i'm after the data obtained by my two queries plus any other data from the driving table. I'm using the following code but have a feeling my results are wrong.
select * from(
select * from tbl_a a
inner join tbl_b b on (a.id = b.id and a.col_a = b.col_b and a.col_c = '1')
union all
select * from tbl_a a
inner join tbl_b b on (a.col_a = b.col_b and a.col_c = '1')
where (1=1)
and a.id <> b.id
and a.start_time <= b.u_start_time
and a.end_time >= b.u_end_time
union all
select * from tbl_a a
where a.another_id
NOT IN ( -- either query above)
) results;
I'd just like to know if this makes sense or how I could possibly simplify some of this...
Here is query for the first 2 unions,and it is not clear what is the third union condition
SELECT *
FROM
tbl_a a
left join tbl_b b on b.id = a.id and b.col_b = a.col_a
left join tbl_b b1 on a.col_a= b1.col_b and a.id<>b1.id and a.start_time<=b1.u_start_time and a.end_time>=b1.u_end_time
WHERE
a.col_c=1
and COALESCE(b.id,b1.id) is not null
Related
I am working on a personal project.
I have the following data
tbl A
id, blah, blah
tbl B
id, id_2
tbl C
id_2, Result
I have check for the following, if id in tbl A exists in tbl B AND if Pass = 'A'.
I can write a query to check for the keys in A exists in B.
Something like,
SELECT * FROM tblA as a
WHERE NOT EXISTS (
SELECT * FROM tblB as b
WHERE a.id = b.id)
And this works fine.
I can also write something with an INNER JOIN
SELECT *
FROM tabC
INNER JOIN tblB ON tblC.id2 = tblB.id2
INNER JOIN tblA ON tblB.id = tblA.id
WHERE Result = 'A' GROUP BY id
But I can't seem to figure out how to combine both these queries together.
you can try like below
SELECT c.*
FROM tabC c
INNER JOIN tblB b ON c.id2 = b.id2
INNER JOIN tblA a ON b.id = a.id
WHERE Result = 'A'
and NOT EXISTS (
SELECT 1 FROM tblB as b1
WHERE a.id = b1.id)
I've got two queries that return single result.
They look something like this
// query 1
SELECT A.id FROM tableA A
INNER JOIN tableB B
ON B.id = A.id
WHERE b.status = 'ACTIVE'
// query 2
SELECT C.id FROM tableC C
WHERE c.status = 'ACTIVE'
How to combine them and make return the pair of values instead of one value from different queries? I mean to get something like [A.id, C.id]
Currently I have to use two queries in the applications and I want to combine them into one.
I think like this will do
SELECT (SELECT A.id FROM tableA A
INNER JOIN tableB B
ON B.id = A.id
WHERE b.status = 'ACTIVE'
) as 'query1',
(
SELECT C.id FROM tableC C
WHERE c.status = 'ACTIVE'
) as 'query2'
As your question is not clear, so i assume that you either needids from mentioned queries in one row or in different rows, you can use union all/union (provided that datatypes are compatible or implicitly convertible and duplicates or allowed or not) as below.
Combining Result in different rows.
SELECT A.id
FROM tableA A
INNER JOIN tableB B
ON B.id = A.id
WHERE b.status = 'ACTIVE'
union all
SELECT C.id
FROM tableC C
WHERE c.status = 'ACTIVE'
Combining Result in Single Row.
select max(id1), max(id2)
from(
SELECT A.id as id1, NULL as id2
FROM tableA A
INNER JOIN tableB B
ON B.id = A.id
WHERE b.status = 'ACTIVE'
union all
SELECT NULL, C.id
FROM tableC C
WHERE c.status = 'ACTIVE'
) t;
SAMPLE DEMO
You can run following query which work fine for me:
select t1.id as aid ,t2.id as cid
from (
SELECT A.id
FROM tableA A
INNER JOIN tableB B ON B.id = A.id
WHERE b.status = 'ACTIVE'
) t1
full outer join (
SELECT C.id
FROM tableC C
WHERE c.status = 'ACTIVE'
) t2 on t1.id=t2.id
You can join your second query with your first query as follows, so that you will get two (A.id, C.id) values in one query...
SELECT A.ID,C.ID FROM
(SELECT A.ID FROM table_A A INNER JOIN
table_B B ON A.ID=B.ID WHERE B.STATUS='A')A
INNER JOIN table_c C
ON C.ID=A.ID WHERE C.STATUS='A';
I have two tables, A and B, and I just want get all the entries in A but not in B, and both tables are partitioned by dt, so I did the following:
1) select A.* from A left join B on A.key=B.key where B.key is null and A.dt=20170101 and B.dt=20170101 -- wrong result
2) select A.* from A left join B on (A.key=B.key and A.dt=20170101 and B.dt=20170101) -- wrong result
3) select A1.* from (select * from A where dt=20170101) A1 left join (select * from B where dt=2017101) B1 on A1.key=B1.key -- correct result
Why 1) and 2) don't work? I'm so confused...
1) select A.* from A left join B on A.key=B.key where B.key is null and A.dt=20170101 and B.dt=20170101 -- wrong result
where B.key is null and B.dt=20170101 are mutually exclusive if A.key=B.key. This basically turned your query into:
select A.*
from A
inner join B
on 1=0
2) select A.* from A left join B on (A.key=B.key and A.dt=20170101 and B.dt=20170101) -- wrong result`
A.dt=20170101 is only applied to the join condition, not the result. This means you would get all of the dt for A.
3) select A1.* from (select * from A where dt=20170101) A1 left join (select * from B where dt=2017101) B1 on A1.key=B1.key -- correct result
These would give you the same result:
select a.*
from A
left join B1
on A.Key = B.Key
and B.dt = 20170101
where A.dt = 20170101
select a.*
from A
left join B
on A.Key = B.Key
and A.dt = B.dt
where A.dt = 20170101
This is a sql server demo, but it might help illustrate: http://rextester.com/JCZENB83359
I have table A, B and C
I want to return all entries in table A that do not exist in table B and of that list do not exist in table C.
select * from table_A as a
where not exists (select 1 from table_B as b
where a.id = b.id)
this gives me the first result of entries in A that are not in B. But now I want only those entries of this result that are also not in C.
I tried flavours of:
select * from table_A as a
where not exists (select 1 from table_B as b
where a.id = b.id)
AND
where not exists (select 1 from table_C as c
where a.id = c.id)
But that isnt the correct logic. If there is a way to store the results from the first query and then select * from that result that are not existent in table C. But I'm not sure how to do that. I appreciate the help.
Try this:
select * from (
select a.*, b.id as b_id, c.id as c_id
from table_A as a
left outer join table_B as b on a.id = b.id
left outer join table_C as c on c.id = a.id
) T
where b_id is null
and c_id is null
Another implementation is this:
select a1.*
from table_A as a1
inner join (
select a.id from table_A
except
select b.id from table_B
except
select c.id from table_c
) as a2 on a1.id = a2.id
Note the restrictions on the form of the sub-query as described here. The second implementation, by most succinctly and clearly describing the desired operation to SQL Server, is likely to be the most efficient.
You have two WHERE clauses in (the external part of) your second query. That is not valid SQL. If you remove it, it should work as expected:
select * from table_A as a
where not exists (select 1 from table_B as b
where a.id = b.id)
AND
not exists (select 1 from table_C as c -- WHERE removed
where a.id = c.id) ;
Tested in SQL-Fiddle (thnx #Alexander)
how about using LEFT JOIN
SELECT a.*
FROM TableA a
LEFT JOIN TableB b
ON a.ID = b.ID
LEFT JOIN TableC c
ON a.ID = c.ID
WHERE b.ID IS NULL AND
c.ID IS NULL
SQLFiddle Demo
One more option with NOT EXISTS operator
SELECT *
FROM dbo.test71 a
WHERE NOT EXISTS(
SELECT 1
FROM (SELECT b.ID
FROM dbo.test72 b
UNION ALL
SELECT c.ID
FROM dbo.test73 c) x
WHERE a.ID = x.ID
)
Demo on SQLFiddle
Option from #ypercube.Thank for the present;)
SELECT *
FROM dbo.test71 a
WHERE NOT EXISTS(
SELECT 1
FROM dbo.test72 b
WHERE a.ID = b.ID
UNION ALL
SELECT 1
FROM dbo.test73 c
WHERE a.ID = c.ID
);
Demo on SQLFiddle
I do not like "not exists" but if for some reason it seems to be more logical to you; then you can use a alias for your first query. Subsequently, you can re apply another "not exists" clause. Something like:
SELECT * FROM
( select * from tableA as a
where not exists (select 1 from tableB as b
where a.id = b.id) )
AS A_NOT_IN_B
WHERE NOT EXISTS (
SELECT 1 FROM tableC as c
WHERE c.id = A_NOT_IN_B.id
)
I can't get the syntax right for aliasing the derived table correctly:
SELECT * FROM
(SELECT a.*, b.*
FROM a INNER JOIN b ON a.B_id = b.B_id
WHERE a.flag IS NULL AND b.date < NOW()
UNION
SELECT a.*, b.*
FROM a INNER JOIN b ON a.B_id = b.B_id
INNER JOIN c ON a.C_id = c.C_id
WHERE a.flag IS NOT NULL AND c.date < NOW())
AS t1
ORDER BY RAND() LIMIT 1
I'm getting a Duplicate column name of B_id. Any suggestions?
The problem isn't the union, it's the select a.*, b.* in each of the inner select statements - since a and b both have B_id columns, that means you have two B_id cols in the result.
You can fix that by changing the selects to something like:
select a.*, b.col_1, b.col_2 -- repeat for columns of b you need
In general, I'd avoid using select table1.* in queries you're using from code (rather than just interactive queries). If someone adds a column to the table, various queries can suddenly stop working.
In your derived table, you are retrieving the column id that exists in table a and table b, so you need to choose one of them or give an alias to them:
SELECT * FROM
(SELECT a.*, b.[all columns except id]
FROM a INNER JOIN b ON a.B_id = b.B_id
WHERE a.flag IS NULL AND b.date < NOW()
UNION
SELECT a.*, b.[all columns except id]
FROM a INNER JOIN b ON a.B_id = b.B_id
INNER JOIN c ON a.C_id = c.C_id
WHERE a.flag IS NOT NULL AND c.date < NOW())
AS t1
ORDER BY RAND() LIMIT 1
First, you could use UNION ALL instead of UNION. The two subqueries will have no common rows because of the excluding condtion on a.flag.
Another way you could write it, is:
SELECT a.*, b.*
FROM a
INNER JOIN b
ON a.B_id = b.B_id
WHERE ( a.flag IS NULL
AND b.date < NOW()
)
OR
( a.flag IS NOT NULL
AND EXISTS
( SELECT *
FROM c
WHERE a.C_id = c.C_id
AND c.date < NOW()
)
)
ORDER BY RAND()
LIMIT 1