maxseq
FROM desktop D inner join
(SELECT Ticket_number, max(assigned_group_seq_no) as maxseq
FROM incident_history
GROUP BY ticket_number) as i2
ON D.Ticket_Number = i2.Ticket_Number
)
SELECT i.Ticket_Number, i.Assigned_Group as MAX_Group, T.maxseq, i.Reported_Date
FROM tmp T inner join incident_history i
ON T.Ticket_Number = i.Ticket_Number and i.assigned_group_seq_no = T.maxseq
I think there are several different method to resolve this question, but I really hope it's helpful for you!
For more information about Common Table Expression: https://www.essentialsql.com/introduction-common-table-expressions-ctes/
I have a simple manufacturing job card system that track parts and labor for an assigned job.
It consists of a JobHeader table that holds the Job Card number (JobHeader.JobNo), ID of the part being manufactured (JobHeader.RegNo) and quantity to be manufactured (JobHeader.RegNo).
There is a child table (JobLabour) that tracks all the times that have been worked on the job (JobLabour.WorkedTime)
I'm looking for a query that will return the average time taken to produce a part accross the last 5 job cards for that particular part.
The following query
SELECT TOP 5 JobHeader.RegNo, JobHeader.BOMQty, sum(JobLabour.WorkedTime) AS TotalTime FROM JobHeader INNER JOIN JobLabour ON JobHeader.JobNo=JobLabour.JobNo
WHERE JobHeader.RegNo='RM-BRU-0134'
GROUP BY JobHeader.BOMQty, JobHeader.JobNo, JobHeader.RegNo
will return this:
But what I'm looking for is a query that will return the average BOMQty and average totalTime. Something like this:
Is there a way to do this?
Your question explicitly mentions the "last five" but does not specify how that is determined. Presumably, you have some sort of date/time column in the data that defines this.
In SQL Server, you can use apply:
select jh.*, jl.*
from jobheader jh outer apply
(select top (5) avg(BOMQty) as avg_BOMQty, avg(totalTime) as avg_totalTime
from (select top (5) jl.*
from joblabour jl
where jl.regno = jh.regno
order by jl.<some datetime> -- however you determine the last five
) jl
) jl;
You can add a where clause to the outer query to filter on one or more particular jobs.
If I understand you correctly this will do the work
this will work for 1 RegNo='RM-BRU-0134' at a time
with topFive as (
SELECT TOP 5 JobHeader.RegNo, JobHeader.BOMQty, sum(JobLabour.WorkedTime) AS TotalTime
FROM JobHeader
INNER JOIN JobLabour ON JobHeader.JobNo = JobLabour.JobNo
WHERE JobHeader.RegNo = 'RM-BRU-0134'
GROUP BY JobHeader.BOMQty, JobHeader.JobNo, JobHeader.RegNo
)
select RegNo, avg(BOMQty) as BOMQty, avg(TotalTime) as TotalTime
from topFive
group by RegNo
is there any other way for this problem .I wanted to use group by cant use ii.
my solution:
SQL> select (select count(dr_id)
from cus_detail c
where c.dr_id=d.dr_id) as count_cus,dr_name from driver_detail d;
COUNT_CUS DR_NAME
---------- ---------------
1 raju
0 mandi
2 sajuman
3 babu ram coi
0 daju
0 bare babu
use this one.
select count(c.dr_id) as count_cus, d.dr_name
from driver_detail d
inner join cus_detail c on c.dr_id=d.dr_id
group by d.dr_name
I'm not totally sure I understand what you're asking but I think you're asking how to group things and bring in data from another table
I typically prefer to do this as a grouping subquery:
select
d.dr_name,
c.ctr
from
(select dr_id, count(dr_id) ctr from cus_detail group by dr_id) c
INNER JOIN driver_detail d ON c.dr_id=d.dr_id
The reason why here is that by grouping on the id when counting means we can keep a count for two different people (i.e. different id) both called John. If instead we joined on id then grouped on the Name then two different people both called John would have their counts added together
It's also good to group and count in a subquery because sometimes grouping and counting in the outer query introduces wrong counts if three or more tables are related in 1:Many fashion. If a record in a had 3 records in b and 4 records in c, and we join all before we count we will count 12 records. If we group first we will be joining in 1:1 relationship instead and the counter won't inflate erroneously
If two DR_NAME are same then GROUP BY can give different result then what your current query will give.
So better to use an analytical function as the following:
SELECT
COUNT(C.DR_ID) OVER(
PARTITION BY C.DR_ID
) AS COUNT_CUS,
DR_NAME
FROM
DRIVER_DETAIL D
JOIN CUS_DETAIL C ON ( C.DR_ID = D.DR_ID )
Cheers!!
I think you want a basic aggregation query. Your method is correct (although it could be formatted better). The more standard method is join/group by:
select d.dr_name, count(c.dr_id)
from driver_detail d left join
cus_detail c
on c.dr_id = d.dr_id
group by d.dr_name;
I am working with POSTGRESQL and I can't find out how to solve a problem. I have a model called Foobar. Some of its attributes are:
FOOBAR
check_in:datetime
qr_code:string
city_id:integer
In this table there is a lot of redundancy (qr_code is not unique) but that is not my problem right now. What I am trying to get are the foobars that have same qr_code and have been in a well known group of cities, that have checked in at different moments.
I got this by querying:
SELECT * FROM foobar AS a
WHERE a.city_id = 1
AND EXISTS (
SELECT * FROM foobar AS b
WHERE a.check_in < b.check_in
AND a.qr_code = b.qr_code
AND b.city_id = 2
AND EXISTS (
SELECT * FROM foobar as c
WHERE b.check_in < c.check_in
AND c.qr_code = b.qr_code
AND c.city_id = 3
AND EXISTS(...)
)
)
where '...' represents more queries to get more persons with the same qr_code, different check_in date and those well known cities.
My problem is that I want to group this by qr_code, and I want to show the check_in fields of each qr_code like this:
2015-11-11 14:14:14 => [2015-11-11 14:14:14, 2015-11-11 16:16:16, 2015-11-11 17:18:20] (this for each different qr_code)
where the data at the left is the 'smaller' date for that qr_code, and the right part are all the other dates for that qr_code, including the first one.
Is this possible to do with a sql query only? I am asking this because I am actually doing this app with rails, and I know that I can make a different approach with array methods of ruby (a solution with this would be well received too)
You could solve that with a recursive CTE - if I interpret your question correctly:
Assuming you have a given list of cities that must be visited in order by the same qr_code. Your text doesn't say so, but your query indicates as much.
WITH RECURSIVE
c AS (SELECT '{1,2,3}'::int[] AS cities) -- your list of city_id's here
, route AS (
SELECT f.check_in, f.qr_code, 2 AS idx
FROM foobar f
JOIN c ON f.city_id = c.cities[1]
UNION ALL
SELECT f.check_in, f.qr_code, r.idx + 1
FROM route r
JOIN foobar f USING (qr_code)
JOIN c ON f.city_id = c.cities[r.idx]
WHERE r.check_in < f.check_in
)
SELECT qr_code, array_agg(check_in) AS check_in_list
FROM (
SELECT *
FROM route
ORDER BY qr_code, idx -- or check_in
) sub
HAVING count(*) = (SELECT array_length(cities) FROM c);
GROUP BY 1;
Provide the list as array in the first (non-recursive) CTE c.
In the recursive part start with any rows in the first city and travel along your array until the last element.
In the final SELECT aggregate your check_in column in order. Only return qr_code that have visited all cities of the array.
Similar:
Recursive query used for transitive closure
Need help on a query using sql server 2005
I am having two tables
code
chargecode
chargeid
orgid
entry
chargeid
itemNo
rate
I need to list all the chargeids in entry table if it contains multiple entries having different chargeids
which got listed in code table having the same charge code.
data :
code
100,1,100
100,2,100
100,3,100
101,11,100
101,12,100
entry
1,x1,1
1,x2,2
2,x3,2
11,x4,1
11,x5,1
using the above data , it query should list chargeids 1 and 2 and not 11.
I got the way to know how many rows in entry satisfies the criteria, but m failing to get the chargeids
select count (distinct chargeId)
from entry where chargeid in (select chargeid from code where chargecode = (SELECT A.chargecode
from code as A join code as B
ON A.chargecode = B.chargeCode and A.chargetype = B.chargetype and A.orgId = B.orgId AND A.CHARGEID = b.CHARGEid
group by A.chargecode,A.orgid
having count(A.chargecode) > 1)
)
First off: I apologise for my completely inaccurate original answer.
The solution to your problem is a self-join. Self-joins are used when you want to select more than one row from the same table. In our case we want to select two charge IDs that have the same charge code:
SELECT DISTINCT c1.chargeid, c2.chargeid FROM code c1
JOIN code c2 ON c1.chargeid != c2.chargeid AND c1.chargecode = c2.chargecode
JOIN entry e1 ON e1.chargeid = c1.chargeid
JOIN entry e2 ON e2.chargeid = c2.chargeid
WHERE c1.chargeid < c2.chargeid
Explanation of this:
First we pick any two charge IDs from 'code'. The DISTINCT avoids duplicates. We make sure they're two different IDs and that they map to the same chargecode.
Then we join on 'entry' (twice) to make sure they both appear in the entry table.
This approach gives (for your example) the pairs (1,2) and (2,1). So we also insist on an ordering; this cuts to result set down to just (1,2), as you described.