ORA-24344: success with compilation error - Trigger APEX - sql

Question

I've been working around this trigger and when I run the script it tells me the previous error message. I can't seem to figure out why it won't compile correctly, every pl/sql trigger tutorial seems to have the structure my trigger has. Code is the following:
create
or replace trigger new_artist before insert
on
Artist referencing new as nvartist declare counter number;
begin select
count( * ) into
counter
from
Performer
where
Stage_name = nvartist.Stage_name;
if counter > 0 then signal sqlstate '45000';
else insert
into
Artist
values(
nvartist.Stage_name,
nvartist.Name
);
insert
into
Performer
values(nvartist.Stage_name);
end if;
end;
It checks if the new artist already exists in its supertype (Performer), if it does exist it gives an error if it doesn't it inserts both into artist(Stage_name varchar2, Name varchar2) and Performer(Stage_name). Another subtype of Performer (and sibling to Artist) is Band(Stage_name), which in turn has a relationship with Artist. Why does the compiler yell at me for this trigger?
Thanks in advance

Answer 1

You may want to try this variant (I slightly modified names of your tables).
Creating tables with sample data:
CREATE table test_artist(
stage_name varchar2(100)
, name varchar2(100)
);
create table test_performer(
stage_name varchar2(100)
);
/*inserting test performer on which trigger will rise an error*/
insert into test_performer
select 'performer_1' from dual;
Creating trigger:
create or replace trigger new_artist
before insert
on TEST_ARTIST
referencing new as nvartist
for each row
declare
counter number;
begin
select count(*)
into counter
from test_performer
where Stage_name = :nvartist.Stage_name;
if counter > 0 then
--signal sqlstate '45000' ;
raise_application_error( -20001, 'No insertion with existing Performer');
else
/*you cant update the same table, in other case you'll get
ora-04091 table mutating error.
But nevertheless this values will be inserted by sql triggered this trigger.*/
--insert into test_artist values(:nvartist.Stage_name, :nvartist.Name);
insert into test_performer values(:nvartist.Stage_name);
end if;
end new_artist;
After that this insert will work, cause the is no 'performer_2' in 'test_performer' table:
insert into test_artist
select 'performer_2', 'name_2' from dual;
And this will fail:
insert into test_artist
select 'performer_1', 'name_1' from dual;