How to achieve the below??
Anyone help me out
col_1 col_2
A 1
B 1
C 1
B 2
C 4
A 2
A 6
Output:
A B C
1 1 1
2 2 4
6
This will do the job, but it seems like quite an odd thing to want to do, so I am probably missing something?
CREATE TABLE #table (col1 CHAR(1), col2 INT);
INSERT INTO #table SELECT 'A', 1;
INSERT INTO #table SELECT 'B', 1;
INSERT INTO #table SELECT 'C', 1;
INSERT INTO #table SELECT 'B', 2;
INSERT INTO #table SELECT 'C', 4;
INSERT INTO #table SELECT 'A', 2;
INSERT INTO #table SELECT 'A', 6;
WITH Ranked AS (
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY col1 ORDER BY col2) AS rank_id
FROM
#table),
Numbers AS (
SELECT 1 AS number
UNION ALL
SELECT number + 1 FROM Numbers WHERE number < 50)
SELECT
MAX(CASE WHEN col1 = 'A' THEN col2 END) AS [A],
MAX(CASE WHEN col1 = 'B' THEN col2 END) AS [B],
MAX(CASE WHEN col1 = 'C' THEN col2 END) AS [C]
FROM
Numbers n
INNER JOIN Ranked r ON r.rank_id = n.number
GROUP BY
n.number;
Results are:
A B C
1 1 1
2 2 4
6 NULL NULL
Looks like you are trying to pivot without aggregation? Here is another option:
select A, B, C from
( select col1, col2, dense_rank() over (partition by col1 order by col2) dr from #table) t
pivot
( max(t.col2) for t.col1 in (A, B, C)) pvt;
Also check this out for more examples/discussion: TSQL Pivot without aggregate function
Related
For example: I have a table with these records below
1 A
2 A
3 B
4 C
...
and I need to migrate these record in to another table
1 AA
2 AB
3 B
4 C
...
Meaning if the record is duplicate, it will automatically add one more letter alphabetically.
Just a slightly different approach
Example
Declare #YourTable Table (ID int,[SomeCol] varchar(50))
Insert Into #YourTable Values
(1,'A')
,(2,'A')
,(3,'B')
,(4,'C')
Select *
,NewVal = concat(SomeCol,IIF(sum(1) over (partition by SomeCol)=1,'',char(64+row_number() over ( partition by SomeCol order by ID ))) )
From #YourTable
Returns
ID SomeCol NewVal
1 A AA
2 A AB
3 B B
4 C C
EDIT - Requested UPDATE
Declare #YourTable Table (ID int,[SomeCol] varchar(50))
Insert Into #YourTable Values
(1,'A')
,(2,'A')
,(3,'B')
,(4,'C')
Select *
,NewVal = concat(SomeCol,IIF(sum(1) over (partition by SomeCol)=1,'',replace(char(63+row_number() over ( partition by SomeCol order by ID )),'#','')) )
From #YourTable
Returns
ID SomeCol NewVal
1 A A
2 A AA
3 B B
4 C C
We might be able to handle this requirement with the help of a calendar table mapping secondary letters to duplicate sequence counts:
WITH letters AS (
SELECT 1 AS seq, 'A' AS let UNION ALL
SELECT 2, 'B' UNION ALL
SELECT 3, 'C' UNION ALL
...
SELECT 26, 'Z' UNION ALL
...
),
cte AS (
SELECT id, let, ROW_NUMBER() OVER (PARTITION BY let ORDER BY id) rn,
COUNT(*) OVER (PARTITION BY let) cnt
FROM yourTable
)
SELECT t1.id, t1.let + CASE WHEN t1.cnt > 1 THEN t2.let ELSE '' END AS let
FROM cte t1
LEFT JOIN letters t2
ON t1.id = t2.seq
ORDER BY t1.id;
Demo
I've got a table A with 3 columns that contains the same data, for exemple:
TABLE A
KEY COL1 COL2 COL3
1 A B C
2 B C null
3 A null null
4 D E F
5 null C B
6 B C A
7 D E F
As a result I expect the distinct values of this table and the order doesn't matter. So key 1 and 6 are the same and 2 and 5 also and 4 and 7. The rest is different.
Ofcourse, I can't use a distinct in my select that will only filter 4 and 7.
I could use a very complex case statement, or a select in a select with an order by. But this needs to be used in a conversion, so performance is an issue here.
Does anyone have a good performant way to do this?
The result I expect
COL1 COL2 COL3
A B C
B C null
A null null
D E F
If you can have many columns then you can UNPIVOT then order the values and then PIVOT and take the DISTINCT rows:
Oracle Setup:
CREATE TABLE table_name ( KEY, COL1, COL2, COL3 ) AS
SELECT 1, 'A', 'B', 'C' FROM DUAL UNION ALL
SELECT 2, 'B', 'C', null FROM DUAL UNION ALL
SELECT 3, 'A', null, null FROM DUAL UNION ALL
SELECT 4, 'D', 'E', 'F' FROM DUAL UNION ALL
SELECT 5, null, 'C', 'B' FROM DUAL UNION ALL
SELECT 6, 'B', 'C', 'A' FROM DUAL UNION ALL
SELECT 7, 'D', 'E', 'F' FROM DUAL
Query:
SELECT DISTINCT
COL1, COL2, COL3
FROM (
SELECT key,
value,
ROW_NUMBER() OVER ( PARTITION BY key ORDER BY value ) AS rn
FROM table_name
UNPIVOT ( value FOR name IN ( COL1, COL2, COL3 ) ) u
)
PIVOT ( MAX( value ) FOR rn IN (
1 AS COL1,
2 AS COL2,
3 AS COL3
) )
Output:
COL1 | COL2 | COL3
:--- | :--- | :---
A | B | C
B | C | null
D | E | F
A | null | null
db<>fiddle here
The complicated case expression is going to have the best performance. But the simplest method is going to be conditional aggregation:
select key,
max(case when seqnum = 1 then col end) as col1,
max(case when seqnum = 2 then col end) as col2,
max(case when seqnum = 3 then col end) as col3
from (select key,col,
row_number() over (partition by key order by col asc) as seqnum
from ((select key, col1 as col from t) union all
(select key, col2 as col from t) union all
(select key, col3 as col from t)
) kc
where col is not null
) kc
group by key;
Assume I have a table with 4 columns:
Col1 Col2 Col3 Col4
My initial query is :
SELECT Col1, Col2, Col3, Col4
FROM myTable
ORDER BY Col1, Col2, Col3 DESC, Col4
My desired result is all 4 columns, but with this condition that Top N Col3 different row when Col1, Col2 is equal.
Example with N=2 :
Table sample data:
Col1 Col2 Col3 Col4
---------------------
1 a 2000 s
1 a 2002 c
1 a 2001 b
2 b 1998 s
2 b 2002 c
2 b 2000 b
3 c 2000 b
1 f 1998 n
1 g 1999 e
Desired result:
1 a 2002 c
1 a 2001 b
1 f 1998 n
1 g 1999 e
2 b 2002 c
2 b 2000 b
3 c 2000 b
In another description, when (col1, col2) is repeated in multiple records, just export top N rows of those records when order by Col3 descending.
Can I do this with SQL script, without hard coding?
declare #t table (Col1 int, Col2 char, Col3 int, Col4 char);
insert into #t values
(1, 'a', 2000, 's'),
(1, 'a', 2002, 'c'),
(1, 'a', 2001, 'b'),
(2, 'b', 1998, 's'),
(2, 'b', 2002, 'c'),
(2, 'b', 2000, 'b'),
(3, 'c', 2000, 'b'),
(1, 'f', 1998, 'n'),
(1, 'g', 1999, 'e');
declare #N int = 2; -- number per "top"
with cte as
(
select *,
row_number() over(partition by col1, col2 order by col3 desc) as rn
from #t
)
select *
from cte c
where rn <= #N;
I think below code was as expected
declare #tab table (Col1 int, Col2 char(1), Col3 int, Col4 char(1))
declare #N int
insert into #tab
select 1, 'a' , 2000, 's'
union all
select 1 , 'a' , 2002 , 'c'
union all
select 1 , 'a' , 2001 , 'b'
union all
select 2 , 'b' , 1998 , 's'
union all
select 2 , 'b' , 2002 ,'c'
union all
select 2 , 'b' , 2000 ,'b'
union all
select 3 , 'c' , 2000 ,'b'
union all
select 1 , 'f' , 1998 ,'n'
union all
select 1 , 'g' , 1999 ,'e'
;with tab as
(
select ROW_NUMBER() over(partition by t.col1,t.col2 order by t.col3 desc) as row,t.*
from #tab t
)
select Col1,Col2,Col3,Col4
from tab
where row < 3
output
Col1 Col2 Col3 Col4
1 a 2002 c
1 a 2001 b
1 f 1998 n
1 g 1999 e
2 b 2002 c
2 b 2000 b
3 c 2000 b
METHOD 1- FOR MSSQL
http://sqlfiddle.com/#!6/4bda39/6
with a as (
select ROW_NUMBER() over(partition by t.col1,t.col2 order by t.col3 desc) as row,t.*
from myTable as t)
select * from a where a.row <= 2
Replace a.row <= 2 (2 with your N)
METHOD 2- FOR MYSQL
http://sqlfiddle.com/#!9/79e81a/63
SELECT myTable.Col1, myTable.Col2, myTable.Col3, myTable.Col4
FROM (
Select Col1 as Col1, Col2 as Col2, count(Col1) as cc, AVG(Col3) as aa
From myTable
group by Col1, Col2) as tt
join myTable on myTable.Col1 = tt.Col1 and myTable.Col2 = tt.Col2
where myTable.Col3 >= tt.aa
Order by Col1 ,Col2 ,Col3 Desc,Col4
METHOD 3- FOR MYSQL
http://sqlfiddle.com/#!9/79e81a/79
SELECT * FROM (
SELECT CASE Col1
WHEN #Col1 THEN
CASE Col2
WHEN #Col2 THEN #curRow := #curRow + 1
ELSE #curRow := 1
END
ELSE #curRow :=1
END AS rank,
#Col1 := Col1 AS Col1,
#Col2 := Col2 AS Col2,
Col3, Col4
FROM myTable p
JOIN (SELECT #curRow := 0, #Col1 := 0, #Col2 := '') r
ORDER BY Col1, Col2, Col3 DESC) as tt
WHERE tt.rank <= 2
Replace tt.rank <= 2 replace 2 by your desired index
If I have a table like this:
Col 1 | Col 2
-------------
A | 1
A | 2
B | 1
C | 1
C | 2
C | 3
How can I write a query to pull one column that looks like this --
Col 1
------
A
1
2
B
1
C
1
2
3
SELECT col1
FROM Some_Table_You_Did_Not_Name
UNION ALL
SELECT col2
FROM Some_Table_You_Did_Not_Name
If the order matters in your example then you want this:
WITH data AS
(
SELECT col1, col2, ROW_NUMBER() OVER (ORDER BY col1, col2) as RN
FROM Some_Table_You_Did_Not_Name
)
SELECT col
FROM (
SELECT DISTINCT col1 as col, RN, 1 as O
FROM data
UNION ALL
SELECT DISTINCT col2 as col, RN, 2 as O
FROM data
) JC_IS_THAT_GUY
ORDER BY RN ASC, O ASC, col ASC
You can use a query like the following:
SELECT Col1
FROM (
SELECT DISTINCT Col1, Col1 AS Col2, 0 AS grp
FROM mytable
UNION ALL
SELECT Col2 AS Col1, Col1 AS Col2, 1 AS grp
FROM mytable) AS t
ORDER BY Col2, grp, Col1
Demo here
There is absolutely no need to do a UNION, UNION ALL or reference the table more than once to unpivot data...
-- if Col2 is always a well ordered sequense like the test data...
SELECT
Col1 = x.Value
FROM
#TestData td
CROSS APPLY ( VALUES (IIF(td.Col2 = 1, td.Col1, NULL)), (CAST(td.Col2 AS CHAR(1))) ) x (Value)
WHERE
x.Value IS NOT NULL;
-- if it isn't...
WITH
cre_Add_RN AS (
SELECT
td.Col1,
td.Col2,
RN = ROW_NUMBER() OVER (PARTITION BY td.Col1 ORDER BY td.Col2)
FROM
#TestData td
)
SELECT
x.Value
FROM
cre_Add_RN arn
CROSS APPLY ( VALUES (IIF(arn.RN = 1, arn.Col1, NULL)), (CAST(arn.Col2 AS CHAR(1))) ) x (Value)
WHERE
x.Value IS NOT NULL;
HTH,
Jason
I have a table as such
Col 1 Col 2 Col 3
1 A 1
2 A 2
3 B 1
4 C 1
5 C 2
6 D 1
How do I only get unique rows which have Col 3 = 1?
I want to get rows 3 and 6 (Col 2 = B and D respectively). I do not want A nor C since they have Col 3 = 2 as well.
I've tried something along the lines of:
select col 2 from table group by col 2 having count(col 3) = 1
But that only brings up Col 2 for results so I'm uncertain if Col 3 contents = 1 or not.
EDIT: Sorry guys maybe I've not worded my question clearly. I want to get all of the rows of Col 2 which contain only Col 3 = 1 AND ONLY 1.
So if I tried WHERE Col 3= 1, it would return 4 rows because A has 1. But since A also has a row where Col 3 = 2, I do not want that, same for C. From this example table, I would want the end result to only show 2 rows, B and D.
My example table is an example, I actually have about 5000 rows to filter through, otherwise I'd do as you guys have suggested :)
SELECT col2
FROM your_table
GROUP BY col2
HAVING MAX(col3) = 1 AND MIN(Col3) = 1
Or
SELECT a.col2
FROM your_table a
WHERE a.col3=1 AND NOT EXISTS(SELECT *
FROM your_table b
WHERE a.col2=b.col2 AND b.col3<>1)
What you are probably looking for is WHERE clause.
SELECT * FROM YouTable WHERE col3 = 1 AND col2 in ('B','D');
;with T ([Col 1], [Col 2], [Col 3]) as
(
select 1, 'A', 1 union all
select 2, 'A', 2 union all
select 3, 'B', 1 union all
select 4, 'C', 1 union all
select 5, 'C', 2 union all
select 6, 'D', 1
)
select *
from T
left outer join
(
select distinct [Col 2]
from T
where [Col 3] <> 1
) as T2
on T.[Col 2] = T2.[Col 2]
where T.[Col 3] = 1 and
T2.[Col 2] is null
It's a bit hard to know exactly what you're trying to get, but this is my best guess:
SELECT * FROM theTable WHERE col2 NOT IN
(SELECT col2 FROM theTable WHERE col3 <> 1)
SELECT * FROM #temp t1
WHERE EXISTS
(
select Col2 from #Temp t2
WHERE t2.Col2 = t1.Col2
group by col2
having count(col3) = 1
)
tested with MS SQL2008 and the following (so if my answer is not the correct one it may halp others test theirs...):
CREATE TABLE #temp
(
Col1 INT,
Col2 CHAR(1),
Col3 INT
)
INSERT INTO #Temp
(Col1, Col2, Col3)
SELECT 1,'A',1
UNION
SELECT 2,'A',2
UNION
SELECT 3,'B', 1
UNION
SELECT 4,'C',1
UNION
SELECT 5,'C',2
UNION
SELECT 6,'D',1
SELECT * FROM #temp t1
WHERE EXISTS
(
select Col2 from #temp t2
WHERE t2.Col2 = t1.Col2
group by col2
having count(col3) = 1
)
DROP TABLE #temp