I have a schema with about 3000 tables in a PostgreSQL DB, all having one row with the following columns:
id, area, use, geom, site_id
However, I just discovered that there's at least one table that misses the column site_id. I'm wondering if there are more of those.. How can I query for tables NOT having the column site_id?
My following idea doesn't work. Any suggestions?
SELECT table_name
FROM information_schema.columns
WHERE table_schema = 'schema_A' AND column_name NOT LIKE 'site_id'
GROUP BY table_name;
An easy way would be counting how many times side_id appears in that table's column listing. If the sum is zero, the table has no site_id:
SELECT table_name
FROM information_schema.columns
WHERE table_schema = 'schema_A'
GROUP BY table_name
HAVING SUM(CASE WHEN column_name LIKE 'site_id' THEN 1 ELSE 0 END) = 0;
I'm also not sure if it was intentional or not, but LIKE 'site_id' will have the same effect as = 'site_id'. If you meant to check if it contains site_id, LIKE '%site_id%' would be more appropriate.
Related
I want to select for all tables with columns that contain the word deposit from a list of all tables when the owner is like bi. How can I implement this?
For example, I can select all tables and owner:
SELECT * FROM ALL_TABLES WHERE OWNER LIKE '%BI';
But I want to then select all tables from table_name and run a query to find those columns that are type character and contain the string deposit. This I cannot understand how to do.
UPDATE:
The following query worked:
SELECT *
FROM ALL_TAB_COLUMNS
WHERE OWNER LIKE '%BI'
AND DATA_TYPE
LIKE '%NUMBER'
AND COLUMN_NAME
LIKE '%DEPOSIT%';
Just change the data_type to varchar% (to catch varchar and varchar2):
SELECT DISTINCT TABLE_NAME
FROM DBA_TAB_COLUMNS TBLS
WHERE UPPER(TBLS.OWNER) LIKE '%BI'
AND UPPER(COLUMN_NAME) LIKE '%DEPOSIT%'
AND UPPER(DATA_TYPE) LIKE 'VARCHAR%';
My question is, is it possible to list all the columns from the whole database not just in specific tables based on 3 different criteria which ones are in an "OR" relationship. so for example I have database called "Bank" and I have 3 criterias "Criteria1; Criteria2; Criteria3" and if any of them is true so the relation between them should be OR and not AND than I will get back all the columns matching the criterias and the output put should provide "account_id" or "customer_id" from the same table.
How do I procced in this case?
It is possible, but you probably don't want to do it. Anyway, you could write a stored procedure that finds all tables that contain the columns you want:
select distinct table_name from user_tab_cols utc
where exists (select * from user_tab_cols where table_name = utc.table_name
and column_name = 'ACCOUNT_ID')
and exists (select * from user_tab_cols where table_name = utc.table_name
and column_name = 'CUSTOMER_ID');
Given the tables you could run a query where you append table name and your criteria:
execute immediate 'select account_id, customer_id from agreement where '
|| your_criteria_here;
A bit messy, inefficient and treat this as pseudo-code. However, if you really want to do this for an ad-hoq query it should point you in the right direction!
System is HP VERTICA 7.1
I am trying to create a SQL query which will dynamically find all particular tables in a specific schema that have a Timestamp column named DWH_CREATE_TIMESTAMP from system tables. (I have completed this part successfully)
Then, pass this list of tables to an outer query or some kind of looping statement which will select the MAX(DWH_CREATE_TIMESTAMP) and TABLE_NAME from all the tables in the list (200+) and union all the results together into one list.
The expected output is a 2 column table with all said tables with that TS field and the max of each value. Tables are constantly being created and dropped, so the point is to make everything totally dynamic where no TABLE_NAME values are ever hard-coded.
Any idea of Vertica specific ways to accomplish this without UDF's would be greatly appreciated.
Inner Query (working):
select distinct(table_name)
from columns
where column_name = 'DWH_CREATE_TIMESTAMP'
and table_name in (select DISTINCT(table_name) from all_tables where schema_name = 'PTG_DWH')
Outer Query (attempted - not working):
SELECT Max(DWH_CREATE_DATE) from
WITH table_name AS (
select distinct(table_name)
from columns
where column_name = 'DWH_CREATE_DATE' and table_name in (select DISTINCT(table_name) from all_tables where schema_name = 'PTG_DWH'))
SELECT MAX(DWH_CREATE_DATE)
FROM table_name
Thanks!!!
No way to do that in one SQL .
You can used the below method for node max timestamp columns values
select projections.anchor_table_name,vs_ros.colname,max(max_value) from vs_ros,vs_ros_min_max_values,storage_containers,projections where vs_ros.colname ilike 'timestamp'
and vs_ros.salstorageid=storage_containers.sal_storage_id
and vs_ros_min_max_values.rosid=vs_ros.rosid
and storage_containers.projection_name=projections.projection_name
group by projections.anchor_table_name,vs_ros.colname
I have a table tblEmployeeInfowhich has atleast a 100+ column name.
I want to know how many column name are in that table. Is that possible?
NOTE:
tbleEmployeeInfo has no data inside yet.
I would recommend using the INFORMATION_SCHEMA views. You can see all the columns and their types by doing:
select c.*
from INFORMATION_SCHEMA.COLUMNS c
where table_name = 'tbleEmployeeInfo';
(You might want to include the table_schema as well.)
To get the count, just use COUNT(*):
select count(*)
from INFORMATION_SCHEMA.COLUMNS c
where table_name = 'tbleEmployeeInfo';
SELECT COUNT(*)
FROM sys.columns
WHERE object_id = object_id('tblEmployeeInfo')
I want to find the tables that contain both of the two columns together in one table. I tried this:
SELECT COLUMN_NAME, TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME in ('CurrencyName', 'CurrencyKey');
This query generates all the tables that has either one of the CurrencyName or CurrencyKey column.
But I want the table that has both of these columns together.
Please shoot some ideas.
Thanks!
You are close. You want to use group by and then validate that you have two matches using a having clause:
SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME in ('CurrencyName', 'CurrencyKey')
GROUP BY TABLE_NAME
HAVING COUNT(*) = 2;
Note: To be sure you have the right table, you should use TABLE_SCHEMA as well in the query.