Is there any way to generate a custom sequential number like the following?
I want the Number to be incremented with grouping by the Code and Year.
Code Year Number
A 2016 1
A 2016 2
A 2016 3
B 2016 1
B 2016 2
C 2016 1
A 2017 1
A 2017 2
Any suggestion would be appreciated.
EDIT
Sorry, I was too ambiguous what I want. I want to generate the unique number when I query, so if I ask a new number in the above data context with Code:A and Year:2017, I want the Number to be 3. I guess to get the Number properly in a future I need to save the Code and Year with the Number.
Use ROW_NUMBER to assign Number per Code,Year grouping.
SELECT *,
Number = ROW_NUMBER() OVER(PARTITION BY Code, [Year] ORDER BY (SELECT NULL))
FROM tbl
Replace SELECT NULL with the column you want the order to be based from.
Related
I'm trying to get the minimum value of open, across multiple rows of year. This is from app.mode.com and the site only says SQL, not sure which version
SELECT year, open
FROM tutorial.aapl_historical_stock_price
WHERE open =
(
select MIN(open)
FROM tutorial.aapl_historical_stock_price
)
When I use the code above, the result is
Table result vs actual output
Year
Open
2000
0
2000
0
2000
0
What I'm trying to get is
Year
Open
2002
0
2001
0
2000
0
Can someone help point me what I'm doing wrong?
select year and get the min by grouping each year as following:
select
year
, min(open) as <desired_alias>
from your_table
group by 1
order by 1 desc;
Not sure how to put this in a straight forward manner but I'm trying to make something work in Hive SQL. I need to create a sequence of numbers from lower limit to upper limit.
Ex:
select min(year) from table
Let's assume it results in 2010
select max(year) from table
Let's assume it results in 2015
I need to publish each year from 2010 to 2015 in a select query.
And I'm trying to put the min calculation & max calculation inside the same SQL which will/should create sequential years in the output.
Any ideas?
Well I have an idea but in order to use it, you will have to define the lowest possible and the largest possible values for the years that might be present in your table.
Let's say the smallest possible year is 1900 and the largest possible year is 2200.
Since the largest possible difference in this case is 2200-1900=300, you will have to use the following string: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 ... ... 298 299 300.
In the query, you split this string using space as a delimiter thus getting an array, and then you explode that array.
Have a look:
SELECT
minval + delta
FROM
(
SELECT
min(year) minval,
max(year) maxval,
split('0 1 2 3 4 5 6 7 8 9 10 11 12 13 ... ... ... 298 299 300', ' ') delta_list
FROM
table
) t
LATERAL VIEW explode(delta_list) dlist AS delta
WHERE (maxval-minval) >= delta
;
So you end up with 301 rows but you only need the rows with delta values not exceeding the difference between max year and min year, which is reflected in the where clause
set hivevar:end_year=2019;
set hivevar:start_year=2010;
select ${hivevar:start_year}+i as year
from
(
select posexplode(split(space((${hivevar:end_year}-${hivevar:start_year})),' ')) as (i,x)
)s;
Result:
year
2010
2011
2012
2013
2014
2015
2016
2017
2018
2019
Have a look also at this answer about generating missing dates.
How do I average the last 6 months of sales within SQL?
Here are my tables and fields:
IM_ItemWhseHistoryByPeriod.FISCALCALPERIOD,
IM_ItemWhseHistoryByPeriod.FISCALCALYEAR,
And I need to average these fields
IM_ItemWhseHistoryByPeriod.DOLLARSSOLD,
IM_ItemWhseHistoryByPeriod.QUANTITYSOLD,
The hard part I'm having is understanding how to average the last whole 6 months, ie. fsicalcalperiod 2-6(inside fiscalcalyear 2017).
I'm hoping for some help on what the SQL command text should look like since I'm very new to manipulating SQL outside of the UI.
Sample Data
My Existing SQL String:
SELECT IM_ItemWhseHistoryByPeriod.ITEMCODE,
IM_ItemWhseHistoryByPeriod.DOLLARSSOLD,
IM_ItemWhseHistoryByPeriod.QUANTITYSOLD,
IM_ItemWhseHistoryByPeriod.FISCALCALPERIOD,
IM_ItemWhseHistoryByPeriod.FISCALCALYEAR
FROM MAS_AME.dbo.IM_ItemWhseHistoryByPeriod
IM_ItemWhseHistoryByPeriod
ScaisEdge Attempt #1
if fiscalyear and fiscalperiod are number you could use
select avg(IM_ItemWhseHistoryByPeriod.DOLLARSSOLD) ,
avg(IM_ItemWhseHistoryByPeriod.QUANTITYSOLD)
from my_table
where IM_ItemWhseHistoryByPeriod.FISCALCALYEAR = 2017
and IM_ItemWhseHistoryByPeriod.FISCALCALPERIOD between 2 and 6
or for each item code
select itemcode, avg(IM_ItemWhseHistoryByPeriod.DOLLARSSOLD) ,
avg(IM_ItemWhseHistoryByPeriod.QUANTITYSOLD)
from my_table
where IM_ItemWhseHistoryByPeriod.FISCALCALYEAR = 2017
and IM_ItemWhseHistoryByPeriod.FISCALCALPERIOD between 2 and 6
group by itemcode
Try the following solution and see if it works for you:
select avg(DOLLARSSOLD) as AvgDollarSod,
avg(QUANTITYSOLD) as AvgQtySold
from IM_ItemWhseHistoryByPeriod
where FISCALCALYEAR = '2017
and FISCALCALPERIOD between 2 and 6
I have the following table, let's call it Names:
Name Id Date
Dirk 1 27-01-2015
Jan 2 31-01-2015
Thomas 3 21-02-2015
Next I have the another table called Consumption:
Id Date Consumption
1 26-01-2015 30
1 01-01-2015 20
2 01-01-2015 10
2 05-05-2015 20
Now the problem is, that I think that doing this using SQL is the fastest, since the table contains about 1.5 million rows.
So the problem is as follows, I would like to match each Id from the Names table with the Consumption table provided that the difference between the dates are the lowest, so we have: Dirk consumes on 27-01-2015 about 30. In case there are two dates that have the same "difference", I would like to calculate the average consumption on those two dates.
While I know how to join, I do not know how to code the difference part.
Thanks.
DBMS is Microsoft SQL Server 2012.
I believe that my question differs from the one mentioned in the comments, because it is much more complicated since it involves comparison of dates between two tables rather than having one date and comparing it with the rest of the dates in the table.
This is how you could it in SQL Server:
SELECT Id, Name, AVG(Consumption)
FROM (
SELECT n.Id, Name, Consumption,
RANK() OVER (PARTITION BY n.Id
ORDER BY ABS(DATEDIFF(d, n.[Date], c.[Date]))) AS rnk
FROM Names AS n
INNER JOIN Consumption AS c ON n.Id = c.Id ) t
WHERE t.rnk = 1
GROUP BY Id, Name
Using RANK with PARTITION BY n.Id and ORDER BY ABS(DATEDIFF(d, n.[Date], c.[Date])) you can locate all matching records per Id: all records with the smallest difference in days are going to have rnk = 1.
Then, using AVG in the outer query, you are calculating the average value of Consumption between all matching records.
SQL Fiddle Demo
I have a question regarding Oracle SQL.
My data looks like this:
id year
-- ----
1 2000
1 2001
1 2002
1 2003
1 2006
1 2000
2 2001
2 2002
2 2003
3 2003
3 2005
4 2012
4 2013
I want the id's which have the years 2001, 2002, 2003.
My result set:
id
--
1
2
Please help me with this. I actually tried searching this, but couldn't figure a way to search about my particular problem.
SQL
SELECT t.id
FROM TABLE t
WHERE t.year in(2001,2002,2003)
GROUP BY t.id
Sample SqlFiddle
http://sqlfiddle.com/#!2/4ec9f/2/0
Explanation
You want to filter your data set to only show rows with certain years, so that is what you put in the where clause WHERE t.year in(2001,2002,2003).
Since a single id can be in multiple years, your result set would contain duplicates. To remove the duplicates you could GROUP BY the ID or use the DISTINCT statement to only show unique elements.
UPDATE
Based on comments, here's a version that will only display id's that have all three years. We use DISTINCT t.YEAR to avoid counting id's that perhaps would have a single year repeated multiple times. The HAVING COUNT(DISTINCT t.YEAR) = 3 part ensures that we only include id's that have all three years.
SELECT t.id
FROM years t
WHERE t.year in(2001,2002,2003)
GROUP BY t.id
HAVING COUNT(DISTINCT t.YEAR) = 3
Updated sqlFiddle, which includes a data set where id of 3 has two rows for 2003 to show off the logic that only counts unique years for an ID.
select distinct id
from table
where year in(2001,2002,2003)